How to query jsonb column using spring data specification? - spring-data

Question

I have below table temp_tbl (postgres):
ID(int) NAME(TEXT) LINKS(jsonb)
-------- ---------- -------------------
1 Name1 ["1","23","3", "32]
2 Name2 ["11","3","31", "2]
3 Name3 ["21","13","3", "12]
Now my native query to get rows which has 'LINKS' with value as "3" is:
select * from temp_tbl where links #> '["3"]'
returns rows 2 & 3.
I want implement this query using org.springframework.data.jpa.domain.Specification
I have implemented something like below where the jsonb column is not-an-array, but has key-value json using jsonb_extract_path_text. But the above column stores only values in an array.
My entity class.
#Entity
#Table(name = "temp_tbl")
public class TempTbl {
#Id
#Column(name = "ID")
private Long id;
#Column(name = "NAME", nullable = false)
private String name;
#Column(name = "LINKS", columnDefinition = "jsonb null")
#Convert(converter = JsonbConverter.class)
private List<String> linkIds;
}
I need help in translating above query into specification using criteriabuilder.

Answer 1

One way to check if a jsonb array contains a String using Jpa specifications is to use the functions jsonb_contains and jsonb_build_array, the latter of which is used to change the String into a jsonb array for use in jsonb_contains.
public static Specification<TempTbl> linkInLinks(String linkId) {
return (root, query, builder) -> {
Expression toJsonbArray = builder.function("jsonb_build_array", String.class, builder.literal(linkId));
return builder.equal(builder.function("jsonb_contains", String.class, root.get("linkIds"), toJsonbArray), true);
};
}