I'm trying to get records inserted after a certain date given to me by the client.
2018-06-06
Here's how I'm writing the query:
{:ok, date} = NaiveDateTime.from_iso8601(date_string)
from(
m in query,
where: m.inserted_at > ^date
)
(MatchError) no match of right hand side value: {:error, :invalid_format}
And when I try to use a simple Date object:
** (Ecto.Query.CastError) lib/messages/search.ex:77: value ~D[2018-06-06] in where cannot be cast to type :naive_datetime in query
How can I find all messages inserted after that dummy string date the client is passing me?
You have an ISO 8601 date there, not a datetime. You can convert it into a NaiveDateTime (with hour, minute, second all set to 0) like this:
iex(1)> date_string = "2018-06-06"
"2018-06-06"
iex(2)> ndt = NaiveDateTime.from_iso8601!(date_string <> " 00:00:00")
~N[2018-06-06 00:00:00]
Now you can use ndt in your query and it will work.
Related
I have a syntax, but it doesn't work.
Here is my query:
SELECT *
FROM aqua.reading
WHERE
CAST(reading.pres_date AS VARCHAR)
BETWEEN LIKE '2022-10-18%' AND LIKE '2022-10-18%'
it says:
ERROR: type "like" does not exist
LINE 1: ... WHERE CAST(reading.pres_date AS VARCHAR) BETWEEN LIKE '2022...
^
SQL state: 42704
Character: 77
I am trying to get all the data with timestamp and timezone and implement a date range
Don't compare dates (or timestamps) as strings. Compare them to proper date (or timestamp) values. Given the fact that you use the same "date" but with a wildcard at the end, I am assuming(!) that pres_date is in fact a timestamp column and you want to find all rows with a given date regardless of the time value of the timestamp.
The best approach is to use a range query with >= ("greater than or equal) on the lower value and < (strictly lower than) on the next day:
SELECT *
FROM aqua.reading
WHERE reading.pres_date >= DATE '2022-10-18'
AND reading.pres_date < DATE '2022-10-19'
Alternatively you can cast the timestamp to a date and use the = operator if you really want to pick just one day:
SELECT *
FROM aqua.reading
WHERE cast(reading.pres_date as DATE) = DATE '2022-10-18'
However that will not make use of a potential index on pres_date so is likely to be slower than the range query from the first solution
I'm trying to select records from a DB2 Iseries system where the date field is greater than the first of this year.
However, the date fields I'm selecting from are actually PACKED fields, not true dates.
I'm trying to convert them to YYYY-MM-DD format and get everything greater than '2018-01-01' but no matter what I try it says it's invalid.
Currently trying this:
SELECT *
FROM table1
WHERE val = 145
AND to_date(char(dateShp), 'YYYY-MM-DD') >= '2018-01-01';
it says expression not valid using format string specified.
Any ideas?
char(dateshp) is going to return a string like '20180319'
So your format string should not include the dashes.. 'YYYYMMDD'
example:
select to_date(char(20180101), 'YYYYMMDD')
from sysibm.sysdummy1;
So your code should be
SELECT *
FROM table1
WHERE val = 145
AND to_date(char(dateShp), 'YYYYMMDD') >= '2018-01-01';
Charles gave you a solution that converts the Packed date to a date field, and if you are comparing to another date field, this is a good solution. But if you are comparing to a constant value or another numeric field, you could just use something like this:
select *
from table1
where val = 145
and dateShp >= 20180101;
I'm trying to convert value for DIM_DT_ID to MMddYY. I'm successful in doinf that. However, query fails because ultimately I'm comparing a character value to date here. Is there a way by which I can get value for DIM_DT_ID in MMddyy format and its data type still remains DATE ?
Here DIM_DT_ID
SELECT DIM_DT_ID
DIM_DT_ID >= FORMATDATE('MMddyy',ADDDAY(TO_date('yyyy-MM-dd','2016-12-21'), -25)); from abc;
Regards,
Ajay
In Denodo, to convert a string to a date field, use "to_date()" (which returns a date).
Then, don't convert back to a string, leave that field as a date (so don't use "Formatdate()", which returns a string).
