I have a map of Map[String, Info], it contains keys which can be either uppercase or lowercase, like this:
person1: PersonInfo1
person2: PersonInfo2
PERSON1: PersonInfo1
i want to get the value for key 'person1', if nothing found I'll try with key of 'PERSON1', I tried this code:
val info = map.get(key) match {
case Some(personInfo) => personInfo
case None =>
map.get(key.toUpperCase()) match {
case Some(personInfo) => personInfo
case None => None
}
}
but this return info as type of Product with Serializable, how can I have info returned as type of PersonInfo? Is there a way in Scala that allow me to get value from map by key and ignore cases of the key?
There are comparators for sorted maps which allow getting from the map case insensitively. Example: https://scastie.scala-lang.org/PfHTh16CROag7PNrknx1sQ
val map = scala.collection.immutable.SortedMap("key1" -> 45, "Key2" -> 43, "KEY3" -> 42)(scala.math.Ordering.comparatorToOrdering(String.CASE_INSENSITIVE_ORDER))
map.get("key1") // Some(45)
map.get("key2") // Some(43)
map.get("key3") // Some(42)
map.get("key4") // None
Your actual problem can be fixed if you return Options on all cases, for example:
val info = map.get(key) match {
case somePi#Some(personInfo) => somePi
case None => map.get(key.toUpperCase()) match {
case Some(personInfo) => Some(personInfo)
case None => None
}
}
Note the somePi# => somePi parts for referring the expression or the Some(personInfo).
Probably worth explaining why you got this error message. I assume personInfo is a case class which implements Product and Serializable, just like None. The common type for them is Product with Serializable.
You could chain gets with orElse. I would create an extension method for that:
implicit class CaseInsensitiveGetMap[V] (m: Map[String,V]) {
def iget (key: String): Option[V] = m.get(key)
.orElse(m.get(key.toUpperCase())) //you can add more orElse in chain
}
Then you can just use it like:
map.iget("person2")
The reason you're getting Product with Serializable is because your code is trying to return either a String (if key is good) or an Option (i.e. None if key not found). Those two types are not compatible. You should decide if you want String (maybe an empty string if key not found) or Option (i.e. Some[String] or None).
See if this works for you. It returns an Option[String].
map.get(key).fold(pm.get(key.toUpperCase))(Some(_))
The 1st get() returns an Option. The fold()() unwraps the Option and either tries a 2nd get() with upper case key value, or, if the 1st get returned a value, the value is re-wrapped in an Option so that the types match up.
If, on the other hand, you want to return a String instead, you might do this.
map.getOrElse(key, pm.getOrElse(key.toUpperCase, ""))
You can do a find instead of a get but you may want to consider performance when doing this.
map.find(k => k._1.equalsIgnoreCase(key)) match {
case Some =>
case None =>
}
Related
I have a collection with elements that have a field field1. I want to get all field1s that are options of type MyType.
Currently this is my code.
elems.map(_.field1).map {case Some(found: MyType) => found}
I'm sure this can be done in a much nicer way.. It bugs me that I need to use map twice. Is there a way to do this with only one map/collect ?
EDIT: My code works. I'm just wondering if it can be done in a better (i.e. shorter or prettier way).
elems.flatMap(_.field1.collect { case x: MyType => x })
I believe utilising .flatMap may solve this issue for you
elems.flatMap(_.field1 match {
case myType: MyType => Some(myType)
case _ => None
}
Calling iterator before transforming the collection accumulates all the transformations into a single one so perhaps try
elems
.iterator
.flatMap(_.field1)
.collect { case v: MyType => v }
.toList
if your Seq type is case class you can use pattern matching with one collect function like so (see actual seq):
case class MyTypeWrapper(field1: Option[MyType])
case class MyType(x: String)
val elems = Seq.empty[MyTypeWrapper]
val expected: Seq[MyType] = elems.map(_.field1).map{ case Some(found: MyType) => found }
val actual: Seq[MyType] = elems.collect{ case MyTypeWrapper(Some(mt: MyType)) => mt }
// expected and actual should contains the same elements
I have been working with Scala for close to a year, but every now and then I come across a piece of code that I don't really understand. This time it is this one. I tried looking into documents on "scala methods with generic parameter type", but I am still confused.
def defaultCall[T](featureName : String) (block : => Option[T])(implicit name: String, list:Seq[String]) : Option[T] =
{
val value = block match {
case Some(n) => n match {
case i : Integer => /*-------Call another method----*/
case s : String => /*--------Call another method----*/
}
case _ => None
}
The method is called using the code shown below :
var exValue = Some(10)
val intialization = defaultCall[Integer]("StringName"){exValue}
What I don't understand in the above described code is the "case" statement in the defaultCall method.
