I want to test a wicket component which shows a context menu on click with the secondary mouse button.
With WicketTester.click(Component) I can click obviously simulate a click on a component. But how do I simulate a click with the secondary mouse button?
WicketTester does not provide means to test JavaScript!
If the context menu is being shown with Wicket Ajax call to the server to make it visible then you can do tester.executeAjaxBehavior(...).
If the menu is shown via JavaScript in the browser then WicketTester cannot check whether it is visible or not. But in that case you should be able to test selecting a menu item, i.e. sending an Ajax call with the appropriate value for the item.
Related
I am trying to make a side menu bar in my app. the side menu is showing. but I can't click those links. When I inspect the page and select an item, it is selected tag.
Assuming that you have used this example. This example does not implement click events, to add them:
In React, use onClick() handler.
In Angular, use ng-click or bind event (click)
This should be added to every "ion-item" tag in above example.
I'm using Jubula to automate a JavaFX application. The problem is that, when I selected a tabbed component, I want to click right on this component. However, this component isn't mapped cause I selected it with index.
Is there a way to click on it with the right button?
If the mouse in in the component, Jubula does not change the position for the next action(except it is specified in the action).
This means if you select the tab with the select tab action. You could do another action e.g. "select context menu" at the exact same position.
I need a way of capturing onclick event when a user clicks out of a FocusPanel(in the form of a dialog box). I need to warn the user to save their work before clicking outside thus losing the panel. I know how to do it in JavaScript but it I am stuck with GWT. Any assistance will be appreciated.
Every click event provides coordinates of a click. Check that these coordinates are outside of your popup panel.
Alternatively, make your PopupPanel modal, so that users can exit it only by clicking on UI elements that you provide, for example, submit and cancel/close buttons.
I plan to add a menu that pop ups when a user performs a certain action. This menu will include some fields that the user will fill out and then hit "Submit" which will close the dialog box and update the client based on information inputed.
However, I want the user to be able to close the dialog window by hitting cancel or submit, and not by clicking on the screen outside of the dialog box.
How can i do this? Or maybe I should just use a PopupPanel?
It's as easy as setting the auto-hide behavior to false, either at construction time or later.
I have doubt regarding GWT .In Gwt if i click one button than it shows one dialog box at th same time the form outside the dialog box disabled.What component can be used for this task?
Thanks in advance
So, you want to open a popup dialog box, and at the same time disable the rest of the page until the user closes the dialog box?
If so, you can simply use gwt's DialogBox.
Use the constructor with the autohide flag set to false, and the box will not close until the user responds, thus disabling the rest of the page. If you want to make this even more clear, use the glass effect:
yourBox.setGlassEnabled(true);
You can also use the PopupPanel directly and build your own custom dialog box.
Now, if I got it wrong and you want to disable the form so it remains disabled after the popup, just disable it in the onClick handler of the button that opens the box.