Define goto in scheme - macros

As an exercise to learn call/cc and macros, I tried to define goto.
(define-syntax label
(syntax-rules ()
((_ name)
(begin
(define name)
(call/cc (lambda (c) (set! name c)))))))
(define (goto label) (label))
(define i 0)
(label start)
(display i) (newline)
(set! i (+ i 1))
(if (< i 3) (goto start))
(display "done") (newline)
It works in guile-2.0, but in chez scheme and racket (r6rs) it just prints
0
done
Which implementation is correct?

I think top level is different in different implementations. For Racket, call/cc captures continuation up to a single, top-most expression, not the whole program. I think Guile captures up to the whole program. Hence the difference.
You can get Guile's behavior by writing your code in a function:
#lang r5rs
(define-syntax label
(syntax-rules ()
((_ name)
(begin
(define name #f)
(call-with-current-continuation (lambda (c) (set! name c)))))))
(define (goto label) (label))
(define (main)
(define i 0)
(label start)
(display i) (newline)
(set! i (+ i 1))
(if (< i 3) (goto start) #f)
(display "done") (newline))
(main)
This outputs:
0
1
2
done
Note that if you use Racket, you can create a new language and redefine toplevel (via #%module-begin) to get Guile's behavior without any modification to the program.

Related

How to expand a macro in MIT Scheme

I have written a simple macro:
(define-syntax myif
(syntax-rules ()
((_ condition a b)
(if condition a b))))
Usage example: (myif #t "yes" "no").
In MIT Scheme, how do I show the macro expansion of the example above? Is there something similar to Common Lisp's macroexpand and macroexpand-1 or Racket's expand and expand-once?
(MIT Scheme version: 11.2)
% cat macro.scm
(define-syntax myif
(syntax-rules ()
((_ condition a b)
(if condition a b))))
% mit-scheme --silent
(sf "macro.scm")
;Generating SCode for file: "macro.scm" => "macro.bin"...
; This program does not have a USUAL-INTEGRATIONS declaration.
; Without this declaration, the compiler will be unable to perform
; many optimizations, and as a result the compiled program will be
; slower and perhaps larger than it could be. Please read the MIT
; Scheme User's Guide for more information about USUAL-INTEGRATIONS.
;... done
(pp (fasload "macro.bin"))
;Loading "macro.bin"... done
(define-syntax myif
(er-macro-transformer
(lambda (form rename compare)
(if (and (pair? form)
(let ((temp (cdr form)))
(and (pair? temp)
(let ((temp (cdr temp)))
(and (pair? temp)
(let ((temp (cdr temp)))
(and (pair? temp)
(null? (cdr temp)))))))))
(list (rename 'if)
(car (cdr form))
(car (cdr (cdr form)))
(car (cdr (cdr (cdr form)))))
(ill-formed-syntax form)))))
will print the Scode. This is enough for debugging.
As it's expressed in the warning of compilation, it is important not to activate the optimizations, otherwise you won't see any more the literal translation into Scode.
This is the starting point when I debug (not only macros).

How to insert literal identifier from input pattern as symbol in syntax-rules macro

