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Why the result of this query is always one :
SELECT stats1.cnt1 FROM staging.memberships_autoship_box b JOIN staging.memberships_autoship a ON a.id = b.autoship_box_id JOIN (SELECT COUNT(bn.autoship_box_id) cnt1,bn.autoship_box_id FROM staging.memberships_autoship_box bn GROUP BY bn.autoship_box_id ) stats1 ON
(stats1.autoship_box_id = a.id)
The group by clause, unlike the order by clause, doesn't take column ordinals. In this clause, 1 and 2 are just integer literals, and since every row of your query has the same value for these two literals, they are all grouped in to a single result row.
Instead, you should use the actual columns from your query:
GROUP BY sql_activity_days.styleship_start_month, memberCountSql."122_days"
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this is the data table
how to do to get below result:
Here is the result i want to get
I only can get lowest and highest without (name), any ideas to get above result?
Use GROUP BY for grouping the subjects and then fetch max_mark, min_mark using MAX(), MIN() functions respectively
SELECT subject AS "sub1",
MAX(scc) AS "max_mark",
MIN(scc) AS "min_mark"
FROM Subjects_mark
GROUP BY 1
Now use subquery for formatting the output
SELECT sub1,
CONCAT(min_mark,'(',studentnar,')') AS "lowest point",
CONCAT(max_mark,'(',studentnar,')') AS "highest point"
FROM Subjects_mark AS s1
JOIN (
SELECT subjects AS "sub1",
MAX(scc) AS "max_mark",
MIN(scc) AS "min_mark"
FROM Subjects_mark
GROUP BY 1
) AS dt
ON dt.sub1 = s1.subjects
AND dt.max_mark = s1.scc
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I'd like to get the last N rows in ascending order. Is it possible without using nested SELECTs?
The reason of this question if it is know if there is other way more efficient.
Nested selects:
select id, timestamp, col3, col4
from (
select * from t_myTable
order by timestamp DESC LIMIT 5
) as d
order by timestamp ASC
The id column is auto-incremental.
thanks.
Since you need two different orderings, I cannot imagine that there is a different way to do it without a subquery. And even if there were, I am pretty confident that that query would be more complicated and would perform worse.
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trying to comment out the join fields with this PostgreSQL statement:
select
veh."Truck Name",
veh."Truck Type",
veh.office,
--off.address,
--off.city,
--off.state,
--off.zipcode
from
vehicles veh
--join offices off on veh.office = off.office
order by
veh.office asc;
I get the following error:
SQL Error [42601]: ERROR: syntax error at or near "from"
Position: 180
I want to be able to remove the -- indicators and run the report
just remove comma after veh.office
select
veh."Truck Name",
veh."Truck Type",
veh.office
--off.address,
--off.city,
--off.state,
--off.zipcode
from
vehicles veh
--join offices off on veh.office = off.office
order by
veh.office asc;
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How can we get this output
results from query should be like:
Assessment
penalty
both values are coming from two different columns. I want to join these two columns but want results like above in single cell. so there should be new line for second column(but in same cell)
select assessment || E'\n' || penalty from wherever
or
select concat_ws(chr(10), assessment, penalty) from wherever
Note: I am assuming, since you didn't say, that neither column can be null.
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Is there a way to find the values of last 5 columns of a table?
Suppose if i have a table of 20 columns, i want to select all the values from the last 5 columns.
Any help will be appreciated. Thanks in advance.
Don't. It's stupid.
There shouldn't really be any order to the columns - they should just have names. It's just a convenience when testing or sitting at a DB console that SELECT * gives you them all.
There are very few cases where SELECT * makes sense in a live system. I can't think of any where you want whatever columns happen to be "last" on a table.
If you are really committed to doing this then you'll have to query the information-schema or system catalogues. Get a list of the columns on a particular table and then build your SQL to query them.
However, if you aren't in control of this table then it's a meaningless task since you won't know what the information means. If you are in control of the table then you know what column-names there are and that's a better way to do it.
Seems simple enough unless I misunderstood.
Select col16, col17, col18, col19, col20
From yourtable
i got the answer
SELECT column_name
FROM information_schema.columns
WHERE table_name='your_table'
order by ordinal_position
From ordinal_position we can get last 'n' columns we want.
Thanks for all the answers.