I want to see the previous quarter's max month(as a new column) value in the current quarter using a big query.
When in Q1 2022 it should display Q4 December 2021 as a new column
When in Q2 2022 it should display Q1 March 2022 (in this case 60000)
When in Q3 2022 it should display Q2 June 2022 (in this case 40000)
My data is like below
date Sales
2022-09-01 10000
2022-08-02 20000
2022-07-01 30000
2022-06-01 40000
2022-05-01 30000
2022-04-01 50000
2022-03-01 60000
2022-02-01 10000
2022-01-01 89090
Output
your given result table fits not the task: previous quarter's max month.
Here several outputs. Do you want the maximum of the last months, or the values from three month ago? Both columns are included here.
The formula of the 1st month of quarter can be edit to the last month by changing the 1 to -1. As You want zero values for all other months, you need to multiply this with the other column.
Window function do the job. But for each month there must be one row. This is filled up with the all_months table.
with tbl as
(
Select date("2022-09-01") as dates, 10000 money
union all select date("2022-08-02"), 20000
union all select date("2022-07-01"), 30000
union all select date("2022-06-01"), 40000
union all select date("2022-05-01"), 30000
union all select date("2022-04-01"), 50000
union all select date("2022-03-01"), 60000
union all select date("2022-02-01"), 10000
union all select date("2022-01-01"), 89090
),
all_months as
(select dates,0 from (Select max(dates) A, min(dates) B from tbl), unnest(generate_date_array(A,B,interval 1 month)) dates)
select *,
if( date_trunc(dates,quarter)= date_trunc(date_sub(dates,interval 1 month),quarter),0,1) as first_month_of_quarter,
lag(money_max_this_quarter) over (order by dates) as money_max_last_quarter,
lag(money,3) over (order by dates) as money_three_months_ago,
from
(
select * ,
max(money) over (partition by date_trunc(dates,quarter ) ) as money_max_this_quarter
from
(
Select dates,sum(money) as money from tbl group by 1
union all select * from all_months
)
)
order by 1 desc
Related
6.Hive: Given a table t with schema (date, revenue), like this
6.Hive: Given a table t with schema (date, revenue), like this
date r
Jan. 1 100
Jan. 2 120
Jan. 3 80
Jan. 4 150
Jan. 5 50
What does the following query do?
SELECT t1.date AS date, sum(t2.revenue) AS revenue
FROM t as t1 JOIN t as t2 ON t2.date <= t1.date GROUP BY 1 ORDER BY 1
I am trying to build a cohort analysis for monthly retention but experiencing challenge getting the Month Number column right. The month number is supposed to return month(s) user transacted i.e 0 for registration month, 1 for the first month after registration month, 2 for the second month until the last month but currently, it returns negative month numbers in some cells.
It should be like this table:
cohort_month total_users month_number percentage
---------- ----------- -- ------------ ---------
January 100 0 40
January 341 1 90
January 115 2 90
February 103 0 73
February 100 1 40
March 90 0 90
Here is the SQL:
with cohort_items as (
select
extract(month from insert_date) as cohort_month,
msisdn as user_id
from mfscore.t_um_user_detail where extract(year from insert_date)=2020
order by 1, 2
),
user_activities as (
select
A.sender_msisdn,
extract(month from A.insert_date)-C.cohort_month as month_number
from mfscore.t_wm_transaction_logs A
left join cohort_items C ON A.sender_msisdn = C.user_id
where extract(year from A.insert_date)=2020
group by 1, 2
),
cohort_size as (
select cohort_month, count(1) as num_users
from cohort_items
group by 1
order by 1
),
B as (
select
C.cohort_month,
A.month_number,
count(1) as num_users
from user_activities A
left join cohort_items C ON A.sender_msisdn = C.user_id
group by 1, 2
)
select
B.cohort_month,
S.num_users as total_users,
B.month_number,
B.num_users * 100 / S.num_users as percentage
from B
left join cohort_size S ON B.cohort_month = S.cohort_month
where B.cohort_month IS NOT NULL
order by 1, 3
I think the RANK window function is the right solution. So the idea is to assigne a rank to months of user activities for each user, order by year and month.
