i'm trying to build a function that will tell me the range of a string at an occurrence.
For example if I had the string "hello, hello, hello", I want to know the range of hello at it's, lets say, third occurrence.
I've tried building this simple function, but it doesn't work.
Note - the top functions were constructed at an earlier date and work fine.
Any help appreciated.
- (NSString *)stringByTrimmingString:(NSString *)stringToTrim toChar:(NSUInteger)toCharacterIndex {
if (toCharacterIndex > [stringToTrim length]) return #"";
NSString *devString = [[[NSString alloc] init] autorelease];
for (int i = 0; i <= toCharacterIndex; i++) {
devString = [NSString stringWithFormat:#"%#%#", devString, [NSString stringWithFormat:#"%c", [stringToTrim characterAtIndex:(i-1)]]];
}
return devString;
[devString release];
}
- (NSString *)stringByTrimmingString:(NSString *)stringToTrim fromChar:(NSUInteger)fromCharacterIndex {
if (fromCharacterIndex > [stringToTrim length]) return #"";
NSString *devString = [[[NSString alloc] init] autorelease];
for (int i = (fromCharacterIndex+1); i <= [stringToTrim length]; i++) {
devString = [NSString stringWithFormat:#"%#%#", devString, [NSString stringWithFormat:#"%c", [stringToTrim characterAtIndex:(i-1)]]];
}
return devString;
[devString release];
}
- (NSRange)rangeOfString:(NSString *)substring inString:(NSString *)string atOccurence:(int)occurence {
NSString *trimmedString = [inString copy]; //We start with the whole string.
NSUInteger len, loc, oldLength;
len = 0;
loc = 0;
NSRange tempRange = [string rangeOfString:substring];
len = tempRange.length;
loc = tempRange.location;
for (int i = 0; i != occurence; i++) {
NSUInteger endOfWord = len+loc;
trimmedString = [self stringByTrimmingString:trimmedString fromChar:endOfWord];
oldLength += [[self stringByTrimmingString:trimmedString toChar:endOfWord] length];
NSRange tmp = [trimmedString rangeOfString:substring];
len = tmp.length;
loc = tmp.location + oldLength;
}
NSRange returnRange = NSMakeRange(loc, len);
return returnRange;
}
Instead of trimming the string a bunch of times (slow), just use rangeOfString:options:range:, which searches only within the range passed as its third argument. See Apple's documentation.
So try:
- (NSRange)rangeOfString:(NSString *)substring
inString:(NSString *)string
atOccurence:(int)occurence
{
int currentOccurence = 0;
NSRange rangeToSearchWithin = NSMakeRange(0, string.length);
while (YES)
{
currentOccurence++;
NSRange searchResult = [string rangeOfString: substring
options: NULL
range: rangeToSearchWithin];
if (searchResult.location == NSNotFound)
{
return searchResult;
}
if (currentOccurence == occurence)
{
return searchResult;
}
int newLocationToStartAt = searchResult.location + searchResult.length;
rangeToSearchWithin = NSMakeRange(newLocationToStartAt, string.length - newLocationToStartAt);
}
}
You need to rework the whole code. While it may seem to work, it's poor coding and plain wrong, like permanently reassigning the same variable, initializing but reassigning one line later, releasing after returning (which will never work).
For your question: Just use rangeOfString:options:range:, and do this the appropriate number of times while just incrementing the starting point.
Related
Code Snippet:
NSString *tempStr = self.consumerNumber.text;
if ([tempStr hasPrefix:#"0"] && [tempStr length] > 1) {
tempStr = [tempStr substringFromIndex:1];
[self.consumerNumbers addObject:tempStr];>
}
I tried those things and removing only one zero. how to remove more then one zero
Output :001600240321
Expected result :1600240321
Any help really appreciated
Thanks in advance !!!!!
Try to use this one
NSString *stringWithZeroes = #"001600240321";
NSString *cleanedString = [stringWithZeroes stringByReplacingOccurrencesOfString:#"^0+" withString:#"" options:NSRegularExpressionSearch range:NSMakeRange(0, stringWithZeroes.length)];
NSLog(#"Clean String %#",cleanedString);
Clean String 1600240321
convert string to int value and re-assign that value to string,
NSString *cleanString = [NSString stringWithFormat:#"%d", [string intValue]];
o/p:-1600240321
You can add a recursive function that is called until the string begin by something else than a 0 :
-(NSString*)removeZerosFromString:(NSString *)anyString
{
if ([anyString hasPrefix:#"0"] && [anyString length] > 1)
{
return [self removeZerosFromString:[anyString substringFromIndex:1]];
}
else
return anyString;
}
so you just call in your case :
NSString *tempStr = [self removeZerosFromString:#"000903123981000"];
NSString *str = #"001600240321";
NSString *newStr = [#([str integerValue]) stringValue];
If the NSString contains numbers only.
