Hey, been looking for a while but I can't seem to find any info on how to handle date in classic asp.
For now, I need a way to calculate the number of days passed in the current year. I was thinking about a simple function that would take the current date, then make another date with (day = 1, month = 1, year(now)). And finally get the datediff(day) for these two. Easy enough, but I can't figure out how to do this. Help is appreciated!
Perhaps this example can help you? https://web.archive.org/web/20211020135923/https://www.4guysfromrolla.com/webtech/110398-1.shtml
DateDiff("d",DateSerial(Year(Now),1,1),Date)
Related
I want to convert date into a Day
I am using LibreOffice
I used some of its syntax weekday and text but it returns nothing
WEEKDAY("30-04-2019"; 1) is there any way to do that?
in google sheet i used =TEXT(C7758,"dddd") but it didn't work
how can I do that?
thanks in advance
Try the combination of functions WEEKDAY and DATE:
=WEEKDAY(DATE(2019;4;30))
The specific example will return 3 which is Tuesday (see all days and other options at https://wiki.openoffice.org/wiki/Documentation/How_Tos/Calc:_WEEKDAY_function)
Hope that helps.
Here's a screenshot:
Here's a screenshot http://www.coletrumbo.com/wp-content/uploads/2015/05/dateformat-1024x575.png
I'm trying to turn the current date into July 1st of the current year using DATEFORMAT(). I learned how to do that in MySQL from this question, and I hoped it would work similarly in Jaspersoft Studio- turns out date_format( curdate(), '%Y-07-01' ) doesn't translate into
DATEFORMAT( TODAY(), '%Y-07-01' ) or DATEFORMAT( TODAY(), YY/07/01 ). Neither worked.
I could keep trying to get creative and hopefully find something that works, but I'd rather actually understand how to use DATEFORMAT().
I checked the Jaspersoft Studio User Guide, but it's not there. From the prompts on the screen, it makes a lot of sense, but I just can't figure out the "format pattern" that I'm allowed to apply, or even how to correctly write any format pattern at all. Also, this conveniently named question, DateFormat Pattern, didn't actually help at all. And community.jaspersoft.com/answers is kind of a joke in my opinion. When I checked it a couple days ago, it was filled with spam linking to live hockey games.
Thanks in advance. I'm sure this is a beginner level question, so I feel dumb asking it, and I feel like I'm wasting other people's space and time with it because I should already know. So I really appreciate your willingness to care.
I am using the following to get the todays date in a danish format
"Dato: "+new java.text.SimpleDateFormat("dd MMMM yyyy",new
Locale("da", "DK")).format(new Date())
you can find the source code for the DateTime functions directly in JR repository: https://sourceforge.net/p/jasperreports/code/ci/master/tree/jasperreports/demo/samples/functions/src/net/sf/jasperreports/functions/standard/DateTimeFunctions.java
As you can see the code is fairly simple and relies on the Joda Time library.
Therefore the second parameter you are trying to enter is a String, while the first one is a Date object.
Indeed something that could work for you is an expression like this DATEFORMAT(TODAY(), "07-01-YYYY")
Regards,
Massimo.
Can someone please shed some light on why when I create a date object I receive the wrong month like so:
new Date("2013-11-25").getMonth()
output> 10
new Date("2013-11-25").toISOString()
output> 2013-11-25T00:00:00.000Z
I've seen this happen a couple of times and it's confusing me slightly. Is it a bug or am I missing something?
It is correct. This happens because in javascript month start from 0 not 1.
You can read in details here.
does anyone know where I can download this zip file called "businessdays.zip" which was mentioned from this link ... http://www.tek-tips.com/viewthread.cfm?qid=136159 ... I mean is there a better way of calculating business days/holidays than what is previously written here ... http://www.experts-exchange.com/Database/Reporting_/Crystal_Reports/Q_21376129.html ... I've tried this but method from experts-exchange, registered the dll but still not working for me. Can anyone help?
You could create a custom function that returns an array of holidays. See my answer to Crystal Report exclude time entries based on holiday rules.
In this post there is a function that takes a start date, and end date and return the number of working days in between. Also takes holidays into account.
I have been trying to write Scheme code to get the date and store the month in a variable, but have no clue how, even after reading the online manual.
What I understand now is there is a struct called Date that needs 10 arguments, but not sure how to retrieve the month, or even date, from the library..could anyone please enlighten me on this.
Thank you.
I found it..
(let ((date (seconds->date (current-seconds))))
(display (date-month date)))
working the manual took more effort than i thought.