In my graph Api for facebook..
I am getting this data..
from Json..
"updated_time" = "2011-05-17T14:52:16+0000";
and I am using this code to convert it into valid date format
NSDateFormatter *df = [[[NSDateFormatter alloc] init] autorelease];
//2010-12-01T21:35:43+0000
[df setDateFormat:#"yyyy-mm-ddHH:mm:ssZZZZ"];
NSDate *date = [df dateFromString:[[forTable valueForKey:#"updated_time"] stringByReplacingOccurrencesOfString:#"T" withString:#""]];
[df setDateFormat:#"eee MMM dd, yyyy hh:mm"];
pastDate = [df stringFromDate:date];
NSLog(#"and the date string is %#",pastDate);
and it is giving me this result in the console
and the date string is Mon 01 17, 2011 08:22
though json value is giving me the date of May.this code is giving me the date January
can anyone tell me what is happening here?
It looks like your date format string isn't taking the letter "T" into account – and you should probably be enclosing literal text between apostrophes, just to be safe. Try:
[df setDateFormat:#"yyyy'-'MM'-'dd'T'HH':'mm':'ssZZZZ"];
The dateFormat was wrong, it should be with capital Ms for the month:
[df setDateFormat:#"yyyy-MM-ddTHH:mm:ssZZZZ"];
Related
I am trying to convert NSString into NSDate in 12 hours format. (in iOS 6)
Code :
NSString *Bdt = #"05/23/2012 08:00 AM"
NSDateFormatter *df = [[[NSDateFormatter alloc] init] autorelease];
[df setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0]];
[df setDateFormat:#"MM/dd/yyyy hh:mm a"];
NSDate *bd = [df dateFromString:Bdt];
NSLog(#"%#",bd);
Output:
2012-05-23 08:00:00 +0000 it should be 2012-05-23 08:00 AM
Whats wrong in the code ?
Thanks
If you want date in 2012-05-23 08:00 AM style
Create a dateformatter and setDateFormat as yyyy-MM-dd hh:mm a
NSString *Bdt = #"05/23/2012 08:00 AM";
NSDateFormatter *df = [[NSDateFormatter alloc] init] ;
[df setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0]];
[df setDateFormat:#"MM/dd/yyyy hh:mm a"];
NSDate *bd = [df dateFromString:Bdt];
NSDateFormatter *dateFormatter=[NSDateFormatter new];
[dateFormatter setDateFormat:#"yyyy-MM-dd hh:mm a" ];
NSString *datestr=[dateFormatter stringFromDate:bd];
NSLog(#"%#",datestr);
*Note : I am using ARC, so objects are not released/autoreleased.
EDIT:
NSDate will be in this format ONLY : 2012-05-23 08:00:00 +0000.
For any other format you need to use NSString.
Nothing is wrong with it. You are printing an NSDate in NSLog which is very different than creating an NSString with a specific format.
It seems your confusing the internal NSDate representation with string formatting. NSDate stores the date internally in a way different from how it is represented by humans. Just like NSString stores strings in a format that may not be what you ultimately want it encoded as, eg. ASCII or UTF-8. When you are calling NSLog you are getting a diagnostic message showing the date according to the string returned by - (NSString *)description or possibly - (NSString *)debugDescription.
One simple thing on conversion from NSString to NSDate. How can I convert Mon, 27 August 2012 01:30 AM to NSDate in this same format. I tried with NSDateFormatter. But I am not getting it in this required format. Can anyone help? This is what I tried.
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEEE,dd MM yyyy HH:mm a"];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
NSDateFormatter is to specify the format that will appear in the date-string when extracting string from date or the format that is in the date-string when extracting date from string
So whenever you extract NSDate from a NSString, NSDate is always obtained in default date format(eg 2012-08-27 00:30:00 +0000)... only the when you extract NSString from NSDate, NSString can be obtained in desired(custom) format that you set in NSDateFormatter.
I hope this will help you sure!
NSDateFormatter *dateformater=[[[NSDateFormatter alloc] init]autorelease];
[dateformater setDateFormat:#"EEEE,dd MMMM yyyy HH:mm a"];
NSDate *todayTmp=[NSDate date];
NSString *conversionDate=[dateformater stringFromDate:todayTmp];
Note : (Upper case) HH for 24h time format, (Lower case) hh for 12h time format
NSString *myDateAsAStringValue = #"Mon, 27 August 2012 01:30 AM";
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE, dd MMM yyyy HH:mm a"];
NSDate *myDate = [[NSDate alloc]init];
myDate = [df dateFromString:myDateAsAStringValue];
[df release];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"EEE, dd MMM yyyy HH:mm a"];
NSString *strDate = [dateFormatter stringFromDate:myDate];
NSLog(#"%#", strDate);
[dateFormatter release];
please use below code
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE,dd MMMM yyyy hh:mm a"];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
your formatter is wrong
check this one
NSLog will return NSDate in a fixed format, i guess.
