When I jump to the settings page and click Cancel in the pop-up dialog box, it will automatically return to the home page. How can I avoid this problem?
import SwiftUI
struct ContentView: View {
#State private var settingActive: Bool = false
var body: some View {
NavigationView {
TabView {
VStack {
NavigationLink(destination: SettingView(), isActive: $settingActive) {
EmptyView()
}
Button {
settingActive.toggle()
} label: {
Text("Setting")
}
}
.padding()
}
}
}
}
struct SettingView: View {
#State private var logoutActive: Bool = false
var body: some View {
VStack {
Button {
logoutActive.toggle()
} label: {
Text("Logout")
}
.confirmationDialog("Logout", isPresented: $logoutActive) {
Button("Logout", role: .destructive) {
}
}
}
}
}
struct ContentView_Previews: PreviewProvider {
static var previews: some View {
ContentView()
}
}
This seems to be an issue with using TabView inside NavigationView.
You can solve this by moving TabView to be your top level object (where it really should be), or replacing NavigationView with the new NavigationStack.
Here's an implementation that also removes the deprecated NavigationLink method:
enum Router {
case settings
}
struct ContentView: View {
#State private var path = NavigationPath()
var body: some View {
TabView {
NavigationStack(path: $path) {
VStack {
Button {
path.append(Router.settings)
} label: {
Text("Setting")
}
}
.navigationDestination(for: Router.self) { router in
switch router {
case .settings:
SettingView(path: $path)
}
}
.padding()
}
}
}
}
struct SettingView: View {
#Binding var path: NavigationPath
#State private var logoutActive: Bool = false
var body: some View {
VStack {
Button {
logoutActive = true
} label: {
Text("Logout")
}
.confirmationDialog("Logout", isPresented: $logoutActive) {
Button("Logout", role: .destructive) {
}
}
}
}
}
I have an issue with NavigationLinks with conditions. It doesn't react what I'm expected. When a user click on the button the function "test" must be called and give a return value. If the return value is true the "SheetView" must be openend directly without clicking on the NavigationLink text. Please could someone give me a help on this one. Thanks in advance
I made a small (sample) program for showing the issue.
import SwiftUI
struct LoginView: View {
#State var check = false
#State var answer = false
var body: some View {
NavigationView {
VStack{
Text("it doesn't work")
Button(action: {
answer = test(value: 2)
if answer {
//if the return value is true then directly navigate to the sheetview
NavigationLink(
destination: SheetView(),
label: {
Text("Navigate")
})
}
}, label: {
Text("Calculate")
})
}
}
}
func test(value: Int) -> Bool {
if value == 1 {
check = false
} else {
print("Succes")
check = true
}
return check
}
}
struct SheetView: View {
var body: some View {
NavigationView {
VStack{
Text("Test")
.font(.title)
}
}
}
}
The answer from Yodagama works if you were trying to present a sheet (because you called your navigation destination SheetView), but if you were trying to navigate to SheetView instead of present a sheet, the following code would do that.
struct LoginView: View {
#State var check = false
#State var answer = false
var body: some View {
NavigationView {
VStack{
Text("it doesn't work")
NavigationLink(destination: SheetView(), isActive: $answer, label: {
Button(action: {
answer = test(value: 2)
}, label: {
Text("Calculate")
})
})
}
}
}
func test(value: Int) -> Bool {
if value == 1 {
check = false
} else {
print("Succes")
check = true
}
return check
}
}
struct SheetView: View {
var body: some View {
NavigationView {
VStack{
Text("Test")
.font(.title)
}
}
}
}
struct LoginView: View {
#State var check = false
#State var answer = false
var body: some View {
NavigationView {
VStack{
Text("it doesn't work")
Button(action: {
answer = test(value: 2)
//<= here
}, label: {
Text("Calculate")
})
}
.sheet(isPresented: $answer, content: { //<= here
SheetView()
})
}
}
...
