Writing a generic mean function in Scala - scala

Question

I'm trying to write a generic mean function that operates on an Iterable that contains numeric types. It would operate, say, on arrays, as so:
val rand = new scala.util.Random()
val a = Array.fill(1000) { rand.nextInt(101) }
val b = Array.fill(1000) { rand.nextDouble }
println(mean(a))
println(mean(b))
etc., hopefully being able to work on other iterables, such as lists.
I have tried various incantations for the mean method, to no avail:
def mean[T <% Numeric[T]](xs: Iterable[T]) = xs.sum.toDouble / xs.size
def mean[A](xs: Iterable[Numeric[A]]):Double = xs.sum.toDouble / xs.size
def mean[T](xs: Iterable[T])(implicit num: Numeric[T]):Double = xs.sum / xs.size
def mean(xs: Iterable[Double]) = xs.sum / xs.size
What is the proper way to do this in Scala?

Answer 1

This works:
def mean[T : Numeric](xs: Iterable[T]): T = implicitly[Numeric[T]] match {
case num: Fractional[_] => import num._; xs.sum / fromInt(xs.size)
case num: Integral[_] => import num._; xs.sum / fromInt(xs.size)
case _ => sys.error("Undivisable numeric!")
}
So, let's make some explanations. First, Numeric must be used in type class pattern. That is, you don't say a type T is, or can be converted into, Numeric. Instead, Numeric provides methods over a type T. One such example is num.fromInt.
Next, Numeric does not provide a common division operator. Instead, one must choose between Fractional and Integral. Here, I'm matching on Numeric[T] to distinguish between both.
Note that I don't use T on the match, because Scala cannot check for type parameters on matches, as they are erased. Instead, I use _, and Scala infers the correct type if possible (as it is here).
After that, I'm importing num._, where num is either Fractional or Integral. This brings some implicit conversions into context that let me do stuff like calling the method / directly. If I did not do that import, I'd be forced to write this:
num.div(xs.sum, num.fromInt(xs.size))
Note that I do not have to pass the implicit parameter to xs.sum, since it is already implicitly available in the scope.
I guess that's it. Did I miss anything?

Answer 2

One of your version is pretty close:
def mean[T](xs: Iterable[T])(implicit num: Numeric[T]):Double =
num.toDouble(xs.sum) / xs.size
Here is the other syntax:
def mean[T: Numeric](xs: Iterable[T]):Double =
implicitly[Numeric[T]].toDouble(xs.sum) / xs.size

Answer 3

def mean[A](it:Iterable[A])(implicit n:Numeric[A]) = {
it.map(n.toDouble).sum / it.size
}

Answer 4

This is quite an old question, but I am basically doing this
def average[A](list: List[Any])(implicit numerics: Numeric[A]): Double = {
list.map(Option(_)).filter(_.isDefined).flatten match {
case Nil => 0.0
case definedElements => numerics.toDouble(list.map(_.asInstanceOf[A]).sum) / definedElements.length.toDouble
}
}
for a list which might contain null values (I have to keep interoperability with Java). The null elements are not counted towards the average.