I am trying to sort a result by nested collection element value. I have a very simple model:
#Entity
public class User {
#Id
#NotNull
#Column(name = "userid")
private Long id;
#OneToMany(mappedBy = "user")
private Collection<Setting> settings = new HashSet<>();
// getters and setters
}
#Entity
public class Setting {
#Id
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "userid")
private User user;
private String key;
private String value;
// getters and setters
}
public interface UserRepository extends JpaRepository<User, Long>, QuerydslPredicateExecutor<User> {
}
I want to have a result returned sorted by the value of one setting.
Is it possible to order by user.settings.value where settings.name = 'SampleName' using Spring Data JPA with QueryDSL?
I've used JpaSpecificationExecutor. let's see findAll for example.
Page<T> findAll(#Nullable Specification<T> spec, Pageable pageable);
Before call this method you can create your specification dynamically (where condition) and Pageable object with dynamic Sort information.
For example
...
Specification<T> whereSpecifications = Specification.where(yourWhereSpeficiation);
Sort sortByProperty = Sort.by(Sort.Order.asc("property"));
PageRequest orderedPageRequest = PageRequest.of(1, 100, sortByProperty);
userRepository.findAll(whereSpecifications, PageRequest.of(page, limit, orderedPageRequest));
Related
I have entities that are persisted in MongoDB and use spring data MongoRepository to fetch data. Now i want to apply filter to all queries that executed on the entites, so i decided to use hibernate filter, something like this:
#Entity
#QueryEntity
#Document(collection = "Opportunity")
#NoArgsConstructor
#AllArgsConstructor
#Getter
#Setter
#CompoundIndexes({
#CompoundIndex(name = "productGroup_userId_uniqueness", def = "{'productGroupCode' : 1, 'userId': 1}", unique = true)
})
#FilterDef(name = "defaultFilter",parameters = #ParamDef(name = "unitCode",type = "string"))
#Filter(name = "defaultFilter" , condition = " unitCode like :unitCode")
public class Opportunity {
#Id
#Indexed
private String id;
#Indexed
#Enumerated(EnumType.STRING)
private OpportunityStatus opportunityStatus = OpportunityStatus.OPEN;
private LeadType leadType;
#Indexed
private String userId;
#Indexed
private String productCode;
#Indexed
private String productGroupCode;
#Indexed
private Long actionId;
private String assigneeId;
#Transient
private List<AbstractCommand> commandHistory = new ArrayList<>();
#Transient
private Map<Long, Boolean> actionStatus = new HashMap<>();
private String unitCode;
}
and this is the repository class:
#Repository
public interface OpportunityRepository extends MongoRepository<Opportunity, String>, QuerydslPredicateExecutor<Opportunity> {
// this repository contains more than 20 methods
// and all of theme removed for question brevity
}
And I enabled hibernate filter on session with this way:
Session session = (entityManager).unwrap(Session.class);
session.enableFilter(filterName).setParameter("unitCode", this.getCurrentUserUnitCode());
Now, when I call OpportunityRepository.findAll(Predicate predicate, Pageable pageable) i expected to apply the defined filter on the entity, but it didn't work.
I think the reason is that MongoRepository hasn't any sense of hibernate #Filter and i should use another way to append where clause to all mongo queries that running on the Opportunity entity.
I used spring jpa specification to build dynamically an entity query.
It's working perfect but the query returns all entity fields which makes the performance slower.
I want to fetch specific entity fields only and not fetching all entity fields and dependencies which I don't want and I will not use.
I search on the web, I tried some scenarios but without any lack.
Can anyone suggest any solution on this?
