How to disable celery task result logging? - celery

I have working Celery 3.1 app which logs some sensitive info. Ideally I would to have the same log, but without result part.
Currently it looks like:
worker_1 | [2019-12-10 13:46:40,052: INFO/MainProcess] Task xxxxx succeeded in 13.19569299298746s: yyyyyyy
I would like to have:
worker_1 | [2019-12-10 13:46:40,052: INFO/MainProcess] Task xxxxx succeeded in 13.19569299298746s
How to do that?
Edit:
It seems that this could do the job: https://docs.celeryproject.org/en/3.1/reference/celery.worker.job.html#celery.worker.job.Request.success_msg but I have no idea how to actually use it.

Just in case it's useful to anyone in near future, I found in Celery 4.4 the success_msg in the Request class has been moved to the application tracer.
Luckily, it seems this can be easily overridden in your Django app's celery.py like so:
from celery.app import trace
trace.LOG_SUCCESS = """\
Task %(name)s[%(id)s] succeeded in %(runtime)ss\
"""
You can change it to anything you like of course, this just removes the return value portion. Full context here.

You need to override the success message being sent, remove the return_value format from there.
For that you need to override the Request class, as described here.
You can also override the logging config as mentioned here.

worker_1 | [2019-12-10 13:46:40,052: INFO/MainProcess] Task xxxxx succeeded in 13.19569299298746s: yyyyyyy
yyyyyyy is the result that your function returns, to remove that simply return what you want.
in your case only return will work

Related

upgrading celery 4.x.x to 5.x.x in Django app - execute_from_commandline() replacement

the usage in 4.x.x was as following:
from tenant_schemas_celery.app import CeleryApp
class TenantCeleryApp(CeleryApp):
def create_task_cls(self):
return self.subclass_with_self('...', abstract=True, name='...', attribute='_app')
tenant_celery = TenantCeleryApp()
base = celery.CeleryCommand(app=tenant_celery)
base.execute_from_commandline('...')
...
Now when updating celery lib to 5.x.x the following error show:
base = celery.CeleryCommand(app=tenant_celery)
TypeError: __init__() got an unexpected keyword argument 'app'
from the documentation, the new CeleryCommand use click.Command class, how do I change my code to fit - what is the replacement usage for execute_from_commandline()?
EDIT:
after some tries hard the following code works:
tenant_celery.worker_main(argv=['--broker=amqp://***:***#rabbitmq:5672//***',
'-A', f'{__name__}:tenant_celery',
'worker', '-c', '1', '-Q', 'c1,c2,c3,c4'])
You can do a few things here.
The typical way to invoke / start a worker from within python is discussed at this answer:
worker = tenant_celery.Worker(
include=['project.tasks']
)
worker.start()
In this case, you would be responsible for making the worker exit when you are done.
To execute the CeleryCommand / click.Command, you pass in the arguments to the main function
base = CeleryCommand()
base.main(args=['worker', '-A', f'{__name__}:tenant_celery'])
You would still be responsible for controlling how celery exits in this case, too. You may choose a verb other than worker such as multi for whatever celery subcommand you were expecting to call.
You may also want to explicitly specify the name of the celery module for the -A parameter as discussed here.