Other wise use this:
-(NSString *)stringByRemovingStartingZeros:(NSString *)string
{
NSString *newString = string;
NSInteger count = 0;
for(int i=0; i<[string length]; i++)
{
if([[NSString stringWithFormat:#"%c",[string characterAtIndex:i]] isEqualToString:#"0"])
{
newString = [newString stringByReplacingCharactersInRange:NSMakeRange(i-count, 1) withString:#""];
count++;
}
else
{
break;
}
}
return newString;
}
Simply call this method:-
NSString *stringWithZeroes = #"0000000016909tthghfghf";
NSLog(#"%#", [self stringByRemovingStartingZeros:stringWithZeroes]);
OutPut: 16909tthghfghf
Try the `stringByReplacingOccurrencesOfString´ methode like this:
NSString *new = [old stringByReplacingOccurrencesOfString: #"0" withString:#""];
SORRY: This doesn't help you due to more "0" in the middle part of your string!
i am trying to convert my hex value to binary value , but i am facing little problem .
as i am new trying to learn my faults .
my code :
NSMutableString *str;
NSString *dd = #"192:168:1:2:0B:2:D:00";
NSCharacterSet *donotwant1 = [NSCharacterSet characterSetWithCharactersInString:#":""];
dd =[[dd componentsSeparatedByCharactersInSet:donotwant1] componentsJoinedByString:#" "];
NSMutableArray *array = [[dd componentsSeparatedByString:#" "] mutableCopy];
[array removeObjectAtIndex:0];
//NSLog(#"%#",array);
for (int j=0; j<[array count]; j++) {
NSScanner *scan = [NSScanner scannerWithString:[array objectAtIndex:j]];
unsigned int i=0;
if ([scan scanHexInt:&i]) {
// NSLog(#"numbner is %ustr", i);
}
NSInteger theNumber = i;
str = [NSMutableString string];
for(NSInteger numberCopy = theNumber; numberCopy > 0; numberCopy >>= 1) {
// Prepend "0" or "1", depending on the bit
[str insertString:((numberCopy & 1) ? #"1" : #"0") atIndex:0];
[array removeObjectAtIndex:j];
[array insertObject:str atIndex:j];
}
}
NSLog(#"Binary version: %#", array);
I'm getting
1,1100,11001111,1111,1111,11101111.....
in my code 0 values are eliminated . i want 8bits like(00000001,00001100.....) can any one tell me the reason
When the most significant bit is reached, your algorithm stops the conversion. Why not force the loop to always execute 8 times?
for (int numberCopy = theNumber, int i = 0; i < 8; numberCopy >>= 1, i++) {
// loop body here
}
By the way, here's a cleaner/shorter/simpler approach that doesn't involve highly superfluous copying and uses characters instead of string objects for hyper efficiency (just kidding, I'm all against micro-optimizations, but I feel like inserting an NSString before another one is unnecessary, especially if the number of bits is known and constant). This also assumes UTF-8 and exploits the fact that hexadecimal and binary representation have a very nice relationship, 16 being the 4th power of 2:
NSString *dd = #"01:0C:CF:0F:EF:AF:BD:00";
NSArray *bytes = [dd componentsSeparatedByString:#":"];
NSMutableArray *binaries = [NSMutableArray array];
NSString *lookup[256];
lookup['0'] = #"0000";
lookup['1'] = #"0001";
lookup['2'] = #"0010";
lookup['3'] = #"0011";
lookup['4'] = #"0100";
lookup['5'] = #"0101";
lookup['6'] = #"0110";
lookup['7'] = #"0111";
lookup['8'] = #"1000";
lookup['9'] = #"1001";
lookup['A'] = #"1010";
lookup['B'] = #"1011";
lookup['C'] = #"1100";
lookup['D'] = #"1101";
lookup['E'] = #"1110";
lookup['F'] = #"1111";
for (NSString *s in bytes) {
unichar n1 = [s characterAtIndex:0];
unichar n0 = [s characterAtIndex:1];
[binaries addObject:[lookup[n1] stringByAppendingString:lookup[n0]]];
}
NSLog(#"%#", binaries);
I am having a string like NSString *str = #"123".I want to fill the digits of this string into UIPickerView.But how to get the digits from this string?I added the following code
- (void)pickerView:(UIPickerView *)pickerView didSelectRow: (NSInteger)row inComponent:(NSInteger)component
{
int number = [str intValue];
if(component == 0)
{
}
else if(component == 1)
{
}
else
{
}
}
Please see this..