I have code like this:
(define-syntax macron
(syntax-rules ()
((_ name)
(lambda (x)
(eval (cons 'name x) (interaction-environment))))))
(define x (map (macron lambda)
'(((x) (display x)) ((a b) (+ a b)))))
(let ((square (car x))
(sum (cadr x)))
(display (square 10))
(newline)
(display (sum 1 2 3))
(newline))
the code is working it use macro as value by wrapping it with lambda. My question is how can I put inside syntax-rule macro literal symbol 'name instead of (cons 'lambda ...) so the output code is:
(lambda (x)
(eval (cons 'name x) (interaction-environment)))
so it work with code like this:
(define (name x)
(display x)
(newline))
(for-each (macron lambda) ;; lambda can be anything
'((1) (2) (3)))
and it print all the numbers.
I know that I can change the name in pattern into something else, but I want to know more about syntax-rules and it's edge cases. So is it possible to have name if I use it as input pattern?
I'm looking for answers with R7RS, that have more of this type of edge cases covered.
All macros happens in compile time so runtime stuff might not exist. That means that you should think of it as syntax sugar and use it as susch. eg.
(for-each (macron something) '((1) (2) (3)))
Should then have an expansion based on that. Your current expansion is that it turns into this:
(for-each (lambda (x)
(eval (cons 'someting x) (interaction-environment))
'((1) (2) (3)))
For something being a macro this will apply the macro in runtime. It is bad. It also removes the need for the macro in the first place. You could do this instead:
(define (macron-proc name)
(lambda (x)
(eval (cons name x) (interaction-environment))))
(for-each (macron-proc 'something) '((1) (2) (3)))
I made a programming language that had passable macros:
(define xor (flambda (a b) `(if ,a (not ,b) ,b)))
(define (fold comb init lst)
(if (null? lst)
init
(fold comb (comb (car lst) init) (cdr lst))))
(fold xor #f '(#t #t)) ; ==> #f
It's not a very good approach if you are targeting an efficient compiled end product. The first macros were indeed like this and they removed it in LISP 1.5 before Common Lisp. Scheme avoided macros for many years and opted for syntax-rules in R4RS as an optional feature. R6RS is the only version that has full power macros.
With a procedure instead of macros this is actually the same as the following code with the bad eval removed:
(for-each (lambda (x)
(apply something x))
'((1) (2) (3)))
Which means you can implement macron much easier:
(define-syntax macron
(syntax-rules ()
((_ name)
(lambda (x)
(apply name x)))))
But from looking at this now you don't need a macro at all. This is partial application.
(define (partial proc arg)
(lambda (lst)
(apply proc arh lst)))
(map (partial + 3) '((1 2) (3 4) (4 5)))
; ==> (6 10 12)
There is actually a SRFI-26 called cut/cute which allows us to do something similar where it wraps it in a lambda:
(map (cut apply + 3 <>) '((1 2) (3 4) (4 5)))
The syntax-rules are the macros with the least power. You cannot do anything unhygienic and you cannot make new identifiers based on other ones. Eg. it' impossible to implement a racket style struct where you can do (struct complex [real imag]) and have the macro create complex?, complex-real, and complex-imag as procedures. You need to do as SRFI-57 does and require th euser to specify all the names such that you don't need to concatenate to new identifiers.
Right now R7RS-small only has syntax-rules. I think it was a mistake not to have a more powerful macro as an alternative since now the R7RS-large cannot be implemented with R7RS-small.

My lisp macro stops working in latest guile

I have macro that I've written in 2010, it was for managing structures like in Common Lips using Alists (here is whole file including functions https://jcubic.pl/struct.txt).
(define-macro (defstruct name . fields)
"Macro implementing structures in guile based on assoc list."
(let ((names (map (lambda (symbol) (gensym)) fields))
(struct (gensym))
(field-arg (gensym)))
`(if (not (every-unique ',fields))
(error 'defstruct "Fields must be unique")
(begin
(define (,(make-name name) ,#names)
(map cons ',fields (list ,#names)))
,#(map (lambda (field)
`(define (,(make-getter name field) ,struct)
(cdr (assq ',field ,struct)))) fields)
,#(map (lambda (field)
`(define (,(make-setter name field) ,struct ,field-arg)
(assq-set! ,struct ',field ,field-arg)
,field-arg)) fields)
(define (,(make-predicate name) ,struct)
(and (struct? ,struct)
(let ((result #t))
(for-each (lambda (x y)
(if (not (eq? x y)) (set! result #f)))
',fields
(map car ,struct))
result)))))))
It was working fine. I've recently updated this macro for my LIPS in JavaScript (it's based on scheme) and when I call it, it was returning false and wanted to know if this is how it would work in guile. But it turns out it don't work in guile at all. It shows this error:
While compiling expression: ERROR: Syntax error: unknown location:
definition in expression context, where definitions are not allowed,
in form (define (make-point #{ g746}# #{ g747}#) (map cons (quote (x
y)) (list #{ g746}# #{ g747}#))
Why I've got this error and how to fix it, so it work in guile again? I was long ago I don't remember how I was testing this code but opening guile using load function or copy paste the code into interpreter all give same error.
I'm using guile 2.0.14 on GNU/Linux.
PS: I prefer to use lisp macros IMO they are superior to weird scheme hygienic macros.
It looks like modern guile scheme does not see the begin in the if as a valid option to start a new definition context. This is perhaps a bug or better alignment of the scheme spec donough. But the following example code shows the technique to fix your code for more recent guile (you might need to create define-values as it is a more recent addition to guile. P.S. using lisps macros in guile is a clludge and it will get you into trouble if you plan to scheme a lot, the macros is like the parens, if you get used to it will feel natural.
Here is the code,
(define-macro (defstruct name . fields)
"Macro implementing structures in guile based on assoc list."
(let* ((names (map (lambda (symbol) (gensym)) fields))
(struct (gensym))
(field-arg (gensym))
(sname (make-name name))
(predname (make-predicate name))
(getnames (map (lambda (f) (make-getter name f)) fields))
(setnames (map (lambda (f) (make-setter name f)) fields)))
`(define-values (,sname ,predname ,#getnames ,#setnames)
(if (not (every-unique ',fields))
(error 'defstruct "Fields must be unique")
(let ()
(define (,sname ,#names)
(map cons ',fields (list ,#names)))
,#(map (lambda (field)
`(define (,(make-getter name field) ,struct)
(cdr (assq ',field ,struct)))) fields)
,#(map (lambda (field)
`(define (,(make-setter name field) ,struct ,field-arg)
(assq-set! ,struct ',field ,field-arg)
,field-arg)) fields)
(define (,predname ,struct)
(and (struct? ,struct)
(let ((result #t))
(for-each (lambda (x y)
(if (not (eq? x y)) (set! result #f)))
',fields
(map car ,struct))
result)))
(values ,sname ,predname ,#getnames ,#setnames))))))
Here is a version of define-values (look at the code after #' to see what it does)
(define-syntax define-values
(lambda (x)
(syntax-case x ()
((_ (f ...) code ...)
(with-syntax (((ff ...) (generate-temporaries #'(f ...))))
#'(begin
(define f #f)
...
(call-with-values (lambda () code ...)
(lambda (ff ...)
(set! f ff)
...))))))))

