How can i use alias column sisa to lag function in case statement
select i.item_name , i.item_code, DATE(ic.transaction_date), doc_no, qty,
case when count(item_name) over(partition by item_name) = 1
then sum(qty) over(partition by doc_no)
else
case when row_number() over(partition by item_code) = 1
then first_value(qty) over(partition by item_code)
else
qty + lag(sisa)over (partition by item_code)
end
end as sisa
from item_card_today ic
join item i on i.item_id = ic.item_id
where transaction_date
between '2019-03-31 00:11:42'::timestamp and '2019-04-02 08:17:35'::timestamp
and i.item_code = 'CLDXMZM3NTDGSHCKPRFHBHTM'
order by item_code asc, item_name asc
How i can use sisa in the code?
Related
I have a SELECT in Postgres:
SELECT DISTINCT ON (price) price, quantity, is_ask, final_update_id
FROM (SELECT *
FROM ((SELECT price, quantity, is_ask, book_depth.final_update_id
FROM order_depth
LEFT JOIN book_depth ON book_depth_id = book_depth.id
WHERE book_depth_id IN (SELECT id
FROM book_depth
WHERE final_update_id > (SELECT last_update_id
FROM order_book
WHERE symbol_name = 'XRPRUB'
ORDER BY last_update_id DESC
LIMIT 1)
AND symbol_name = 'XRPRUB'))
UNION
(SELECT price, quantity, is_ask, order_book_id
FROM "order"
WHERE order_book_id = (SELECT id
FROM order_book
WHERE symbol_name = 'XRPRUB'
ORDER BY last_update_id DESC
LIMIT 1))
ORDER BY final_update_id DESC) AS t) AS t1
ORDER BY price, final_update_id DESC;
It works for about 20 seconds.
But when I create function with this select this function works for about 1 min 40 seconds. Can someone explain me is it normal or I make mistake somewhere?
Name Value AnotherColumn
-----------
Pump 1 8000.0 Something1
Pump 1 10000.0 Something2
Pump 1 10000.0 Something3
Pump 2 3043 Something4
Pump 2 4594 Something5
Pump 2 6165 Something6
My table looks something like this. I would like to know how to select max value for each pump.
select a.name, value from out_pumptable as a,
(select name, max(value) as value from out_pumptable where group by posnumber)g where and g.value = value
this code does the job, but i get two entries of Pump 1 since it has two entries with same value.
select name, max(value)
from out_pumptable
group by name
select name, value
from( select name, value, ROW_NUMBER() OVER(PARTITION BY name ORDER BY value desc) as rn
from out_pumptable ) as a
where rn = 1
SELECT
b.name,
MAX(b.value) as MaxValue,
MAX(b.Anothercolumn) as AnotherColumn
FROM out_pumptabl
INNER JOIN (SELECT
name,
MAX(value) as MaxValue
FROM out_pumptabl
GROUP BY Name) a ON
a.name = b.name AND a.maxValue = b.value
GROUP BY b.Name
Note this would be far easier if you had a primary key. Here is an Example
SELECT * FROM out_pumptabl c
WHERE PK in
(SELECT
MAX(PK) as MaxPK
FROM out_pumptabl b
INNER JOIN (SELECT
name,
MAX(value) as MaxValue
FROM out_pumptabl
GROUP BY Name) a ON
a.name = b.name AND a.maxValue = b.value)
select Name, Value, AnotherColumn
from out_pumptable
where Value =
(
select Max(Value)
from out_pumptable as f where f.Name=out_pumptable.Name
)
group by Name, Value, AnotherColumn
Try like this, It works.
select * from (select * from table order by value desc limit 999999999) v group by v.name
Using analytic function is the easy way to find max value of every group.
Documentation : https://learn.microsoft.com/en-us/sql/t-sql/functions/row-number-transact-sql?view=sql-server-ver15
Select name,
value,
AnotherColumn
From(
SELECT Row_Number() over(partition by name order by value desc)as
row_number, *
FROM students
)
Where row_number = 1
SELECT t1.name, t1.Value, t1.AnotherColumn
FROM mytable t1
JOIN (SELECT name AS nameMax, MAX(Value) as valueMax
FROM mytable
GROUP BY name) AS t2
ON t2.nameMax = t1.name AND t2.valueMax = t1.Value
WHERE 1 OR <anything you would like>
GROUP BY t1.name;
SELECT DISTINCT (t1.ProdId), t1.Quantity FROM Dummy t1 INNER JOIN
(SELECT ProdId, MAX(Quantity) as MaxQuantity FROM Dummy GROUP BY ProdId) t2
ON t1.ProdId = t2.ProdId
AND t1.Quantity = t2.MaxQuantity
ORDER BY t1.ProdId
this will give you the idea.
Have a table with 3 columns: ID, Signature, and Datetime, and it's grouped by Signature Having Count(*) > 9.
select * from (
select s.Signature
from #Sigs s
group by s.Signature
having count(*) > 9
) b
join #Sigs o
on o.Signature = b.Signature
order by o.Signature desc, o.DateTime
I now want to select the 1st and 10th records only, per Signature. What determines rank is the Datetime descending. Thus, I would expect every Signature to have 2 rows.
Thanks,
I would go with a couple of common table expressions.
