I have a spreadsheet that has quite a few tables and I wonder what would be the formula to lookup table name from cell in iWork Numbers? For example I have table with name TableA, inside of that table I want to put something like "=$B1" or whatever to get the name "January01" in it. Just typing it is not acceptable, cause those table names will change for multiple day of the month (we planning to have 30-31 tables in one spreadsheet and have 12 spreadsheets for number of months).
It is possible to use text in another cell to specify a sheet and/or table name in the cell or range address within a formula in another cell.
You can use the INDIRECT function.
"The INDIRECT function returns the contents of a cell or range
referenced by an address specified as a string value."
from the iWork Numbers function browser
Example:
Assume the cells in column A of a particular table contain the names of the sheets in the workbook.
In column B you could count the number of cells that contain the text 'equal' in column D of Table 1 in each sheet using:
=COUNTIF(INDIRECT($A2&"::Table 1::$D", 1),"=equal")
Here the sheet name is specified in column A so the formula can be used for the entire column without having to manually edit the formula to specify the sheet name.
According to this support forum entry that is not possible. Came across it as I was looking for a solution to the same problem.
This is a very old thread, but here is how to get the table name:
You need to use the REFERENCE.NAME function to get the name of the table (plus some extraneous info, that you get rid of by using the TEXTBEFORE function).
TEXTBEFORE(REFERENCE.NAME(SomeTableName::$A$1,1),":")
The entry "SomeTableName::$A$1" is a random cell reference (in this case cell A1) from the table whose name you are interested to get. During formula entry, you merely click on a cell of the table in question to generate this reference, and then lock cell column and row, as needed.
The parameter "1" following the cell reference tells the REFERENCE.NAME function to return the name of the table and the cell name. There is no option to return just the table name.
The TEXTBEFORE function truncates the returned string to everything before the first colon, returning just the table name.
Related
I have some samples I need to take.
In order to create a good identifier/serial number for the samples, I want it to be a product of its characteristics.
For example, if the sample was taken from India and the temperature was 40 degrees then I would click dropdowns in the form to create those two entries and then a serial number would be spat out in the form "Ind40".
Assuming that your form is bound to a table, you can create a calculated column in the table that concatenates the values from other columns into a single value.
For instance, create a new column and give it a name (for example, SerialNbr). Then for Data Type select "Calculated". An expression builder window will appear:
Enter the columns you'd like to concatenate and separate them with &. Here is an example of how the expression could look:
Left([Country],3) & [Temperature]
This expression takes the first 3 chars from the Country column and combines it with the value from Temperature column to create the value in column SerialNbr. The calculated column will automatically update when values are entered into the other fields. I'd also suggest adding another value to the calculated expression to help avoid duplicates, such as date/time of submission.
I have a problem with Tableau.
I have a Dataset with some rows and some columns. I want to write a IFELSE structure where
The IF condition is that the Value of special field(fixed by a row and a column) is equal to the header of a column (it is every time equal to one name(header) of the different columns).
So to summarize: one value is every time equal to the name of a column and to find the column shall be the if-structure
Does someone know if there is a function to call the name (header) of a column? I didn't find it
Here is an small example, in which the Calculated_function choose the right price according to the Barcode. Everything in the first raw, is the header_name of the column below. enter image description here
Best regards
Jonas
You can work like this.
I created a sample dataset as given by you
Step-1: Connected With data in tableau. Clicked all columns having price (4 here), pivoted them so that they look like this..
Step_2: Create calculated_field like this
if [Barcode] = [Barcode_c]
then [Price] END
Step3: Filtered out null values from calculatedField and got a view like this which can be tweaked as per liking.
I have a collection of addresses on one LibreOffice Calc sheet (7 columns, 1st name, 2nd street and so one) and want to create an invoice template on another sheet.
I know how to retrieve and transpose a known row - the solution on this other question explains that: Transpose column on one sheet to row on another, with linking
However, this does not seem to work if I use Data > Validity to fill the first cell in the address area (7 cells below each other).
What I am basically trying to accomplish is a dropdown in the first cell where I select the name and it automatically retrieves the address from the other sheet into the cells below.
Is this possible or am I overthinking here?
