I have a form that I want to change views from if a Bool is false:
var body: some View {
NavigationView {
Form {
Section {
Toggle(isOn: $ClientAnswer) {
Text("Client answer")
}
if ClientAnswer {
Toggle(isOn: $submission.fieldOne ) {
Text("Field One")
}
Toggle(isOn: $submission.fieldTwo ) {
Text("Field Two")
}
}
}
Section {
Button(action: {
if self.ClientAnswer{
self.placeSubmission()
}
else {
ShowRS() //**change views here.**
print("test")
}
}){
Text("Submit")
}
}.disabled(!submission.isValid)
}
}
}
The code is being executed as print("test") works, but it doesn't change view it just stays on the same view?
The view I am trying to switch to is:
struct ShowRS: View {
var body: some View {
Image("testImage")
}
}
You have to include ShowRS in your view hierarchy -- right now, it's just in your Buttons action callback. There are multiple ways to achieve this, but here's one option:
struct ContentView : View {
#State private var moveToShowRSView = false
var body: some View {
NavigationView {
Button(action: {
if true {
moveToShowRSView = true
}
}) {
Text("Move")
}.overlay(NavigationLink(destination: ShowRS(), isActive: $moveToShowRSView, label: {
EmptyView()
}))
}
}
}
struct ShowRS: View {
var body: some View {
Image("testImage")
}
}
I've simplified this down from your example since I didn't have all of your code with your models, etc, but it demonstrates the concept. In the Button action, you test a boolean (in this case, it'll always return true) and then set the #State variable moveToShowRSView.
If moveToShowRSView is true, there's an overlay on the Button that has a NavigationLink (which is invisible because of the EmptyView) which will only be active if moveToShowRSView is true
Related
I am trying to show a pause button if a sound file is playing, i have a uniform source of truth for the sound file, which i can access via ViewModel, now all works well on other Views, but on parent View where all navigation links are, when i go back to it using the back button from other Views, the miniplayer that shows pause disappears...
So i decided that on the .onAppear of NavigationView or text view of parent View i will implement the logic that can detect if a sound file is playing and if so , show a button at bottom to pause the sound file.
Now i can use print and it shows correct value on onAppear in terms of sound file playing or not, but the moment i try to use HStack or any other View to be added i get warning -
Result of 'HStack<Content>' initializer is unused
Now if i decide to use State then also i get similar warning, how can i make the View rerender onAppear, or is that not possible, if that is the case from where i can implement this logic, thanks ....
import Foundation
import SwiftUI
struct HomePageTabView: View {
#Binding var songLVM: SongListVM
#State var miniBar: Bool = false
init(songLVM: Binding<SongListVM>){
self._songLVM = songLVM
UITableView.appearance().backgroundColor = UIColor(.white)
}
var body: some View {
NavigationView {
List {
//Artists
NavigationLink(
destination: ArtistList(songLVM: $songLVM))
{
HStack {
Image(systemName: "music.mic")
Text("Artists")
}
}
//Albums
NavigationLink(
destination: Text("Albums"))
{
HStack {
Image(systemName: "music.note.list")
Text("Albums")
}
}
//Collections
NavigationLink(
//destination: ArtistView())
destination: ArtistViewMain( songLVM: $songLVM))
{
HStack {
Image(systemName: "music.quarternote.3")
Text("Collections")
}
}
//About Us
NavigationLink(
destination: Text("About Us"))
{
HStack {
Image(systemName: "music.note.house.fill")
Text("About Us")
}
}
//Contact Us
NavigationLink(
destination: ArtistView())
{
HStack {
Image(systemName: "phone.circle")
Text("Contact Us")
}
}
}
}
.onAppear {
if(songLVM.audioPlayer?.isPlaying != nil){
HStack {
Button("Stop") {
songLVM.audioPlayer?.stop()
}
}
}
}
}
}
I had also tried
.onAppear{
miniBar.toggle()
if(miniBar == true){
HStack {
Text("Stop")
}
}
}
but got Result of 'HStack<Content>' initializer is unused
I will give easy and basic template for working with swift's ui states.