The first will select all records from the table as well as a count of records per signature, and the second one will select from the first where the record count > 9 and add row_number partitioned by signature - and then just select from that where the row_number is either 1 or 10:
With cte1 AS
(
SELECT ID, Signature, Datetime, COUNT(*) OVER(PARTITION BY Signature) As NumberOfRows
FROM #Sigs
), cte2 AS
(
SELECT ID, Signature, Datetime, ROW_NUMBER() OVER(PARTITION BY Signature ORDER BY DateTime DESC) As Rn
FROM cte1
WHERE NumberOfRows > 9
)
SELECT ID, Signature, Datetime
FROM cte2
WHERE Rn IN (1, 10)
ORDER BY Signature desc
Because I don't know what your data looks like, this might need some adjustment.
The simplest way here, since you already know your sort order (DateTime DESC) and partitioning (Signature), is probably to assign row numbers and then select the rows you want.
SELECT *
FROM
(
select o.Signature
,o.DateTime
,ROW_NUMBER() OVER (PARTITION BY o.Signature ORDER BY o.DateTime DESC) [Row]
from (
select s.Signature
from #Sigs s
group by s.Signature
having count(*) > 9
) b
join #Sigs o
on o.Signature = b.Signature
order by o.Signature desc, o.DateTime
)
WHERE [Row] IN (1,10)
(SELECT
(SELECT ROW_NUMBER() OVER (order by t.NotificationID)) as RowNumber,
[NotificationID],[ProjectID],[TeamMemberID],[OperationType],
[Hours],[Occurance],[Period],[NotificationText],
[NotificationRecipientIDs],[NotificationRecipientClienitsIDs]
FROM tblIA_Notifications t
WHERE IsDeleted = 0 AND IsActive = 1
)
The above query always returns rownumber 1 for each row. When I use the select statement outside, its problem. Otherwise if I remove the outer select statement its fine.
I don't understand the behavior.
Uou are getting row_number 1 for each row because you are selecting the Row_Number for each row
try this--->
SELECT ROW_NUMBER() OVER (order by t.NotificationID) as RowNumber,
[NotificationID],
[ProjectID],
[TeamMemberID],
[OperationType],
[Hours],
[Occurance],
[Period],
[NotificationText],
[NotificationRecipientIDs],
[NotificationRecipientClienitsIDs]
FROM tblIA_Notifications t
WHERE IsDeleted = 0
AND IsActive = 1
Try this...
SELECT ROW_NUMBER() OVER (order by T.COLUMN_NAME) as RowNumber FROM [dbo].[TABLE_NAME] T
I have a stored procedure that does paging for the front end and is working fine. I now need to modify that procedure to group by four columns of the 20 returned and then only return the row within each group that contains the lowest priority. So when resort_id, bedrooms, kitchen and checkin (date) all match then only return the row that has the min priority. I have to still maintain the paging functionality. The #startIndex and #upperbound are parms passed into the procedure from the front end for paging. I’m thinking that RANK OVER (PARTITION BY) is the answer I just can’t quite figure out how to put it all together.
SELECT I.id,
I.resort_id,
I.[bedrooms],
I.[kitchen],
I.[checkin],
I.[priority],
I.col_1,
I.col_2 /* ..... (more cols) */
FROM (
SELECT ROW_NUMBER() OVER(ORDER by checkin) AS rowNumber,
*
FROM Inventory
) AS I
WHERE rowNumber >= #startIndex
AND rowNumber < #upperBound
ORDER BY rowNumber
Example 2 after fix:
SELECT I.resort_id,
I.[bedrooms],
I.[kitchen],
I.[checkin],
I.[priority],
I.col_1,
I.col_2 /* ..... (more cols) */
FROM Inventory i
JOIN
(
SELECT ROW_NUMBER() OVER(ORDER BY h.checkin) as rowNumber, MIN(h.id) as id
FROM Inventory h
JOIN (
SELECT resort_id, bedrooms, kitchen, checkin, id, MIN(priority) as priority
FROM Inventory
GROUP BY resort_id, bedrooms, kitchen, checkin, id
) h2 on h.resort_id = h2.resort_id and
h.bedrooms = h2.bedrooms and
h.kitchen = h2.kitchen and
h.checkin = h2.checkin and
h.priority = h2.priority
GROUP BY h.resort_id, h.bedrooms, h.kitchen, h.checkin, h.priority
) AS I2
on i.id = i2.id
WHERE rowNumber >= #startIndex
AND rowNumber < #upperBound
ORDER BY rowNumber
I would accompish it this way.
SELECT I.resort_id,
I.[bedrooms],
I.[kitchen],
I.[checkin],
I.[priority],
I.col_1,
I.col_2 /* ..... (more cols) */
FROM Inventory i
JOIN
(
SELECT ROW_NUMBER(ORDER BY Checkin) as rowNumber, MIN(id) id
FROM Inventory h
JOIN (
SELECT resort_id, bedrooms, kitchen, checkin id, MIN(priority) as priority
FROM Inventory
GROUP BY resort_id, bedrooms, kitchen, checkin
) h2 on h.resort_id = h2.resort and
h.bedrooms = h2.bedrooms and
h.kitchen = h2.kitchen and
h.checkin = h2.checkin and
h.priority = h2.priority
GROUP BY h.resort_id, h.bedrooms, h.kitchen, h.checkin, h.priority
) AS I2
on i.id = i2.id
WHERE rowNumber >= #startIndex
AND rowNumber < #upperBound
ORDER BY rowNumber