I suggest:
Name the data in your first column (eg CName)
Name your array of data (eg Clients)
Set the Source for Validity Criteria to CName
Assuming the validation is in A1, in A2 and copied down to suit:
=VLOOKUP(A$1,Clients,ROW()-0,0)
The -0 is not required if the validation is in Row1 but is where an offset should be made if not.
I have a collumn with this contend inside:
=sheet1.F8
=sheet1.F15
=sheet1.F22
Normally in the excel I select the three cells and pull down, excel understand the logic and the next cell above will be "sheet1.F29". But if I do this in Libreoffice it puts "sheet1.F11".
Do you have any idea of how to do this ? (I have several sheets like this logic and I'd like to use Libreoffice instead Excel).
I found a workaround and replying here:
It is setting the reference to “F11” because the first row contains a reference to F8 and the new entry is 3 rows beneath this i.e., the offset is based on the first cell of the selection, thus 8+3=11. A workaround is to use the addresses of the destination and combine this with the INDIRECT() function. For example, create a separate column with “Sheet1.F8”, “Sheet1.F15”, and Sheet1.F22” etc. Highlight and drag this column of values to obtain a column of correct address references. Then adjacent to this use (given “Sheet1.F8” in sheet 2 cell A1) =INDIRECT(A1) in B1. Now drag this down the B column to obtain the required values.
Is it possible to have add a row to an SSRS 2008 Matrix that spans all of the matrix's columns?
This crude diagram shows roughly what I'm looking for:
The basic idea is that each line item is a person, and each column is a field in a form for that person. The fields themselves are dynamic (and implemented as column groups on the matrix). Additional column groups are included to append non-dynamic form fields, like the time the record was entered and who entered it. Under each person's record is a comments field, which should span all of the form fields above it.
At the moment I have the matrix embedded in another tablix, with the name and fields in the matrix and the comments in the parent tablix. This works for the data (each instance of the matrix ends up being one row), but the header repeats too often (once per person) because it's attached to the matrix. The only thought I have as to how to fix this is to create another matrix in the parent tablix with the same grouping and use it to display the headers... But this will require quite a lot of manual synchronization to keep the two matrices the same.
Edit: The key problem here is making the second row span multiple column groups.
Here's what you can do:
Select the column grouping you want to add above and right click and select
Add Group... Parent Group...
Group the column by something that will not aggregate the data. You'll have to select a field from your dataset to group by so that it creates an overlapping column grouping.
Check the Add group header box
You should now see something similar to this:
Now you just need to move the Value1 field and it's header over under the new column to the right beyond the matrix dividers. Once that's done, simply delete the ungrouped column where you just copied Value1 from and be sure to select Delete columns only checkbox.
Your finished product should look like this:
It is possible - And the above answers are partial answers leaving out one key step: Merging the cells of the child row.
First, right click on your grouped row, then select Insert Row -> Inside Group - Below and you will get two rows with the cells aligning on the columns
Second, ctrl click all the cells in your new row (ie row without the data) then right click on one of the highlighted cells, and then select Merge Cells.
Now you have the table you like. To add a value to the new row: first right click your new (multi column) cell,select Create Placeholder, and then add the dataset item you desire to the placeholder.
[Edit]
After several attempts, I'm going to say this isn't possible in SSRS. The best I could come up with is a group footer that spans columns 1,2, and 3, but not the User column.
[Original Response]
I recently did something similar to this.
First, what tool are you using to create SSRS reports? (I used SQL Server Business Intelligence Development Studio)
You'll want to create a row group (grouped on Person)
Append a row to your table in "Design" view (Right click, "Insert Row --> Inside Group - Below").
Add an expression to the row that pulls the value for your "Comment" column (=Fields!Comment.Value).
Let me know if that helps...
Try adding in you column group "header" with a grouping expression of (1=1). Then a detail field will need to be defined. If you define the other group with correct data then the "header" will stretch across all details columns. You may need to merger depending on other options.
The easiest way to do this is to create a Tablix with only one column, and your row grouping.
Then, you create two rows inside this group.
In the first row inside the group, you insert a Matrix, wich you can then subgroup as you prefer.
I just had a similar problem, and this was my solution.
I banged my head against the wall for a lot of time, until i realized the solution to my problem wasn't "making a cell span multiple column groups", but "making a cell split into multiple column groups".
You can accomplish the goal by using a subreport for each person. The subreport will receive the employee id and create the hierarchy for you. Make sure your subreport column widths match the widths of the parent report.