In webview, I click a link that takes me to an activity through following code :
public boolean shouldOverrideUrlLoading(WebView view, String url) {
// TODO Auto-generated method stub
if(url.equals("factory.cpp")){
Toast.makeText(getApplicationContext(), "Clicked on link", Toast.LENGTH_SHORT).show() ;
Intent intent = new Intent(getApplicationContext(), FactoryCppFiles.class) ;
startActivity(intent) ;
return false ;
}
else
return true ;
}
The FactoryCppFiles activity is displayed properly, but when I press the back button, it shows me the following standard error message.
Web page not available
I want to show the web view where I clicked on the link. How do I achieve this?
Just realized I should return true if I want to handle the URL myself. I switched the return statements and it works fine now.
Related
Bonjour,
In Android Studio, I am trying to open a fragment from the onOptionsItemSelected in a navigationdrawer, it opens the frgament but the fragment will ovelap the one who was there and it remains there.
so now when I call another fragmentit will be shown at the back so I will have many occurencse of the fragment overlapping.
I hope I am clear
this is the code i use in the MainActivity to call the fragment from onOptionsItemSelected
#Override
public boolean onOptionsItemSelected(MenuItem item) {
//Handle item selection
switch (item.getItemId()) {
case R.id.action_apropos:e:
FragmentTransaction transaction = getSupportFragmentManager().beginTransaction();
transaction.replace(R.id.nav_host_fragment_content_main,
new AnnoncesFragment(),null).commit();
return true;
default:
return super.onOptionsItemSelected(item);
}
}
if I use this code:
NavController navController = Navigation.findNavController(this,
R.id.nav_host_fragment_content_main);
navController.navigate(R.id.nav_apropos);
everything works fine but I will not be abble to pass arguments
Thanks for your help
I am developing an app in Xamarin.Forms, before I was trying to make a master detail page to become my MainPage when I logged in to my app, this I have already achieved. Now I have the problem that when I use the button behind the phone my app is miimiza and goes to the background which is the behavior I hope, but when I return to my app does not continue showing my master detail page, but returns to my LginPage.
It is as if my app was running twice or at least there were two instances of LoginPage existing at the same time, this is because in my LoginPage I trigger some DisplayAlert according to some messages that my page is listening through the MessaginCenter and they are they shoot twice.
Can someone tell me how I can return the same to my app on the master detail page and not restart in the strange way described?
LoginView.xaml.cs:
public partial class LogonView : ContentPage
{
LogonViewModel contexto = new LogonViewModel();
public LogonView ()
{
InitializeComponent ();
BindingContext = contexto;
MessagingCenter.Subscribe<LogonViewModel>(this, "ErrorCredentials", async (sender) =>
{
await DisplayAlert("Error", "Email or password is incorrect.", "Ok");
}
);
}
protected override void OnDisappearing()
{
base.OnDisappearing();
MessagingCenter.Unsubscribe<LogonViewModel>(this, "ErrorCredentials");
}
}
Part of my ViewModel:
if (Loged)
{
App.token = token;
Application.Current.MainPage = new RootView();
}
else
{
MessagingCenter.Send(this, "ErrorCredentials");
}
Thanks.
I hope this is in Android. All you can do is, you can override the backbuttonpressed method in MainActivity for not closing on back button pressed of the entry page. like below, you can add some conditions as well.
public override void OnBackPressed()
{
Page currentPage = Xamarin.Forms.Application.Current.MainPage.Navigation.NavigationStack.LastOrDefault();
if (currentPage != null)
{
if (currentPage.GetType().Name == "HomePage" || currentPage.GetType().Name == "LoginPage")
{
return;
}
}
base.OnBackPressed();
}
When you press the Home button, the application is paused and the
current state is saved, and finally the application is frozen in
whatever state it is. After this, when you start the app, it is
resumed from the last point it was saved with.
However, when you use the Back button, you keep traversing back in
the activity stack, closing one activity after another. in the end,
when you close the first activity that you opened, your application
exits. This is why whenever you close your application like this, it
gets restarted when you open it again.
Answer taken from this answer. The original question asks about the native Android platform, but it still applies here.
It means you have to Use Setting Plugin or save data in Application properties.