I have a form that I want to change views from if a Bool is false:
var body: some View {
NavigationView {
Form {
Section {
Toggle(isOn: $ClientAnswer) {
Text("Client answer")
}
if ClientAnswer {
Toggle(isOn: $submission.fieldOne ) {
Text("Field One")
}
Toggle(isOn: $submission.fieldTwo ) {
Text("Field Two")
}
}
}
Section {
Button(action: {
if self.ClientAnswer{
self.placeSubmission()
}
else {
ShowRS() //**change views here.**
print("test")
}
}){
Text("Submit")
}
}.disabled(!submission.isValid)
}
}
}
The code is being executed as print("test") works, but it doesn't change view it just stays on the same view?
The view I am trying to switch to is:
struct ShowRS: View {
var body: some View {
Image("testImage")
}
}
You have to include ShowRS in your view hierarchy -- right now, it's just in your Buttons action callback. There are multiple ways to achieve this, but here's one option:
struct ContentView : View {
#State private var moveToShowRSView = false
var body: some View {
NavigationView {
Button(action: {
if true {
moveToShowRSView = true
}
}) {
Text("Move")
}.overlay(NavigationLink(destination: ShowRS(), isActive: $moveToShowRSView, label: {
EmptyView()
}))
}
}
}
struct ShowRS: View {
var body: some View {
Image("testImage")
}
}
I've simplified this down from your example since I didn't have all of your code with your models, etc, but it demonstrates the concept. In the Button action, you test a boolean (in this case, it'll always return true) and then set the #State variable moveToShowRSView.
If moveToShowRSView is true, there's an overlay on the Button that has a NavigationLink (which is invisible because of the EmptyView) which will only be active if moveToShowRSView is true
I am trying to create a startup screen then animate to the mainMenu, but I get the error specified in the title. You can probably see how I am trying to do this. Please help.
struct Content: View {
#State var ShowMainMenu = false
var body: some View {
VStack {
if (ShowMainMenu) {
MainMenu()
} else {
ContentView(ToMainMenu: $ShowMainMenu)
}
}
}
}
struct ContentView: View {
#Binding var ToMainMenu:Bool
var body: some View {
VStack {
Text("I hate phone numbers")
DispatchQueue.main.asyncAfter(deadline: .now()+1.5) {
withAnimation {
self.ToMainMenu.toggle()
}
}
}
}
}
You cannot execute code in a view but you could execute something in onAppear of that view:
struct ContentView: View {
#State var ShowMainMenu = false
var body: some View {
VStack {
if (ShowMainMenu) {
Text("Hello")
} else {
Content(ToMainMenu: $ShowMainMenu)
}
}
}
}
struct Content: View {
#Binding var ToMainMenu: Bool
var body: some View {
VStack {
Text("I hate phone numbers")
}.onAppear() {
DispatchQueue.main.asyncAfter(deadline: .now()+1.5) {
withAnimation {
self.ToMainMenu.toggle()
}
}
}
}
}
Note: I had to change the names of Content and ContentView
I hope this helps.
I'm trying to setup a view that can display multiple modals depending on which button is tapped.
When I add just one sheet, everything works:
.sheet(isPresented: $showingModal1) { ... }
But when I add another sheet, only the last one works.
.sheet(isPresented: $showingModal1) { ... }
.sheet(isPresented: $showingModal2) { ... }
UPDATE
I tried to get this working, but I'm not sure how to declare the type for modal. I'm getting an error of Protocol 'View' can only be used as a generic constraint because it has Self or associated type requirements.
struct ContentView: View {
#State var modal: View?
var body: some View {
VStack {
Button(action: {
self.modal = ModalContentView1()
}) {
Text("Show Modal 1")
}
Button(action: {
self.modal = ModalContentView2()
}) {
Text("Show Modal 2")
}
}.sheet(item: self.$modal, content: { modal in
return modal
})
}
}
struct ModalContentView1: View {
var body: some View {
Text("Modal 1")
}
}
struct ModalContentView2: View {
var body: some View {
Text("Modal 2")
}
}
This works:
.background(EmptyView().sheet(isPresented: $showingModal1) { ... }
.background(EmptyView().sheet(isPresented: $showingModal2) { ... }))
Notice how these are nested backgrounds. Not two backgrounds one after the other.