NSMutableArray *arrNumbers = [[NSMutableArray] alloc] initWithCapacity:[YOURSTRING length]];
for (i=0;i<[YOURSTRING length];i++)
{
unichaar ch = [YOURSTRING characterAtIndex:i];
NSLog(#"Processing charachter %c",ch);
// If you really want
[arrNumbers addObject:(id)ch];
}
Other solutions seem to be excessive, considering NSString is already an array of characters. More lightweight solution:
NSString *str = #"123";
for (int i = 0; i < [str length]; i++) {
int digit = [str characterAtIndex:i] - '0';
// do something with your digit
}
If you have it as a string you can just do
NSArray * digitStrings = [str componentsSeparatedByString:""];
And each element in the array would be a digit as a NSString.
not tested but you can give it a try, this is supposed to scan all numeric entries of your string.
-(NSArray*)getDigitsFromString:(NSString*)str{
NSMutableString *outpuString = [NSMutableString
stringWithCapacity:str.length];
NSScanner *scanner = [NSScanner scannerWithString:str];
NSCharacterSet *numbers = [NSCharacterSet
characterSetWithCharactersInString:#"0123456789"];
while ([scanner isAtEnd] == NO) {
NSString *buffer;
if ([scanner scanCharactersFromSet:numbers intoString:&buffer]) {
[outpuString appendString:buffer];
} else {
[scanner setScanLocation:([scanner scanLocation] + 1)];
}
}
NSArray * digitStr = [outpuString componentsSeparatedByString:#""];
return digitStr;
}
NSMutableArray * digit=[[NSMutableArray alloc]init];
NSString *string = #"123456";
for (int i=0;i<[string length]; i++) {
NSString * newString = [string substringWithRange:NSMakeRange(i, 1)];
[digit addObject:newString];
}
NSLog(#"String %# ", digit)
One more answer which addresses more the idea of the original question by solving the problem of separating an int into it's digits:
NSString *numberString = #"68243";
int result[numberString.length];
NSInteger number = [numberString integerValue];
int j = numberString.length - 1;
while (j >= 0)
{
int power = pow(10, j);
int rest = (number % power);
result[j] = (number - rest)/power;
number = rest;
j--;
}
I have a string:
He said "hello mate" yesterday.
I want to get an NSRange from the first quotation to the last quotation. So I tried something like this:
NSRange openingRange = [title rangeOfString:#"\""];
NSRange closingRange = [title rangeOfString:#"\""];
NSRange textRange = NSMakeRange(openingRange.location, closingRange.location+1 - openingRange.location);
But I'm not sure how to make it distinguish between the first quote and the second quote. How would I do this?
You could use a regular expression for this:
NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"([\"])(?:\\\\\\1|.)*?\\1" options:0 error:&error];
NSRange range = [regex rangeOfFirstMatchInString:myString options:0 range:NSRangeMake(0, [myString length]];
Don't forget to check for errors ;)
You can always use 'rangeOfString:options:range:' for the second one (starting after the 'location' of the first one).
Option 1
- (NSRange)rangeOfQuoteInString:(NSString *)str {
int firstMatch = [str rangeOfString:#"\""].location;
int secondMatch = [str rangeOfString:#"\"" options:0 range:NSMakeRange(firstMatch + 1, [str length] - firstMatch - 1)].location;
return NSMakeRange(firstMatch, secondMatch + 1 - firstMatch);
}
I hope this is right. Done on my phone at dinner. ;-)
One other thing, though, since range of string likely does a similar implementation, why not iterate the 'char' values in the string and look for matches #1 & #2? Could be as fast or faster.