Thanks in advance
Here is what I have.I'm using spring boot 2.2.4
public class Concert {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column
private String name;
#Column
private String code;
#Column
private double totalIncome;
#Column
private double totalExpenses;
#Column
private double totalBudget;
#ManyToOne(targetEntity = Orchestra.class, fetch = FetchType.EAGER, optional = false)
#JoinColumn(name = "orchestra_id")
private Orchestra orchestra;
#ManyToOne(targetEntity = ConcertStatus.class, fetch = FetchType.EAGER, optional = false)
#JoinColumn(name = "concert_status_id")
private ConcertStatus status;
/* other fields */
}
Specification:
public class ConcertSpecification implements Specification<Concert> {
#Override
public Predicate toPredicate(Root<Concert> root, CriteriaQuery<?> query, CriteriaBuilder builder) {
List<Predicate> predicates = new ArrayList<>();
//add add criteria to predicates
for (Criterion criteria : criteriaList) {
/* predicates builder here */
}
return builder.and(predicates.toArray(new Predicate[0]));
}
}
Repository:
public interface ConcertDao extends JpaRepository<Concert, Long>, JpaSpecificationExecutor<Concert>, PagingAndSortingRepository<Concert, Long> { }
ConcertService:
public interface ConcertService {
Page<Concert> findAll(#Nullable Specification<Concert> spec, Pageable pageable);
}
ConcertServiceImpl:
#Service(value = "concertService")
public class ConcertServiceImpl implements ConcertService {
public Page<Concert> findAll(#Nullable Specification<Concert> spec, Pageable pageable){
List<Concert> list = new ArrayList<>();
concertDao.findAll(spec).iterator().forEachRemaining(list::add);
return new PageImpl<Concert>(list);
}
}
Usage of projections with specifications are not supported and there is a PR for it that has been hanging for over five years.
I am using springboot and springdata with Mysql.
I have 2 entities, Customer & Order:
#Entity
#Table(name = "customers")
public class Customer {
#Id
#GeneratedValue(strategy= GenerationType.IDENTITY)
#Column(name="id", nullable = false)
protected long id;
#Column(name = "name")
private String name;
}
#Entity
#Table(name = "orders")
public class Order {
#Id
#GeneratedValue(strategy= GenerationType.IDENTITY)
#Column(name="id", nullable = false)
protected long id;
#Column(name="customer_id")
private long customerId;
}
I also have a repository:
#Repository
public interface OrdersRepository extends JpaRepository<Order, Long> {
#Query("select o from Order o, Customer c where o.customerId = c.id")
Page<Order> searchOrders(final Pageable pageable);
}
The method has some more arguments for searching, but the problem is when I send a PageRequest object with sort that is a property of Customer.
e.g.
Sort sort = new Sort(Sort.Direction.ASC, "c.name");
ordersRepository.search(new PageRequest(x, y, sort));
However, sorting by a field of Order works well:
Sort sort = new Sort(Sort.Direction.ASC, "id");
ordersRepository.search(new PageRequest(x, y, sort));
The error I get is that c is not a property of Order (but since the query is a join of the entities I would expect it to work).
Caused by: org.hibernate.QueryException: could not resolve property c of Order
Do you have any idea how I can sort by a field of the joined entity?
Thank you
In JPA , the thing that you sort with must be something that is returned in the select statement, you can't sort with a property that is not returned
You got the error because the relationship is not modeled properly. In your case it is a ManyToOne relation. I can recomend the wikibooks to read further.
#Entity
#Table(name = "orders")
public class Order {
#Id
#GeneratedValue(strategy= GenerationType.IDENTITY)
#Column(name="id", nullable = false)
protected long id;
#ManyToOne
#JoinColumn(name="customer_id", referencedColumnName = "id")
private Customer customer;
}
The query is not needed anymore because the customer will be fetched.
#Repository
public interface OrdersRepository extends PagingAndSortingRepository<Order, Long> {
}
Now you can use nested properties.
Sort sort = new Sort(Sort.Direction.ASC, "customer.name");
ordersRepository.findAll(new PageRequest(x, y, sort));
I've setup JPA auditing with Spring Data JPA AuditingEntityListener and AuditorAware bean. What I want is to be able to persist auditor details even on entities with predefined identifiers.
The problem is that when JPA entity with predefined id is being persisted and flushed it's auditor details cannot be persisted:
object references an unsaved transient instance - save the transient instance before flushing: me.auditing.dao.AuditorDetails
The interesting part is that when an entity with a generated id is saved - everything's fine. In both cases the entities are new. I could not pinpoint the problem digging through hibernate code so I've created a sample project to demonstrate this (test class me.auditing.dao.AuditedEntityIntegrationTest) It has both entities with predefined and generated identifiers and should be audited.
