is there a simple way to remove the extra spaces in a string? ie like...
NSString *str = #"this string has extra empty spaces";
result should be:
NSString *str = #"this string has extra empty spaces";
Thanks!
replace all double space with a single space until there are no more double spaces in your string.
- (NSString *)stripDoubleSpaceFrom:(NSString *)str {
while ([str rangeOfString:#" "].location != NSNotFound) {
str = [str stringByReplacingOccurrencesOfString:#" " withString:#" "];
}
return str;
}
Related
I have a huge amount of NSStrings in a database that get passed to a view controller in an iOS app. They are formatted as "This is a message with $specially formatted$ content".
However, I need to change the '$' at the start of the special formatting with a '[' and the '$' at the end with ']'. I have a feeling I can use an NSScanner but so far all of my attempts have produced wackily concatenated strings!
Is there a simple way to recognise a substring encapsulated by '$' and swap them out with start/end characters? Please note that a lot of the NSStrings have multiple '$' substrings.
Thanks!
You can use regular expressions:
NSMutableString *str = [#"Hello $World$, foo $bar$." mutableCopy];
NSRegularExpression *regex;
regex = [NSRegularExpression regularExpressionWithPattern:#"\\$([^$]*)\\$"
options:0
error:NULL];
[regex replaceMatchesInString:str
options:0
range:NSMakeRange(0, [str length])
withTemplate:#"[$1]"];
NSLog(#"%#", str);
// Output:
// Hello [World], foo [bar].
The pattern #"\\$([^$]*)\\$" searches for
$<zero_or_more_characters_which_are_not_a_dollarsign>$
and all occurrences are then replaced by [...]. The pattern contains so many backslashes because the $ must be escaped in the regular expression pattern.
There is also stringByReplacingMatchesInString if you want to create a new string instead of modifying the original string.
I think replaceOccurrencesOfString: won't work cause you have start$ and end$.
But if you seperate the Strings with [string componentsSeperatedByString:#"$"] you get an Array of substrings, so every second string is your "$specially formatted$"-string
This should work!
NSString *str = #"This is a message with $specially formatted$ content";
NSString *original = #"$";
NSString *replacement1 = #"[";
NSString *replacement2 = #"]";
BOOL start = YES;
NSRange rOriginal = [str rangeOfString: original];
while (NSNotFound != rOriginal.location) {
str = [str stringByReplacingCharactersInRange: rOriginal withString:(start?replacement1:replacement2)];
start = !start;
rOriginal = [str rangeOfString: original];
}
NSLog(#"%#", str);
Enjoy Programming!
// string = #"This is a $special markup$ sentence."
NSArray *components = [string componentsSeparatedByString:#"$"];
// sanity checks
if (components.count < 2) return; // maybe no $ characters found
if (components.count % 2) return; // not an even number of $s
NSMutableString *out = [NSMutableString string];
for (int i=0; i< components.count; i++) {
[out appendString:components[i]];
[out appendString: (i % 2) ? #"]" : #"[" ];
}
// out = #"This is a [special markup] sentence."
Try this one
NSMutableString *string=[[NSMutableString alloc]initWithString:#"This is a message with $specially formatted$ content. This is a message with $specially formatted$ content"];
NSMutableString *string=[[NSMutableString alloc]initWithString:#"This is a message with $specially formatted$ content. This is a message with $specially formatted$ content"];
BOOL open=YES;
for (NSUInteger i=0; i<[string length];i++) {
if ([string characterAtIndex:i]=='$') {
if (open) {
[string replaceCharactersInRange:NSMakeRange(i, 1) withString:#"["];
open=!open;
}
else{
[string replaceCharactersInRange:NSMakeRange(i, 1) withString:#"]"];
open=!open;
}
}
}
NSLog(#"-->%#",string);
Output:
-->This is a message with [specially formatted] content. This is a message with [specially formatted] content
i have an UITextField which is allowing space
using the following code snippet it trims all the white space from the string (Text Field Text)
NSCharacterSet *whitespace = [NSCharacterSet whitespaceAndNewlineCharacterSet];
NSString *trimmed = [rawString stringByTrimmingCharactersInSet:whitespace];
but i want to trim only the starting space of the Text that means
Example: #" SAMPLE TEXT"= #"SAMPLE TEXT"
can any one help me how to achieve this
First find the first character that is not a whitespace or newline. Then create a substring from that character's location and onwards.
NSString *justLeaveAPonyTail = #" Bla bla bla ";
NSCharacterSet *allExceptWhitespace = [[NSCharacterSet whitespaceAndNewlineCharacterSet] invertedSet];
NSRange range = [justLeaveAPonyTail rangeOfCharacterFromSet:allExceptWhitespace];
if (range.location != NSNotFound)
{
justLeaveAPonyTail = [justLeaveAPonyTail substringFromIndex:range.location];
}
// justLeaveAPonyTail is now #"Bla bla bla "
NSString *str = #" SAMPLE TEXT";
NSString *newStr = [str substringFromIndex:1];
Try this:
NSString *String = #" SAMPLE TEXT";
NSString *firstLetter = [String substringToIndex:0];
if ([firstLetter isEqualToString:#" "])
String = [String stringByReplacingCharactersInRange:NSMakeRange(0, 1) withString:#""];
I have a string NSString *Original=#"88) 12-sep-2012"; or Original=#"8) blablabla";
I want to print only the characters before the ")" so how to find the index of the character ")". or how could i do it?
