Render view in higher script path with Zend Framework - zend-framework

Question

Lets assume the following code within a controller:
$this->view->addScriptPath('dir1/views/scripts');
$this->view->addScriptPath('dir2/views/scripts');
$this->render('index.phtml');
Where dir1/views/scripts contains 2 files:
-index.phtml
-table.phtml
And dir2/views/scripts:
-table.phtml
Now, it will render the index.phtml in dir1 since dir 2 doesn't have an index.phtml.
Index.phtml looks something like:
<somehtml>
<?= $this->render('table.phtml') ?>
</somehtml>
This is where the confusion starts for me. I would expect it to render the table.phtml in the last directory added to the script path stack, but it doesn't.
Is there a simple solution/explanation to my problem?

Answer 1

Seems that paths are used in LIFO order.
Take a look at viewRednderer and view source files to see how does it work.

Answer 2

u can use
> $this->view->setBasePath("../application/dir1/views");
that is more specific

Answer 3

I ended up extending Zend_View and adding the function renderParent:
class My_View extends Zend_View
{
private $_file = null;
private $_name = null;
/**
* Finds a view script from the available directories.
*
* #param $name string The base name of the script.
* #return void
*/
protected function _script($name)
{
$this->_file = parent::_script($name);
$this->_name = $name;
return $this->_file;
}
/**
* Renders the parent script by looping through all the script paths.
*
* #return void
*/
public function renderParent()
{
$scriptPaths = $this->getScriptPaths();
$found = false;
for ($i = 0; $i < count($scriptPaths); $i++) {
if ($this->_file == $scriptPaths[$i] . $this->_name) {
$found = true;
} elseif ($found) {
if (is_readable($scriptPaths[$i] . $this->_name)) {
return $this->_run($scriptPaths[$i] . $this->_name);
}
}
}
}
}