The entities are:
#Entity
public class AuditedEntityWithPredefinedId extends AuditableEntity {
#Id
private String id;
public String getId() {
return id;
}
public AuditedEntityWithPredefinedId setId(String id) {
this.id = id;
return this;
}
}
and:
#Entity
public class AuditedEntityWithGeneratedId extends AuditableEntity {
#Id
#GeneratedValue(generator = "uuid")
#GenericGenerator(name = "uuid", strategy = "uuid")
private String id;
public String getId() {
return id;
}
public AuditedEntityWithGeneratedId setId(String id) {
this.id = id;
return this;
}
}
where parent class is:
#MappedSuperclass
#EntityListeners(AuditingEntityListener.class)
public abstract class AuditableEntity implements Serializable {
private static final long serialVersionUID = -7541732975935355789L;
#ManyToOne(fetch = FetchType.EAGER, cascade = {CascadeType.ALL})
#CreatedBy
private AuditorDetails createdBy;
#CreatedDate
private LocalDateTime createdDate;
#ManyToOne(fetch = FetchType.EAGER, cascade = {CascadeType.ALL})
#LastModifiedBy
private AuditorDetails modifiedBy;
#LastModifiedDate
private LocalDateTime modifiedDate;
And the auditor getter implementation is:
#Override
public AuditorDetails getCurrentAuditor() {
return new AuditorDetails()
.setId(null)
.setUserId("someUserId")
.setDivisionId("someDivisionId");
}
Edit 2016-08-08: It seems that when a new entity with predefined id is saved, it gets two different instances of createdBy and modifiedBy AuditorDetails, which is quite logical if the entity wouldn't be actually new. So, a completely new entity with generated gets both AuditorDetails of same instance, and the one with manually set id doesn't. I tested it by saving auditor details in AuditorAware bean before returning it to AuditingHandler.
Ok, so for now the only solution I could find is to actually persist AuditorDetails before writing it to audited entities like so:
#Override
#Transactional
public AuditorDetails getCurrentAuditor() {
AuditorDetails details = new AuditorDetails()
.setId(null)
.setUserId("someUserId")
.setDivisionId("someDivisionId");
return auditorDetailsRepository.save(details);
}
It is not the most elegant solution, but it works for now.
I have the following entities and would like to seek help on how to query for selected attributes from both side of the relationship. Here is my model. Assume all tables are properly created in the db. JPA provider I am using is Hibernate.
#Entity
public class Book{
#Id
private long id;
#Column(nullable = false)
private String ISBNCode;
#ManyToOne(cascade = CascadeType.DETACH, fetch = FetchType.LAZY, optional = false)
private Person<Author> author;
#ManyToOne(cascade = CascadeType.DETACH, fetch = FetchType.LAZY, optional = true)
private Person<Borrower> borrower;
}
#Inheritance
#DiscriminatorColumn(name = "personType")
public abstract class Person<T>{
#Id
private long id;
#OneToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
private Info information;
}
#Entity
#DiscriminatorValue(PersonType.Author)
public class Author extends Person<Author> {
private long copiesSold;
}
#Entity
#DiscriminatorValue(PersonType.Borrower)
public class Borrower extends Person<Borrower> {
.....
}
#Entity
public class Info {
#Id
private long id;
#Column(nullable=false)
private String firstName;
#Column(nullable=false)
private String lastName;
......;
}
As you can see, the book table has a many to one relation to Person that is not nullable and Person that is nullable.
I have a requirement to show, the following in a tabular format -
ISBNCode - First Name - Last Name - Person Type
How can I write a JPA query that will allow me to select only attributes that I would want. I would want to get the attributes ISBN Code from Book, and then first and last names from the Info object that is related to Person Object that in turn is related to the Book object. I would not want to get all information from Info object, interested only selected information e.g first and last name in this case.
Please note that the relation between the Borrower and Book is marked with optional=true, meaning there may be a book that may not have been yet borrowed by someone (obviously it has an author).
Example to search for books by the author "Marc":
Criteria JPA Standard
CriteriaQuery<Book> criteria = builder.createQuery( Book.class );
Root<Book> personRoot = criteria.from( Book.class );
Predicate predicate = builder.conjunction();
List<Expression<Boolean>> expressions = predicate.getExpressions();
Path<Object> firtsName = personRoot.get("author").get("information").get("firstName");
expressions.add(builder.equal(firtsName, "Marc"));
criteria.where( predicate );
criteria.select(personRoot);
List<Book> books = em.createQuery( criteria ).getResultList();
Criteria JPA Hibernate
List<Book> books = (List<Book>)sess.createCriteria(Book.class).add( Restrictions.eq("author.information.firstName", "Marc") ).list();
We recommend using hibernate criterias for convenience and possibilities.
Regards,