Find the index of a character in a string - iphone

I have a string NSString *Original=#"88) 12-sep-2012"; or Original=#"8) blablabla";
I want to print only the characters before the ")" so how to find the index of the character ")". or how could i do it?
Thanks in advance.

To print the characters before the first right paren, you can do this:
NSString *str = [[yourString componentsSeparatedByString:#")"] objectAtIndex:0];
NSLog(#"%#", str);
// If you need the character index:
NSUInteger index = str.length;

U can find index of the character ")" like this:
NSString *Original=#"88) 12-sep-2012";
NSRange range = [Original rangeOfString:#")"];
if(range.location != NSNotFound)
{
NSString *result = [Original substringWithRange:NSMakeRange(0, range.location)];
}

You can use the following code to see the characters before ")"
// this would split the string into values which would be stored in an array
NSArray *splitStringArray = [yourString componentsSeparatedByString:#")"];
// this would display the characters before the character ")"
NSLog(#"%#", [splitStringArray objectAtIndex:0]);

NSUInteger index = [Original rangeOfString:#")"];
NSString *result = [Original substringWithRange:NSMakeRange(0, index)];

try the below code to get the index of a particular character in a string:-
NSString *string = #"88) 12-sep-2012";
NSCharacterSet *charSet = [NSCharacterSet characterSetWithCharactersInString:#")"];
NSRange range = [string rangeOfCharacterFromSet:charSet];
if (range.location == NSNotFound)
{
// ... oops
}
else {
NSLog(#"---%d", range.location);
// range.location is the index of character )
}
and to get the string before the ) character use this:-
NSString *str = [[string componentsSeparatedByString:#")"] objectAtIndex:0];

Another soluation:
NSString *Original=#"88) 12-sep-2012";
NSRange range = [Original rangeOfString:#")"];
NSString *result = Original;
if (range.location != NSNotFound)
{
result = [Original substringToIndex:range.location];
}
NSLog(#"Result: %#", result);

Related

How to remove starting 0's in uitextfield text in iphone sdk

Code Snippet:
NSString *tempStr = self.consumerNumber.text;
if ([tempStr hasPrefix:#"0"] && [tempStr length] > 1) {
tempStr = [tempStr substringFromIndex:1];
[self.consumerNumbers addObject:tempStr];>
}
I tried those things and removing only one zero. how to remove more then one zero
Output :001600240321
Expected result :1600240321
Any help really appreciated
Thanks in advance !!!!!
Try to use this one
NSString *stringWithZeroes = #"001600240321";
NSString *cleanedString = [stringWithZeroes stringByReplacingOccurrencesOfString:#"^0+" withString:#"" options:NSRegularExpressionSearch range:NSMakeRange(0, stringWithZeroes.length)];
NSLog(#"Clean String %#",cleanedString);
Clean String 1600240321
convert string to int value and re-assign that value to string,
NSString *cleanString = [NSString stringWithFormat:#"%d", [string intValue]];
o/p:-1600240321
You can add a recursive function that is called until the string begin by something else than a 0 :
-(NSString*)removeZerosFromString:(NSString *)anyString
{
if ([anyString hasPrefix:#"0"] && [anyString length] > 1)
{
return [self removeZerosFromString:[anyString substringFromIndex:1]];
}
else
return anyString;
}
so you just call in your case :
NSString *tempStr = [self removeZerosFromString:#"000903123981000"];
NSString *str = #"001600240321";
NSString *newStr = [#([str integerValue]) stringValue];
If the NSString contains numbers only.
Other wise use this:
-(NSString *)stringByRemovingStartingZeros:(NSString *)string
{
NSString *newString = string;
NSInteger count = 0;
for(int i=0; i<[string length]; i++)
{
if([[NSString stringWithFormat:#"%c",[string characterAtIndex:i]] isEqualToString:#"0"])
{
newString = [newString stringByReplacingCharactersInRange:NSMakeRange(i-count, 1) withString:#""];
count++;
}
else
{
break;
}
}
return newString;
}
Simply call this method:-
NSString *stringWithZeroes = #"0000000016909tthghfghf";
NSLog(#"%#", [self stringByRemovingStartingZeros:stringWithZeroes]);
OutPut: 16909tthghfghf
Try the `stringByReplacingOccurrencesOfString´ methode like this:
NSString *new = [old stringByReplacingOccurrencesOfString: #"0" withString:#""];
SORRY: This doesn't help you due to more "0" in the middle part of your string!

