If I'm asked to plot a function S with "level lines" abs(S) = 0:0.1:1, how do I do that?
I looked up the solution:
[X,Y] = meshgrid(-15:0.1:15);
Z = X + i*Y;
contourf(X,Y,abs(S),[1 1]);
where they pass in the fourth argument [1 1] but I've no idea what it's doing. Why do they pass in [1 1] if they ask me for lines between 0 and 1?
Any help is much appreciated!
They're making a mistake.
The help to contourf states
To draw a single contour of level i, use contour(Z,[i i])
So they're drawing a single contour line at 1.
You want to write
contourf(X,Y,abs(S),0:0.1:1);
because the help says
contourf(Z,v) draws a filled contour
plot of matrix Z with contour lines at
the data values specified in the
monotonically increasing vector v. The
number of contour levels is equal to
length(v)
Related
I need some help with MATLAB coding. I have two variables x=0:0.1:1 and y=0:0.1:1. I want to generate the meshgrid only for those points which satisfy the condition x+y<=1. Please help me.
[X,Y] = meshgrid(x,y) returns two matrixes, representing points from (0,0) to (1,1). The requirement to remove values where x + y >= 1 works well on a graph - basically just draw a diagonal line, creating a triangle. However, it doesn't work very well for matrices - who's ever heard of a triangle matrix?
What you can do is set the excluded values to some 'bad' value, and then ignore them. I chose to set them to NaN, because functions like surf won't plot nan's:
x = 0:.1:1;
y = 0:.1:1;
[X,Y] = surf(x,y);
X(X+Y>=1) = nan;
Y(X+Y>=1) = nan;
surf(X,Y,X.*Y)
I'm very new to Matlab. I'm trying to plot X, where X is an 100x1 vector, against Y, which is an 100x10 matrix. I want the result to be X vs 10 different Y values all in the same graph, different colors for each column. The only way I can think of plotting each column of this matrix is by using the hold command, but then I have to split it up so I get each column individually. Is there an easy way to do this?
Use repmat to expand X to be the same size as Y. Try plotting them with plot(X,Y) and if it looks strange, transpose each one (plot(X',Y')).
You can use linespec arguments to select linestyle, marker style, etc. For example, plot(X,Y,'.') would indicate a point at each vertex with no connecting lines.
You don't need to use repmat, just use plot instead of scatter:
plot(X,Y,'o')
Here's an example:
% some arbitrary data:
X = linspace(-2*pi,2*pi,100).'; % size(X) = 100 1
Y = bsxfun(#plus,sin(X),rand(100,10)); % size(Y) = 100 10
% you only need the next line:
plot(X,Y,'o')
legend('show')
Im just trying to draw a line through the following points in matlab. Currently the line extends only to the points. I need to to extend and intercept the x axis. The code is below
A = [209.45 198.066 162.759];
B = [1.805 1.637 1.115];
plot(A,B,'*');
axis([0 210 0 2]);
hold on
line(A,B)
hold off
If you want to augment your points with a corresponding y==0 point, I suggest using interp1 to obtain the x-intercept:
A = [209.45 198.066 162.759];
B = [1.805 1.637 1.115];
x0 = interp1(B,A,0,'linear','extrap'); %extrapolate (y,x) at y==0 to get x0
[newA, inds] = sort([x0 A]); %insert x0 where it belongs
newB = [0 B];
newB = newB(inds); %keep the same order with B
plot(A,B,'b*',newA,newB,'b-');
This will use interp1 to perform a linear interpolant, with extrapolation switched on. By interpolating (B,A) pairs, we in effect invert your linear function.
Next we add the (x0,0) point to the data, but since matlab draws lines in the order of the points, we have to sort the vector according to x component. The sorting order is then used to keep the same order in the extended B vector.
Finally the line is plotted. I made use of plot with a linespec of '-' to draw the line in the same command as the points themselves. If it doesn't bother you that the (x0,0) point is also indicated, you can plot both markers and lines together using plot(newA,newB,'*-'); which ensures that the colors match up (in the above code I manually set the same blue colour on both plots).
I'm looking to create a "web" between a set of points where the data tells whether there is a link between any two points.
