How to insert "29-SEP-22 12.00.17.225 AM" in PostgreSQL DB ?
In Oracle Table,
"29-SEP-22 12.00.17.225 AM"
In PostgreSQL Table , ??
How to capture above date format in PostgreSQL table ?
what will be the datatype PostgreSQL side ?
The data type would be timestamp. Use to_timestamp with format specification dd-mon-yy hh12.mi.ss.ms pm.
Example:
select to_timestamp('29-SEP-22 12.00.17.225 AM', 'dd-mon-yy hh12.mi.ss.ms pm');
Related
I have a date time field which is coming from an external system in UTC format 2022-01-02T08:00:00.000+00:00. This value should be queried in DB2 to determine whether the record exists or not. The date stored in DB2 is in the format 2022-01-01 08:00:00.000 Is there any way to convert the incoming date in the format 2022-01-01 08:00:00.000 ?
The final query should be something like
select * from table where changedate = '2022-01-02T08:00:00.000+00:00'
Db2 doesn't store timestamps in a string format. Some binary format is used for that.
So, if I got you right, your question should be changed to "how to convert YYYY-MM-DDTHH24.MI.SS.FF3XXXXXX string representation of timestamp to the timestamp data type".
Unfortunately, there is no such a built-in pattern in the TO_DATE / TIMESTAMP_FORMAT function, but you can use the following expression. T column has the timestamp data type, and you may use this expression in the select * from table where changedate = ... statement.
SELECT
S
, TO_DATE (TRANSLATE (SUBSTR (S, 1, 23), ' ', 'T'), 'YYYY-MM-DD HH24:MI:SS.FF3')
+ CAST (TRANSLATE (SUBSTR (S, 24), '', ':', '') || '00' AS DEC (6)) AS T
FROM
(
VALUES
'2022-01-02T08:00:00.000+00:00'
, '2022-01-02T08:00:00.000+03:30'
, '2022-01-02T08:00:00.000-03:30'
) T (S)
S
T
2022-01-02T08:00:00.000+00:00
2022-01-02-08.00.00.000000
2022-01-02T08:00:00.000+03:30
2022-01-02-11.30.00.000000
2022-01-02T08:00:00.000-03:30
2022-01-02-04.30.00.000000
I want to show date in string format as current month name(String) and year(e.g -> SEPTEMBER, 2019). How to write query for this in PostgreSQL?
I tried this query:
select
date(date_trunc('month', current_date));
but it gives me only current months starting date.
Try to_char() and add the year formatter to the string like this:
SELECT to_char(current_date, 'MONTH YYYY')
This will return:
SEPTEMBER 2019
Here's a sqlfiddle
If you want to format the output of a DATE value, use to_char()
select to_char(current_date, 'Month, yyyy');
we can do it like this also in Postgresql -
SELECT TO_CHAR(NOW() :: DATE, 'Month , yyyy');
output - September, 2019
In the view I have a text column which contains a timestamp in this format '20/03/2018 00:00' and I'm trying to make a selection with a between clause but it's not working
SELECT id,entry_date
FROM v_view
WHERE entrada BETWEEN to_timestamp('20/03/2018 00:00','DD/MM/YYYY')::timestamp and to_timestamp('22/03/2018 00:00')::timestamp
order entry_date
with this error message
ERROR: el operador no existe: text >= timestamp without time zone
LINE 3: WHERE entry_date BETWEEN to_timestamp('20/03/2018 00:00','DD/MM.
you need to convert the entrada column value to a timestamp.
Also: casting the result of to_timestamp() to a timestamp is useless because to_timestamp() already returns a timestamp
SELECT id,entry_date
FROM v_view
WHERE to_timestamp(entrada, 'dd/mm/yyyy hh24:mi')
BETWEEN to_timestamp('20/03/2018', 'DD/MM/YYYY')
and to_timestamp('22/03/2018', 'dd/mm/yyyy')
order entry_date;
I prefer to use ANSI SQL timestamp literals over the to_timestamp function:
SELECT id,entry_date
FROM v_view
WHERE to_timestamp(entrada, 'dd/mm/yyyy hh24:mi')
BETWEEN timestamp '2018-03-20 00:00:00'
and timestamp '2018-03-22 00:00:00'
order entry_date
Do not store date, time or timestamp values in a text or varchar column. You should define that column as timestamp then you don't need to convert anything and you don't need to deal with invalid timestamp values in that column.
how do I convert
'25/02/2014 10:49:13 -8'(datatype is VARCHAR)
to
'2014-02-25 13:50:13.000000'(datatype is TIMESTAMP)
in postgreSQL
I believe the timestamp is EST timezone.
Try the method
to_timestamp
Example:
to_timestamp('01 Jan 2007 09:09:09', 'DD Mon YYYY HH:MI:SS')
Hope This helps
I have a column in a table in which we are storing date in DATETIME format. (DD-MON-RRRR HH24:MI:SS) - Database Oracle 11g.
Data Type of a column is DATE, and storing date in 01-01-2012 01:00 PM (i.e. jan 1, 2012) format.
entity
#NotNull
#Column(name = "dateColumnName")
#Temporal(TemporalType.TIMESTAMP)
private Date sampleDate;
I am fetching all data by passing date
SAMPLE_QUERY = "select * from TableA tab where tab.dateWithTime = :sampleDate order by tab.dateWithTime ASC "
singleDate is "Tue Jan 24 00:00:00 IST 2012" , fasttime :
1327343400000
The problem is I am passing only date in the query, though Date through which records are being fetched is in DATE TIME format i.e 01-01-2012 01:00 PM.
How can i change my query so that it fetches all the records in ascending order of DateTime.
If you want to fetch all times for that day, then change your query to be more like
SELECT ... WHERE dateField >= :lowerParam AND dateField < :upperParam
Oracle has no DATE TIME datatype. The DATE datatype contains both a date and a time component, down to the second. TIMESTAMPS get a bit more complicated.
If your dateWithTime column is indeed a DATE datatype, the ORDER BY dateWithTime ASC clause should order your results in ascending order.
You may not be displaying the time component of your date. You can convert a date to a string in that format with TO_CHAR( dateWithTime, 'dd/mm/yyyy hh24/mm/ss' ) or whatever format you want.
Edit:
Oh, do you mean you want to find the cases where the date component of the DATE matches, but you don't care about the time component? That can be handled in the where clause with something like:
WHERE TRUNC( tab.dateWithTime ) = TRUNC( :sampledate )
TRUNC by default truncates a date to the beginning of the day.