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trying to comment out the join fields with this PostgreSQL statement:
select
veh."Truck Name",
veh."Truck Type",
veh.office,
--off.address,
--off.city,
--off.state,
--off.zipcode
from
vehicles veh
--join offices off on veh.office = off.office
order by
veh.office asc;
I get the following error:
SQL Error [42601]: ERROR: syntax error at or near "from"
Position: 180
I want to be able to remove the -- indicators and run the report
just remove comma after veh.office
select
veh."Truck Name",
veh."Truck Type",
veh.office
--off.address,
--off.city,
--off.state,
--off.zipcode
from
vehicles veh
--join offices off on veh.office = off.office
order by
veh.office asc;
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Closed 5 months ago.
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this is the data table
how to do to get below result:
Here is the result i want to get
I only can get lowest and highest without (name), any ideas to get above result?
Use GROUP BY for grouping the subjects and then fetch max_mark, min_mark using MAX(), MIN() functions respectively
SELECT subject AS "sub1",
MAX(scc) AS "max_mark",
MIN(scc) AS "min_mark"
FROM Subjects_mark
GROUP BY 1
Now use subquery for formatting the output
SELECT sub1,
CONCAT(min_mark,'(',studentnar,')') AS "lowest point",
CONCAT(max_mark,'(',studentnar,')') AS "highest point"
FROM Subjects_mark AS s1
JOIN (
SELECT subjects AS "sub1",
MAX(scc) AS "max_mark",
MIN(scc) AS "min_mark"
FROM Subjects_mark
GROUP BY 1
) AS dt
ON dt.sub1 = s1.subjects
AND dt.max_mark = s1.scc
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Closed 4 years ago.
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Why the result of this query is always one :
SELECT stats1.cnt1 FROM staging.memberships_autoship_box b JOIN staging.memberships_autoship a ON a.id = b.autoship_box_id JOIN (SELECT COUNT(bn.autoship_box_id) cnt1,bn.autoship_box_id FROM staging.memberships_autoship_box bn GROUP BY bn.autoship_box_id ) stats1 ON
(stats1.autoship_box_id = a.id)
The group by clause, unlike the order by clause, doesn't take column ordinals. In this clause, 1 and 2 are just integer literals, and since every row of your query has the same value for these two literals, they are all grouped in to a single result row.
Instead, you should use the actual columns from your query:
GROUP BY sql_activity_days.styleship_start_month, memberCountSql."122_days"
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Closed 4 years ago.
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How can we get this output
results from query should be like:
Assessment
penalty
both values are coming from two different columns. I want to join these two columns but want results like above in single cell. so there should be new line for second column(but in same cell)
select assessment || E'\n' || penalty from wherever
or
select concat_ws(chr(10), assessment, penalty) from wherever
Note: I am assuming, since you didn't say, that neither column can be null.
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For example:
Query1
abc:='select * from table1';
Query2
result:='create view'||quote_ident(view1)||'as'||abc;
I'm going to take a wild guess and assume you're trying to use dynamic SQL to create a view.
If so, use the EXECUTE statement.
abc := 'select * from table1';
result := 'create view '||quote_ident(view1)||' as ' || abc;
EXECUTE result;
Your query text looked OK except for the missing spaces, assuming that view1 is a text parameter.
(In future: include PostgreSQL version, exact text of any error message, the full code you're using, etc).
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Closed 9 years ago.
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Select COLUMN_name
from TABLE_name
where COLUMN NAME = 'something's'
While executing this query in PostgreSQL, it is showing an error as like below,
syntax error at or near "S".
The apostrophe in KEPLER'S is terminating the string early. Escape it, and proofread next time.
Select CONCEPTNAME from KM_CONCEPT_MAST where CONCEPTNAME='KEPLER''S LAWS OF PLANETARY MOTION'