You have to add below code in App.xaml.cs file:
if (SettingClass.UserName == null)
MainPage = new LoginPage();
else
MainPage = new MasterDetailPage();
For Setting Plugin you can refer this link.
I am working on Netbeans building a JavaFX application.
I started using ControlsFX (http://fxexperience.com/controlsfx/)
I have implemented a simple Dialog that uses custom AbstractDialogAction s as I want specific number of buttons to appear.
I do this like this:
Action a = new AbstractDialogAction(" button a ", Dialog.ActionTrait.CLOSING) {
#Override
public void execute(ActionEvent ae) {
}
};
ArrayList<Action> actions = new ArrayList<>();
actions.add(a);
actions.add(b); // other button
actions.add(c); // another button
dialog.actions(actions);
Action response = dialog.showConfirm();
Dialog is shown correctly with the given buttons.
My question is how to force the Dialog to close when a button is pressed ?
I thought setting a Dialog.ActionTrait.CLOSING would do the trick, but the Dialog stays open.
From eugener in ControlsFX mailing list
public void execute(ActionEvent ae) {
if (ae.getSource() instanceof Dialog ) {
((Dialog) ae.getSource()).setResult(this);
}
}
The above sets the result of the Dialog to be the current Action and closes the Dialog
But maybe that is a little redundant as I can simply call:
((Dialog) ae.getSource()).hide();
.hide() hides the Dialog and also sets the current action as the result.
I can't suggest which is a better solution (hide() was suggested by jewelsea)
In addition I would suggest to always override the toString() method of class AbstractDialogAction, in order to get readable result from:
Action response = dialog.showConfirm();
System.out.println("RESPONSE = "+ response.toString());
Hide the dialog to close it => dialog.hide()
I have created a Dialog with two buttons Yes, No, and then I have add action listener to them, my problem is that I want no button to hide the Dialog that I have created
the code is looks like:
dialog = new Dialog(title);
dialog.setDialogType(Dialog.TYPE_CONFIRMATION);
ta = new TextArea(text);
ta.getStyle().setBorder(Border.createEmpty());
ta.setEditable(false);
yesCommand = new Button("YES");
noCommand = new Button("NO");
yesCommand.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent ae) {
LGBMainMidlet.getLGBMidlet().notifyDestroyed();
}
});
noCommand.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent ae) {
Logger.Log("Bye Bye");
dialog = null;
System.gc();
}
});
dialog.addComponent(ta);
dialog.addComponent(yesCommand);
dialog.addComponent(noCommand);
dialog.show();
the code is not working for me, can anyone told me what is the problem?
B.N. I have used dialog.dispose(), but it exit the whole application
It is better to use
dialog.setTimeout(1000); the number show the time limit the dialog box wait in milliseconds. So by doing this you can exit the dialog form automatically.
Dialog.dispose() does not exit the whole application, it just closes the dialog.
If you have nothing in your application you might see nothing if you dispose the dialog.
I want to add the bookmark function to my app, when I clicked on the webview which display the HTML files (The file's main part is string), I want to capture the first line of the content which display on the screen. Anyone knows the answer?
Thanks very much in advance.
-Shawn
you can identify the some content of the page as It contains img tag or not
Use this API of webView click here
WebView.HitTestResult hr = ((WebView)v).getHitTestResult();
int i=hr.getType() ;
and use the int values of this class for the content
Hope it help
If there is a link into the WebView and you want to do a specific action when the user click on this link you must catch the link click using the following code:
Somewhere in your activity code (commonly in the onCreate method):
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState, R.layout.news_details);
...
mWebView.setWebViewClient(new MyWebViewClient());
...
}
And the WebViewClient class:
class MyWebViewClient extends WebViewClient {
#Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
if (DEBUG) {
Log.d(TAG, "shouldOverrideUrlLoading url= " + url);
}
if ( the url is like you want) {
// TODO: add the code to do what you need to do with the url
// the webview should not do anything with this link.
return true;
} else {
// let the webview normally handle the link
return false;
}
}
}
If what you want to do is get the actual displayed content of the WebView, there is no API to do that.
Have a look on those post:
Is it possible to get the HTML code from WebView
Retrieve webview content
Both redirect on this website:
http://lexandera.com/2009/01/extracting-html-from-a-webview/