I want to make date by date formatter
2012-07-12 but it display like
2012-07-11
My code:
NString * today_selected=[NSString stringWithFormat:#"%d%#%d%#%d",year_for_activated,#"-",month_for_activated,#"-",taged]; NSDateFormatter *Df=[[NSDateFormatter alloc]init];
//here year_of_=2012 and month_of_ac=7, and tag=12
but it display 2012-07-11 instead of 12.
[Df setDateFormat:#"YYYY-MM-DD" ];
NSDate *date_selected=[Df dateFromString: today_selected];
NSLog(#"today_selected:%#",date_selected);
but it display 2012-01-12
Please read the documentation which states
It uses yyyy to specify the year component. A common mistake is to use
YYYY. yyyy specifies the calendar year whereas YYYY specifies the year
(of "Week of Year"), used in the ISO year-week calendar. In most
cases, yyyy and YYYY yield the same number, however they may be
different. Typically you should use the calendar year.
Also you will note that the day is dd, NOT DD
When you find a problem like this, your first stop should be the documentation
try this:
NString *today_selected=#"2012-07-12";
NSDateFormatter *Df=[[NSDateFormatter alloc]init];
[Df setDateFormat:#"yyyy-MM-dd" ];
NSDate *date_selected=[Df dateFromString: today_selected];
NSLog(#"today_selected:%#",date_selected);
try this for get the 2012-07-12 ,this type of Formatter :
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"yyyy-MM-dd"];
NSDate *now = [[NSDate alloc] init];
NSString *theDate = [dateFormat stringFromDate:now];
Related
I have a string date in UTC format:
"2012-11-20T05:23:02.34"
now I want the UTC NSDate object for this... and I implemented this function.
+ (NSDate *)utcDateFromString:(NSString *)string withFormat:(NSString *)format {
NSDateFormatter *inputFormatter = [[NSDateFormatter alloc] init];
inputFormatter.timeZone =[NSTimeZone timeZoneWithAbbreviation:#"UTC"];
[inputFormatter setDateFormat:format];
NSDate *date = [inputFormatter dateFromString:string];
[inputFormatter release];
return date;
}
and called it like this...
NSDate* submittedDate =[NSDate utcDateFromString:submittedDateString withFormat:#"YYYY-MM-dd'T'HH:mm:ss.SS"];
but this returns the NSDate description as this..
2011-11-20 05:23:02 +0000
Now if you notice there is one year difference in the dates... can anyone explain why is this happening..?
Thanks for your help.
in the dateformmater, use yyyy instead of YYYY
It should be
NSDate* submittedDate =[NSDate utcDateFromString:submittedDateString withFormat:#"yyyy-MM-dd'T'HH:mm:ss.SS"];
That will solve the problem.
In the following link, search for YYYY.
https://developer.apple.com/library/mac/#documentation/Cocoa/Conceptual/DataFormatting/Articles/dfDateFormatting10_4.html
It uses yyyy to specify the year component. A common mistake is to use YYYY. yyyy specifies the calendar year whereas YYYY specifies the year (of “Week of Year”), used in the ISO year-week calendar. In most cases, yyyy and YYYY yield the same number, however they may be different. Typically you should use the calendar year.
try this bellow method..
-(NSDate *)getUTCFormateDate:(NSString *)localDate withFormat:(NSString *)format
{
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:format];
NSTimeZone *timeZone = [NSTimeZone timeZoneWithName:#"UTC"];
[dateFormatter setTimeZone:timeZone];
NSDate *date = [dateFormatter dateFromString:localDate];
return date;
}
And Use Like bellow..
NSDate *dateHere = [[NSDate alloc]init];
dateHere = [self getUTCFormateDate:#"2012-11-20T05:23:02.34" withFormat:#"yyyy-MM-dd'T'HH:mm:ss.SS"];
NSLog(#"Date here %#",dateHere);
and i get output is Date here 2012-11-20 05:23:02 +0000
see my another answer which return string date with UTF format..
convert NSstring date to UTC dateenter link description here
One simple thing on conversion from NSString to NSDate. How can I convert Mon, 27 August 2012 01:30 AM to NSDate in this same format. I tried with NSDateFormatter. But I am not getting it in this required format. Can anyone help? This is what I tried.
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEEE,dd MM yyyy HH:mm a"];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
NSDateFormatter is to specify the format that will appear in the date-string when extracting string from date or the format that is in the date-string when extracting date from string
So whenever you extract NSDate from a NSString, NSDate is always obtained in default date format(eg 2012-08-27 00:30:00 +0000)... only the when you extract NSString from NSDate, NSString can be obtained in desired(custom) format that you set in NSDateFormatter.