So:
SELECT *
FROM MyTable
WHERE now() >= to_date('yyyy-MM-dd',myStringFieldThatLooksLikeADate)
In my example, "now()" is a date, and so is the output of the to_date function... so you can do a comparison.
If you try to convert the date back to a string using formatdate, it won't work:
#This doesn't work:
SELECT *
FROM MyTable
WHERE now() >= formatdate('MMddyy',to_date('yyyy-MM-dd',myStringFieldThatLooksLikeADate))
It doesn't work because we are comparing a date ("now()") to a string.
I'm new to crystal report. I have a date in string format like 2015-03-25 (Wed) and I want to convert it to date format like 03/25/2015. I tried with CDate and DateValue but it returned bad date string format. Any suggestions to convert such date string to proper date format?
If you have a DateTime field in Crystal Reports, you will see Date and Time tab option on the Format Editor when you right click on the field and select Format Field menu item. From the Date and Time tab, you may select the desired format and select OK.
It would be recommended to use the formats you want to use.
For eg : if you are giving string format for money or decimal you may not be able to use it at its full,like you may not be able to auto sum and other properties related to the datatype you intend to use
Not to do any thing in the code, Crystal Report have facility to this type of simple format.
#utility, you are near to answer.
As above image, in last Custom Format option, where you just go in Date tab and give format as
http://www.c-sharpcorner.com/UploadFile/mahesh/DateFormatInCR06132007092248AM/DateFormatInCR.aspx
Updated : sorry for above answer, that will work if you have valid date string.
In your case, where any arbitrary string need to convert into other date format. There is 2 option. In both case you have to extract the date and then format as you need and again combined with other sub-string.
Second you already done ie. crsytal report side, grab the date , format it and concatenate. this will slow down as need to process for each row.
SqlServer side - This option is faster from first option.
declare #t nvarchar(16) = '2015-03-25 (Wed)'
--get the acual date select SUBSTRING ( #t, 1, charindex('(' , #t ) -1 )
--above result give the charter datatype, so you first convert into date and then convert into other format select cast( SUBSTRING ( #t,
1, charindex('(' , #t ) -1 ) as date) --convert into date select
convert (varchar(15) , cast( SUBSTRING ( #t, 1, charindex('(' , #t )
-1 ) as date) , 103) --convert into dd/mm/yyyy format
--Above is for your understand, this is the actual execution of your code (Only write the below line) select convert (varchar(15) , cast(
SUBSTRING ( #t, 1, charindex('(' , #t ) -1 ) as date) , 103) + ' ' +
datename(dw, getdate() )
I suggest, go with Sqlserver side.
Currently I'm storing it as a String, but got problems using it when it comes to querying by date with GQL.
Date date = Calendar.getInstance().getTime();
DateFormat formatter = new SimpleDateFormat("hh:mm:ss, z");
String todayDate = formatter.format(date);
The query:
"SELECT FROM SomeTable p WHERE date = 01/01/2011"
Error:
Exception:
org.datanucleus.store.appengine.query.DatastoreQuery$UnsupportedDatastoreFeatureException:
Problem with query : Right side of expression is
composed of unsupported components.
Left:
org.datanucleus.query.expression.Literal,
Op: / , Right:
DyadicExpression{Literal{5} /
Literal{11}}
How can I search by date?
Always as a date - the database should check on the types of data that it stores thus making sure the data is what it says. the information about what type is known on the insert so check it then rather than later when none has any idea of what the correct value should have been.
the error you are getting is probably not due to this but because the date in the query needs to be made a date if types are correct or if a string needs to be as a single-quoted string see GQL Reference
e.g.
"SELECT FROM SomeTable p WHERE date = '01/01/2011'"
but what date is 06/07/2011 ? I think it is today 6th July, others 7th June. So even if you use strings use the ISO format 2011-07-06 A date type will hide this detail making it easier. Note that GQL only uses the ISO form so even if you got the command to have the date in a string it would fail.
but better as
SELECT FROM SomeTable p WHERE date = DATE( 2011, 1, 1)