can someone help me to write a query?
I have for example columns:
Date
product_key
category_code
In one day I expect to have same category_code for one product, but I want to check this with SQL.
Thank you.
If you want to find the day, the product_key and the category_code that doubles, You should use query like this:
SELECT
date,
product_key,
category_code,
count(1)
FROM your_table
GROUP BY date, product_key, category_code
HAVING count(1) > 1;
You can group your results by date and product, and use count and distinct to find if there is more than one category code for a product. You can then filter rows having more than 1 distinct category in the group.
SELECT
Date, product_key, count(distinct category_code) AS categories
FROM
my_table
GROUP BY
Date, product_key
HAVING
count(distinct category_code) > 1
Related
I have a table called Table1. I am trying to get the weekly average, but I only have daily data. My table contains the following attributes: caseID, date, status and some other (irrelevant) attributes. With the following query, I made the following table which comes close to what I want:
However, I would like to add a average per week of the number of cases. I have look everywhere, but I am not sure how to include that. Has anybody any clues for how to add that.
Thanks.
To expand on #luuk's answer...
SELECT
date,
COUNT(id) as countcase,
EXTRACT(WEEK FROM date) AS weeknbr,
AVG(COUNT(id)) OVER (PARTITION BY EXTRACT(WEEK FROM date)) as weeklyavg
FROM table1
GROUP BY date, weeknbr
ORDER BY date, weeknbr
This is possible as the Aggregation / GROUP BY is applied before the window/analytic function.
select
date,
countcase,
extract(week from date) as weeknbr,
avg(countcase) over (partition by extract(week from date)) as weeklyavg
from table1;
I have this query
SELECT DISTINCT ON (tours.departure.departure_month)
tours.departure.departure_month
FROM tours.departure
But I want to order the distinct months by month name. I've tried this from a similar question to_date(tours.departure.departure_month, 'Month'),
but I cannot get it to work with DISTINCT ON.
What is the column type of departure_month is it date or month names, if its date type column you can try the following:
SELECT DISTINCT ON (tours.departure.departure_month)
tours.departure.departure_month
FROM tours.departure
ORDER BY month(tours.departure.departure_month) DESC;
To make the example super simple, lets say that I have a table with three rows, ID, Name, and Date. I need to find the count of all ID's belonging to a specific name where the ID does not belong to this month.
Using that example, I would want this output:
In other words, I want to count how many ID's that a name has that aren't this month/year.
I'm more into PowerShell and still fairly new to SQL. I tried doing a case statement, but because it's not a foreach it seems to be returning "If the Name has ANY date in this month, return NULL" which is not what I want. I want it to count how many ID's per name do not appear in this month.
SELECT NAME,
CASE
WHEN ( Month(date) NOT LIKE Month(Getdate())
AND Year(date) NOT LIKE Year(Getdate()) ) THEN Count(id)
END AS TotalCount
FROM dbo.table
GROUP BY NAME,
date
I really hope this makes sense, but if it doesn't please let me know and I can try to clarify more. I tried researching cursors, but I'm having a hard time grasping them to get them into my statement. Any help would be greatly appreciated!
You only want to group by the non-aggregated columns that are in the result set (in this case, Name). You totally don't need a cursor for this, it's a fairly straight-forward query.
select
Name,
Count(*) count
from
tbl
where
tbl.date > eomonth(getdate()) or
tbl.date <= eomonth(dateadd(mm, -1, getdate())
group by
Name
I did a little bit of trickery on the exclusion of rows that are in the current month. Generally, you want to avoid running functions on the columns you're comparing to if you can so that SQL Server can use an index to speed up its search. I assumed that the ID column is unique, if it's not, change count(*) to count(distinct ID).
Alternative where clause if you're using older versions of sql server. If the table is small enough, you can just do it directly (similar to what you tried originally, it just goes in the query where clause and not embedded in a case)
where
Month(date) <> Month(Getdate())
AND Year(date) <> Year(Getdate())
If you have a large table and sarging on the index is important, there some fun stuff you can build eomonth with dateadd and the date part functions, but it's a pain.
SELECT Name, COUNT(ID) AS TotalCount
FROM dbo.[table]
WHERE DATEPART(MONTH, [Date]) != DATEPART(MONTH, GETDATE()) OR DATEPART(YEAR, [Date]) != DATEPART(YEAR, GETDATE())
GROUP BY Name;
In T-SQL:
SELECT
NAME,
COUNT(id)
FROM dbo.table
WHERE MONTH(Date_M) <> MONTH(GETDATE())
GROUP BY NAME
How to get the total count for particular date by selecting different dates.
For Example:
Record contains from '2014-04-01' to till date. Each date contains multiple records with different IST time.
How to get the total count from each date?
depending on your table structure and result you want, Query should look somewhat like this
SELECT DATE(date_column), COUNT(*)
FROM tablename
WHERE date_column IN (your_date_list)
GROUP BY date(date_column);
Have a look at the following sql (I have not tested)
SELECT date_column, COUNT(*)
FROM tablename
WHERE date_column BETWEEN date_column AND current_date
GROUP BY to_date(date_column::text,'YYYY-MM-DD')
I need to group by the product name and by the date.
so from the above example, I am expecting to see the result as below. Is it possible . Can some one help me out please.Thanks!
Maybe I'm missing something in your question, but this is as simple as:
select product_name,
date,
count(*) as cnt
from the_table
group by product_name,
date
order by product_name
Btw: date is a horrible name for a column. First because it's a reserved word but more importantly because it does not document what you store in the column. It could be a "purchase_date", a "sold_date", an "expiry_date", ... ?