The way I thought of would be by plotting every couple points, and overlaying each couple on top of eachother.
However, if there is a way to just simple draw a line between two points that would be much easier.
Any help would be appreciated!
If you can organize the x and y coordinates of your line segments into 2-by-N arrays, you can use the function PLOT to plot each column of the matrices as a line. Here's a simple example to draw the four lines of a unit square:
x = [0 1 1 0; ...
1 1 0 0];
y = [0 0 1 1; ...
0 1 1 0];
plot(x,y);
This will plot each line in a different color. To plot all of the lines as black, do this:
plot(x,y,'k');
Use plot. Suppose your two points are a = [x1 y1] and b = [x2 y2], then:
plot([x1 x2],[y1 y2]);
If you meant by I'm looking to create a "web" between a set of points where the data tells whether there is a link between any two points actually some kind of graph represented by its adjacency matrix (opposite to other answers simple means to connect points), then:
this gplot function may indeed be the proper tool for you. It's the basic visualization tool to plot nodes and links of a graph represented as a adjacency matrix.
use this function:
function [] = drawline(p1, p2 ,color)
%enter code here
theta = atan2( p2(2) - p1(2), p2(1) - p1(1));
r = sqrt( (p2(1) - p1(1))^2 + (p2(2) - p1(2))^2);
line = 0:0.01: r;
x = p1(1) + line*cos(theta);
y = p1(2) + line*sin(theta);
plot(x, y , color)
call it like:
drawline([fx(i) fy(i)] ,[y(i,1) y(i,2)],'red')
Credit: http://www.mathworks.com/matlabcentral/answers/108652-draw-lines-between-points#answer_139175
Lets say you want a line with coordinates (x1,y1) and (x2,y2). Then you make a vector with the x and y coordinates: x = [x1 x2] and y=[y1 y2].
Matlab has a function called 'Line', this is used in this way:
line(x,y)
If you want to see the effect of drawing lines, you can use plot inside for loop note that data is a n*2 matrix containing the 'x,y' of 'n' points
clf(figure(3))
for i = 1 : length(data)-1
plot([data(i,1),data(i+1,1)], [data(i,2),data(i+1,2)], '-*');
hold on
end
hold off
Or can use this statement to draw it in one step
plot(data(:,1), data(:,2), '-*');
If you plot
sin(x*y)
you see some lines.
Now if u have all coordinates of all points of these lines and want to plot theme
(connecting dots without using sin(x*y) function), how is possible?
by this codes, i try to obtain coordinates of each 'x'(beta-bar) for each 'lam' and
save roots in a matrix.
clc; clear;
lmin=0.8; lmax=2.5;
bmin=1; bmax=1.5;
lam=linspace(lmin,lmax,100);
for n=length(lam):-1:1
increment=0.001; tolerence=1e-14; xstart=bmax-increment;
x=xstart;
dx=increment;
m=0;
while x > bmin
while dx/x >= tolerence
if sign(f(lam(n),x))*sign(f(lam(n),x-dx))<0
dx=dx/2;
else
x=x-dx;
end
end
m=m+1;
r(m,n)=x;
dx=increment;
x=0.999*x;
end
end
figure
hold on,plot(lam,r(1,:),'b')
plot(lam,r(2,:),'c')
plot(lam,r(3,:),'r')
xlim([lmin,lmax]);ylim([bmin,bmax]),
xlabel('\lambda(\mum)'),ylabel('\beta-bar')
and
function y=f(x,y)
y=sin(4*x*y);
end
what is wrong with it?
how to separately plot each line?
Use plot(X1,Y1,...,Xn,Yn)
See link for more details
http://www.mathworks.com/help/techdoc/ref/plot.html
use the plot() command. From the Matlab docu ('help plot' on the command line):
'PLOT(X,Y) plots vector Y versus vector X. If X or Y is a matrix,
then the vector is plotted versus the rows or columns of the matrix,
whichever line up. If X is a scalar and Y is a vector, disconnected
line objects are created and plotted as discrete points vertically at
X.'
So while plot(sin(X,Y)) used the plot(X) overload of the function, you will use the plot(X,Y) overload.