I am trying to parse some JSON. I've passed a constant key value and a string - butI'm receivng 16 objects in the statuses array and 20 objects in ststuses1.
Are any of the parsing steps wrong?
I have included the code for the JSON parser.
Thanks in advance.
SBJSON *parser = [[SBJSON alloc] init];
NSString *urlString =[NSString stringWithFormat:#"http://api.shiki.com/api/serch?key=%#&q=%#",apiKey, string];
NSURL *url = [NSURL URLWithString:urlString];
NSURLRequest *request = [[NSURLRequest alloc] initWithURL: url];
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];
NSMutableArray *statuses = nil;
statuses = [[NSMutableArray alloc]init];
statuses = [parser objectWithString:json_string error:nil];
NSMutableArray *statuses0 = [[statuses valueForKey:#"offers"] valueForKey:#"offer"];
NSLog(#"Array Contents: %#", statuses0);
I guess that's not the only syntax-error in your code...
Please define statuses and ststuses1. I can only see statuses (redefined 2 times) and statuses0. Also please post a sample of the json-data you're parsing so I can take a look at it.
Related
Api Address：
http://suggest.taobao.com/sug?area=etao&code=utf-8&callback=KISSY.Suggest.callback&q=iphone
return：
KISSY.Suggest.callback({"result": [["iphone4s", "9809"], ["iphone5", "13312"], ["iphone4 手机", "69494400"], ["iphone5 港行", "14267"], ["iphone5三网", "2271160"], ["iphone4手机壳", "6199679"], ["iphone 5手机壳", "2527284"], ["iphone 5 保护壳", "5727586"], ["iphone 4贴膜", "147271"], ["iphone5壳", "2628540"]]})
NSURL * url = [NSURL URLWithString:#"http://suggest.taobao.com/sug?area=etao&code=utf-8&callback=KISSY.Suggest.callback&q=iphone"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
NSHTTPURLResponse* urlResponse = nil;
NSError * error = nil;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&error];
NSData *date = [NSData alloc]init
SBJsonParser *jsonParser = [[SBJsonParser alloc] init];
// NSMutableArray *array=[NSJSONSerialization JSONObjectWithData:responseData options:NSJSONReadingMutableLeaves error:&error];
NSMutableArray *array = [jsonParser objectWithData:responseData];
NSLog(#"%#",array);
this array is null. i dont know the reason.
as i refer you request URL ,it has callback in it, if you keep it, it will not return you json as response, so remove "&callback=KISSY.Suggest.callback" from your URL
// Make sure you have include SBJSON files in your Project, as well you have imported header in your View Controller
#import "JSON.h"
// your request URL
NSURL * url = [NSURL URLWithString:#"http://suggest.taobao.com/sug?area=etao&code=utf-8&q=iphone"];
// URL Request
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
NSHTTPURLResponse* urlResponse = nil;
NSError * error = nil;
// initiate Request to get Data
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&error];
// Encode your Response
NSString *content = [[NSString alloc] initWithBytes:[responseData bytes] length:[responseData length] encoding:NSUTF8StringEncoding];
// Now read a Dictionary from it using SBJSON Parser
NSDictionary *responseDict = [content JSONValue];
NSLog(#"Response [%#]",responseDict);
I'm not familiar with the SBJsonParser, but the format of the returned string looks like JSONP, not JSON. I would imagine simply cleaning out the wrapper call would get you what you are after.
Also, note that the 'root' of your response is a dictionary, not an array.
{"result": [[...
means that the code might should look like this:
NSDictionary *response = //... decode
NSArray *results = [response objectForKey:#"result"];
Edited
You just need to use http://suggest.taobao.com/sug?area=etao&code=utf-8&q=iphone instead of http://suggest.taobao.com/sug?area=etao&code=utf-8&callback=KISSY.Suggest.callback&q=iphone you own code will work..
I am new to iOS, so if any help it will be appreciated.
I am trying to get the longitude and latitude from address, earlier the code was working fine but now the JSON data are coming null.
Here my sample code,
url = [NSString stringWithFormat:#"http://maps.google.com/maps/api/geocode/json?address=%#&sensor=false",appDelegate.sAddress];
url=[url stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSLog(#"Address URL: %#",url);
//Formulate the string as a URL object.
NSURL *requestURL=[NSURL URLWithString:url];
NSData* data = [NSData dataWithContentsOfURL: requestURL];
NSString *returnString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(#"my Coordinate : %#",returnString);
NSError* error;
NSDictionary* json = [NSJSONSerialization
JSONObjectWithData:data
options:kNilOptions
error:&error];
But i am getting the output as null.
So please help me out.
Thanks!
Thanks for your replies that all make me learn a lots.
As one of my friend just tell me the solution so i am sharing with you.
Here is the code,
url = [NSString stringWithFormat:#"http://maps.google.com/maps/api/geocode/json?address=%#&sensor=false",appDelegate.sAddress];
url=[url stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSLog(#"Address URL: %#",url);
//Formulate the string as a URL object.
NSURL *requestURL=[NSURL URLWithString:url];
NSData* data = [NSData dataWithContentsOfURL: requestURL];
NSString *returnString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
SBJSON *parser = [[SBJSON alloc] init];
NSDictionary *locationResult = [parser objectWithString:returnString];
//[reverseGeoString copy]`
And its working fine.
But still there is a question that why this happen.As earlier that code is working fine but it suddenly stopped working.
You must construct your returnString in the following method that actually receives the data:
- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response
Check out this for additional information on how to use NSURLConnection and the delegate methods.
I would say you're missing the all-important "REQUEST"...