Something like:
WITH activity_per_user AS (
SELECT
user_id,
event_date,
RANK() OVER (PARTITION BY user_id ORDER BY DATE_PART('year', event_date) , DATE_PART('month', event_date) ASC) AS month_number
FROM user_activities_table
)
RANK number starts from 1, so you may want to substract 1.
Then, you can group by user_id and month_number to get the number of interactions for each user per month from the subscription (adapt to your use case accordingly).
SELECT
user_id,
month_number,
COUNT(1) AS n_interactions
FROM activity_per_user
GROUP BY 1, 2
Here is the documentation:
https://docs.aws.amazon.com/redshift/latest/dg/r_WF_RANK.html
I would like to insert subquery a date based on it day. Plus, each date can only be used four times. Once it reached fourth times, the fifth value will use another date of same day. In other word, use date of Monday of next week. Example, Monday with 6 JUNE 2016 to Monday with 13 JUNE 2016 (you may check the calendar).
I have a query of getting a list of date based on presentationdatestart and presentationdateend from presentation table:
select a.presentationid,
a.presentationday,
to_char (a.presentationdatestart + delta, 'DD-MM-YYYY', 'NLS_CALENDAR=GREGORIAN') list_date
from presentation a,
(select level - 1 as delta
from dual
connect by level - 1 <= (select max (presentationdateend - presentationdatestart)
from presentation))
where a.presentationdatestart + delta <= a.presentationdateend
and a.presentationday = to_char(a.presentationdatestart + delta, 'fmDay')
order by a.presentationdatestart + delta,
a.presentationid; --IMPORTANT!!!--
For example,
presentationday presentationdatestart presentationdateend
Monday 01-05-2016 04-06-2016
Tuesday 01-05-2016 04-06-2016
Wednesday 01-05-2016 04-06-2016
Thursday 01-05-2016 04-06-2016
The query result will list all possible dates between 01-05-2016 until 04-06-2016:
Monday 02-05-2016
Tuesday 03-05-2016
Wednesday 04-05-2016
Thursday 05-05-2016
....
Monday 30-05-2016
Tuesday 31-05-2016
Wednesday 01-06-2016
Thursday 02-06-2016 (20 rows)
This is my INSERT query :
insert into CSP600_SCHEDULE (studentID,
studentName,
projectTitle,
supervisorID,
supervisorName,
examinerID,
examinerName,
exavailableID,
availableday,
availablestart,
availableend,
availabledate)
select '2013816591',
'mong',
'abc',
'1004',
'Sue',
'1002',
'hazlifah',
2,
'Monday', //BASED ON THIS DAY
'12:00:00',
'2:00:00',
to_char (a.presentationdatestart + delta, 'DD-MM-YYYY', 'NLS_CALENDAR=GREGORIAN') list_date //FOR AVAILABLEDATE
from presentation a,
(select level - 1 as delta
from dual
connect by level - 1 <= (select max (presentationdateend - presentationdatestart)
from presentation))
where a.presentationdatestart + delta <= a.presentationdateend
and a.presentationday = to_char(a.presentationdatestart + delta, 'fmDay')
order by a.presentationdatestart + delta,
a.presentationid;
This query successfully added 20 rows because all possible dates were 20 rows. I would like modify the query to be able to insert based on availableDay and each date can only be used four times for each different studentID.
Possible outcome in CSP600_SCHEDULE (I am removing unrelated columns to ease readability):
StudentID StudentName availableDay availableDate
2013 abc Monday 01-05-2016
2014 def Monday 01-05-2016
2015 ghi Monday 01-05-2016
2016 klm Monday 01-05-2016
2010 nop Tuesday 02-05-2016
2017 qrs Tuesday 02-05-2016
2018 tuv Tuesday 02-05-2016
2019 wxy Tuesday 02-05-2016
.....
