I'm new to crystal report. I have a date in string format like 2015-03-25 (Wed) and I want to convert it to date format like 03/25/2015. I tried with CDate and DateValue but it returned bad date string format. Any suggestions to convert such date string to proper date format?
If you have a DateTime field in Crystal Reports, you will see Date and Time tab option on the Format Editor when you right click on the field and select Format Field menu item. From the Date and Time tab, you may select the desired format and select OK.
It would be recommended to use the formats you want to use.
For eg : if you are giving string format for money or decimal you may not be able to use it at its full,like you may not be able to auto sum and other properties related to the datatype you intend to use
Not to do any thing in the code, Crystal Report have facility to this type of simple format.
#utility, you are near to answer.
As above image, in last Custom Format option, where you just go in Date tab and give format as
http://www.c-sharpcorner.com/UploadFile/mahesh/DateFormatInCR06132007092248AM/DateFormatInCR.aspx
Updated : sorry for above answer, that will work if you have valid date string.
In your case, where any arbitrary string need to convert into other date format. There is 2 option. In both case you have to extract the date and then format as you need and again combined with other sub-string.
Second you already done ie. crsytal report side, grab the date , format it and concatenate. this will slow down as need to process for each row.
SqlServer side - This option is faster from first option.
declare #t nvarchar(16) = '2015-03-25 (Wed)'
--get the acual date select SUBSTRING ( #t, 1, charindex('(' , #t ) -1 )
--above result give the charter datatype, so you first convert into date and then convert into other format select cast( SUBSTRING ( #t,
1, charindex('(' , #t ) -1 ) as date) --convert into date select
convert (varchar(15) , cast( SUBSTRING ( #t, 1, charindex('(' , #t )
-1 ) as date) , 103) --convert into dd/mm/yyyy format
--Above is for your understand, this is the actual execution of your code (Only write the below line) select convert (varchar(15) , cast(
SUBSTRING ( #t, 1, charindex('(' , #t ) -1 ) as date) , 103) + ' ' +
datename(dw, getdate() )
I suggest, go with Sqlserver side.
Related
The column is a nvachar(20).
select [shipment_posted_date_arch]
FROM [RxIntegrity].[dbo].[DiscrepancyReport_Receipts]
When I pull this, the date is in this format of 1200819 for that column. I need to convert to normal date.
This seemed to work:
cast(convert(nvarchar(20), (19000000 + CONVERT(int, shipment_posted_date_arch))) as date)
Below is a script i am trying to run in Presto; Subtracting today's date from an integer field I am attempting to convert to date. To get the exacts days between. Unfortunately, it seems the highlighted block does not always convert the date correctly and my final answer is not correct. Please does anyone know another way around this or a standard method on presto of converting integer values to date.
Interger value in the column is in the format '20191123' for year-month-date
select ms, activ_dt, current_date, date_diff('day',act_dt,current_date) from
(
select ms,activ_dt, **CAST(parse_datetime(CAST(activ_dt AS varchar), 'YYYYMMDD') AS date) as act_dt**, nov19
from h.A_Subs_1 where msisdn_key=23480320012
) limit 19
You can convert "date as a number" (eg. 20180527 for May 27, 2018) using the following:
cast to varchar
parse_datetime with appropriate format
cast to date (since parse_datetime returns a timestamp)
Example:
presto> SELECT CAST(parse_datetime(CAST(20180527 AS varchar), 'yyyyMMdd') AS date);
_col0
------------
2018-05-27
You can use below sample query for your requirement:
select date_diff('day', date_parse('20191209', '%Y%m%d'), current_timestamp);
I'm trying to select records from a DB2 Iseries system where the date field is greater than the first of this year.
However, the date fields I'm selecting from are actually PACKED fields, not true dates.
I'm trying to convert them to YYYY-MM-DD format and get everything greater than '2018-01-01' but no matter what I try it says it's invalid.
Currently trying this:
SELECT *
FROM table1
WHERE val = 145
AND to_date(char(dateShp), 'YYYY-MM-DD') >= '2018-01-01';
it says expression not valid using format string specified.
