i want to trim an output of wipe command with sed.
i try to use this one:
wipe -vx7 /dev/sdb 2>&1 | sed -u 's/.*\ \([0-9]\+\).*/\1/g'
but it don't work for some reason.
when i use echo & sed to print the output of wipe command it works!
echo "/dev/sdb: 10%" | sed -u 's/.*\ \([0-9]\+\).*/\1/g'
what i'm doing wrong?
Thanks!
That looks like a progress indicator. They are often output directly to the tty instead of to stdout or stderr. You may be able to use the expect script called unbuffer (source) or some other method to create a pseudo tty. Be aware that there will probably be more junk such as \r, etc., that you may need to filter out.
Demonstration:
$ cat foo
#!/bin/sh
echo hello > /dev/tty
$ a=$(./foo)
hello
$ echo $a
$ a=$(unbuffer ./foo)
$ echo $a
hello
Related
First let me explain that I have very little expertise with bash scripting. I only use it for very simple applications.
My script is used to generate a grep command.
I use the echo command as an interim debug tool. I figure that if I can get the echo command to show the command I want to execute, all I have to do is remove the echo and the quotes and the command inside the echo should do what I want.
Here is my script (called grepper3.sh). Again, I am not an expert at this:
#!/bin/bash
echo "what should I grep?"
read this
echo "grep -Ri \"$this\" > \"$this\""
Here is what happens when I execute:
master#master-Latitude-E6440:~$ ./grepper3.sh
what should I grep?
all that
grep -Ri "all that" > "all that"
The grep command being echoed by the code is exactly what I want. But when I remove the echo and the surrounding double quotes:
was: echo "grep -Ri \"$this\" > \"$this\""
changed to: grep -Ri \"$this\" > \"$this\"
I get this:
master#master-Latitude-E6440:~$ ./grepper3.sh
what should I grep?
all that
./grepper3.sh: line 5: \"$this\": ambiguous redirect
I'm guessing that there is a simple fix, but I can't figure it out.
You can add . to recursive search.
#!/bin/bash
echo "what should I grep?"
read this
grep -Ri $this > $this .
All you need to to is to change the quotation marks to backticks.
Your new code would be:
#!/bin/bash
echo "what should I grep?"
read this
echo `grep -Ri \"$this\" > \"$this\"`
Here is what I finally got to work. Thanks for all of your help!
#!/bin/bash
echo "what should I grep?"
read this
DEST="/home/master/results/$this"
grep -Ri "$this" > "$DEST"
I have the following sed command:
sed -i -E "s/\{\{(.*)\}\}/$(echo "$\1")/g" test.conf
In test.conf, I have this:
this is a {{TEST}}
and this is an {{ANSWER}} here.
And I have the follow environment variables set:
export TEST=1234
export ANSWER=5678
When I run the sed command, I end up with this result:
this is a $TEST
and this is an $ANSWER here.
I want 1234 and 5678 there respectively. Is there a reason the echo command is interpreting things literally?
Backreferences are used internally by a single sed command. The echo has no idea about sed backreferences and would have been invoked by the shell before the sed command has even run so the $(echo "$\1") is outputing $\1 so
sed -i -E "s/\{\{(.*)\}\}/$(echo "$\1")/g" test.conf
is really:
sed -i -E "s/\{\{(.*)\}\}/$\1/g" test.conf
hence the output you are seeing.
Anyway, sed is for simple subsitutions on individual lines, for anything else you should be using awk:
$ export TEST=1234 ANSWER=5678
$ awk 'match($0,/(.*)\{\{(.*)\}\}(.*)/,a){$0=a[1] ENVIRON[a[2]] a[3]} 1' file
this is a 1234
and this is an 5678 here.
The above uses GNU awk for the 3rd arg to match(), with other awks it'd be:
$ awk 'match($0,/\{\{(.*)\}\}/){$0=substr($0,1,RSTART-1) ENVIRON[substr($0,RSTART+2,RLENGTH-4)] substr($0,RSTART+RLENGTH)} 1' file
this is a 1234
and this is an 5678 here.
If anyone suggests running eval or similar on the sed output - don't do it (google eval is evil and friends), just use the awk command above for simple string operations.
You can use perl which conveniently has a %ENV hash variable, see perldoc for more info
perl -pe 's/\{\{(.*)\}\}/$ENV{$1}/' test.conf
I can use the command to devices id from /var/log/20140522.device.log.
Here is my command.
for i in `cat /var/log/20140522.device.log`; do echo ---$i; done
Now I want to make it by daily cron job, but it is not working.
for i in `cat /var/log/`/bin/date +%Y%m%d`.device.log`; do echo ---$i; done
Is it possible to put cat and date in one line?
Yes; you can use cat and date on the same line using command substution.
for file in $(cat /var/log/$(date +'%Y%m%d').device.log); do echo ----$file; done
Using the $(…) notation makes that nested operation much simpler than the back-tick notation:
for file in `cat /var/log/\`date +'%Y%m%d'\`.device.log`; do echo ----$file; done
You don't have to think as hard about where backslash escapes are needed.