Option 2
- (NSRange)rangeOfQuoteInString:(NSString *)str {
int firstMatch = -1;
int secondMatch = -1;
for (int i = 0; i < [str length]; i = i + 1) {
unichar c = [str characterAtIndex:i];
if (c == '"') {
if (firstMatch == -1) {
firstMatch = i;
} else {
secondMatch = i;
break;
}
}
}
if (firstMatch == -1 || secondMatch == -1) {
// No full quote was found
return NSMakeRange(NSNotFound, 0);
} else {
return NSMakeRange(firstMatch, secondMatch + 1 - firstMatch);
}
}
I have an array which contains strings like frame_10#3x.png , frame_5#3x.png,frame_19#3x.png etc.
So I want to sort this array according to the number after the underscore i.e. the correct sequence will be frame_5#3x.png,frame_10#3x.png,frame_19#3x.png.
I tried to use the following method but no result:
NSInteger firstNumSort(id str1, id str2, void *context) {
int num1 = [str1 integerValue];
int num2 = [str2 integerValue];
if (num1 < num2)
return NSOrderedAscending;
else if (num1 > num2)
return NSOrderedDescending;
return NSOrderedSame;
}
Please suggest how to do this sorting for array.
NSArray *sry_img = [[NSArray alloc] initWithObjects:#"frame_18#3x.png",#"frame_17#3x.png",#"frame_1222#3x.png",#"frame_10#3x.png",#"frame_3#3x.png",#"frame_4#3x.png",#"frame_4#3x.png",#"frame_1#3x.png",#"frame_4#3x.png",#"frame_4#3x.png",nil];
NSArray *sortedStrings = [sry_img sortedArrayUsingSelector:#selector(localizedStandardCompare:)];
NSLog(#"%#",sortedStrings);
Enjy .......
But
localizedStandardCompare:, added in 10.6, should be used whenever file names or other strings are presented in lists and tables where Finder-like sorting is appropriate. The exact behavior of this method may be tweaked in future releases, and will be different under different localizations, so clients should not depend on the exact sorting order of the strings.
you want to do something like:
NSArray *components1 = [str1 componentsSeparatedByString:#"_"];
NSArray *components2 = [str2 componentsSeparatedByString:#"_"];
NSString *number1String = [components1 objectAtIndex:([components1 count] - 1])];
NSString *number2String = [components2 objectAtIndex:([components2 count] - 1])];
return [number1String compare:number2String];
I am not sure if my solution is the best possible approach but it can solve your problem for the time being :) .
1) First I have written a function to get the numbers before # character in your string and then I implemented simple SELECTION SORT algo to sort the array using this functions.
- (NSString*)getSubStringForString:(NSString*)value {
// First we will cut the frame_ string
NSMutableString *trimmedString = [NSMutableString stringWithString:[value substringWithRange:NSMakeRange(6, [value length]-6)]];
// New String to contain the numbers
NSMutableString *newString = [[NSMutableString alloc] init];
for (int i = 0; i < [trimmedString length] ; i++) {
NSString *singleChar = [trimmedString substringWithRange:NSMakeRange(i, 1)];
if (![singleChar isEqualToString:#"#"]) {
[newString appendString:singleChar];
} else {
break;
}
}
return newString;
}
This is the selection Implementation of the algo for sorting. The main logic is in the for loop. You can copy the code in viewDidLoad method to test.
NSMutableArray *array = [[NSMutableArray alloc] initWithObjects:#"frame_10#3x.png",#"frame_5#3x.png",
#"frame_3#3x.png", #"frame_19#3x.png",
nil];
NSLog(#"Values before Sort: %#", array);
int iPos;
int iMin;
for (iPos = 0; iPos < [array count]; iPos++)
{
iMin = iPos;
for (int i = iPos+1; i < [array count]; i++)
{
if ([[self getSubStringForString:[array objectAtIndex:i]] intValue] >
[[self getSubStringForString:[array objectAtIndex:iMin]] intValue]) {
iMin = i;
}
}
if ( iMin != iPos )
{
NSString *tempValue = [array objectAtIndex:iPos];
[array replaceObjectAtIndex:iPos withObject:[array objectAtIndex:iMin]];
[array replaceObjectAtIndex:iMin withObject:tempValue];
}
}
NSLog(#"Sorted Values: %#", array);
I hope that it can atleast keep you going. :)
You can try this-
NSString *str1 = [[[[str1 componentsSeparatedByString:#"frame_"] objectAtIndex:1] componentsSeparatedByString:#"#3x.png"] objectAtIndex:0];
int num1 = [str1 integerValue];