I hope this will help you sure!
NSDateFormatter *dateformater=[[[NSDateFormatter alloc] init]autorelease];
[dateformater setDateFormat:#"EEEE,dd MMMM yyyy HH:mm a"];
NSDate *todayTmp=[NSDate date];
NSString *conversionDate=[dateformater stringFromDate:todayTmp];
Note : (Upper case) HH for 24h time format, (Lower case) hh for 12h time format
NSString *myDateAsAStringValue = #"Mon, 27 August 2012 01:30 AM";
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE, dd MMM yyyy HH:mm a"];
NSDate *myDate = [[NSDate alloc]init];
myDate = [df dateFromString:myDateAsAStringValue];
[df release];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"EEE, dd MMM yyyy HH:mm a"];
NSString *strDate = [dateFormatter stringFromDate:myDate];
NSLog(#"%#", strDate);
[dateFormatter release];
please use below code
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE,dd MMMM yyyy hh:mm a"];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
your formatter is wrong
check this one
NSLog will return NSDate in a fixed format, i guess.
If we need Date in different format, we should have to format it via NSDateFormatter and get it as NSString.
Just a guess.
Don't forget to set the correct locale! If your device does not use an english locale NSDateFormatter can have problems to convert Mon and August into useful information because Mon is not the correct abbreviation for Monday in your language. For example in Germany the correct three letter abbreviation for Monday is Mon..
If you parse dates that have words in it you have to set the correct locale.
This should work:
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE,dd MMMM yyyy hh:mm a"];
NSLocale *posixLocale = [[NSLocale alloc] initWithLocaleIdentifier:#"en_US_POSIX"];
[df setLocale:posixLocale];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
EEE is the dateformatter code for a three letter weekday abbreviation.
hh is the dateformatter code for Hours between 1 and 12. HH means 0-23
MMMM is the full month, MM would be the numeric value (= 08) of the month.
I have stuck in issue in which i have to convert date format is Thu, 28 Jul 2011 22:33:57 +0000 into yyyy-mm-dd hh:mm:ss
please give me some idea how to do this?
What you want is to use the NSDateFormatter. Something like this:
NSDateFormatter* f = [[[NSDateFormatter alloc] init] autorelease];
[f setDateFormat:#"yyyy-MM-dd hh:mm:ss"];
NSString* dateString = [f stringFromDate:date];
Do note that the hours will still follow the users selected locale. Use kk:mm:ss to enforce a 24-hour time.
what have you tried? it's difficult to answer questions like this...
first you have to parse the date into an NSDate, use an NSDateFormatter, the incoming format looks like POSIX date format so should be easy.
then you want to output to the format you specify with another NSDateFormatter
You need to use an NSDateformatter to convert the first date to a string with the following syntax.
NSDateFormatter * dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat: #"yyyy-MM-dd hh:mm:ss"];
NSString *dateString = [dateFormatter stringFromDate: [NSDate date]]; //Put whatever date you want to convert
Then if you want the date as an NSDate and you have the string generated above just put the following code.
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat: #"yyyy-MM-dd hh:mm:ss"];
NSDate * date = [dateFormatter dateFromString: dateString]; //String generated above
NSDate *My_StartDate,*My_EndDate ;
NSDateFormatter * df= [[NSDateFormatter alloc]init];
[df setDateFormat:#"dd/MM/yyyy hh:mm:ss"];
My_StartDate = [df dateFromString:#"01/05/2010 10:15:33"];
My_EndDate = [df dateFromString:#"01/05/2010 10:45:33"];
NSLog(#"%#",My_StartDate);
NSLog(#"%#",My_EndDate);
In the log i get something like this for the my_startdate as 2010-05-01 04:45:33 +0000 and end date as 2010-05-01 05:15:33 +0000 instead i should have got value as for start date as 2010-05-01 10:15:33 +0000 and end date as 2010-05-01 10:45:33 +0000
Try with below function:
-(NSString *)getDateStringFromDate :(NSDate *)dateValue{
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"yyyy-MM-dd"];
NSDateFormatter *timeFormat = [[NSDateFormatter alloc] init];
[timeFormat setTimeStyle:NSDateFormatterShortStyle];
[timeFormat setDateFormat:#"HH:mm:ss"];
//[timeFormat setDateFormat:#"HH:mm"];
//[timeFormat setDateFormat:#"HH:mm a"];
////
NSString *theDate = [dateFormat stringFromDate:dateValue];
NSString *theTime = [timeFormat stringFromDate:dateValue];
NSLog(#"\n"
"theDate: |%#| \n"
"theTime: |%#| \n"
, theDate, theTime);
return theDate;
}
Change Format of data as per your need.
