I need to group by the product name and by the date.
so from the above example, I am expecting to see the result as below. Is it possible . Can some one help me out please.Thanks!
Maybe I'm missing something in your question, but this is as simple as:
select product_name,
date,
count(*) as cnt
from the_table
group by product_name,
date
order by product_name
Btw: date is a horrible name for a column. First because it's a reserved word but more importantly because it does not document what you store in the column. It could be a "purchase_date", a "sold_date", an "expiry_date", ... ?
Related
So I am trying and struggling for few days to extend the schema with the custom groupby using something like this
I have a table with few fields like id, country, ip, created_at.
Then I am trying to get them as groups. For example, group the data based on date, hourly of date, or based on country, and based on country with DISTINCT ip.
I am zero with SQLs honestly. But I tried to play around and get what I want. Here's an example.
SELECT Hour(created_at) AS date,
COUNT(*) AS count
FROM session where CAST(created_at AS date) = '2021-04-05'
GROUP BY Hour(created_at)
ORDER BY date;
SELECT country,
count(*) AS count from (SELECT * FROM session where CAST(created_at AS date) <= '2021-05-12' GROUP BY created_at) AS T1
GROUP BY country;
SELECT country, COUNT(*) as count
FROM (SELECT DISTINCT ip, country FROM session) AS T1
GROUP BY country;
SELECT DATE(created_at) AS date,
COUNT(*) AS count
FROM session
GROUP BY DATE(created_at)
ORDER BY date;
Now I am struggling with two things.
How do I make the date as variables? I mean, if I want to group them for a particular date range/ or today's data hourly, or per quarter gap (more of configurable), how do I add the variables in Hasura's Raw SQL?
Also for this approach I have to add schema for each one of them? Like this
CREATE
OR REPLACE VIEW "public"."unique_session_counts_date" AS
SELECT
date(session.created_at) AS date,
count(*) AS count
FROM
session
GROUP BY
(date(session.created_at))
ORDER BY
(date(session.created_at));
Is there a way to make it more generalized? What I mean is, if it
was in Nodejs I could have done something like
return rawQuery(
`
select ${field} x, count(*) y
from ${table}
where website_id=$1
and created_at between $2 and $3
${domainFilter}
${urlFilter}
group by 1
order by 2 desc
`,
params,
);
In this case, based on whatever field and where clause I send, one query would do the trick for me. Can do something similar in hasura?
Thank you so much in advance.
How do I make the date as variables? I mean, if I want to group them for a particular date range/ or today's data hourly, or per quarter gap (more of configurable), how do I add the variables in Hasura's Raw SQL?
My first thought is this. If you're thinking about passing in variables via a GraphQL for example, the GraphQL would look something like:
query MyQuery {
unique_session_counts_date(where: {created_at: {_gte: "<start date here>", _lte: "<end date here>"}}) {
<...any fields, rollups, etc here...>
}
}
The underlying view/query would follow the group by and order by that you've detailed. Then you'd be able to submit a query of the graphql query and just pass in the pertinent parameters like the $1, $2, and $3 in the raqQuery call.
Also for this approach I have to add schema for each one of them?
The schema? The view? I don't think a view specifically would be required, if a multilevel select or similar query can handle it and perform then a view wouldn't particularly be needed.
That's my first stab at the problem. I'm going to try to work through this problem in a few hours via a Twitch stream # HasuraHQ if you can join, happy to walk through it live.
I have this query
SELECT DISTINCT ON (tours.departure.departure_month)
tours.departure.departure_month
FROM tours.departure
But I want to order the distinct months by month name. I've tried this from a similar question to_date(tours.departure.departure_month, 'Month'),
but I cannot get it to work with DISTINCT ON.
What is the column type of departure_month is it date or month names, if its date type column you can try the following:
SELECT DISTINCT ON (tours.departure.departure_month)
tours.departure.departure_month
FROM tours.departure
ORDER BY month(tours.departure.departure_month) DESC;
can someone help me to write a query?
I have for example columns:
Date
product_key
category_code
In one day I expect to have same category_code for one product, but I want to check this with SQL.
