how to get digits of a integer from NSString? - iphone

Question

I am having a string like NSString *str = #"123".I want to fill the digits of this string into UIPickerView.But how to get the digits from this string?I added the following code
- (void)pickerView:(UIPickerView *)pickerView didSelectRow: (NSInteger)row inComponent:(NSInteger)component
{
int number = [str intValue];
if(component == 0)
{
}
else if(component == 1)
{
}
else
{
}
}

Answer 1

Please see this..
NSMutableArray *arrNumbers = [[NSMutableArray] alloc] initWithCapacity:[YOURSTRING length]];
for (i=0;i<[YOURSTRING length];i++)
{
  unichaar ch = [YOURSTRING characterAtIndex:i];
  NSLog(#"Processing charachter %c",ch);
  // If you really want
  [arrNumbers addObject:(id)ch];
}

Answer 2

Other solutions seem to be excessive, considering NSString is already an array of characters. More lightweight solution:
NSString *str = #"123";
for (int i = 0; i < [str length]; i++) {
int digit = [str characterAtIndex:i] - '0';
// do something with your digit
}

Answer 3

If you have it as a string you can just do
NSArray * digitStrings = [str componentsSeparatedByString:""];
And each element in the array would be a digit as a NSString.

Answer 4

not tested but you can give it a try, this is supposed to scan all numeric entries of your string.
-(NSArray*)getDigitsFromString:(NSString*)str{
NSMutableString *outpuString = [NSMutableString
stringWithCapacity:str.length];
NSScanner *scanner = [NSScanner scannerWithString:str];
NSCharacterSet *numbers = [NSCharacterSet
characterSetWithCharactersInString:#"0123456789"];
while ([scanner isAtEnd] == NO) {
NSString *buffer;
if ([scanner scanCharactersFromSet:numbers intoString:&buffer]) {
[outpuString appendString:buffer];
} else {
[scanner setScanLocation:([scanner scanLocation] + 1)];
}
}
NSArray * digitStr = [outpuString componentsSeparatedByString:#""];
return digitStr;
}

Answer 5

NSMutableArray * digit=[[NSMutableArray alloc]init];
NSString *string = #"123456";
for (int i=0;i<[string length]; i++) {
NSString * newString = [string substringWithRange:NSMakeRange(i, 1)];
[digit addObject:newString];
}
NSLog(#"String %# ", digit)

Answer 6

One more answer which addresses more the idea of the original question by solving the problem of separating an int into it's digits:
NSString *numberString = #"68243";
int result[numberString.length];
NSInteger number = [numberString integerValue];
int j = numberString.length - 1;
while (j >= 0)
{
int power = pow(10, j);
int rest = (number % power);
result[j] = (number - rest)/power;
number = rest;
j--;
}