I am calling a FTP file from DOS, which holds ftp set of commands as follows:
ftp -s:ftpcmd1.txt
Now, the change requirement says, file is to be called multiple times with different file paths.
so, I need to write above statement, each time passing new file path as argument with FTP filename and writing something like "%1" in command inside ftp-file. Please help me with same. How do I do it.
Thanks.
I dont know if we can pass parameter to ftp script (atleast in DOS). But in the above case dynamically written out ftp script file would help. Small bat file which would do that is like below.
echo "user username pwd">ftpcmd1.txt
echo "bin">>ftpcmd1.txt
echo "put %1">>ftpcmd1.txt
echo "bye">>ftpcmd1.txt
ftp -n -i -v servername<ftpcmd1.txt
If you call this bat file with any file name as the first command line argument, it would transfer the file to target servername. Hope this is what you are looking for.
Related
imagine I have a files with certain extensions (for example '.abc').
The default program I set for files with this special extension is a batch script with powershell commands in it, so when I doubleclick the file, it runs the script. It works.
Now my question is, can I somehow get the file path of the .'abc' file I opened? Is there a command for this?
Thank you.
Inside of your batch file it should be possible to access the ".abc" file via parameter %1.
Per default Windows sends the filename of the file you doubleclick to the receiving program (or batch script) as parameter one.
Try this inside of your batch file (near the top) and pick what suits your needs:
echo param1: %1
echo param1 unquoted: %~1
echo drive: %~d1
echo drive and path: %~dp1
echo filename and extension only: %~nx1
set myparam=%~1
echo myParam: %myparam%
See the help documentation of for for the "%~..." syntax by executing for /? in a cmd.exe command window. (Or read here: What does %~dp0 mean, and how does it work?)
I have created a .sed file for input in iexpress.exe. The entry in .sed file has two applications. One is a batch file and another is an .exe file, for example:
AppLaunched=cmd.exe /c abc.bat
AppLaunched2=setup.exe
After creating the setup and executing, only the batch file is executed. I want to execute both files.
Any idea?
If I understand your problem correctly you could try using & to chain commands,
AppLaunched=cmd.exe /c abc.bat & setup.exe
There are a few other ways but this is one of the most simplistic.
I have a script in one of my application folders.Usually I just cd into that locatin in Unix box and run the script e.g.
UNIX> cd My\Folder\
My\Folder> MyScript
This prints the required result.
I am not sure how do I do this in Bash script.I have done the following
#!/bin/bash
mydir=My\Folder\
cd $mydir
echo $(pwd)
This basically puts me in the right folder to run the required script . But I am not sure how to run the script in the code?
If you can call MyScript (as opposed to ./MyScript), obviously the current directory (".") is part of your PATH. (Which, by the way, isn't a good idea.)
That means you can call MyScript in your script just like that:
#!/bin/bash
mydir=My/Folder/
cd $mydir
echo $(pwd)
MyScript
As I said, ./MyScript would be better (not as ambiguous). See Michael Wild's comment about directory separators.
Generally speaking, Bash considers everything that does not resolve to a builtin keyword (like if, while, do etc.) as a call to an executable or script (*) located somewhere in your PATH. It will check each directory in the PATH, in turn, for a so-named executable / script, and execute the first one it finds (which might or might not be the MyScript you are intending to run). That's why specifying that you mean the very MyScript in this directory (./) is the better choice.
(*): Unless, of course, there is a function of that name defined.
#!/bin/bash
mydir=My/Folder/
cd $mydir
echo $(pwd)
MyScript
I would rather put the name in quotes. This makes it easier to read and save against mistakes.
#!/bin/bash
mydir="My Folder"
cd "$mydir"
echo $(pwd)
./MyScript
Your nickname says it all ;-)
When a command is entered at the prompt that doesn't contain a /, Bash first checks whether it is a alias or a function. Then it checks whether it is a built-in command, and only then it starts searching on the PATH. This is a shell variable that contains a list of directories to search for commands. It appears that in your case . (i.e. the current directory) is in the PATH, which is generally considered to be a pretty bad idea.
If the command contains a /, no look-up in the PATH is performed. Instead an exact match is required. If starting with a / it is an absolute path, and the file must exist. Otherwise it is a relative path, and the file must exist relative to the current working directory.
So, you have two acceptable options:
Put your script in some directory that is on your PATH. Alternatively, add the directory containing the script to the PATH variable.
Use an absolute or relative path to invoke your script.
I am doing a batch scripting assignment where I have to call one script from inside another. I need the script to run the second script no matter where my lecturer saves these scripts. How would I do this. Is there some way to find the path of script inside the script and use that to execute the file. Any help would be great. I think I need to use %'s but i'm not sure.
The name of the script is Hello World.bat.
How would I copy Hello World.bat to the C:\ if I don't know which directory the lecturer has placed it in. what command/s would I use so that the copy would work regardless of the scripts location.
I don't see the "DOS" tag, but I'll assume that it is for now. If you want the entire path, you can get it by doing this:
echo %cd%
If you want just the last folder, this works (inside a .bat file):
for %%* in (.) do #echo %%~n*
Note that from the command line, the above command will work with single %'s:
for %* in (.) do #echo %~n*
If the script you are executing is calling other scripts in the SAME folder location, you can prefix the path statement with "%~dp0" or "%~dps0" but do not put a backslash between that and the name of the script you are calling. In other words, if script1.bat is calling script2.bat in the same folder, the statement in script1.bat would refer to "%~dp0script2.bat"
sorry about batch files, am not familiar, but in nix shell, there is the locate command which can return the path of the file , if you know the filename exactly and the name is unique.
like
name=$(locate filname)
In SQL I'm using xp_cmdShell to run FTP commands. I have no problem getting the list of files or copying files to the local server, but I want to compare copied file size to the original to make sure the get has been successful.
Any ideas on how to compare file sizes?
From a command prompt you can use the DOS File Compare command (fc). In your case you probably want to do a binary compare (there is no file size compare). I binary compare should work in your case.
Most DOS commands will return some code that let s you know the status.
http://www.computerhope.com/fchlp.htm
EDIT
Sorry, I read your question and realized you want to compare it against a file on the ftp server. I think this is a moot point since if ftp reports a successful file transfer there is no reason to compare (unless your source of comparison for not the ftp site). Does that make sense?
What you could do it use the FTP command ls command.
ftp> ls <filename>
where ftp> is the ftp prompt and not part of the command. This command gives you the file size in bytes. Then you need to use the dos command for the local file. Here is a StackOverflow question (and answer) about that.
Windows command for file size only?