If we need Date in different format, we should have to format it via NSDateFormatter and get it as NSString.
Just a guess.
Don't forget to set the correct locale! If your device does not use an english locale NSDateFormatter can have problems to convert Mon and August into useful information because Mon is not the correct abbreviation for Monday in your language. For example in Germany the correct three letter abbreviation for Monday is Mon..
If you parse dates that have words in it you have to set the correct locale.
This should work:
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE,dd MMMM yyyy hh:mm a"];
NSLocale *posixLocale = [[NSLocale alloc] initWithLocaleIdentifier:#"en_US_POSIX"];
[df setLocale:posixLocale];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
EEE is the dateformatter code for a three letter weekday abbreviation.
hh is the dateformatter code for Hours between 1 and 12. HH means 0-23
MMMM is the full month, MM would be the numeric value (= 08) of the month.
I want to make date by date formatter
2012-07-12 but it display like
2012-07-11
My code:
NString * today_selected=[NSString stringWithFormat:#"%d%#%d%#%d",year_for_activated,#"-",month_for_activated,#"-",taged]; NSDateFormatter *Df=[[NSDateFormatter alloc]init];
//here year_of_=2012 and month_of_ac=7, and tag=12
but it display 2012-07-11 instead of 12.
[Df setDateFormat:#"YYYY-MM-DD" ];
NSDate *date_selected=[Df dateFromString: today_selected];
NSLog(#"today_selected:%#",date_selected);
but it display 2012-01-12
Please read the documentation which states
It uses yyyy to specify the year component. A common mistake is to use
YYYY. yyyy specifies the calendar year whereas YYYY specifies the year
(of "Week of Year"), used in the ISO year-week calendar. In most
cases, yyyy and YYYY yield the same number, however they may be
different. Typically you should use the calendar year.
Also you will note that the day is dd, NOT DD
When you find a problem like this, your first stop should be the documentation
try this:
NString *today_selected=#"2012-07-12";
NSDateFormatter *Df=[[NSDateFormatter alloc]init];
[Df setDateFormat:#"yyyy-MM-dd" ];
NSDate *date_selected=[Df dateFromString: today_selected];
NSLog(#"today_selected:%#",date_selected);
try this for get the 2012-07-12 ,this type of Formatter :
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"yyyy-MM-dd"];
NSDate *now = [[NSDate alloc] init];
NSString *theDate = [dateFormat stringFromDate:now];
I have stuck in issue in which i have to convert date format is Thu, 28 Jul 2011 22:33:57 +0000 into yyyy-mm-dd hh:mm:ss
please give me some idea how to do this?
What you want is to use the NSDateFormatter. Something like this:
NSDateFormatter* f = [[[NSDateFormatter alloc] init] autorelease];
[f setDateFormat:#"yyyy-MM-dd hh:mm:ss"];
NSString* dateString = [f stringFromDate:date];
Do note that the hours will still follow the users selected locale. Use kk:mm:ss to enforce a 24-hour time.
what have you tried? it's difficult to answer questions like this...
first you have to parse the date into an NSDate, use an NSDateFormatter, the incoming format looks like POSIX date format so should be easy.
then you want to output to the format you specify with another NSDateFormatter
You need to use an NSDateformatter to convert the first date to a string with the following syntax.
NSDateFormatter * dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat: #"yyyy-MM-dd hh:mm:ss"];
NSString *dateString = [dateFormatter stringFromDate: [NSDate date]]; //Put whatever date you want to convert
Then if you want the date as an NSDate and you have the string generated above just put the following code.
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat: #"yyyy-MM-dd hh:mm:ss"];
NSDate * date = [dateFormatter dateFromString: dateString]; //String generated above
Getting a NSString as follows:
NSString *lastSyncDate = [[items objectAtIndex:0] objectForKey:#"LastSyncDate"];
This value is: 1/1/2010 12:00:00 AM
I am using the following to convert to a date:
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setTimeStyle:NSDateFormatterFullStyle];
[df setDateFormat:#"MMMM d, y HH:mm:ss ZZZ"];
NSDate *mySyncDate = [df dateFromString:lastSyncDate];
This gives me a null value?
Your date format doesn't match the format of the string.
Try
[df setDateFormat:#"M/d/y hh:mm:ss a"];
or
[df setDateFormat:#"M/d/y h:mm:ss a"]; // if the hours aren't zero-padded
The format strings are a Unicode standard described at http://unicode.org/reports/tr35/tr35-6.html#Date_Format_Patterns
I agree with Seamus Campbell. However, be aware that setting the time style on the formatter (NSDateFormatter) will have no effect on the result returned by dateFromString.