Any ideas?
char(dateshp) is going to return a string like '20180319'
So your format string should not include the dashes.. 'YYYYMMDD'
example:
select to_date(char(20180101), 'YYYYMMDD')
from sysibm.sysdummy1;
So your code should be
SELECT *
FROM table1
WHERE val = 145
AND to_date(char(dateShp), 'YYYYMMDD') >= '2018-01-01';
Charles gave you a solution that converts the Packed date to a date field, and if you are comparing to another date field, this is a good solution. But if you are comparing to a constant value or another numeric field, you could just use something like this:
select *
from table1
where val = 145
and dateShp >= 20180101;
Using the following sample query below in SSRS would return month as single number(1-12). What I want to is to display the date as is something like Jan 2000. How would I go about changing my code to be able to format from single number month to a MMM YYYY format? I tried the formatting in visual studio itself but it is currently returning as MMM YYYY.
select distinct count(*) as Count,
con.STATE,
month(con.sub_Date) as Month,
year(con.sub_Date) as Year
from contract con
group by con.STATE,month(con.sub_date),year(con.sub_date)
I strongly recommend that you perform the formatting of the date at the report level.
Return the date from your query as the first date of the desired period, but then set the format string for the placeholder/text box.
The reason to do this is so that sorting and data manipulation works as expected when the report is exported to Excel.
So I would use a query as:
SELECT DISTINCT
COUNT(*) AS Count ,
con.STATE ,
DATEADD(MONTH, DATEDIFF(MONTH, 0, con.sub_Date), 0) AS FirstOfMonth
FROM
contract con
GROUP BY
con.STATE ,
DATEADD(MONTH, DATEDIFF(MONTH, 0, con.sub_Date), 0)
and then use formatting codes in the report such as MMM, YYYY for display and break the date apart with =Month(fields!FirstOfMonth.Value) if you need the components for grouping. This will allow the users to pivot the data appropriately if needed.
Formatting of the dates is presentation logic, and should be kept out of SQL if possible.
You could add the following into the query to return the pre-formatted month/year as part of the report dataset - maybe easier than trying to reconstruct it at the report level:
select distinct count(*) as Count,
con.STATE,
month(con.sub_Date) as Month,
year(con.sub_Date) as Year,
left(datename(mm, sub_Date), 3) + ' ' + cast(year(sub_Date) as char(4)) as MonthYear
from contract con
group by con.STATE,
month(con.sub_date),
year(con.sub_date),
left(datename(mm, sub_Date), 3) + ' ' + cast(year(sub_Date) as char(4))
I usually prefer to use CONVERT to get partial dates, though I don't see any CONVERT date formats that would leave you cleanly with a MON YYYY output. However, format 106 will get you most of the way there. So combining that with RIGHT() will get you the date in the format you're looking for.
SELECT DISTINCT
COUNT(*) AS Count ,
[con].[STATE] ,
MONTH([con].[sub_Date]) AS Month ,
YEAR([con].[sub_Date]) AS Year ,
RIGHT(CONVERT(CHAR(11), [con].[sub_Date], 106), 8) AS MonthYear
FROM [dbo].[contract] AS con
GROUP BY [con].[STATE] ,
MONTH([con].[sub_Date]) ,
YEAR([con].[sub_Date]) ,
RIGHT(CONVERT(CHAR(11), [con].[sub_Date], 106), 8)
Let's say that I have a range of SQL tables that are named name_YYYY_WW where YYYY = year and WW = week number. If I call upon a function that guides a user defined date to the right table.
If the date entered is "20110101":
SELECT EXTRACT (WEEK FROM DATE '20110101') returns 52 and
SELECT EXTRACT (YEAR FROM DATE '20110101') returns 2011.
While is nothing wrong with these results I want "20110101" to either point to table name_2010_52 or name_2011_01, not name_2011_52 as it does now when I concanate the results to form the query for the table.
Any elegant solutions to this problem?
The function to_char() will allow you to format a date or timestamp to output correct the iso week and iso year.
SELECT to_char('2011-01-01'::date, 'IYYY_IW') as iso_year_week;
will produce:
iso_year_week
---------------
2010_52
(1 row)
You could use a CASE:
WITH sub(field) AS (
SELECT CAST('20110101' AS date) -- just to test
)
SELECT
CASE
WHEN EXTRACT (WEEK FROM field ) > 1 AND EXTRACT (MONTH FROM field) = 1 AND EXTRACT (DAY FROM field) < 3 THEN 1
ELSE
EXTRACT (WEEK FROM field)
END
FROM
sub;