2039 rrr Monday 09-05-2016
.....
You may check the calendar :)
I think what you're asking for is to list your students and then batch them up in groups of 4 - each batch is then allocated to a date. Is that right?
In which case something like this should work (I'm using a list of tables as the student names just so I don't need to insert any data into a custom table) :
WITH students AS
(SELECT table_name
FROM all_tables
WHERE rownum < 100
)
SELECT
table_name
,SYSDATE + (CEIL(rownum/4) -1)
FROM
students
;
I hope that helps you
...okay, following your comments, I think this might be a better solution :
WITH students AS
(SELECT table_name student_name
FROM all_tables
WHERE rownum < 100
)
, dates AS
(SELECT TRUNC(sysdate) appointment_date from dual UNION
SELECT TRUNC(sysdate+2) from dual UNION
SELECT TRUNC(sysdate+4) from dual UNION
SELECT TRUNC(sysdate+6) from dual UNION
SELECT TRUNC(sysdate+8) from dual UNION
SELECT TRUNC(sysdate+10) from dual UNION
SELECT TRUNC(sysdate+12) from dual UNION
SELECT TRUNC(sysdate+14) from dual
)
SELECT
s.student_name
,d.appointment_date
FROM
--get a list of students each with a sequential row number, ordered by student name
(SELECT
student_name
,ROW_NUMBER() OVER (ORDER BY student_name) rn
FROM students
) s
--get a list of available dates with a sequential row number, ordered by date
,(SELECT
appointment_date
,ROW_NUMBER() OVER (ORDER BY appointment_date) rn
FROM dates
) d
WHERE 1=1
--allocate the first four students to date rownumber1, next four students to date rownumber 2...
AND CEIL(s.rn/4) = d.rn
;
I'm trying to query some transactional data to establish the CurrentProductionHours value for each Report at the end of each month.
Providing there has been a transaction for each report in each month, that's pretty straight-forward... I can use something along the lines of the code below to partition transactions by month and then pick out the rows where TransactionByMonth = 1 (effectively, the last transaction for each report each month).
SELECT
ReportId,
TransactionId,
CurrentProductionHours,
ROW_NUMBER() OVER (PARTITION BY [ReportId], [CalendarYear], [MonthOfYear]
ORDER BY TransactionTimestamp desc
) AS TransactionByMonth
FROM
tblSource
The problem that I have is that there will not necessarily be a transaction for every report every month... When that's the case, I need to carry forward the last known CurrentProductionHours value to the month which has no transaction as this indicates that there has been no change. Potentially, this value may need to be carried forward multiple times.
Source Data:
ReportId TransactionTimestamp CurrentProductionHours
1 2014-01-05 13:37:00 14.50
1 2014-01-20 09:15:00 15.00
1 2014-01-21 10:20:00 10.00
2 2014-01-22 09:43:00 22.00
1 2014-02-02 08:50:00 12.00
Target Results:
ReportId Month Year ProductionHours
1 1 2014 10.00
2 1 2014 22.00
1 2 2014 12.00
2 2 2014 22.00
I should also mention that I have a date table available, which can be referenced if required.
** UPDATE 05/03/2014 **
I now have query which is genertating results as shown in the example below but I'm left with islands of data (where a transaction existed in that month) and gaps in between... My question is still similar but in some ways a little more generic - What is the best way to fill gaps between data islands if you have the dataset below as a starting point?
ReportId Month Year ProductionHours
1 1 2014 10.00
1 2 2014 12.00
1 3 2014 NULL
2 1 2014 22.00
2 2 2014 NULL
2 3 2014 NULL
Any advice about how to tackle this would be greatly appreciated!