Let me know in case of any difficulty.
Cheers.
This shows date which follow American standard time string but by this reason you don't get any problem in making your logic.Also
[df setDateFormat:#"dd/MM/yyyy hh:mm:ss"];
this format using 12 hour format (means 2:03 pm and 2:03 am) and date object never use am and pm for showing date object value but when you convert it correctly then it gives you right date and time.
If you feel you get any problem then use different locale for that.
It is displaying asper the GMT+4.30 time.It displays like that only.When you are converting that date to string using the DateFormatter it gives the same date(Whichever you want like start date as 01/05/2010 10:15:33 and end date as 01/05/2010 10:45:33).
NSDateFormatter * dateformatter= [[NSDateFormatter alloc]init];
[dateformatter setDateFormat:#"dd/MM/yyyy hh:mm:ss"];
NSString *dat = [dateformatter stringfromDate:My_StartDate];
then you will get the output as 01/05/2010 10:15:33
You might want to set the time zone of the date formatter to GMT here. Do it using
[df setTimeZone:[NSTimeZone timeZoneWithName:#"GMT"]];
before you do dateFromString: calls. This will give you what you want.
Just need to update here in your code:
I might be like that your time would be in 24 hours format, so at that time you need to use this ....other than that you need to set the timezone.
Follow this link for All zone : http://unicode.org/reports/tr35/tr35-6.html#Date%5FFormat%5FPatterns
[df setDateFormat:#"dd/MM/yyyy hh:mm:ss"];
to
[df setDateFormat:#"dd/MM/yyyy HH:mm:ss"];
You are Done ;)
I'm new to iPhone development. I want to set default date to NSDate Object as string. I don't see any easy way or method...
I think there might be a method in NSCalender? If there's such a method, please tell me.
Thanks in advance.
I'm not totally clear on what you are asking, but to create an instance of an NSDate object with the current date, one calls:
NSDate * myDate = [NSDate date];
If you are saying that you have a c-string or NSString that needs to be parsed to initialize an NSDate object, that's another question.
I have some code posted here:
How get a datetime column in SQLite with Objective C
that shows how to create NSDates from NSStrings using NSDateFormatter.
If you want to create an NSDate from a string, you need to use an NSDateFormatter to do it. It's important to note that the formatter will use the current locale's time zone when constructing the date, unless you put a time-zone in as part of the format. For more information about constructing time zones, see NSTimeZone.
For example, to create a date using the ubiquitous format '2011-01-16 00:00' in UTC, you would do:
NSDateFormatter* formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"yyyy-MM-dd HH:mm"];
// Only certain abbreviations are okay, like UTC. See docs for more info
[formatter setTimeZone:[NSTimeZone timeZoneWithAbbreviation:#"UTC"]];
NSDate* midnight_26_jan_2011_utc = [formatter dateFromString:#"2011-01-26 00:00"];
// this will display in your system locale
// (for me, it shows 2011-01-25 19:00 +0500 because I'm America/New_York time)
NSLog(#"date: %#", midnight_26_jan_2011_utc);
[formatter release];
Edit: Added time to format string.
You will need to look at the NSDate and NSDateFormatter classes. Here's a simple example of how to use them:
NSString* defaultDateString = [NSString stringWithFormat:#"2011-01-22 15:30:00"];
NSDateFormatter* dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"yyyy-MM-dd HH:mm:ss"];
NSDate* defaultDate = [dateFormatter dateFromString:defaultDateString];
[dateFormatter release];
and if you wanted to get the string from a date you can just use:
NSString* defaultDateString = [dateFormatter stringFromDate:defaultDate];
NSDateFormatter *DateFormatter=[[NSDateFormatter alloc] init];
[DateFormatter setTimeZone:[NSTimeZone defaultTimeZone]];
[DateFormatter setDateFormat:#"yyyy-MM-dd hh:mm:ss"]; //here,you can set the date format as you need
NSDate *now = [[[NSDate alloc] init]autorelease];
NSString *theDate = [DateFormatter stringFromDate:now];
Now, you can use the string the date. :)
NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc]init]autorelease];
[dateFormatter setDateFormat:#"yyyy-mm-dd"];
NSDate *yourDate = [dateFormatter dateFromString:#"2011-01-26"];