Retrieving Celery task kwargs from task-failed / uuid

Main Issue
I'm testing how to handle certain task failure, for example handling a 'TimeLimitExceeded' exception which instantly kills the task and is not 'catchable' (Yes...I'm aware of the existence of 'SoftTimeLimit' but it doesn't fit my needs).
First Approach
This is my tasks.py (The worker runs with a --time-limit flag):
import logging
from celery import Celery
import time
app = Celery('tasks', broker='pyamqp://guest#localhost//')
def my_fail(task, exc, req_id, req_args, req_kwargs, einfo, *ext_args, **kwargs):
logger.info("args: %r", req_args)
logger.info("kw: %r", req_kwargs)
#app.task(on_failure=my_fail)
def sum(x, y, delay=0, **kw):
result = x+y
if result == 4:
raise Exception("Some Error")
time.sleep(delay)
return x+y
The main idea when a task fails, to be able to perform some handling based on the args/kwargs of the task
For example if I run sum.delay(3, 1, foo="bar") the Exception("Some Error") is raised and the following is logged:
[2019-06-30 17:21:45,120: INFO/Worker-1] args: (3, 1)
[2019-06-30 17:21:45,121: INFO/Worker-1] kw: {'foo': 'bar'}
[2019-06-30 17:21:45,122: ERROR/MainProcess] Task tasks.sum[9e9de032-1469-44e7-8932-4c490fcee2e3] raised unexpected: Exception('Some Error',)
Traceback (most recent call last):
File "/home/apernin/.virtualenvs/dr/local/lib/python2.7/site-packages/celery/app/trace.py", line 240, in trace_task
R = retval = fun(*args, **kwargs)
File "/home/apernin/.virtualenvs/dr/local/lib/python2.7/site-packages/celery/app/trace.py", line 438, in __protected_call__
return self.run(*args, **kwargs)
File "/home/apernin/test/tasks.py", line 89, in sum
raise Exception("Some Error")
Exception: Some Error
Note the args/kwargs are printed by my on-failure handler.
Now if I run sum.delay(3, 2, delay=7) the TimeLimit is triggered
[2019-06-30 17:23:15,244: INFO/MainProcess] Received task: tasks.sum[8c81398b-4378-401d-a674-a3bd3418ccde]
[2019-06-30 17:23:21,070: ERROR/MainProcess] Task tasks.sum[8c81398b-4378-401d-a674-a3bd3418ccde] raised unexpected: TimeLimitExceeded(5.0,)
Traceback (most recent call last):
File "/home/apernin/.virtualenvs/dr/local/lib/python2.7/site-packages/billiard/pool.py", line 645, in on_hard_timeout
raise TimeLimitExceeded(job._timeout)
TimeLimitExceeded: TimeLimitExceeded(5.0,)
[2019-06-30 17:23:21,071: ERROR/MainProcess] Hard time limit (5.0s) exceeded for tasks.sum[8c81398b-4378-401d-a674-a3bd3418ccde]
[2019-06-30 17:23:21,629: ERROR/MainProcess] Process 'Worker-1' pid:15472 exited with 'signal 15 (SIGTERM)'
Note the args/kwargs are note printed, because of the on-failure handler not being excuted. This is somewhat to be expected due to the nature of Celery's Hard Time Limit.
Second Approach
My second approach is to use a event-listener.
from celery import Celery
def my_monitor(app):
state = app.events.State()
def announce_failed_tasks(event):
state.event(event)
# task name is sent only with -received event, and state
# will keep track of this for us.
task = state.tasks.get(event['uuid'])
with app.connection() as connection:
recv = app.events.Receiver(connection, handlers={
'task-failed': announce_failed_tasks,
})
recv.capture(limit=None, timeout=None, wakeup=True)
if __name__ == '__main__':
app = Celery(broker='amqp://guest#localhost//')
my_monitor(app)
The only info I was able to retrieve was the task uuid, I wasn't able to retrieve the name, args or kwargs of the task (the task object contains the attributes but are all None).
Question
Is there a way to either:
Make the on_failure handler in case of a Hard Time Limit?
Retrieve the tasks args/kwargs of a task with a task-failed event listener?
Thanks in advance
First, the timeout is handled by the Worker (the MainProcess) and it is not treated the same as failures happened INSIDE the task, such as exceptions being thrown, etc. This is why you see it as TimeLimitExceeded raised by the MainProcess in the log. So, unfortunately you can't rely on the same logic...
However, your second approach will prove useful in tracking down what is going on.
I have developed (in-house) a Celery monitoring tool that grabs all the events, and populates a database with them so that later we can do all sort of analytics (see average and worst running times for an example, frequency of failures, etc).
In order to grab the details you need from the data given by the task-failed event you also need to record (store it in some dictionary for an example) the task-received event data. This information contains args, task names, and all sort of useful information you may need. You relate them both by the task UUID.

How to manipulate the status of current job-execution from inside of an inline script?

The following code returns an error to rundeck.
#!/bin/bash
exit -1
And rundeck decides how to deal with it by running the next step or changing the execution "status" to "failed".
I would like to modify the status directly by inline script to support more than 2 states. I need "succeeded", "failed" and "nodata" to express that the data are missing.
Is there a way to express this?
There is none. Just like bash can return zero or non-zero
One possible alternative is raise an exception with message nodata and exit with non-zero code. Rundeck will mark this job as fail with NonZeroResultCode error. You should be able to get your error message nodata with ${result.message}

