I want to compare from_date and to_date with date_order using search orm in odoo.
I just want to extract date alone because in date_order it is given date with date time. how to work with it ?
here is my code :
from_date = fields.Date(string="From", default="Today")
to_date = fields.Date(string="To")
def update_commission(self):
sale_br = self.env['sale.order']
sale_sr = sale_br.search([('date_order', '=', self.from_date)])
Modify your function like this:
def update_commission(self):
sale_br = self.env['sale.order']
sale_sr = sale_br.search([]).filtered(lambda sale: sale.date_order.date < self.from_date)
If you are working in odoo's past version like 10,11 than you need to convert this datetime into datetime object because when you call this field it will return date in string format so you need to do fields.Datetime.from_string(sale.date_order.date)
Related
I'm trying to get records inserted after a certain date given to me by the client.
2018-06-06
Here's how I'm writing the query:
{:ok, date} = NaiveDateTime.from_iso8601(date_string)
from(
m in query,
where: m.inserted_at > ^date
)
(MatchError) no match of right hand side value: {:error, :invalid_format}
And when I try to use a simple Date object:
** (Ecto.Query.CastError) lib/messages/search.ex:77: value ~D[2018-06-06] in where cannot be cast to type :naive_datetime in query
How can I find all messages inserted after that dummy string date the client is passing me?
You have an ISO 8601 date there, not a datetime. You can convert it into a NaiveDateTime (with hour, minute, second all set to 0) like this:
iex(1)> date_string = "2018-06-06"
"2018-06-06"
iex(2)> ndt = NaiveDateTime.from_iso8601!(date_string <> " 00:00:00")
~N[2018-06-06 00:00:00]
Now you can use ndt in your query and it will work.
I'm trying to select records from a DB2 Iseries system where the date field is greater than the first of this year.
However, the date fields I'm selecting from are actually PACKED fields, not true dates.
I'm trying to convert them to YYYY-MM-DD format and get everything greater than '2018-01-01' but no matter what I try it says it's invalid.
Currently trying this:
SELECT *
FROM table1
WHERE val = 145
AND to_date(char(dateShp), 'YYYY-MM-DD') >= '2018-01-01';
it says expression not valid using format string specified.
Any ideas?
char(dateshp) is going to return a string like '20180319'
So your format string should not include the dashes.. 'YYYYMMDD'
example:
select to_date(char(20180101), 'YYYYMMDD')
from sysibm.sysdummy1;
So your code should be
SELECT *
FROM table1
WHERE val = 145
AND to_date(char(dateShp), 'YYYYMMDD') >= '2018-01-01';
Charles gave you a solution that converts the Packed date to a date field, and if you are comparing to another date field, this is a good solution. But if you are comparing to a constant value or another numeric field, you could just use something like this:
select *
from table1
where val = 145
and dateShp >= 20180101;
I'm trying to convert value for DIM_DT_ID to MMddYY. I'm successful in doinf that. However, query fails because ultimately I'm comparing a character value to date here. Is there a way by which I can get value for DIM_DT_ID in MMddyy format and its data type still remains DATE ?
Here DIM_DT_ID
SELECT DIM_DT_ID
DIM_DT_ID >= FORMATDATE('MMddyy',ADDDAY(TO_date('yyyy-MM-dd','2016-12-21'), -25)); from abc;
Regards,
Ajay
In Denodo, to convert a string to a date field, use "to_date()" (which returns a date).
Then, don't convert back to a string, leave that field as a date (so don't use "Formatdate()", which returns a string).
So:
SELECT *
FROM MyTable
WHERE now() >= to_date('yyyy-MM-dd',myStringFieldThatLooksLikeADate)
In my example, "now()" is a date, and so is the output of the to_date function... so you can do a comparison.
If you try to convert the date back to a string using formatdate, it won't work:
#This doesn't work:
SELECT *
FROM MyTable
WHERE now() >= formatdate('MMddyy',to_date('yyyy-MM-dd',myStringFieldThatLooksLikeADate))
It doesn't work because we are comparing a date ("now()") to a string.
I have a fusion table with two date_time columns. The fist one is the start date (Startdatum) and in the other column is the end date (Einddatum).
I want to do a query with the current date, and only show the KML-lines on a map where the current date lies between the start and end date.
I tried to use the code below to create a string with a date format:
var time_date = new Date();
var day = time_date.getDate();
var month = time_date.getMonth()+1;
var year = time_date.getFullYear();
var date = (year+"."+month+"."+day);
To show the KML-lines on the map I tried to use the following code:
layer = new google.maps.FusionTablesLayer({
map: map,
heatmap: { enabled: false },
query: {
select: "col2",
from: "1mOMP1seJq4FdiNTugsfylZaJc8sKcSlfJKUuTJjv",
where: "'Startdatum' <= date AND 'Einddatum' >= date"
},
options: {
styleId: 2,
templateId: 2
}
});
Unfortunatly the map shows all the KMS-lines regardless what date is in one of the columns.
What am I doing wrong?
the where-clause is wrong, it has to be
where: "Startdatum <= '"+date+"' AND Einddatum >= '"+date+"'"
the date-format seems to be wrong. Although the used format yyyy.MM.dd is defined in the documentation, it doesn't work. The format yyyy-MM-dd currently works for me(but it's not defined in the documentation).
var date = (year+"-"+month+"-"+day);
(in case that day and month be less than 10 they wouldn't match the pattern, but that doesn't seem to be an issue)
Beyond that: when you fix these 2 mentioned parts it currently works(for me), but I've tried it a couple of hours ago and got unstable results.
Currently I'm storing it as a String, but got problems using it when it comes to querying by date with GQL.
Date date = Calendar.getInstance().getTime();
DateFormat formatter = new SimpleDateFormat("hh:mm:ss, z");
String todayDate = formatter.format(date);
The query:
"SELECT FROM SomeTable p WHERE date = 01/01/2011"
Error:
Exception:
org.datanucleus.store.appengine.query.DatastoreQuery$UnsupportedDatastoreFeatureException:
Problem with query : Right side of expression is
composed of unsupported components.
Left:
org.datanucleus.query.expression.Literal,
Op: / , Right:
DyadicExpression{Literal{5} /
Literal{11}}
How can I search by date?
Always as a date - the database should check on the types of data that it stores thus making sure the data is what it says. the information about what type is known on the insert so check it then rather than later when none has any idea of what the correct value should have been.
the error you are getting is probably not due to this but because the date in the query needs to be made a date if types are correct or if a string needs to be as a single-quoted string see GQL Reference
e.g.
"SELECT FROM SomeTable p WHERE date = '01/01/2011'"
but what date is 06/07/2011 ? I think it is today 6th July, others 7th June. So even if you use strings use the ISO format 2011-07-06 A date type will hide this detail making it easier. Note that GQL only uses the ISO form so even if you got the command to have the date in a string it would fail.
but better as
SELECT FROM SomeTable p WHERE date = DATE( 2011, 1, 1)