Elisp lambdas, quoting, and lexical-let

I'm trying to understand the following two snippets of code:
(defun make-adder1 (n) `(lambda (x) (+ ,n x)))
(defun make-adder2 (n) (lexical-let ((n n)) (lambda (x) (+ n x))))
These both seem to produce callables:
(funcall (make-adder1 3) 5) ;; returns 8
(funcall (make-adder2 3) 5) ;; returns 8
These both work. I have two main questions:
1) I don't understand the disparity in "quoting level" between the two approaches. In the first case, the lambda expression is quoted, which means the "symbol itself" is returned instead of the value. In the second case, it seems like the statement with the lambda will get evaluated, so the value of the lambda will be returned. Yet, these both work with funcall. When using funcall on a defun'ed function, it has to be quoted. Is lexical-let doing some kind of quoting automatically? Isn't this, kind of surprising?
2) Reading other posts on this topic, I'm given to understand that the first approach will break down under certain circumstances and deviate from what one would expect from working with lambdas and higher order functions in other languages, because elisp has dynamic scoping by default. Can someone give a concrete example of code that makes this difference apparent and explain it?
In the first example there is no variable n in the resulting function, which is just (lambda (x) (+ 3 x)). It does not need lexical binding because there is no free variable in the lambda, i.e., no variable that needs to be kept in a binding of a closure. If you don't need the variable n to be available, as a variable in uses of the function, i.e., if its value at function definition time (=3) is all you need, then the first example is all you need.
(fset 'ad1 (make-adder1 3))
(symbol-function 'ad1)
returns:
(lambda (x) (+ 3 x))
The second example creates what is, in effect, a function that creates and applies a complicated closure.
(fset 'ad2 (make-adder2 3))
(symbol-function 'ad2)
returns
(lambda (&rest --cl-rest--)
(apply (quote (closure ((--cl-n-- . --n--) (n . 3) t)
(G69710 x)
(+ (symbol-value G69710) x)))
(quote --n--)
--cl-rest--))
A third option is to use a lexical-binding file-local variable and use the most straightforward definition. This creates a simple closure.
;;; foo.el --- toto -*- lexical-binding: t -*-
(defun make-adder3 (n) (lambda (x) (+ n x)))
(fset 'ad3 (make-adder3 3))
(symbol-function 'ad3)
returns:
(closure ((n . 3) t) (x) (+ n x))
(symbol-function 'make-adder1)
returns:
(lambda (n)
(list (quote lambda)
(quote (x))
(cons (quote +) (cons n (quote (x))))))
(symbol-function 'make-adder2)
returns:
(closure (t)
(n)
(let ((--cl-n-- (make-symbol "--n--")))
(let* ((v --cl-n--)) (set v n))
(list (quote lambda)
(quote (&rest --cl-rest--))
(list (quote apply)
(list (quote quote)
(function
(lambda (G69709 x)
(+ (symbol-value G69709) x))))
(list (quote quote) --cl-n--)
(quote --cl-rest--)))))
(symbol-function 'make-adder3)
returns
(closure (t) (n) (function (lambda (x) (+ n x))))

What is wrong with the following Common Lisp macro using gensym?