How can I hide skipped tasks output in Ansible

I have Ansible role, for example
---
- name: Deploy app1
include: deploy-app1.yml
when: 'deploy_project == "{{app1}}"'
- name: Deploy app2
include: deploy-app2.yml
when: 'deploy_project == "{{app2}}"'
But I deploy only one app in one role call. When I deploy several apps, I call role several times. But every time there is a lot of skipped tasks output (from tasks which do not pass condition), which I do not want to see. How can I avoid it?
I'm assuming you don't want to see the skipped tasks in the output while running Ansible.
Set this to false in the ansible.cfg file.
display_skipped_hosts = false
Note. It will still output the name of the task although it will not display "skipped" anymore.
UPDATE: by the way you need to make sure ansible.cfg is in the current working directory.
Taken from the ansible.cfg file.
ansible will read ANSIBLE_CONFIG,
ansible.cfg in the current working directory, .ansible.cfg in
the home directory or /etc/ansible/ansible.cfg, whichever it
finds first.
So ensure you are setting display_skipped_hosts = false in the right ansible.cfg file.
Let me know how you go
Since ansible 2.4, a callback plugin name full_skip was added to suppress the skipping of task names and skipping keyword in the ansible output. You can try the below ansible configuration:
[defaults]
stdout_callback = full_skip
Ansible allows you to control its output by using custom callbacks.
In this case you can simply use the skippy callback which will not output anything on a skipped task.
That said, skippy is now deprecated and will be removed in ansible v2.11.
If you don't mind losing colours you can elide the skipped tasks by piping the output through sed:
ansible-playbook whatever.yml | sed -nr '/^TASK/{h;n;/^skipping:/{n;b};H;x};p'
If you are using roles, you can use when to cancel the include in main.yml
# roles/myrole/tasks/main.yml
- include: somefile.yml
when: somevar is defined
# roles/myrole/tasks/somefile.yml
- name: this task will only run (and be seen in the output) if somevar is defined
debug:
msg: "Hello World"

How to make a celery task fail from within the task?

Under some conditions, I want to make a celery task fail from within that task. I tried the following:
from celery.task import task
from celery import states
#task()
def run_simulation():
if some_condition:
run_simulation.update_state(state=states.FAILURE)
return False
However, the task still reports to have succeeded:
Task sim.tasks.run_simulation[9235e3a7-c6d2-4219-bbc7-acf65c816e65]
succeeded in 1.17847704887s: False
It seems that the state can only be modified while the task is running and once it is completed - celery changes the state to whatever it deems is the outcome (refer to this question). Is there any way, without failing the task by raising an exception, to make celery return that the task has failed?
To mark a task as failed without raising an exception, update the task state to FAILURE and then raise an Ignore exception, because returning any value will record the task as successful, an example:
from celery import Celery, states
from celery.exceptions import Ignore
app = Celery('tasks', broker='amqp://guest#localhost//')
#app.task(bind=True)
def run_simulation(self):
if some_condition:
# manually update the task state
self.update_state(
state = states.FAILURE,
meta = 'REASON FOR FAILURE'
)
# ignore the task so no other state is recorded
raise Ignore()
But the best way is to raise an exception from your task, you can create a custom exception to track these failures:
class TaskFailure(Exception):
pass
And raise this exception from your task:
if some_condition:
raise TaskFailure('Failure reason')
I'd like to further expand on Pierre's answer as I've encountered some issues using the suggested solution.
To allow custom fields when updating a task's state to states.FAILURE, it is important to also mock some attributes that a FAILURE state would have (notice exc_type and exc_message)
While the solution will terminate the task, any attempt to query the state (For example - to fetch the 'REASON FOR FAILURE' value) will fail.
Below is a snippet for reference I took from:
https://www.distributedpython.com/2018/09/28/celery-task-states/
#app.task(bind=True)
def task(self):
try:
raise ValueError('Some error')
except Exception as ex:
self.update_state(
state=states.FAILURE,
meta={
'exc_type': type(ex).__name__,
'exc_message': traceback.format_exc().split('\n'),
'custom': '...'
})
raise Ignore()
I got an interesting reply on this question from Ask Solem, where he proposes an 'after_return' handler to solve the issue. This might be an interesting option for the future.
In the meantime I solved the issue by simply returning a string 'FAILURE' from the task when I want to make it fail and then checking for that as follows:
result = AsyncResult(task_id)
if result.state == 'FAILURE' or (result.state == 'SUCCESS' and result.get() == 'FAILURE'):
# Failure processing task