In a graph I'm trying to show last month with this expression:
=If( [SH_historico_1.ANOMES] >= '$(=Max([SH_historico_1.ANOMES])-1)' and [SH_historico_1.ANOMES] <= '$(=Max([SH_historico_1.ANOMES]))', [SH_historico_1.ANOMES])
When I write [SH_historico_1.ANOMES] I'm referring to Period, Like 'YYYYMM'
And when I subtract -1 I'm just substact 1 to, example: 202002 -1 = 202001, so works, because It will calculate the correct period.
But... If the month it is january? YYYY01? example 202001 -1 = 202000 00 month number it does not exist. The 00 it should be 12.
So I'm wondering what if I treat the number as a date?
I'm trying to use Date() function but I'm little stuck.
How it could be with correct syntax?
Another solution I'm thinking it is to set some code in editor code, but still developing the idea.
Any help it is welcome.
When you want to add/subtract months its better to use AddMonths() function: AddMonths( DateField, NumberOfMonths). This function will deal with the January issue
In your case will be: =AddMonths(Max([SH_historico_1.ANOMES]), -1) (as you can see the number of months can be negative number which will subtract the months from the date)
And a bit on advice: If you are planning to use this calculation in expression then consider using Set Analysis instead of if..then..else statement. if statements are slower and they are consuming more resources when used in expressions
Related
I am working on a large nested IF statement that checks several validation points for each row of my sheet. There are several date validations, including chronological order and certain fields not being future dates. However, our system requires that if we must null any dates for processing, that date becomes 1/1/2500, and no matter what I do I cannot seem to get the formula to ignore this date when accounting for future dates or chronology.
//The date cannot be later than the current date - I want this to ignore 1/1/2500
IF(K1<>1/1/2500,"",IF(AND(K1>TODAY()),"Date A cannot be future date",""))
//The two dates must be in chronological order, also ignoring 1/1/2500
IF(U1<>1/1/2500,"",IF(AND(U1>AA1,AA1),"Date A, Date B should be in chronological order",""))
The above approach does not seem to recognize 1/1/2500, even though I got it to work with other dates.
I also tried going with >12/31/2099 (ignore any date greater than 12/31/2099) but it just ignores every date.
Any help would be appreciated.
It looks as though it is failing because K1 is compared to 12/31/2099.
If you use an expression like this in a formula, it will interpret it as an arithmetic expression 12 divided by 31 divided by 2099, which is a very small number, so the greater than test will always be true.
Try starting the formula with Date to convert a year, month, and day into a date.
If(K1>date(2099,12,31)
and you should get the right answer.
See my previous answer for Excel.
I have read in this online PostgreSQL documentation... http://www.postgresql.org/docs/9.4/static/datatype-datetime.html#INTERVAL-STYLE-OUTPUT-TABLE
in the point 8.5.5 something about how to tweak the default Interval Output. . I mean the default interval is shown like this...
00:00:00.000 (if the timedifference is lower than a day or month or year)
1 day 00:00:00.000 (if the timedifference reaches days, but is lower than a month or a year)
1 month 1 day 00:00:00.000 (if the timediffence reaches months, but is lower than a year)
1 year 1 month 1 day 00:00:00.000 (if it reaches years, months, days)
it evens uses plurarl cases (years, mons, days) when their values are greater than one.
All these variations make difficult to any other app when SELECTing (query) this interval values (as text) to convert it to a proper time. So I would like postgresql to always show year, month n days, even if their value are 0 (it could be even better if it could show the date part of the interval like this... 01-11-30, adding zeros to the left side when values are less than ten)
I know I can change the interval to text, using to_char() but I really would like to avoid that, I would like some good fellow postgresql programmer to tell me if it is true that there is a way to tweak the Interval Output as is said in the postgresql documentation.
Thanks Advanced.
PD: two more links about the subject
https://my.vertica.com/docs/7.1.x/HTML/Content/Authoring/SQLReferenceManual/Statements/SET/SETDATESTYLE.htm
http://my.vertica.com/docs/6.1.x/HTML/index.htm#13874.htm
You can set the interval output style, but only to one of a few pre-defined formats that are unambigious on input, and that PostgreSQL knows how to parse back into intervals. Per the documentation these are the SQL standard interval format, two variants of PostgreSQL specific syntax, and iso_8601 intervals.
If you want something familiar and easy to parse, consider using:
SET intervalstyle = 'iso_8601'
and using an off-the-shelf parser for ISO1601 intervals.
I have a data set in which month and year are in one variable and come in the form 200801 which equates to 2008, January. How can I create a SAS date from this integer?