Thank you.
If you want to find the day, the product_key and the category_code that doubles, You should use query like this:
SELECT
date,
product_key,
category_code,
count(1)
FROM your_table
GROUP BY date, product_key, category_code
HAVING count(1) > 1;
You can group your results by date and product, and use count and distinct to find if there is more than one category code for a product. You can then filter rows having more than 1 distinct category in the group.
SELECT
Date, product_key, count(distinct category_code) AS categories
FROM
my_table
GROUP BY
Date, product_key
HAVING
count(distinct category_code) > 1
To make the example super simple, lets say that I have a table with three rows, ID, Name, and Date. I need to find the count of all ID's belonging to a specific name where the ID does not belong to this month.
Using that example, I would want this output:
In other words, I want to count how many ID's that a name has that aren't this month/year.
I'm more into PowerShell and still fairly new to SQL. I tried doing a case statement, but because it's not a foreach it seems to be returning "If the Name has ANY date in this month, return NULL" which is not what I want. I want it to count how many ID's per name do not appear in this month.
SELECT NAME,
CASE
WHEN ( Month(date) NOT LIKE Month(Getdate())
AND Year(date) NOT LIKE Year(Getdate()) ) THEN Count(id)
END AS TotalCount
FROM dbo.table
GROUP BY NAME,
date
I really hope this makes sense, but if it doesn't please let me know and I can try to clarify more. I tried researching cursors, but I'm having a hard time grasping them to get them into my statement. Any help would be greatly appreciated!
You only want to group by the non-aggregated columns that are in the result set (in this case, Name). You totally don't need a cursor for this, it's a fairly straight-forward query.
select
Name,
Count(*) count
from
tbl
where
tbl.date > eomonth(getdate()) or
tbl.date <= eomonth(dateadd(mm, -1, getdate())
group by
Name
I did a little bit of trickery on the exclusion of rows that are in the current month. Generally, you want to avoid running functions on the columns you're comparing to if you can so that SQL Server can use an index to speed up its search. I assumed that the ID column is unique, if it's not, change count(*) to count(distinct ID).
Alternative where clause if you're using older versions of sql server. If the table is small enough, you can just do it directly (similar to what you tried originally, it just goes in the query where clause and not embedded in a case)
where
Month(date) <> Month(Getdate())
AND Year(date) <> Year(Getdate())
If you have a large table and sarging on the index is important, there some fun stuff you can build eomonth with dateadd and the date part functions, but it's a pain.
SELECT Name, COUNT(ID) AS TotalCount
FROM dbo.[table]
WHERE DATEPART(MONTH, [Date]) != DATEPART(MONTH, GETDATE()) OR DATEPART(YEAR, [Date]) != DATEPART(YEAR, GETDATE())
GROUP BY Name;
In T-SQL:
SELECT
NAME,
COUNT(id)
FROM dbo.table
WHERE MONTH(Date_M) <> MONTH(GETDATE())
GROUP BY NAME
Sorry if the title is confusing. Here is the query I have
Select MONTH(DATE(TIMESTAMP)), SUM(FIELD1), SUM(FIELD2) from TABLE WHERE TIMESTAMP BETWEEN '2009-07-26 00:00:00' AND '2010-02-24 23:59:59' GROUP BY MONTH(DATE(TIMESTAMP))
This will let me get the month number out of the query. The problem is that right now it is sorting the months 1,2,3,4.... when it spans two separate years. I need to be able to sort this query by year then month.
If I add "ORDER BY TIMESTAMP" at the end of my query I get this error:
Column TIMESTAMP or expression in SELECT list not valid. SQLCODE=-122
Also I changed the field names for this question to keep it clear the field isn't actually called TIMESTAMP
You need to group by year then month.:
SELECT YEAR(YourField),
Month(YourField),
SUM(Field1),
SUM(Field2)
FROM Table
WHERE...
GROUP BY
YEAR(YourField),
Month(YourField)
ORDER BY
YEAR(YourField),
Month(YourField)