Learning Common Lisp (using GNU CLISP 2.43) .. so might be a noob mistake. Example is the 'print prime numbers between x and y'
(defun is-prime (n)
(if (< n 2) (return-from is-prime NIL))
(do ((i 2 (1+ i)))
((= i n) T)
(if (= (mod n i) 0)
(return NIL))))
(defun next-prime-after (n)
(do ((i (1+ n) (1+ i)))
((is-prime i) i)))
(defmacro do-primes-v2 ((var start end) &body body)
`(do ((,var (if (is-prime ,start)
,start
(next-prime-after ,start))
(next-prime-after ,var)))
((> ,var ,end))
,#body))
(defmacro do-primes-v3 ((var start end) &body body)
(let ((loop-start (gensym))
(loop-end (gensym)))
`(do ((,loop-start ,start)
(,loop-end ,end)
(,var (if (is-prime ,loop-start)
,loop-start
(next-prime-after ,loop-start))
(next-prime-after ,var)))
((> ,var ,loop-end))
,#body )))
do-primes-v2 works perfectly.
[13]> (do-primes-v2 (p 10 25) (format t "~d " p))
11 13 17 19 23
Next I tried using gensym to avoid naming clashes in macro expansion - do-primes-v3. However I'm stuck with a
*** - EVAL: variable #:G3498 has no value
Tried using macro-expand to see if i could spot the mistake but I can't.
[16]> (macroexpand-1 `(do-primes-v3 (p 10 25) (format t "~d " p)))
(DO
((#:G3502 10) (#:G3503 25)
(P (IF (IS-PRIME #:G3502) #:G3502 (NEXT-PRIME-AFTER #:G3502))
(NEXT-PRIME-AFTER P)))
((> P #:G3503)) (FORMAT T "~d " P)) ;
Use DO* instead of DO.
DO Initializes the bindings in a scope where they are not yet visible. DO* initializes the bindings in a scope where they are visible.
In this particular case var needs to reference the other binding loop-start.
You don't actually need the gensym here for avoiding variable capture, because you do not introduce any variables that would be "local to the macro". When you macroexpand your do-primes-v2, you will see that no variable is introduced that didn't exist outside of the macro.
You do need it for a different thing, though: avoiding multiple evaluation.
If you call the macro like this:
(do-primes-v2 (p (* x 2) (* y 3))
(format "~a~%" p))
it expands to
(do ((p (if (is-prime (* x 2))
(* x 2)
(next-prime-after (* x 2))
(next-prime-after p)))
((> p (* y 3))
(format "~a~%" p))
At best, this is inefficient, because those multiplications are done multiple times. However, if you use a function with side effects as inputs, like setf or incf, this can be a big problem.
Either move the binding of your loop-start and loop-end to an enclosing LET block or use DO*. The reason is that all loop variables in DO are bound "in parallel", so for the first binding, the (expanded) loop-start variable does not yet have a binding.
I know this doesn't really answer your question, but I do think it is relevant. In my experience, the type of macro you are attempting to write is a very common one. One problem I have with the way you have approached the problem is that it doesn't handle another common use case: functional composition.
I don't have the time to highlight some of the difficulties you will probably encounter using your macro, I will however highlight that, had you built your prime iterator geared towards functional composition, your macro turns out to be extremely simple, avoiding your question altogether.
Note: I have slightly modified some of your functions.
(defun is-prime (n)
(cond
((< n 2)
nil)
((= n 2)
t)
((evenp n)
nil)
(t
(do ((i 2 (1+ i)))
((= i n) t)
(when (or (= (mod n i) 0))
(return nil))))))
(defun next-prime (n)
(do ((i n (1+ i)))
((is-prime i) i)))
(defun prime-iterator (start-at)
(let ((current start-at))
(lambda ()
(let ((next-prime (next-prime current)))
(setf current (1+ next-prime))
next-prime))))
(defun map-primes/iterator (fn iterator end)
(do ((i (funcall iterator) (funcall iterator)))
((>= i end) nil)
(funcall fn i)))
(defun map-primes (fn start end)
(let ((iterator (prime-iterator start)))
(map-primes/iterator fn iterator end)))
(defmacro do-primes ((var start end) &body body)
`(map-primes #'(lambda (,var)
,#body)
,start ,end))
I too recommend that you look at Series. The generator pattern is also a very common occurrence in lisp programs. You may also want to look at Alexandria, in particular the function ALEXANDRIA:COMPOSE to see what cool stuff you can do with functional composition.
I suggest avoiding DO/DO* and macros altogether and instead going for Series (an implementation of which can be found on series.sourceforge.net).
If that's too complex then consider just generating a list of primes with recursion or a generator (for on-demand generation).