You can refer it and add your views or navigation link.
struct YourView: View {
/// If you want to pass it on init, use #ObservedObject instead
/// https://www.hackingwithswift.com/quick-start/swiftui/whats-the-difference-between-observedobject-state-and-environmentobject
#StateObject var viewModel = YourViewModel()
var body: some View {
NavigationView {
VStack {
if viewModel.isPlaying {
Button {
viewModel.stop()
} label: {
Text("Stop")
}
} else {
Button {
viewModel.start()
} label: {
Text("Start")
}
}
Toggle(isOn: $viewModel.isPlaying) {
Text("isPlaying")
}
}
}
.onAppear {
viewModel.transform()
}
}
}
class YourViewModel: ObservableObject {
#Published var isPlaying = false
func transform() {
fetchStatus()
}
func fetchStatus() {
isPlaying = true
}
func stop() { isPlaying = false }
func start() { isPlaying = true }
}
I have tried several options to switch views in SwiftUI. However, each one had issues like lagging over time when switching back and forth many times. I am trying to find the best and cleanest way to switch views using SwiftUI. I am just trying to make a multiview user interface.
In View1.swift:
import SwiftUI
struct View1: View {
#State var GoToView2:Bool = false
var body: some View {
ZStack {
if (GoToView2) {
View2()
//What should I do if I created another swiftui view under the name View2?
//Just calling View2() like that causes lag as described in the linked question before it was deleted, if from view2 I switch back to view1 and so on.
//If I directly put the code of View2 here, then adding other views would get too messy.
} else {
VStack {
Button(action: {self.GoToView2.toggle()}) {
Text("Go to view 2")
}
}
}
}
}
}
In View2.swift:
import SwiftUI
struct View2: View {
#State var GoToView1:Bool = false
var body: some View {
ZStack {
if (GoToView1) {
View1()
} else {
VStack {
Button(action: {self.GoToView1.toggle()}) {
Text("Go to view 1")
}
}
}
}
}
}
I hope the problem can be understood. To replicate the behavior, please compile the code in a SwiftUI app, then switch be repeatedly switching between the two buttons quickly for 30 seconds, then you should notice a delay between each switch, and resizing the window should look chunky. I am using the latest version of macOS and the latest version of Xcode.
So I tried to show that each of the calls to the Views would add an instance to the view stack... I might be wrong here but the following should show this:
struct View1: View {
#State var GoToView2:Bool = false
var counter: Int
init(counter: Int) {
self.counter = counter + 1
}
var body: some View {
VStack {
if (GoToView2) {
Text("\(self.counter)")
View2(counter: self.counter)
} else {
VStack {
Button(action: {
withAnimation {
self.GoToView2.toggle()
}
}) {
Text("Go to view 2")
}
}
}
}
}
}
struct View2: View {
#State var GoToView1:Bool = false
var counter: Int
init(counter: Int) {
self.counter = counter + 1
}
var body: some View {
VStack {
if (GoToView1) {
Text("\(self.counter)")
View1(counter: self.counter)
} else {
VStack {
Button(action: {
withAnimation {
self.GoToView1.toggle()
}
}) {
Text("Go to view 1")
}
}.transition(.move(edge: .leading))
}
}
}
}
The I tried to show that the other method wouldn't do that:
struct View1: View {
#State var GoToView2: Bool = false
var counter: Int
init(counter: Int) {
self.counter = counter + 1
}
var body: some View {
VStack {
if (GoToView2) {
Text("\(self.counter)")
View2(counter: self.counter, GoToView1: self.$GoToView2)
} else {
VStack {
Button(action: {
withAnimation {
self.GoToView2.toggle()
}
}) {
Text("Go to view 2")
}
}
}
}
}
}
struct View2: View {
#Binding var GoToView1: Bool
var counter: Int
init(counter: Int, GoToView1: Binding<Bool>) {
self._GoToView1 = GoToView1
self.counter = counter + 1
}
var body: some View {
VStack {
Text("\(self.counter)")
Button(action: {
withAnimation {
self.GoToView1.toggle()
}
}) {
Text("Go to view 1")
}
}.transition(.move(edge: .leading))
}
}
I don't know if the lag is really coming from this or if there is a better method of proof, but for now this is what I came up with.
Original answer
I would recommend doing the following:
struct View1: View {
#State var GoToView2:Bool = false
var body: some View {
ZStack {
if (GoToView2) {
View2(GoToView1: self.$GoToView2)
} else {
VStack {
Button(action: {
withAnimation {
self.GoToView2.toggle()
}
}) {
Text("Go to view 2")
}
}
}
}
}
}
struct View2: View {
#Binding var GoToView1: Bool
var body: some View {
VStack {
Button(action: {
withAnimation {
self.GoToView1.toggle()
}
}) {
Text("Go to view 1")
}
}.transition(.move(edge: .leading))
}
}
I want to show the user another view when the login is successful, otherwise stay on that view. I've done that with UIKit by performing a segue. Is there such an alternative in SwiftUI?
The NavigationButton solution does not work as I need to validate the user input before transitioning to the other view.
Button(action: {
let authService = AuthorizationService()
let result = authService.isAuthorized(username: self.username, password: self.password)
if(result == true) {
print("Login successful.")