I see that when the exValue has a value and is not empty, the code works as expected. But in case I change the exValue to None, then my code goes into the "case _ = None" condition. I don't understand why this happens since the match done here is against the "variable" which would be either an Integer or a String.
What happens here is that when you pass a None it will match on the second case, which "catches" everything that is not an instance of a Some[T]:
block match {
case Some(n) => // Will match when you pass an instance of Some[T]
case _ => // Will match on any other case
}
Note that None and Some are two different classes that inherit from Option.
Also, the variable match is only done if the first match succeeds, otherwise not. To achieve the type checking in the first match you could do:
block match {
case Some(n: Int) => // do stuff
case Some(n: String) => // do stuff
case _ => // Will match on any other case
}
Hope that helps
I have the following input string:
"0.3215,Some(0.5123)"
I would like to retrieve the tuple (0.3215,Some(0.5123)) with: (BigDecimal,Option[BigDecimal]).
Here is one of the thing I tried so far:
"\\d+\\.\\d+,Some\\(\\d+\\.\\d+".r findFirstIn iData match {
case None => Map[BigDecimal, Option[BigDecimal]]()
case Some(s) => {
val oO = s.split(",Some\\(")
BigDecimal.valueOf(oO(0).toDouble) -> Option[BigDecimal](BigDecimal.valueOf(lSTmp2(1).toDouble))
}
}
Using a Map and transforming it into a tuple.
When I try directly the tuple I get an Equals or an Object.
Must miss something here...
Your code has several issues, but the big one seems to be that the case None side of the match returns a Map but the Some(s) side returns a Tuple2. Map and Tuple2 unify to their lowest-common-supertype, Equals, which is what you're seeing.
I think this is what you're trying to achieve?
val Pattern = "(\\d+\\.\\d+),Some\\((\\d+\\.\\d+)\\)".r
val s = "0.3215,Some(0.5123)"
s match {
case Pattern(a,b) => Map(BigDecimal(a) -> Some(BigDecimal(b)))
case _ => Map[BigDecimal, Option[BigDecimal]]()
}
// Map[BigDecimal,Option[BigDecimal]] = Map(0.3215 -> Some(0.5123))
How to do pattern matching on a Map in Scala ?
A (non working) attempt includes,
Map("a"->1, "b"->2, "c"->3) match {
case Map(a,b,_*) => a
}
which errs with
value Map is not a case class, nor does it have an unapply/unapplySeq member
case Map(a,b,_*) => a
The error is indicative enough, yet how to enrich Map with an unapply method for pattern matching ?
Many Thanks
Update
Following #Paul's comment, a neater use case may be like this,
Map("a"->1, "b"->2, "c"->3) match {
case Map("b"->2,_*) => "222"
}
namely, in this case, if map contains key b that maps onto value 2.
Most easy way is tramsform Map to List:
Map("a"->1, "b"->2, "c"->3).to[List] match {
case List(a,b,_*) => a
}
An approach to enriching Map with an unapplySeq method for pattern matching includes this,
object MapExtractor {
def unapplySeq[A <% Ordered[A], B <% Ordered[B]]
(s: Map[A,B]): Option[Seq[(A,B)]] = Some(s.toSeq.sorted)
}
where the sorting approach may be changed to any orderable (items comparable) logic. In this example,
Map("b"->2, "a"->1, "c"->3) match {
case MapExtractor ( x, xs # _* ) => println(s"x: $x") ; println(s"xs: $xs")
}
delivers
x: (a,1)
xs: ArrayBuffer((b,2), (c,3))
Consider the following from the Scala interpreter:
scala> JSON.parseFull("""{"name":"jack","greeting":"hello world"}""")
res6: Option[Any] = Some(Map(name -> jack, greeting -> hello world))
Why is the Map returned in Some() thing? And how do I work with it?
I want to put the values in an xml template:
<test>
<name>name goes here</name>
<greeting>greeting goes here</greeting>
</test>
What is the Scala way of getting my map out of Some(thing) and getting those values in the xml?
