In Spring data findAll method reference object is coming as null
I am using Reactive Mongo Repository
Ex Parent Object
#Data
#Document(collection = "country")
public class CountryBean {
#Id
private String id;
private String name;
}
Child Object
#Document(collection = "city")
public class CityBean {
#Id
private String id;
#Field(name = "name")
private String name;
#Field(name = "city_code")
private String cityCode;
#Field(name = "show_city")
private boolean showCity;
#DocumentReference(lazy = false)
private StateBean state;
}
Country Collection
State Collection (Here we can see the country Attribute)
But When trying to fetch from DB, I am getting country attribute as null. Tried both lazy true/false, but not getting country object along with state object.
#GetMapping("/get-all-state")
Flux<StateBean> allState() {
Flux<CountryBean> ct = countryRepository.findAll();
Flux<StateBean> bean= stateRepository.findByCountry(ct.blockFirst());
return bean;
}
[{"id":"6237a912850ceb6261998a53","name":"Bangalore","statecode":"39","country":null},{"id":"6237a94a850ceb6261998a55","name":"delhi","statecode":"39","country":null}]
Related
I have entities that are persisted in MongoDB and use spring data MongoRepository to fetch data. Now i want to apply filter to all queries that executed on the entites, so i decided to use hibernate filter, something like this:
#Entity
#QueryEntity
#Document(collection = "Opportunity")
#NoArgsConstructor
#AllArgsConstructor
#Getter
#Setter
#CompoundIndexes({
#CompoundIndex(name = "productGroup_userId_uniqueness", def = "{'productGroupCode' : 1, 'userId': 1}", unique = true)
})
#FilterDef(name = "defaultFilter",parameters = #ParamDef(name = "unitCode",type = "string"))
#Filter(name = "defaultFilter" , condition = " unitCode like :unitCode")
public class Opportunity {
#Id
#Indexed
private String id;
#Indexed
#Enumerated(EnumType.STRING)
private OpportunityStatus opportunityStatus = OpportunityStatus.OPEN;
private LeadType leadType;
#Indexed
private String userId;
#Indexed
private String productCode;
#Indexed
private String productGroupCode;
#Indexed
private Long actionId;
private String assigneeId;
#Transient
private List<AbstractCommand> commandHistory = new ArrayList<>();
#Transient
private Map<Long, Boolean> actionStatus = new HashMap<>();
private String unitCode;
}
and this is the repository class:
#Repository
public interface OpportunityRepository extends MongoRepository<Opportunity, String>, QuerydslPredicateExecutor<Opportunity> {
// this repository contains more than 20 methods
// and all of theme removed for question brevity
}
And I enabled hibernate filter on session with this way:
Session session = (entityManager).unwrap(Session.class);
session.enableFilter(filterName).setParameter("unitCode", this.getCurrentUserUnitCode());
Now, when I call OpportunityRepository.findAll(Predicate predicate, Pageable pageable) i expected to apply the defined filter on the entity, but it didn't work.
I think the reason is that MongoRepository hasn't any sense of hibernate #Filter and i should use another way to append where clause to all mongo queries that running on the Opportunity entity.
I have the below class as my document.
#Data
#Builder
#Document(collection = "test")
public class TestData {
#Id
private String id;
private String name;
#Indexed(unique = true)
private String hash;
}
Even if I'm using Indexed with unique enabled, I'm able to insert duplicate documents into collection.
But if I generate index in mongo shell then it is working.
Is there any way where I can specify unique Index through code only?
This is how the compound index is used in my code
#Getter
#Setter
#Document
#CompoundIndexes({
#CompoundIndex(name = "name_author_idx", def = "{'name' : 1, 'author' : 1}", unique = true, background = true)})
public class Book implements Transformer {
#Id
private String id;
#Field(name = "name")
private String name;
#Field(name = "author")
private String author;
#Field(name = "qty")
private Integer qty;
#Field(name = "price")
private Double price;
#Field(name = "created_time")
private LocalDateTime createdTime = LocalDateTime.now();
}
Please use following code on application.properties file on spring boot application it will work.
spring.data.mongodb.auto-index-creation: true
Thank you
If you're having a configuration component you should override the autoIndexCreation method like this:
#Configuration
public class MongoConfiguration extends AbstractMongoClientConfiguration
{
#Override
protected boolean autoIndexCreation() {
return true;
}}
I am trying to sort a result by nested collection element value. I have a very simple model:
#Entity
public class User {
#Id
#NotNull
#Column(name = "userid")
private Long id;
#OneToMany(mappedBy = "user")
private Collection<Setting> settings = new HashSet<>();
// getters and setters
}
#Entity
public class Setting {
#Id
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "userid")
private User user;
private String key;
private String value;
// getters and setters
}
public interface UserRepository extends JpaRepository<User, Long>, QuerydslPredicateExecutor<User> {
}
I want to have a result returned sorted by the value of one setting.