Thanks to DevAndArtist for finding this.
Maybe I missed the point, but you can achieve it either with a single call to .sheet(), or multiple calls.:
Multiple .sheet() approach:
import SwiftUI
struct MultipleSheets: View {
#State private var sheet1 = false
#State private var sheet2 = false
#State private var sheet3 = false
var body: some View {
VStack {
Button(action: {
self.sheet1 = true
}, label: { Text("Show Modal #1") })
.sheet(isPresented: $sheet1, content: { Sheet1() })
Button(action: {
self.sheet2 = true
}, label: { Text("Show Modal #2") })
.sheet(isPresented: $sheet2, content: { Sheet2() })
Button(action: {
self.sheet3 = true
}, label: { Text("Show Modal #3") })
.sheet(isPresented: $sheet3, content: { Sheet3() })
}
}
}
struct Sheet1: View {
var body: some View {
Text("This is Sheet #1")
}
}
struct Sheet2: View {
var body: some View {
Text("This is Sheet #2")
}
}
struct Sheet3: View {
var body: some View {
Text("This is Sheet #3")
}
}
Single .sheet() approach:
struct MultipleSheets: View {
#State private var showModal = false
#State private var modalSelection = 1
var body: some View {
VStack {
Button(action: {
self.modalSelection = 1
self.showModal = true
}, label: { Text("Show Modal #1") })
Button(action: {
self.modalSelection = 2
self.showModal = true
}, label: { Text("Show Modal #2") })
Button(action: {
self.modalSelection = 3
self.showModal = true
}, label: { Text("Show Modal #3") })
}
.sheet(isPresented: $showModal, content: {
if self.modalSelection == 1 {
Sheet1()
}
if self.modalSelection == 2 {
Sheet2()
}
if self.modalSelection == 3 {
Sheet3()
}
})
}
}
struct Sheet1: View {
var body: some View {
Text("This is Sheet #1")
}
}
struct Sheet2: View {
var body: some View {
Text("This is Sheet #2")
}
}
struct Sheet3: View {
var body: some View {
Text("This is Sheet #3")
}
}
I'm not sure whether this was always possible, but in Xcode 11.3.1 there is an overload of .sheet() for exactly this use case (https://developer.apple.com/documentation/swiftui/view/3352792-sheet). You can call it with an Identifiable item instead of a bool:
struct ModalA: View {
var body: some View {
Text("Hello, World! (A)")
}
}
struct ModalB: View {
var body: some View {
Text("Hello, World! (B)")
}
}
struct MyContentView: View {
enum Sheet: Hashable, Identifiable {
case a
case b
var id: Int {
return self.hashValue
}
}
#State var activeSheet: Sheet? = nil
var body: some View {
VStack(spacing: 42) {
Button(action: {
self.activeSheet = .a
}) {
Text("Hello, World! (A)")
}
Button(action: {
self.activeSheet = .b
}) {
Text("Hello, World! (B)")
}
}
.sheet(item: $activeSheet) { item in
if item == .a {
ModalA()
} else if item == .b {
ModalB()
}
}
}
}
I personally would mimic some NavigationLink API. Then you can create a hashable enum and decide which modal sheet you want to present.
extension View {
func sheet<Content, Tag>(
tag: Tag,
selection: Binding<Tag?>,
content: #escaping () -> Content
) -> some View where Content: View, Tag: Hashable {
let binding = Binding(
get: {
selection.wrappedValue == tag
},
set: { isPresented in
if isPresented {
selection.wrappedValue = tag
} else {
selection.wrappedValue = .none
}
}
)
return background(EmptyView().sheet(isPresented: binding, content: content))
}
}
enum ActiveSheet: Hashable {
case first
case second
}
struct First: View {
var body: some View {
Text("frist")
}
}
struct Second: View {
var body: some View {
Text("second")
}
}
struct TestView: View {
#State
private var _activeSheet: ActiveSheet?
