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this is the data table
how to do to get below result:
Here is the result i want to get
I only can get lowest and highest without (name), any ideas to get above result?
Use GROUP BY for grouping the subjects and then fetch max_mark, min_mark using MAX(), MIN() functions respectively
SELECT subject AS "sub1",
MAX(scc) AS "max_mark",
MIN(scc) AS "min_mark"
FROM Subjects_mark
GROUP BY 1
Now use subquery for formatting the output
SELECT sub1,
CONCAT(min_mark,'(',studentnar,')') AS "lowest point",
CONCAT(max_mark,'(',studentnar,')') AS "highest point"
FROM Subjects_mark AS s1
JOIN (
SELECT subjects AS "sub1",
MAX(scc) AS "max_mark",
MIN(scc) AS "min_mark"
FROM Subjects_mark
GROUP BY 1
) AS dt
ON dt.sub1 = s1.subjects
AND dt.max_mark = s1.scc
Related
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Data and Question
Select firstname, lastname, h1.date as admission, h2.date as discharge,
DATE_PART('day', h2.date - h1.date) as totaldays from Participant p
join Hospital h1 on p.health_id = h1.health_id
and h1.transaction = 'Admission'
join Hospital h2 on p.health_id = h2.health_id
and h2.transaction = 'Discharge';
That's my code, but it's not giving me any result. The above code is for part two of the below question.
I want to find the number of days the participant spent in hospital over the period 2018-2019.
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I'd like to get the last N rows in ascending order. Is it possible without using nested SELECTs?
The reason of this question if it is know if there is other way more efficient.
Nested selects:
select id, timestamp, col3, col4
from (
select * from t_myTable
order by timestamp DESC LIMIT 5
) as d
order by timestamp ASC
The id column is auto-incremental.
thanks.
Since you need two different orderings, I cannot imagine that there is a different way to do it without a subquery. And even if there were, I am pretty confident that that query would be more complicated and would perform worse.
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I have a table with field name out of type text
I want to get the rows which contains sub string "hello and good morning"
I have tried to write:
select *
from my_table
where out like 'hello and good morning%'
but it seems not working.
How can I get all the rows which contains sub string ?
According to given details, this should work.
select * from my_table where LOWER(out) like LOWER('%hello and good morning%')
Here is the fiddle.
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Why the result of this query is always one :
SELECT stats1.cnt1 FROM staging.memberships_autoship_box b JOIN staging.memberships_autoship a ON a.id = b.autoship_box_id JOIN (SELECT COUNT(bn.autoship_box_id) cnt1,bn.autoship_box_id FROM staging.memberships_autoship_box bn GROUP BY bn.autoship_box_id ) stats1 ON
(stats1.autoship_box_id = a.id)
The group by clause, unlike the order by clause, doesn't take column ordinals. In this clause, 1 and 2 are just integer literals, and since every row of your query has the same value for these two literals, they are all grouped in to a single result row.
Instead, you should use the actual columns from your query:
GROUP BY sql_activity_days.styleship_start_month, memberCountSql."122_days"
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How can we get this output
results from query should be like:
Assessment
penalty
both values are coming from two different columns. I want to join these two columns but want results like above in single cell. so there should be new line for second column(but in same cell)
select assessment || E'\n' || penalty from wherever
or
select concat_ws(chr(10), assessment, penalty) from wherever
Note: I am assuming, since you didn't say, that neither column can be null.