Use of undeclared identifier in json for iOS - iphone

Question

I am getting a use of undeclared identifier error in my json but I am following the example from http://blog.zachwaugh.com/post/309924609/how-to-use-json-in-cocoaobjective-c
how do I fix this? Yes I am very new to objective-c \ ios :) Thanks
I am putting this code in my view based application in my viewcontroller.m file
The issue is with "SBJSON *parser = [[SBJSON alloc] init];"
// Create new SBJSON parser object
SBJSON *parser = [[SBJSON alloc] init];
// Prepare URL request to download statuses from Twitter
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:#"http://twitter.com/statuses/public_timeline.json"]];
// Perform request and get JSON back as a NSData object
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
// Get JSON as a NSString from NSData response
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];
// parse the JSON response into an object
// Here we're using NSArray since we're parsing an array of JSON status objects
NSArray *statuses = [parser objectWithString:json_string error:nil];
// Each element in statuses is a single status
// represented as a NSDictionary
for (NSDictionary *status in statuses)
{
// You can retrieve individual values using objectForKey on the status NSDictionary
// This will print the tweet and username to the console
NSLog(#"%# - %#", [status objectForKey:#"text"], [[status objectForKey:#"user"] objectForKey:#"screen_name"]);
}

Answer 1

Try changing the line to SBJsonParser *parser = [[SBJsonParser alloc] init];
Edit:
A way that can be easier is to use the NSString category that SBJSON provides:
NSArray *statuses = (NSArray *)[json_string JSONValue];