I have a one form tag inside my Index.aspx view. Index.aspx contains several partial views and using the same model to render them.
Now when any partial view is posting the form with submit button form is posted to OneActionMethod. But I want for some partial views to post form to OtherActionMethod.
How can I achieve this, without using action links, just with submit button in this particular patial view?
I`ve wrote the update in comments to this question. Answer is still not clear to me.
i believe a little javascript will get ur job done. u have to hook the submit event of the form and change the action attribute of the form. remember action is attribute of form not of a submit button. in jquery u can do something like
$("#myform").submit(function(){
if(isFirstSubmitButton){
$(this).attr(FirstAction);
}
else if(isSecondSubmitButton)
{
$(this).attr(SecondAction);
}
return true;
});
You sound like you are trying to program "WebForms" style in MVC.
Why do you have one big form enclosing all of your partials? Separate them into unique forms, and have each one post to it's appropriate action.
EDIT: With your further clarification, the only thing I can think of (aside from redesigning to use individual forms, which does lead to problems if they want to share data), is to post to a single action, and then route the request to a private member within the controller for ActionA or ActionB depending on a particular form element.
Related
I would like to know what is the best method to have an action return different views. Let's say you have a form for submitting data, but you want to choose the view depending on what data is submitted. I would prefer not using a redirection, since there is stuff I want to be displayed in the data that is posted.
An example of this would be to have an Edit form that displays a Details view when clicking on Save, but without using a redirection.
I know this could be done with a single view containing a conditional if statement to display this or that, but there are cases where I would prefer my views to stay simple without too much code in them. If the controller could just choose the view to display once the data is posted, this would be great.
There is an overload to the View() method that allows you to specify the name of the View you want to return.
return View("DetailsView", model);
You should be using the Post/Redirect/Get pattern. You can still "display stuff." You can pass an ID on the URI and look them up in the new GET or use TempData.
Attempting to circumvent Post/Redirect/Get is not a good solution. Among other things, it breaks the back button.
I`m using asp.net mvc 2.0 and trying to create reusable web site parts, that can be added at any page dynamically.
The problem I have is how to load a partial view with all related js and data? Ive tried the following ways to do that:
Use partial view and put all the js into it. In main view use render partial. But to initialize partial view I need to add model to current action method model to be able to make RenderPartial("MyPartialView", Model.PartialViewModel).
Also I do not have a place to put additional data I need to fill my form(like drop down lists values, some predefined values etc).
Use RenderAction, but it seems it have same problems as RenderPartial, except for I do not need to add anything to any other model.
Any other oprions are greatly appreciated.
As I understand it, RenderAction performs the full pipeline on the action, then renders the result - so what is rendered is the same as what you'd see if you'd browsed to the action.
I've used RenderAction to render 'widgets' throughout a site, but in my view they should be independent of the page rendering them, otherwise they're not really widgets and should be part of the rendering page's code instead. For instance, if there's a log in form, you will always take the user to a page that can process the information, no matter what page they are currently on, so this makes for a good widget. Other ways I've used it is to show a shopping basket or advertising. Neither of which are dependent on the page being shown.
Hope this helps a little!
I am new to grails and i got stuck with another issue.
I have two form's in my single GSP search.gsp and have two actions in my controller serach and results.
Now when i click on search button in one of my GSP file it takes me to search action which renders me search.gsp.At this time it should display me only first form in it. when i click results button in that form it will take me to results action.which has code line.
redirect(action:"search",params:[merchants:merchant,address:address])
this will take me back to search action but now i want to display 2nd form in search.gsp..
My problem is
how can i make search action once to run with out parameter's and once with parameter's?
how to determine in GSP from which action its been called?
with Advance thanks.
Depending on how different your forms are, you may want to consider having two separate GSP files (e.g., search.gsp and results.gsp). Use render(view:'action', model:[...]) to render a different view in the controller. This is often clearer that a single file with lots of conditionals.
Otherwise, you can find out the action using ${params.action}, so for example:
<g:if test="${params.action == 'search'}">
Text to show if the action is search
</g:if><g:else>
Text to show if the action is results
</g:else>
I would suggest you to separate your result page as template (_search.gsp), and render it from your result action. So that's how you will have different forms in different files.
By the way template is nothing but an ajax response, google it for detail about template in grails.
Is it possible to programatically disable form validation in MVC2?
I'm hoping there is some kind of command that I can put in a custom ActionMethodSelectorAttribute, making it possible to prefix ActionResults where I want form validation disabled.
The reason for this is that I have a form with multiple buttons, one button adds a new row to a child object of the model - which consequently creates a new row on the form.
This works fine, but validation is fired for the form each time "add" is pressed, and so the new fields flag up validation errors before the user has a chance to enter data.
I've found an alternative solution to this.
Rather than use multiple form buttons, I've used a custom html helper which produces a "Add" link.
This helper places the current Model in TempData and produces a Link to Add/{id}.
I'm not sure this is the cleanest solution, but it allows child elements to be added without validation firing. To tidy things up a bit, I specified the form as such:
Html.BeginForm(view, controller, new { id = Model.ID })
Is it possible to post the same form to different controllers?
Each page could be post only to form action url, but may be some how i may say to button to which url form should go?
e.g i have one form and two submit buttons, one button will post form to one controller/url (eg /action/view) anther button submit form to one to another controller/url (eg /action/anothervew).
You can definitely do this, use JQuery (or just javascript) to attach a function to the onclick event of the button(s). Then use that function to change the URL that the form posts to and then submit the form.
JQuery would be something like:
$('#button1').onclick(function(){ $(this).action = url1; $(document).submit();});
$('#button2').onclick(function(){ $(this).action = url2; $(document).submit();});
You will need to use javascript for this. When the button is clicked have the javascript modify the form's action property to the appropriate controller and then submit the form.
We've done this before using javascript, as mentioned in other answers, and that's probably the correct way to go. An alternative, however, is to post to a single controller method which contains logic to decide where to send the form data off to.
Effectively, you submit the form to the controller, and the resubmit that data based on the text or id of the button clicked using an if statement in the body of the controller action.