This is what I do. Hope it helps:
NSString *encodedAddress = (__bridge_transfer NSString *) CFURLCreateStringByAddingPercentEscapes(NULL, (__bridge_retained CFStringRef)searchBar.text, NULL, (CFStringRef) #"!*'();:#&=+$,/?%#[]",kCFStringEncodingUTF8 );
NSString* searchURL = [NSString stringWithFormat:#"http://maps.googleapis.com/maps/api/geocode/json?address=%#&sensor=true",encodedAddress];
NSError* error = nil;
NSURLResponse* response = nil;
NSMutableURLRequest* request = [[NSMutableURLRequest alloc] init];
NSURL* URL = [NSURL URLWithString:searchURL];
[request setURL:URL];
[request setCachePolicy:NSURLRequestReloadIgnoringLocalCacheData];
[request setTimeoutInterval:30];
NSData* data = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
if (error){
NSLog(#"Error performing request %#", searchURL);
return;
}
NSString *jsonString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
if (jsonString!=nil){
NSLog(#"%#",jsonString);
}
I send some credentials to a web-service.
I can get the responce as NSData or as an NSString.
Whats the simpleist way to convert the (NSData or NSString)JSON to a NSDictionary so I can process it?
Building for iOS4.3
Many Thanks,
-Code
From iOS 5.0 and on you can use NSJSONSerialization, docs here.
There is a good tutorial on how to use it, here.
Download SBJsonParser Framework using the link, http://github.com/stig/json-framework/downloads and add required classes to your project (SBJsonParser.h).
Import SBJsonParser.h and use the following code,
SBJsonParser *parser = [[SBJsonParser alloc] init];
//dictionary with name,id
NSDictionary *jsonObject = [parser objectWithString:jsonString error:NULL];
//name array
NSMutableArray *nameArray = [[NSMutableArray alloc]init];
for (NSMutableDictionary *dic in jsonObject){
[nameArray addObject:[dic valueForKey:#"name"]];
}
Use this :
NSString *urlString = [NSString stringWithFormat:kURLString,self.chapter,self.page];
NSMutableURLRequest *urlRequest = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:urlString]];
[urlRequest setHTTPMethod:#"POST"];
[urlRequest setHTTPBody:[urlString dataUsingEncoding:NSISOLatin1StringEncoding]];
NSData* responseData = [NSURLConnection sendSynchronousRequest:urlRequest returningResponse:nil error:nil];
NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSISOLatin1StringEncoding];
NSDictionary* result = [(NSDictionary*)[responseString JSONValue] objectForKey:#"Result"];
I use SBJson
NSArray *arrObj = (NSArray*)[[JsonParser sharedJsonParser] getObjectsFromJsonString:responseString];
response string is a JSON string here
I made NSData from GET request.
NSString *nameID = [[NSString alloc]initWithString: #"1"];
NSString *urlString = [NSString stringWithFormat:#"http://www.xxxxx.com/news/index.php?id=%#",
[nameID stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
NSURL *url = [[NSURL alloc] initWithString:urlString];
NSURLRequest *urlRequest = [NSURLRequest requestWithURL:url];
NSData *urlData;
NSURLResponse *response;
urlData = [NSURLConnection sendSynchronousRequest:urlRequest returningResponse:&response error:nil];
NSString *results = [[NSString alloc] initWithData:urlData encoding:NSUTF8StringEncoding];
NSLog(#"%#",urlData);
And then how to parse that? I've got only something like:
2011-10-21 19:27:06.213 httptest[1674:207] <3c21444f 43545950 45206874 6d6c2050 55424c49 4320222d 2f2f5733 432f2f44 54442058 48544d4c
You are logging urlData (an NSData object) instead of results (the NSString). NSData objects are displayed in the output console as hex digit pairs. If you log 'results' you will see something like:
<!DOCTYPE http...
which is probably what you were expecting.
you have already converted the resulting data to a NSString
at first you have to define what that data is: XML- or JSON-String? or Binary-encoded stuff? and then you have to write your own parser or choose one you like.
I assume that your result is xml and lets just assume that you want to use the TBXML-Dom-Parser. then try:
NSString *results = [[NSString alloc] initWithData:urlData encoding:NSUTF8StringEncoding];
TBXML * tbxml = [TBXML tbxmlWithXmlString:result];
TBXMLElement *rootElement = tbxml.rootElement;
TBXMLElement *childELement = [TBXML childElementNamed:#"myChildTag" parentElement:rootElement]
..... //depends on how your xml looks like
I am getting a use of undeclared identifier error in my json but I am following the example from http://blog.zachwaugh.com/post/309924609/how-to-use-json-in-cocoaobjective-c
how do I fix this? Yes I am very new to objective-c \ ios :) Thanks
I am putting this code in my view based application in my viewcontroller.m file
The issue is with "SBJSON *parser = [[SBJSON alloc] init];"
// Create new SBJSON parser object
SBJSON *parser = [[SBJSON alloc] init];
// Prepare URL request to download statuses from Twitter
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:#"http://twitter.com/statuses/public_timeline.json"]];
// Perform request and get JSON back as a NSData object
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
// Get JSON as a NSString from NSData response
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];
// parse the JSON response into an object
// Here we're using NSArray since we're parsing an array of JSON status objects
NSArray *statuses = [parser objectWithString:json_string error:nil];
// Each element in statuses is a single status
// represented as a NSDictionary
for (NSDictionary *status in statuses)
{
// You can retrieve individual values using objectForKey on the status NSDictionary
// This will print the tweet and username to the console
NSLog(#"%# - %#", [status objectForKey:#"text"], [[status objectForKey:#"user"] objectForKey:#"screen_name"]);
}
Try changing the line to SBJsonParser *parser = [[SBJsonParser alloc] init];
Edit:
A way that can be easier is to use the NSString category that SBJSON provides:
NSArray *statuses = (NSArray *)[json_string JSONValue];