Is it possible to order by user.settings.value where settings.name = 'SampleName' using Spring Data JPA with QueryDSL?
I've used JpaSpecificationExecutor. let's see findAll for example.
Page<T> findAll(#Nullable Specification<T> spec, Pageable pageable);
Before call this method you can create your specification dynamically (where condition) and Pageable object with dynamic Sort information.
For example
...
Specification<T> whereSpecifications = Specification.where(yourWhereSpeficiation);
Sort sortByProperty = Sort.by(Sort.Order.asc("property"));
PageRequest orderedPageRequest = PageRequest.of(1, 100, sortByProperty);
userRepository.findAll(whereSpecifications, PageRequest.of(page, limit, orderedPageRequest));
I have below two Document structures. In the structure CRMContact.orgGroupId == OrganizationGroup.id. I would like to fetch all the CRMContact document that matches with sharedGroupIds and also select only a few fields from CRMContact and only OrganizationGroup.groupownername from OrganizationGroup and match/populate groupId (with only one field [groupownername] populated). I have used below custom implementation but didn't work.
I have included aggregarionsNotWorking which is not working and aggregarions returning entire OrganizationGroup populated. How to achieve this i.e. just to populate groupownername field, using spring data mongodb?
#Document(collection = "ww_crm_contact")
public class CRMContact{
#Id
protected String id;
private String displayName;
private String firstName;
private String middleName;
private String lastName;
private OrganizationGroup groupId; //Ignore //Modified field name orgGroupId
#Indexed(name = "CRMCONTACT_SHAREDGROUPID_IDX",background = true)
private List<String> sharedGroupIds = new LinkedList<>();
#Indexed(name = "CRMCONTACT_ORGGROUPID_IDX",background = true)
private String orgGroupId;
}
#Document(collection = "ww_organization_groups")
public class OrganizationGroup {
private static final long serialVersionUID = 600049975643062552L;
#Id
protected String id;
private String groupName;
private int riaId;
private Boolean isPrivate;
private String description;
private Boolean deleted;
#Transient
private int count;
private String groupownerid;
private String groupownername;
}
#Repository
public class CustomCRMContactDAO {
#Autowired
MongoTemplate mongoTemplate;
public List<CRMContact> getContactsPresentInGroup(List<ObjectId> objectIds){
LookupOperation lookupOperation = LookupOperation.newLookup().from("ww_organization_groups").localField("orgGroupId").foreignField("_id").as("groupId");
ProjectionOperation fields = project("firstName","lastName", "primaryId","displayName","groupId.groupownername");
Aggregation aggregarionsNotWorking = Aggregation.newAggregation(Aggregation.match(Criteria.where("sharedGroupIds").in(objectIds)),lookupOperation,unwind("groupId"),fields); //Not Working even if I change the field only to groupownername
Aggregation aggregarions = Aggregation.newAggregation(Aggregation.match(Criteria.where("sharedGroupIds").in(objectIds)),lookupOperation,fields); //
List<CRMContact> crmContacts = mongoTemplate.aggregate(aggregarions, "ww_crm_contact",CRMContact.class).getMappedResults();
return crmContacts;
}
}
I have the above domain structure where I have list of Companies in the product and the aim is not make entry in mongoDB when I have exact match for companies & productId already present in the DB.
#Entity
public class Mobile {
#Id
private Integer id;
private String imei;
private Product productInfo;
// ...
}
#Entity
public class Product {
#Id
private Integer id;
private String productId;
private List<Company<?>> companies;
// ...
}
#JsonTypeInfo(use = JsonTypeInfo.Id.NAME,
include = JsonTypeInfo.As.PROPERTY, property = "type")
#JsonSubTypes({
#JsonSubTypes.Type(name= "samsung", value = Samsung.class),
#JsonSubTypes.Type(name= "htc",value = Htc.class)})
public class Company<T> implements Serializable {
private static final long serialVersionUID = -8869676577723436716L;
private T companyInfo;
private String type;
// ...
}
I am using mongo template and I have tried to use find as shown below but id didn't work
template.find(Query.query(Criteria.where("product.companies").is(companList),Mobile.class);