// TODO: ADD LOGIC
*** HERE I WANT TO PERFORM THE SEGUE ***
presentation(MainView)
} else {
print("Login failed.")
}
}) {
Text("Login")
}
Xcode 11 beta 5.
NavigationDestinationLink and NavigationButton have been deprecated and replaced by NavigationLink.
Here's a full working example of programatically pushing a view to a NavigationView.
import SwiftUI
import Combine
enum MyAppPage {
case Menu
case SecondPage
}
final class MyAppEnvironmentData: ObservableObject {
#Published var currentPage : MyAppPage? = .Menu
}
struct NavigationTest: View {
var body: some View {
NavigationView {
PageOne()
}
}
}
struct PageOne: View {
#EnvironmentObject var env : MyAppEnvironmentData
var body: some View {
let navlink = NavigationLink(destination: PageTwo(),
tag: .SecondPage,
selection: $env.currentPage,
label: { EmptyView() })
return VStack {
Text("Page One").font(.largeTitle).padding()
navlink
.frame(width:0, height:0)
Button("Button") {
self.env.currentPage = .SecondPage
}
.padding()
.border(Color.primary)
}
}
}
struct PageTwo: View {
#EnvironmentObject var env : MyAppEnvironmentData
var body: some View {
VStack {
Text("Page Two").font(.largeTitle).padding()
Text("Go Back")
.padding()
.border(Color.primary)
.onTapGesture {
self.env.currentPage = .Menu
}
}.navigationBarBackButtonHidden(true)
}
}
#if DEBUG
struct NavigationTest_Previews: PreviewProvider {
static var previews: some View {
NavigationTest().environmentObject(MyAppEnvironmentData())
}
}
#endif
Note that the NavigationLink entity has to be present inside the View body.
If you have a button that triggers the link, you'll use the label of the NavigationLink.
In this case, the NavigationLink is hidden by setting its frame to 0,0, which is kind of a hack but I'm not aware of a better method at this point. .hidden() doesn't have the same effect.
You could do it like bellow, based on this response (it's packed like a Playground for easy testing:
import SwiftUI
import Combine
import PlaygroundSupport
struct ContentView: View {
var body: some View {
NavigationView {
MainView().navigationBarTitle(Text("Main View"))
}
}
}
struct MainView: View {
let afterLoginView = DynamicNavigationDestinationLink(id: \String.self) { message in
AfterLoginView(msg: message)
}
var body: some View {
Button(action: {
print("Do the login logic here")
self.afterLoginView.presentedData?.value = "Login successful"
}) {
Text("Login")
}
}
}
struct AfterLoginView: View {
let msg: String
var body: some View {
Text(msg)
}
}
PlaygroundPage.current.liveView = UIHostingController(rootView: ContentView())
Although this will work, I think that, from an architectural perspective, you try to push an "imperative programming" paradigm into SwiftUI's reactive logic.
I mean, I would rather implement it with the login logic wrapped into an ObjectBinding class with an exposed isLoggedin property and make the UI react to the current state (represented by isLoggedin).
Here's a very high level example :
struct MainView: View {
#ObjectBinding private var loginManager = LoginManager()
var body: some View {
if loginManager.isLoggedin {
Text("After login content")
} else {
Button(action: {
self.loginManager.login()
}) {
Text("Login")
}
}
}
}
I used a Bool state for my login transition, it seems pretty fluid.
struct ContentView: View {
#State var loggedIn = false
var body: some View {
VStack{
if self.loggedIn {
Text("LoggedIn")
Button(action: {
self.loggedIn = false
}) {
Text("Log out")
}
} else {
LoginPage(loggedIn: $loggedIn)
}
}
}
}
I'm trying to setup a view that can display multiple modals depending on which button is tapped.
When I add just one sheet, everything works:
.sheet(isPresented: $showingModal1) { ... }
But when I add another sheet, only the last one works.
.sheet(isPresented: $showingModal1) { ... }
.sheet(isPresented: $showingModal2) { ... }
UPDATE
I tried to get this working, but I'm not sure how to declare the type for modal. I'm getting an error of Protocol 'View' can only be used as a generic constraint because it has Self or associated type requirements.
struct ContentView: View {
#State var modal: View?
var body: some View {
VStack {
Button(action: {
self.modal = ModalContentView1()
}) {
Text("Show Modal 1")
}
Button(action: {
self.modal = ModalContentView2()
}) {
Text("Show Modal 2")
}
}.sheet(item: self.$modal, content: { modal in
return modal
})
}
}
struct ModalContentView1: View {
var body: some View {
Text("Modal 1")
}
}
struct ModalContentView2: View {
var body: some View {
Text("Modal 2")
}
}
This works:
.background(EmptyView().sheet(isPresented: $showingModal1) { ... }
.background(EmptyView().sheet(isPresented: $showingModal2) { ... }))
Notice how these are nested backgrounds. Not two backgrounds one after the other.