Also, in Bash, you can avoid the use of cat with:
for file in $(</var/log/$(date +'%Y%m%d').device.log); do echo ----$file; done
A $ character need to be added as follows:
for i in `cat "/var/log/$(date +"%Y%m%d").device.log"`
I need to replace several URLs in a text file with some content dependent on the URL itself. Let's say for simplicity it's the first line of the document at the URL.
What I'm trying is this:
sed "s/^URL=\(.*\)/TITLE=$(curl -s \1 | head -n 1)/" file.txt
This doesn't work, since \1 is not set. However, the shell is getting called. Can I somehow push the sed match variables to that subprocess?
The accept answer is just plain wrong. Proof:
Make an executable script foo.sh:
#! /bin/bash
echo $* 1>&2
Now run it:
$ echo foo | sed -e "s/\\(foo\\)/$(./foo.sh \\1)/"
\1
$
The $(...) is expanded before sed is run.
So you are trying to call an external command from inside the replacement pattern of a sed substitution. I dont' think it can be done, the $... inside a pattern just allows you to use an already existent (constant) shell variable.
I'd go with Perl, see the /e option in the search-replace operator (s/.../.../e).
UPDATE: I was wrong, sed plays nicely with the shell, and it allows you do to that. But, then, the backlash in \1 should be escaped. Try instead:
sed "s/^URL=\(.*\)/TITLE=$(curl -s \\1 | head -n 1)/" file.txt
Try this:
sed "s/^URL=\(.*\)/\1/" file.txt | while read url; do sed "s#URL=\($url\)#TITLE=$(curl -s $url | head -n 1)#" file.txt; done
If there are duplicate URLs in the original file, then there will be n^2 of them in the output. The # as a delimiter depends on the URLs not including that character.
Late reply, but making sure people don't get thrown off by the answers here -- this can be done in gnu sed using the e command. The following, for example, decrements a number at the beginning of a line:
echo "444 foo" | sed "s/\([0-9]*\)\(.*\)/expr \1 - 1 | tr -d '\n'; echo \"\2\";/e"
will produce:
443 foo
I have a file that contains this kind of paths:
C:\bad\foo.c
C:\good\foo.c
C:\good\bar\foo.c
C:\good\bar\[variable subdir count]\foo.c
And I would like to get the following file:
C:\bad\foo.c
C:/good/foo.c
C:/good/bar/foo.c
C:/good/bar/[variable subdir count]/foo.c
Note that the non matching path should not be modified.
I know how to do this with sed for a fixed number of subdir, but a variable number is giving me trouble. Actually, I would have to use many s/x/y/ expressions (as many as the max depth... not very elegant).
May be with awk, but this kind of magic is beyond my skills.
FYI, I need this trick to correct some gcov binary files on a cygwin platform.
I am dealing with binary files; therefore, I might have the following kind of data:
bindata\bindata%bindataC:\good\foo.c
which should be translated as:
bindata\bindata%bindataC:/good/foo.c
The first \ must not be translated, despite that it is on the same line.
However, I have just checked my .gcno files while editing this text and it looks like all the paths are flanked with zeros, so most of the answers below should fit.
sed -e '/^C:\\good/ s/\\/\//g' input_file.txt
I would recommend you look into the cygpath utility, which converts path names from one format to another. For instance on my machine:
$ cygpath `pwd`
/home/jericson
$ cygpath -w `pwd`
D:\root\home\jericson
$ cygpath -m `pwd`
D:/root/home/jericson
Here's a Perl implementation of what you asked for:
$ echo 'C:\bad\foo.c
C:\good\foo.c
C:\good\bar\foo.c
C:\good\bar\[variable subdir count]\foo.c' | perl -pe 's|\\|/|g if /good/'
C:\bad\foo.c
C:/good/foo.c
C:/good/bar/foo.c
C:/good/bar/[variable subdir count]/foo.c
It works directly with the string, so it will work anywhere. You could combine it with cygpath, but it only works on machines that have that path:
perl -pe '$_ = `cygpath -m $_` if /good/'
(Since I don't have C:\good on my machine, I get output like C:goodfoo.c. If you use a real path on your machine, it ought to work correctly.)
You want to substitute '/' for all '\' but only on the lines that match the good directory path. Both sed and awk will let you do this by having a LHS (matching) expression that only picks the lines with the right path.
A trivial sed script to do this would look like:
/[Cc]:\\good/ s/\\/\//g
For a file:
c:\bad\foo
c:\bad\foo\bar
c:\good\foo
c:\good\foo\bar
You will get the output below:
c:\bad\foo
c:\bad\foo\bar
c:/good/foo
c:/good/foo/bar
Here's how I would do it in awk:
# fixpaths.awk
/C:\\good/ {
gsub(/\\/,"/",$1);
print $1 >> outfile;
}
Then run it using the command:
awk -f fixpaths.awk paths.txt; mv outfile paths.txt
Or with some help from good ol' Bash:
#!/bin/bash
cat file | while read LINE
do
if <bad_condition>
then
echo "$LINE" >> newfile
else
echo "$LINE" | sed -e "s/\\/\//g" >> newfile
fi
done
try this
sed -re '/\\good\\/ s/\\/\//g' temp.txt
or this
awk -F"\\" '{if($2=="good"){OFS="\/"; $1=$1;} print $0}' temp.txt