You should probably use something like this:
res6 collect { case x: Map[String, String] => renderXml(x) }
Where:
def renderXml(m: Map[String, String]) =
<test><name>{m.get("name") getOrElse ""}</name></test>
The collect method on Option[A] takes a PartialFunction[A, B] and is a combination of filter (by a predicate) and map (by a function). That is:
opt collect pf
opt filter (a => pf isDefinedAt a) map (a => pf(a))
Are both equivalent. When you have an optional value, you should use map, flatMap, filter, collect etc to transform the option in your program, avoiding extracting the option's contents either via a pattern-match or via the get method. You should never, ever use Option.get - it is the canonical sign that you are doing it wrong. Pattern-matching should be avoided because it represents a fork in your program and hence adds to cyclomatic complexity - the only time you might wish to do this might be for performance
Actually you have the issue that the result of the parseJSON method is an Option[Any] (the reason is that it is an Option, presumably, is that the parsing may not succeed and Option is a more graceful way of handling null than, well, null).
But the issue with my code above is that the case x: Map[String, String] cannot be checked at runtime due to type erasure (i.e. scala can check that the option contains a Map but not that the Map's type parameters are both String. The code will get you an unchecked warning.
An Option is returned because parseFull has different possible return values depending on the input, or it may fail to parse the input at all (giving None). So, aside from an optional Map which associates keys with values, an optional List can be returned as well if the JSON string denoted an array.
Example:
scala> import scala.util.parsing.json.JSON._
import scala.util.parsing.json.JSON._
scala> parseFull("""{"name":"jack"}""")
res4: Option[Any] = Some(Map(name -> jack))
scala> parseFull("""[ 100, 200, 300 ]""")
res6: Option[Any] = Some(List(100.0, 200.0, 300.0))
You might need pattern matching in order to achieve what you want, like so:
scala> parseFull("""{"name":"jack","greeting":"hello world"}""") match {
| case Some(m) => Console println ("Got a map: " + m)
| case _ =>
| }
Got a map: Map(name -> jack, greeting -> hello world)
Now, if you want to generate XML output, you can use the above to iterate over the key/value pairs:
import scala.xml.XML
parseFull("""{"name":"jack","greeting":"hello world"}""") match {
case Some(m: Map[_,_]) =>
<test>
{
m map { case (k,v) =>
XML.loadString("<%s>%s</%s>".format(k,v,k))
}
}
</test>
case _ =>
}
parseFull returns an Option because the string may not be valid JSON (in which case it will return None instead of Some).
The usual way to get the value out of a Some is to pattern match against it like this:
result match {
case Some(map) =>
doSomethingWith(map)
case None =>
handleTheError()
}
If you're certain the input will always be valid and so you don't need to handle the case of invalid input, you can use the get method on the Option, which will throw an exception when called on None.
You have two separate problems.
It's typed as Any.
Your data is inside an Option and a Map.
Let's suppose we have the data:
val x: Option[Any] = Some(Map("name" -> "jack", "greeting" -> "hi"))
and suppose that we want to return the appropriate XML if there is something to return, but not otherwise. Then we can use collect to gather those parts that we know how to deal with:
val y = x collect {
case m: Map[_,_] => m collect {
case (key: String, value: String) => key -> value
}
}
(note how we've taken each entry in the map apart to make sure it maps a string to a string--we wouldn't know how to proceed otherwise. We get:
y: Option[scala.collection.immutable.Map[String,String]] =
Some(Map(name -> jack, greeting -> hi))
Okay, that's better! Now if you know which fields you want in your XML, you can ask for them:
val z = for (m <- y; name <- m.get("name"); greet <- m.get("greeting")) yield {
<test><name>{name}</name><greeting>{greet}</greeting></test>
}
which in this (successful) case produces
z: Option[scala.xml.Elem] =
Some(<test><name>jack</name><greeting>hi</greeting></test>)
and in an unsuccessful case would produce None.
If you instead want to wrap whatever you happen to find in your map in the form <key>value</key>, it's a bit more work because Scala doesn't have a good abstraction for tags:
val z = for (m <- y) yield <test>{ m.map { case (tag, text) => xml.Elem(null, tag, xml.Null, xml.TopScope, xml.Text(text)) }}</test>
which again produces
z: Option[scala.xml.Elem] =
Some(<test><name>jack</name><greeting>hi</greeting></test>)
(You can use get to get the contents of an Option, but it will throw an exception if the Option is empty (i.e. None).)