Thanks to DevAndArtist for finding this.
Maybe I missed the point, but you can achieve it either with a single call to .sheet(), or multiple calls.:
Multiple .sheet() approach:
import SwiftUI
struct MultipleSheets: View {
#State private var sheet1 = false
#State private var sheet2 = false
#State private var sheet3 = false
var body: some View {
VStack {
Button(action: {
self.sheet1 = true
}, label: { Text("Show Modal #1") })
.sheet(isPresented: $sheet1, content: { Sheet1() })
Button(action: {
self.sheet2 = true
}, label: { Text("Show Modal #2") })
.sheet(isPresented: $sheet2, content: { Sheet2() })
Button(action: {
self.sheet3 = true
}, label: { Text("Show Modal #3") })
.sheet(isPresented: $sheet3, content: { Sheet3() })
}
}
}
struct Sheet1: View {
var body: some View {
Text("This is Sheet #1")
}
}
struct Sheet2: View {
var body: some View {
Text("This is Sheet #2")
}
}
struct Sheet3: View {
var body: some View {
Text("This is Sheet #3")
}
}
Single .sheet() approach:
struct MultipleSheets: View {
#State private var showModal = false
#State private var modalSelection = 1
var body: some View {
VStack {
Button(action: {
self.modalSelection = 1
self.showModal = true
}, label: { Text("Show Modal #1") })
Button(action: {
self.modalSelection = 2
self.showModal = true
}, label: { Text("Show Modal #2") })
Button(action: {
self.modalSelection = 3
self.showModal = true
}, label: { Text("Show Modal #3") })
}
.sheet(isPresented: $showModal, content: {
if self.modalSelection == 1 {
Sheet1()
}
if self.modalSelection == 2 {
Sheet2()
}
if self.modalSelection == 3 {
Sheet3()
}
})
}
}
struct Sheet1: View {
var body: some View {
Text("This is Sheet #1")
}
}
struct Sheet2: View {
var body: some View {
Text("This is Sheet #2")
}
}
struct Sheet3: View {
var body: some View {
Text("This is Sheet #3")
}
}
I'm not sure whether this was always possible, but in Xcode 11.3.1 there is an overload of .sheet() for exactly this use case (https://developer.apple.com/documentation/swiftui/view/3352792-sheet). You can call it with an Identifiable item instead of a bool:
struct ModalA: View {
var body: some View {
Text("Hello, World! (A)")
}
}
struct ModalB: View {
var body: some View {
Text("Hello, World! (B)")
}
}
struct MyContentView: View {
enum Sheet: Hashable, Identifiable {
case a
case b
var id: Int {
return self.hashValue
}
}
#State var activeSheet: Sheet? = nil
var body: some View {
VStack(spacing: 42) {
Button(action: {
self.activeSheet = .a
}) {
Text("Hello, World! (A)")
}
Button(action: {
self.activeSheet = .b
}) {
Text("Hello, World! (B)")
}
}
.sheet(item: $activeSheet) { item in
if item == .a {
ModalA()
} else if item == .b {
ModalB()
}
}
}
}
I personally would mimic some NavigationLink API. Then you can create a hashable enum and decide which modal sheet you want to present.
extension View {
func sheet<Content, Tag>(
tag: Tag,
selection: Binding<Tag?>,
content: #escaping () -> Content
) -> some View where Content: View, Tag: Hashable {
let binding = Binding(
get: {
selection.wrappedValue == tag
},
set: { isPresented in
if isPresented {
selection.wrappedValue = tag
} else {
selection.wrappedValue = .none
}
}
)
return background(EmptyView().sheet(isPresented: binding, content: content))
}
}
enum ActiveSheet: Hashable {
case first
case second
}
struct First: View {
var body: some View {
Text("frist")
}
}
struct Second: View {
var body: some View {
Text("second")
}
}
struct TestView: View {
#State
private var _activeSheet: ActiveSheet?
var body: some View {
print(_activeSheet as Any)
return VStack
{
Button("first") {
self._activeSheet = .first
}
Button("second") {
self._activeSheet = .second
}
}
.sheet(tag: .first, selection: $_activeSheet) {
First()
}
.sheet(tag: .second, selection: $_activeSheet) {
Second()
}
}
}
I wrote a library off plivesey's answer that greatly simplifies the syntax:
.multiSheet {
$0.sheet(isPresented: $sheetAPresented) { Text("Sheet A") }
$0.sheet(isPresented: $sheetBPresented) { Text("Sheet B") }
$0.sheet(isPresented: $sheetCPresented) { Text("Sheet C") }
}
I solved this by creating an observable SheetContext that holds and manages the state. I then only need a single context instance and can tell it to present any view as a sheet. I prefer this to the "active view" binding approach, since you can use this context in multiple ways.