Substring after substring in NSString

I am new in objective and I'm facing my first problem, and I can not continue my first project.
it's quite simple, I have a NSString :
NSString *myString = #"<font face='Helvetica' size=25 color='#d79198'> Here is some text !</font>";
what I want to do is to get the value of the size "25" which is always 2 char long, so I can calculate my UILabel size.
i know how to detect if there is the substring I am looking for "size=" using :
if ([string rangeOfString:#"bla"].location == NSNotFound)
but I have not found or not understand how to extract the string #"size=XX" and then get the XX as a NSString from *myString
Thank for any help.
NSString *myString = #"<font face='Helvetica' size=25 color='#d79198'> Here is some text !</font>";
NSRange range = [myString rangeOfString:#"size="];
if (range.location != NSNotFound)
{
NSLog(#"Found \"size=\" at %d", range.location);
NSString *sizeString = [myString substringWithRange:NSMakeRange(range.location+5, 2)];
NSLog(#"sizeString: %#", sizeString);
}
This should do the trick. You could also at the end do this: int sizeFont = [sizeString intValue];
NSString *myString = #"<font face='Helvetica' size=25 color='#d79198'> Here is some text !</font>";
if ([myString rangeOfString:#"size"].location != NSNotFound)
{
myString = [myString substringFromIndex:[myString rangeOfString:#"size"].location];
myString = [myString substringToIndex:[myString rangeOfString:#" "].location]; // Now , myString ---> size=25 color='#d79198'> Here is some text !</font>
myString = [myString substringFromIndex:[myString length]-2];// Now, myString ---> size=25
NSLog(#"myString -- %#",myString); // Now, myString ---> 25
}
If you have string like stack:overflow then use it as follow :
NSString *Base=#"stack:overflow"
NSString *one = [[Base componentsSeparatedByString:#":"] objectAtIndex:0];
NSString *two = [[Base componentsSeparatedByString:#":"] objectAtIndex:1];
In this case one = stack and two=overflow
Part of an HTML page? Then use the tool that is designed for the task.
You could calculate the range of the number yourself or use a very simple regular expression to get the substring, something like
(?<=size\=)\d*
This means that you are searching for digits (\d*) that is preceded by "size=" ((?<=size\=))
Which using NSRegularExpression would be
NSError *error = NULL;
NSRegularExpression *regex =
[NSRegularExpression regularExpressionWithPattern:#"(?<=size\\=)\\d*"
options:0
error:&error];
NSTextCheckingResult *match =
[regex firstMatchInString:myString
options:0
range:NSMakeRange(0, [myString length])];
NSString *sizeText = [myString substringWithRange:match.range];
Finally you should convert the text "25" into a number using
NSInteger size = [sizeText integerValue];
Use componentsSeparatedByString: method...
NSString *myString = #"<font face='Helvetica' size=25 color='#d79198'> Here is some text !</font>";
NSString *theSizeString = [[[[myString componentsSeparatedByString:#" "] objectAtIndex:2] componentsSeparatedByString:#"="] objectAtIndex:1];
NSLog(#"The sizestring:%#",theSizeString);
I think it will be helpful to you.
You can get the range of the string #"size=". The range has location and length. So what you need next is to call on the myString the substringWithRange: method. The parameter would be an NSRage starting from the location+length of #"size=" and length of 2.

iphone remove next string - leave rest of string after particular occurrence of string

In objective c how to Remove text after a string occurrence.
for example i have to remove a text after occurrence of text 'good'
'iphone is good but..' here i have to remove the but text in the end so the text will be now 'iphone is good'
Try with below code
NSString *str_good = #"iphone is good but...";
NSRange range = [str_good rangeOfString:#"good"];
str_good = [str_good substringToIndex:range.location+range.length];
NSString * a = #"iphone is good but..";
NSRange match = [a rangeOfString:#"good"];
NSString * b = [a substringToIndex:match.location+match.length];
If you want to remove rest of the string after a particular occurrence of "but", you can get the range of "but" and trim the original string down
NSString * test = [NSString stringWithString:#"iphone is good but rest of string"];
NSRange range = [test rangeOfString:#"but"];
if (range.length > 0) {
NSString *adjusted = [test substringToIndex:range.location];
NSLog(#"result %#", adjusted);
}
EDIT
We can assume that the search does not want to cut of "butter is yellow", and can change the range to include " but"
NSRange range = [test rangeOfString:#" but"];
Try this:-
NSArray *array = [string componentsSeperatedBy:#"good"];
NSString *requiredString = [array objectAtIndex:0];
NSArray *array = [string componentsSeparatedByString:stringToSearch];
NSString *requiredString;
if ([array count] > 0) {
requiredString = [[array objectAtIndex:0] stringByAppendingString:stringToSearch];
}