I would like something in the form of Jan 2008 - anything so that SAS recognizes it as a date, as I then need to subtract this value from service date to find out how much time has elapsed since enrollment into the dataset until date of service.
Please also keep in mind that this is a variable, and I have thousands of observations. So I also need the data step/ function to do this for the entire variable.
Any help is appreciated!
You need to put it to a character variable, then input back to numeric. You can do that pretty easily.
date_var = input(put(date_var_orig,6.)||'01',yymmdd8.);
You can also do it this way:
date_var = mdy(mod(date_var_orig,100),1,floor(date_var_orig/100));
Both assume you want the day to equal 1; make a choice there if you want something else (like end of month or middle of month).
I want to calculate the number of days passed between past date and a current date. My past date is in the format dd/mm/yyyy format. I have used below mentioned formulas but giving the proper output.
=DAYS360(A2,TODAY())
=MINUS(D2,TODAY())
In the above formula A2 = 4/12/2012 (dd/mm/yyyy) and I am not sure whether TODAY returns in dd/mm/yyyy format or not. I have tried using 123 button on the tool bar, but no luck.
The following seemed to work well for me:
=DATEDIF(B2, Today(), "D")
DAYS360 does not calculate what you want, i.e. the number of days passed between the two dates – see the end of this post for details.
MINUS() should work fine, just not how you tried but the other way round:
=MINUS(TODAY(),D2)
You may also use simple subtraction (-):
=TODAY()-D2
I made an updated copy of #DrCord’s sample spreadsheet to illustrate this.
Are you SURE you want DAYS360? That is a specialized function used in the
financial sector to simplify calculations for bonds. It assumes a 360 day
year, with 12 months of 30 days each. If you really want actual days, you'll
lose 6 days each year.
[source]
Since this is the top Google answer for this, and it was way easier than I expected, here is the simple answer. Just subtract date1 from date2.
If this is your spreadsheet dates
A B
1 10/11/2017 12/1/2017
=(B1)-(A1)
results in 51, which is the number of days between a past date and a current date in Google spreadsheet
As long as it is a date format Google Sheets recognizes, you can directly subtract them and it will be correct.
To do it for a current date, just use the =TODAY() function.
=TODAY()-A1
While today works great, you can't use a date directly in the formula, you should referencing a cell that contains a date.
=(12/1/2017)-(10/1/2017) results in 0.0009915716411, not 61.
I used your idea, and found the difference and then just divided by 365 days. Worked a treat.
=MINUS(F2,TODAY())/365
Then I shifted my cell properties to not display decimals.
If you are using the two formulas at the same time, it will not work...
Here is a simple spreadsheet with it working:
https://docs.google.com/spreadsheet/ccc?key=0AiOy0YDBXjt4dDJSQWg1Qlp6TEw5SzNqZENGOWgwbGc
If you are still getting problems I would need to know what type of erroneous result you are getting.
Today() returns a numeric integer value: Returns the current computer system date. The value is updated when your document recalculates. TODAY is a function without arguments.
The following worked for me. Kindly note that TODAY() must NOT be the first argument in the function otherwise it will not work.
=DATEDIF( W2, TODAY(), "d")
Today() does return value in DATE format.
Select your "Days left field" and paste this formula in the field
=DAYS360(today(),C2)
Go to Format > Number > More formats >Custom number format and select the number with no decimal numbers.
I tested, it works, at least in new version of Sheets, March 2015.
I am using Objective-C within X-code.
I am iterating through a dictionary which contains a date value as one of it's keys. All I want to do is get an array of all the distinct dates so I can use them in a table, as headers. I just plan on
iterating the dictionary and adding dates to a mutable array each time I encounter a new date.
I must set previous date to new date for comparisons to work and I am having a very difficult time figuring out how to set one date equal to another date.
This seems like it should be such a simple thing to do and I am trying to avoid converting the dates to strings first - but if that's what I have to do, then so be it.
Any help would be appreciated.
Thanks,
Gerry O.
If you know the time offset is same as GMT, you could do it by dividing the date's timestamp by 86400 seconds (or three more 0s in milliseconds) and comparing those. If a time offset is there, add or subtract by 3600 seconds per hour before you divide them. But then again, leap years and seconds would break that...
Most languages have libraries support extracting the year, date, month, etc. They take everything into account, usually.
In Objc, you can get a NSDateComponents from NSCalendar's components:fromDate: method. After this, you can call the components to see exactly what each component (I suggest year, month, day) is.
I think you want code to compare dates and You need two loops nested.... where in outer loops iterates with conditional inner loop... In inner loop you just check that previously you had the same date or not...
please go through the below post on same site...
How to compare two dates in Objective-C
hope you will get solution... else clarify your question....