I describe it in more details in this blog post: https://danielsaidi.com/blog/2020/06/06/swiftui-sheets
I think i found THE solution. It's complicated so here is the teaser how to use it:
Button(action: {
showModal.wrappedValue = ShowModal {
AnyView( TheViewYouWantToPresent() )
}
})
Now you can define at the button level what you want to present. And the presenting view does not need to know anything. So you call this on the presenting view.
.background(EmptyView().show($showModal))
We call it on the background so the main view does not need to get updated, when $showModal changes.
Ok so what do we need to get this to work?
1: The ShowModal class:
public enum ModalType{
case sheet, fullscreen
}
public struct ShowModal: Identifiable {
public let id = ""
public let modalType: ModalType
public let content: () -> AnyView
public init (modalType: ModalType = .sheet, #ViewBuilder content: #escaping () -> AnyView){
self.modalType = modalType
self.content = content
}
}
Ignore id we just need it for Identifiable. With modalType we can present the view as sheet or fullscreen. And content is the passed view, that will be shown in the modal.
2: A ShowModal binding which stores the information for presenting views:
#State var showModal: ShowModal? = nil
And we need to add it to the environment of the view thats responsible for presentation. So we have easy access to it down the viewstack:
VStack{
InnerViewsThatWantToPresentModalViews()
}
.environment(\.showModal, $showModal)
.background(EmptyView().show($showModal))
In the last line we call .show(). Which is responsible for presentation.
Keep in mind that you have to create #State var showModal and add it to the environment again in a view thats shown modal and wants to present another modal.
4: To use .show we need to extend view:
public extension View {
func show(_ modal: Binding<ShowModal?>) -> some View {
modifier(VM_Show(modal))
}
}
And add a viewModifier that handles the information passed in $showModal
public struct VM_Show: ViewModifier {
var modal: Binding<ShowModal?>
public init(_ modal: Binding<ShowModal?>) {
self.modal = modal
}
public func body(content: Content) -> some View {
guard let modalType = modal.wrappedValue?.modalType else{ return AnyView(content) }
switch modalType {
case .sheet:
return AnyView(
content.sheet(item: modal){ modal in
modal.content()
}
)
case .fullscreen:
return AnyView(
content.fullScreenCover(item: modal) { modal in
modal.content()
}
)
}
}
}
4: Last we need to set showModal in views that want to present a modal:
Get the variable with: #Environment(\.showModal) var showModal. And set it like this:
Button(action: {
showModal.wrappedValue = ShowModal(modalType: .fullscreen) {
AnyView( TheViewYouWantToPresent() )
}
})
In the view that defined $showModal you set it without wrappedValue: $showModal = ShowModal{...}
As an alternative, simply putting a clear pixel somewhere in your layout might work for you:
Color.clear.frame(width: 1, height: 1, alignment: .center).sheet(isPresented: $showMySheet, content: {
MySheetView();
})
Add as many pixels as necessary.
I‘m currently playing around with SwiftUI. In SwiftUI it‘s possible, to animate a State change for example like so:
struct Foo: View {
#State private var show = false
var body: some View {
VStack {
if show {
Text("Foo")
}
Button(action: {
withAnimation {
self.show.toggle()
}
}) {
Text(show ? "Hide" : "Show")
}
}
}
}
But if I have for example a TextField:
struct Foo: View {
#State private var text = ""
var body: some View {
VStack {
TextField($text, placeholder: Text("Foo")) {
print("editing ended")
}
if !text.isEmpty {
Button(action: {}) {
Text("Done")
}
}
}
}
}
I‘m not able to find a way to animate this change, because the State property is changed by the TextField without a call to withAnimation().
Is it possible to get this change animated?
Just add the animation modifier to wrap your button
var body: some View {
VStack {
TextField($text, placeholder: Text("Foo")) {
print("editing ended")
}
// if !text.isEmpty {
Button(action: {}) {
Text("Done")
}
.background(text.isEmpty ? Color.red : Color.yellow )
//.animation(.basic(duration: 1))
.animation(Animation.default.speed(1))
}
}
}
TextField("Placeholder", text:$text.animation())
Everything that uses the text will be animated when it is changed.