var body: some View {
print(_activeSheet as Any)
return VStack
{
Button("first") {
self._activeSheet = .first
}
Button("second") {
self._activeSheet = .second
}
}
.sheet(tag: .first, selection: $_activeSheet) {
First()
}
.sheet(tag: .second, selection: $_activeSheet) {
Second()
}
}
}
I wrote a library off plivesey's answer that greatly simplifies the syntax:
.multiSheet {
$0.sheet(isPresented: $sheetAPresented) { Text("Sheet A") }
$0.sheet(isPresented: $sheetBPresented) { Text("Sheet B") }
$0.sheet(isPresented: $sheetCPresented) { Text("Sheet C") }
}
I solved this by creating an observable SheetContext that holds and manages the state. I then only need a single context instance and can tell it to present any view as a sheet. I prefer this to the "active view" binding approach, since you can use this context in multiple ways.
I describe it in more details in this blog post: https://danielsaidi.com/blog/2020/06/06/swiftui-sheets
I think i found THE solution. It's complicated so here is the teaser how to use it:
Button(action: {
showModal.wrappedValue = ShowModal {
AnyView( TheViewYouWantToPresent() )
}
})
Now you can define at the button level what you want to present. And the presenting view does not need to know anything. So you call this on the presenting view.
.background(EmptyView().show($showModal))
We call it on the background so the main view does not need to get updated, when $showModal changes.
Ok so what do we need to get this to work?
1: The ShowModal class:
public enum ModalType{
case sheet, fullscreen
}
public struct ShowModal: Identifiable {
public let id = ""
public let modalType: ModalType
public let content: () -> AnyView
public init (modalType: ModalType = .sheet, #ViewBuilder content: #escaping () -> AnyView){
self.modalType = modalType
self.content = content
}
}
Ignore id we just need it for Identifiable. With modalType we can present the view as sheet or fullscreen. And content is the passed view, that will be shown in the modal.
2: A ShowModal binding which stores the information for presenting views:
#State var showModal: ShowModal? = nil
And we need to add it to the environment of the view thats responsible for presentation. So we have easy access to it down the viewstack:
VStack{
InnerViewsThatWantToPresentModalViews()
}
.environment(\.showModal, $showModal)
.background(EmptyView().show($showModal))
In the last line we call .show(). Which is responsible for presentation.
Keep in mind that you have to create #State var showModal and add it to the environment again in a view thats shown modal and wants to present another modal.
4: To use .show we need to extend view:
public extension View {
func show(_ modal: Binding<ShowModal?>) -> some View {
modifier(VM_Show(modal))
}
}
And add a viewModifier that handles the information passed in $showModal
public struct VM_Show: ViewModifier {
var modal: Binding<ShowModal?>
public init(_ modal: Binding<ShowModal?>) {
self.modal = modal
}
public func body(content: Content) -> some View {
guard let modalType = modal.wrappedValue?.modalType else{ return AnyView(content) }
switch modalType {
case .sheet:
return AnyView(
content.sheet(item: modal){ modal in
modal.content()
}
)
case .fullscreen:
return AnyView(
content.fullScreenCover(item: modal) { modal in
modal.content()
}
)
}
}
}
4: Last we need to set showModal in views that want to present a modal:
Get the variable with: #Environment(\.showModal) var showModal. And set it like this:
Button(action: {
showModal.wrappedValue = ShowModal(modalType: .fullscreen) {
AnyView( TheViewYouWantToPresent() )
}
})
In the view that defined $showModal you set it without wrappedValue: $showModal = ShowModal{...}
As an alternative, simply putting a clear pixel somewhere in your layout might work for you:
Color.clear.frame(width: 1, height: 1, alignment: .center).sheet(isPresented: $showMySheet, content: {
MySheetView();
})
Add as many pixels as necessary.