Thanks in advance.
To print the characters before the first right paren, you can do this:
NSString *str = [[yourString componentsSeparatedByString:#")"] objectAtIndex:0];
NSLog(#"%#", str);
// If you need the character index:
NSUInteger index = str.length;
U can find index of the character ")" like this:
NSString *Original=#"88) 12-sep-2012";
NSRange range = [Original rangeOfString:#")"];
if(range.location != NSNotFound)
{
NSString *result = [Original substringWithRange:NSMakeRange(0, range.location)];
}
You can use the following code to see the characters before ")"
// this would split the string into values which would be stored in an array
NSArray *splitStringArray = [yourString componentsSeparatedByString:#")"];
// this would display the characters before the character ")"
NSLog(#"%#", [splitStringArray objectAtIndex:0]);
NSUInteger index = [Original rangeOfString:#")"];
NSString *result = [Original substringWithRange:NSMakeRange(0, index)];
try the below code to get the index of a particular character in a string:-
NSString *string = #"88) 12-sep-2012";
NSCharacterSet *charSet = [NSCharacterSet characterSetWithCharactersInString:#")"];
NSRange range = [string rangeOfCharacterFromSet:charSet];
if (range.location == NSNotFound)
{
// ... oops
}
else {
NSLog(#"---%d", range.location);
// range.location is the index of character )
}
and to get the string before the ) character use this:-
NSString *str = [[string componentsSeparatedByString:#")"] objectAtIndex:0];
Another soluation:
NSString *Original=#"88) 12-sep-2012";
NSRange range = [Original rangeOfString:#")"];
NSString *result = Original;
if (range.location != NSNotFound)
{
result = [Original substringToIndex:range.location];
}
NSLog(#"Result: %#", result);
How to detect if UISearchBar contains only blank spaces not any other character or string and replace it with #""?
You can trim the string with a character set containing whitespace using the NSString stringByTrimmingCharactersInSet message (using the whitespaceCharacterSet):
NSString * searchString = [searchBar.text stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
if (![searchString length])
// return ... search bar was just whitespace
You can check as
[yourSearchBar.text isEqualToString:#""]
Hope it helps.
if([searchBar.text isEqualToString:#""] && [searchBar.text length] ==0){
// Blank Space in searchbar
else{
// Do Search
}
Use isEqualToString method of NSString
Use stringByTrimmingCharactersInSet to trim the character from NSString.
- (NSString *)stringByTrimmingCharactersInSet:(NSCharacterSet *)set
Use as below.
NSString* myString = mySearchBar.text
myString = [myString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
Here's how you detect and replace it: (assuming the UISearchField is called searchBar)
NSString*replacement;
if ([searchBar.text isEqualToString:#" "])
{
replacement = [NSString stringByReplacingOccurancesOfString:#" " withString:#""];
}
searchBar.text = replacement;
Have a look in the Apple Documentation for NSString for more.
Edit:
If you have more than once space, do this:
NSString *s = [someString stringByReplacingOccurrencesOfString:#" "
withString:#""
options:NSRegularExpressionSearch
range:NSMakeRange(0, [someString length])
];
searchBar.text = s;
This worked for me: if you are using #"" or length already to control say a button then this version really does detect the whitespace, if a space has been entered...
if([activeField.text isEqualToString:#" "] && [activeField.text length] ==1){
// Blank Space in searchbar
{
// an alert example
}
I have an NSString *str, having value #"I like Programming and gaming."
I have to remove "I" "like" & "and" from my string so it should look like as "Programming gaming"
How can I do this, any Idea?
NSString *newString = #"I like Programming and gaming.";
NSString *newString1 = [newString stringByReplacingOccurrencesOfString:#"I" withString:#""];
NSString *newString12 = [newString1 stringByReplacingOccurrencesOfString:#"like" withString:#""];
NSString *final = [newString12 stringByReplacingOccurrencesOfString:#"and" withString:#""];
Assigned to wrong string variable edited now it is fine
NSLog(#"%#",final);
output : Programming gaming
NSString * newString = [#"I like Programming and gaming." stringByReplacingOccurrencesOfString:#"I" withString:#""];
newString = [newString stringByReplacingOccurrencesOfString:#"like" withString:#""];
newString = [newString stringByReplacingOccurrencesOfString:#"and" withString:#""];
NSLog(#"%#", newString);
More efficient and maintainable than doing a bunch of stringByReplacing... calls in series:
NSSet* badWords = [NSSet setWithObjects:#"I", #"like", #"and", nil];
NSString* str = #"I like Programming and gaming.";
NSString* result = nil;
NSArray* parts = [str componentsSeparatedByString:#" "];
for (NSString* part in parts) {
if (! [badWords containsObject: part]) {
if (! result) {
//initialize result
result = part;
}
else {
//append to the result
result = [NSString stringWithFormat:#"%# %#", result, part];
}
}
}
It is an old question, but I'd like to show my solution:
NSArray* badWords = #[#"the", #"in", #"and", #"&",#"by"];
NSMutableString* mString = [NSMutableString stringWithString:str];
for (NSString* string in badWords) {
mString = [[mString stringByReplacingOccurrencesOfString:string withString:#""] mutableCopy];
}
return [NSString stringWithString:mString];
Make a mutable copy of your string (or initialize it as NSMutableString) and then use replaceOccurrencesOfString:withString:options:range: to replace a given string with #"" (empty string).