Try this:
;with a as
(
select dateadd(m, datediff(m, 0, min(TransactionTimestamp))+1,0) minTransactionTimestamp,
max(TransactionTimestamp) maxTransactionTimestamp from tblSource
), b as
(
select minTransactionTimestamp TT, maxTransactionTimestamp
from a
union all
select dateadd(m, 1, TT), maxTransactionTimestamp
from b
where tt < maxTransactionTimestamp
), c as
(
select distinct t.ReportId, b.TT from tblSource t
cross apply b
)
select c.ReportId,
month(dateadd(m, -1, c.TT)) Month,
year(dateadd(m, -1, c.TT)) Year,
x.CurrentProductionHours
from c
cross apply
(select top 1 CurrentProductionHours from tblSource
where TransactionTimestamp < c.TT
and ReportId = c.ReportId
order by TransactionTimestamp desc) x
A similar approach but using a cartesian to obtain all the combinations of report ids/months.
in the first step.
A second step adds to that cartesian the maximum timestamp from the source table where the month is less or equal to the month in the current row.
Finally it joins the source table to the temp table by report id/timestamp to obtain the latest source table row for every report id/month.
;
WITH allcombinations -- Cartesian (reportid X yearmonth)
AS ( SELECT reportid ,
yearmonth
FROM ( SELECT DISTINCT
reportid
FROM tblSource
) a
JOIN ( SELECT DISTINCT
DATEPART(yy, transactionTimestamp)
* 100 + DATEPART(MM,
transactionTimestamp) yearmonth
FROM tblSource
) b ON 1 = 1
),
maxdates --add correlated max timestamp where the month is less or equal to the month in current record
AS ( SELECT a.* ,
( SELECT MAX(transactionTimestamp)
FROM tblSource t
WHERE t.reportid = a.reportid
AND DATEPART(yy, t.transactionTimestamp)
* 100 + DATEPART(MM,
t.transactionTimestamp) <= a.yearmonth
) maxtstamp
FROM allcombinations a
)
-- join previous data to the source table by reportid and timestamp
SELECT distinct m.reportid ,
m.yearmonth ,
t.CurrentProductionHours
FROM maxdates m
JOIN tblSource t ON t.transactionTimestamp = m.maxtstamp and t.reportid=m.reportid
ORDER BY m.reportid ,
m.yearmonth
I got the information I needed from my last post about Postgres: Defining the longest streak (in days) per developer.
However now I want know the longest streak per developer regardless of Saturdays or Sundays. For instance, Bob worked from Thursday 18, Friday 19, Monday 22 and Tuesday 23, hence Bob streak is 4 days.
I understand I can use the DOW window function, which gives me 0 as Sunday , 1 Monday and so on. But
I don’t see how I can apply DOW function in the last solution proposed by Gordon Linoff.
Can some of you help me in this matter? Cheers,
WITH
working_limits AS (
SELECT
MIN(mr_date) AS start_date,
MAX(mr_date) AS end_date
FROM
xxx
),
working_days AS (
SELECT
ROW_NUMBER() OVER () AS day_number,
s.d::date AS date
FROM
GENERATE_SERIES((SELECT start_date FROM working_limits),
(SELECT end_date FROM working_limits),
'1 day') AS s(d)
WHERE
EXTRACT(dow FROM s.d) BETWEEN 1 AND 5),
worked_days AS (
SELECT
ROW_NUMBER() OVER () AS day_number,
developer,
mr_date AS date
FROM
xxx
ORDER BY
developer,
mr_date
)
SELECT
y.developer,
MAX(y.days)
FROM (
SELECT
x.developer,
COUNT(*) AS days
FROM (
SELECT
wngd.date,
wd.developer,
wngd.day_number - wd.day_number AS delta
FROM
working_days wngd INNER JOIN worked_days wd
ON
wngd.date = wd.date) AS x
GROUP BY
x.developer,
x.delta) AS y
GROUP BY
y.developer;