I would like to ignore all case sensitivity to be ignored for my UITextField and UITextView. I would also like to know how to detect if the string is upperCase or lowerCase. Thanks.
[myString uppercaseString] will give you the myString variable transformed to use only uppercase letters, [myString lowercaseString] will give you the lowercase version, respectively.
You can use it to check for uppercase (lowercase) strings like this:
if ([[textField text] isEqualToString:[[textField text] uppercaseString]]) {
NSLog("String is uppercase!");
}
If you have a reference string and want to compare it ignoring the case, you can just use caseInsensitiveCompare: method of NSString:
[referenceString caseInsensitiveCompare:[textField text]];
Related
I'm trying to determine if a string is latin based or Japanese.
I've tried something like the following but it returns YES for Japanese strings as well:
NSCharacterSet *alphaSet = [NSCharacterSet alphanumericCharacterSet];
BOOL isAlpha = [[myStr stringByTrimmingCharactersInSet:alphaSet] isEqualToString:#""];
A string might be a word like "café" or something like "カフェ" or "喫茶店".
Use the canBeConvertedToEncoding: method. For example:
BOOL isLatin = [myString canBeConvertedToEncoding:NSISOLatin1StringEncoding];
Available encodings are here.
I am trying to remove quotes from something like:
"Hello"
so that the string is just:
Hello
Check out Apple's docs:
http://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/
You probably want:
stringByReplacingOccurrencesOfString:withString:
Returns a new string in which all occurrences of a target string in the receiver are replaced by another given string.
- (NSString *)stringByReplacingOccurrencesOfString:(NSString *)target withString:(NSString *)replacement
So, something like this should work:
newString = [myString stringByReplacingOccurrencesOfString:#"\"" withString:#""];
I only wanted to remove the first quote and the last quote, not the quotes within the string so here's what I did:
challengeKey = #"\"I want to \"remove\" the quotes.\"";
challengeKey = [challengeKey substringFromIndex:1];
challengeKey = [challengeKey substringToIndex:[challengeKey length] - 1];
Hope this helps others looking for the same thing. NSLog and you'll get this output:
I want to "remove" the quotes.
I'm trying to extract a string (which contains an integer) from an array and then use it as an int in a function. I'm trying to convert it to a int using intValue.
Here's the code I've been trying.
NSArray *_returnedArguments = [serverOutput componentsSeparatedByString:#":"];
[_appDelegate loggedIn:usernameField.text:passwordField.text:(int)[[_returnedArguments objectAtIndex:2] intValue]];
I get this error:
passing argument 3 of 'loggedIn:::' makes pointer from integer
without a cast
What's wrong?
I really don't know what was so hard about this question, but I managed to do it this way:
[myStringContainingInt intValue];
It should be noted that you can also do:
myStringContainingInt.intValue;
You can just convert the string like that [str intValue] or [str integerValue]
integerValue
Returns the NSInteger value of the receiver’s text.
(NSInteger)integerValue
Return Value
The NSInteger value of the receiver’s text, assuming a decimal representation and skipping whitespace at the beginning of the string. Returns 0 if the receiver doesn’t begin with a valid decimal text representation of a number.
for more information refer here
NSArray *_returnedArguments = [serverOutput componentsSeparatedByString:#":"];
_returnedArguments is an array of NSStrings which the UITextField text property is expecting. No need to convert.
Syntax error:
[_appDelegate loggedIn:usernameField.text:passwordField.text:(int)[[_returnedArguments objectAtIndex:2] intValue]];
If your _appDelegate has a passwordField property, then you can set the text using the following
[[_appDelegate passwordField] setText:[_returnedArguments objectAtIndex:2]];
Basically, the third parameter in loggedIn should not be an integer, it should be an object of some kind, but we can't know for sure because you did not name the parameters in the method call. Provide the method signature so we can see for sure. Perhaps it takes an NSNumber or something.
Keep in mind that international users may be using a decimal separator other than . in which case values can get mixed up or just become nil when using intValue on a string.
For example, in the UK 1.23 is written 1,23, so the number 1.777 would be input by user as 1,777, which, as .intValue, will be 1777 not 1 (truncated).
I've made a macro that will convert input text to an NSNumber based on a locale argument which can be nil (if nil it uses device current locale).
#define stringToNumber(__string, __nullable_locale) (\
(^NSNumber *(void){\
NSLocale *__locale = __nullable_locale;\
if (!__locale) {\
__locale = [NSLocale currentLocale];\
}\
NSString *__string_copy = [__string stringByReplacingOccurrencesOfString:__locale.groupingSeparator withString:#""];\
__string_copy = [__string_copy stringByReplacingOccurrencesOfString:__locale.decimalSeparator withString:#"."];\
return #([__string_copy doubleValue]);\
})()\
)
If I understood you correctly, you need to convert your NSString to int? Try this peace of code:
NSString *stringWithNumberInside = [_returnedArguments objectAtIndex:2];
int number;
sscanf([stringWithNumberInside UTF8String], "%x", &flags);
I am having an issue that I can't figure out.
I'm trying to run the rangeOfString method on a string, and I'm not sure how to determine if the string was not found. For example:
NSRange range = [#"abc" rangeOfString:#"d" options:NSCaseInsensitiveSearch range:NSMakeRange(0,3)];
Clearly, "d" is not contained in the string "abc." I'd like to be able to do this:
if(the range is empty since "d" is not in "abc")
//do something
What is the code for this?
Thanks!!
From the documentation of NSString
-[NSString rangeOfString]
Return Value
An NSRange structure giving the
location and length in the receiver of
the first occurrence of aString.
Returns {NSNotFound, 0} if aString is
not found or is empty (#"").
So it looks like:
if ([#"abc" rangeOfString:#"d"].location == NSNotFound){
//Do something
Is the Apple-approved way.
EDIT:
I made a really bad typo, fixed it, thanks Kalle.
Check the length of the range. If it's non-zero, it was found.
I have a string value where it contains comma. Ex:- 1,234. I want to get the value of the string where i need only 1234. Can you please help me...
Instead of manually stripping out the commas, it might be more elegant (and less error-prone if you support different locales) to use an NSNumberFormatter to convert the string to a number.
NSString *myString = "1,234";
NSString *resultString = [myString stringByReplacingOccurrencesOfString:#"," withString:#""];
If you want to strip the comma then: -
NSString *string = #"1,234";
string = [string stringByReplacingOccurrencesOfString:#"," withString:#""];
This should return you a string with just 1234 in it.
By 'getting the value' do you mean, converting this to a NSNumber object? If so use this
NSNumber *numberFromString = [NSNumber numberWithInteger:[string integerValue]];
I don't know that framework/language, but if an integer converter won't work, then strip out the commas by replacing them with null from the string and then convert to an integer.