NSString to NSArray

I want to split an NSString into an NSArray. For example, given:
NSString *myString=#"ABCDEF";
I want an NSArray like:
NSArray *myArray={A,B,C,D,E,F};
How to do this with Objective-C and Cocoa?
NSMutableArray *letterArray = [NSMutableArray array];
NSString *letters = #"ABCDEF𝍱क्";
[letters enumerateSubstringsInRange:NSMakeRange(0, [letters length])
options:(NSStringEnumerationByComposedCharacterSequences)
usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
[letterArray addObject:substring];
}];
for (NSString *i in letterArray){
NSLog(#"%#",i);
}
results in
A
B
C
D
E
F
𝍱
क्
enumerateSubstringsInRange:options:usingBlock: available for iOS 4+ can enumerate a string with different styles. One is called NSStringEnumerationByComposedCharacterSequences, what will enumerate letter by letter but is sensitive to surrogate pairs, base characters plus combining marks, Hangul jamo, and Indic consonant clusters, all referred as Composed Character
Note, that the accepted answer "swallows" 𝍱and breaks क् into क and ्.
Conversion
NSString * string = #"A B C D E F";
NSArray * array = [string componentsSeparatedByString:#" "];
//Notice that in this case I separated the objects by a space because that's the way they are separated in the string
Logging
NSLog(#"%#", array);
This is what the console returned
NSMutableArray *chars = [[NSMutableArray alloc] initWithCapacity:[theString length]];
for (int i=0; i < [theString length]; i++) {
NSString *ichar = [NSString stringWithFormat:#"%C", [theString characterAtIndex:i]];
[chars addObject:ichar];
}
This link contains examples to split a string into a array based on sub strings and also based on strings in a character set. I hope that post may help you.
here is the code snip
NSMutableArray *characters = [[NSMutableArray alloc] initWithCapacity:[myString length]];
for (int i=0; i < [myString length]; i++) {
NSString *ichar = [NSString stringWithFormat:#"%c", [myString characterAtIndex:i]];
[characters addObject:ichar];
}
Without loop you can use this:
NSString *myString = #"ABCDEF";
NSMutableString *tempStr =[[NSMutableString alloc] initWithString:myString];
if([myString length] != 0)
{
NSError *error = NULL;
// declare regular expression object
NSRegularExpression *regex =[NSRegularExpression regularExpressionWithPattern:#"(.)" options:NSMatchingReportCompletion error:&error];
// replace each match with matches character + <space> e.g. 'A' with 'A '
[regex replaceMatchesInString:tempStr options:NSMatchingReportCompletion range:NSMakeRange(0,[myString length]) withTemplate:#"$0 "];
// trim last <space> character
[tempStr replaceCharactersInRange:NSMakeRange([tempStr length] - 1, 1) withString:#""];
// split into array
NSArray * arr = [tempStr componentsSeparatedByString:#" "];
// print
NSLog(#"%#",arr);
}
This solution append space in front of each character with the help of regular expression and uses componentsSeparatedByString with <space> to return an array
Swift 4.2:
String to Array
let list = "Karin, Carrie, David"
let listItems = list.components(separatedBy: ", ")
Output : ["Karin", "Carrie", "David"]
Array to String
let list = ["Karin", "Carrie", "David"]
let listStr = list.joined(separator: ", ")
Output : "Karin, Carrie, David"
In Swift, this becomes very simple.
Swift 3:
myString.characters.map { String($0) }
Swift 4:
myString.map { String($0) }

NSXMLParser Encoded by Windows-1252

So NSXMLParser has problems parsing strings using the Windows-1252 encoder. Now I did find a solution on this page to convert it to NSUTF8StringEncoding. But now it bumps into characters it can't parse.
So I figured out that it will work if I would escape special characters and then transfer it back after parsing it. For example:
string = [string stringByReplacingOccurrencesOfString:#":" withString:#"__58__"];
Since it is allowed to use the _ character without getting a parser error and in NSXMLParser I can transfer the value back to it's proper character.
So is there a way I can loop through all ASCII character so I can replace all special characters (Except <, > and _ of course)?
Totally untested. I don't even know if it compiles, but it may get you on the right track. string needs to be an NSMutableString.
NSRange r = NSMakeRange(0, [string length]);
while (r.location < [string length])
{
r = [string rangeOfCharactersFromSet:[NSCharacterSet symbolCharacterSet] options:0 range:r];
if (r.location != NSNotFound)
{
NSMutableString *replacement = [[NSMutableString alloc] initWithCapacity:6];
for (NSUInteger i = r.location; i <= NSMaxRange(r); i++)
{
unichar c = [string characterAtIndex:i];
if (c != "_")
{
[replacement appendFormat:#"__%d__", (unsigned)c];
}
}
[string replaceCharactersInRange:r withString:replacement];
[replacement release]; replacement = nil;
r.location = r.location + [string length] + 1;
r.length = [string length] - r.location;
}
}
Assuming you have a NSMutableString str, you can do the following:
NSMutableString *str = ...;
[str replaceOccurrencesOfString:":" withString:#"__58__"
options:NSLiteralSearch
range:NSMakeRange(0, [str length])];
[str replaceOccurrencesOfString:"&" withString:#"__38__"
options:NSLiteralSearch
range:NSMakeRange(0, [str length])];
You see the pattern!
You can also just use XML entities for these values, e.g. replace & with &.
Thanks for the help everybody, this code actually solved my problem:
for (unichar asciiChar = 1; asciiChar <= 255; asciiChar++) {
NSString *stringWithAsciiChar = [NSString stringWithCharacters:&asciiChar length:1];
if (stringWithAsciiChar == nil) continue;
string = [string stringByReplacingOccurrencesOfString:stringWithAsciiChar withString:[NSString stringWithFormat:#"__%d__", asciiChar]];
}