Hi friends... I am using regular expression so I get string but with double quote and slash but I dont want that. I want string value without slash and double quotes. I try this I'm but not getting proper answer.
I get error after running application [/Users/pradeepyadav/Desktop/RegexKitLiteDemo/Classes/RegexKitLiteDemoAppDelegate.m:108:0 /Users/pradeepyadav/Desktop/RegexKitLiteDemo/Classes/RegexKitLiteDemoAppDelegate.m:108: error: incompatible block pointer types initializing 'void (^)(struct NSString *, NSUInteger, BOOL *)', expected 'void (^)(struct objc_object *, NSUInteger, BOOL *)
I get this error line
Second one is this : [/Users/pradeepyadav/Desktop/RegexKitLiteDemo/Classes/RegexKitLiteDemoAppDelegate.m:105:0 /Users/pradeepyadav/Desktop/RegexKitLiteDemo/Classes/RegexKitLiteDemoAppDelegate.m:105: warning: 'NSString' may not respond to '+stringByTrimmingCharactersInSet:
I get this error line [webData length] encoding:NSUTF8StringEncoding];
//NSLog(#"%#",loginStatus);
[connection release];
//
NSString *regexString = #"Stations\\[""(.*)""\\] = new Station\\((.*)new Array\\((.*)\\)\\);"; //#"Stations\\[""(.*)""\\] = new Station\\((.*)\\);"; //#"Stations\[""(.*)""\] = new Station\({[\,,2}(.*)new Array\((.*)\)\);"; //#"<a href=([^>]*)>([^>]*) - ";
matchArray = [loginStatus arrayOfCaptureComponentsMatchedByRegex:regexString];
NSMutableArray *newArray = [[NSMutableArray alloc] initWithCapacity:[matchArray count]];
//NSCharacterSet *charactersToRemove = [NSCharacterSet punctuationCharacterSet];
[matchArray enumerateObjectsUsingBlock:^(NSString *aString, NSUInteger idx, BOOL *stop)
{
NSString *newString = [NSString stringByTrimmingCharactersInSet:[NSCharacterSet punctuationCharacterSet]];//#############
[newArray insertObject:newString atIndex:idx];
NSLog(#"matchArray: %#", matchArray);
}];//******************
//NSLog(#"matchArray: %#", matchArray);
lstAirports = [[NSMutableArray alloc] initWithCapacity:[matchArray count]];
for (int i = 0; i < [matchArray count]; i++) {
airport *air=[[airport alloc]init];
//code
air.Code = [[matchArray objectAtIndex: i] objectAtIndex: 1];
NSLog(#"air.Code: %#\n",air.Code);
//name
NSString *temp=[[matchArray objectAtIndex: i] objectAtIndex: 2];
NSArray *arrParts=[temp componentsSeparatedByString:#""","];
//air.Name=arrParts[2];
air.Name=[arrParts objectAtIndex:2];
NSLog(#"air.Name: %#\n",air.Name);
//destination airports
temp=[[matchArray objectAtIndex: i] objectAtIndex: 3];
arrParts=[temp componentsSeparatedByString:#","];
air.DestinationAirports =arrParts;
NSLog(#"air.DestinationAirports: %#\n",air.DestinationAirports);
[lstAirports addObject: air];
NSLog(#"lstAirports: %#\n",lstAirports);
}
//[webData release];
}
please some help me fast it's vital for me
You don't need RegExp to remove occurrences of string in NSString.
See the example below, i hop it will help you:
NSString *str = #"fdf\"fdsfdsf\"fsdfsf/fsdfsdfsf\\fsdfsdf\\fsdffsd//fsdfsf\"fsdf/\\\"";
str = [str stringByReplacingOccurrencesOfString:#"\"" withString:#""];
str = [str stringByReplacingOccurrencesOfString:#"\\" withString:#""];
str = [str stringByReplacingOccurrencesOfString:#"/" withString:#""];
NSLog(#"%#", str);
Check for the usage of
stringByReplacingOccurrencesOfString:withString:
in
http://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/Reference/NSString.html.
You can replace them with "" characters.
Related
I've got a file with a bunch of string in like so:
item1,01-SR,admin,Missing or broken,undefined, 16/04/2013 18:10:10;
item1,03-SR,admin,In Use,undefined, 16/04/2013 18:10:34;
item1,01-SR,admin,In Use,undefined, 16/04/2013 18:10:45;
item1,02-SR,admin,In Use,undefined, 16/04/2013 18:10:49;
item1,05,admin,In Use,undefined, 16/04/2013 18:10:56;
I'm reading the strings in and then splitting them up so I just get one string at a time. Then I want to split up the string I've got again so each CSV is it's own variable. I've tried this like so (numLines is a count of the number of lines in the file):
while (count1 < numLines) {
NSString *message = [[strings objectAtIndex: count1] copy];
NSMutableArray *items = [[fileContents componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#";"]] mutableCopy];
NSString *items1 = [[items objectAtIndex: count1] copy];
NSLog(#"items: %#", items1);
NSMutableArray *inditems = [[items1 componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#","]] mutableCopy];
NSString * item1 = inditems[0];
NSString * bnum1 = inditems[1];
NSString * user1 = inditems[2];
NSString * state1 = inditems[3];
NSString * gender1 = inditems[4];
NSString * tstamp1 = inditems[5];
NSLog(#"item: %#", item1);
NSLog(#"bnum: %#", bnum1);
NSLog(#"user: %#", user1);
NSLog(#"state: %#", state1);
NSLog(#"gender: %#", gender1);
NSLog(#"tstamp: %#", tstamp1);
count1++;
}
Now, this works as far as selecting one line from the file and it puts the first two items into the array and then writes the values of item1 and bnum1 to the log but then it throws an exception for some reason. Now this would usually suggest to me that item 2 doesn't exist in the array so I did a count like so:
NSLog(#"count = %d", [inditems count]);
Which correctly returns 6. I then wanted to check that it could actually read another item from the array so I did:
NSString *tstamp1 = [[inditems lastObject] copy];
Which when logged correctly returns the time stamps like so:
16/04/2013 18:10:10
So I thought "oh at least item 5 works" and tried just getting that item:
while (count1 < numLines) {
NSString *message = [[strings objectAtIndex: count1] copy];
NSMutableArray *items = [[fileContents componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#";"]] mutableCopy];
NSString *items1 = [[items objectAtIndex: count1] copy];
NSLog(#"items: %#", items1);
NSMutableArray *inditems = [[items1 componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#","]] mutableCopy];
NSString * item1 = inditems[0];
NSString * bnum1 = inditems[1];
NSString * tstamp1 = inditems[5];
NSLog(#"item: %#", item1);
NSLog(#"bnum: %#", bnum1);
NSLog(#"tstamp: %#", tstamp1);
count1++;
}
But that also throws an exception! I'm probably doing something stupid here, but I would appreciate any help.
Thanks!
My guess is your NSArray *strings is including empty value which is causing your error. You need to check it first and then do your logic.
//path is your file path
NSString* fileContents = [NSString stringWithContentsOfFile:path encoding:NSUTF8StringEncoding error:nil];
NSArray *strings = [fileContents componentsSeparatedByCharactersInSet:[NSCharacterSet newlineCharacterSet]];
for (int i = 0; i < [strings count]; i++){
if (![[strings objectAtIndex:i] isEqualToString:#""]){
//Here do your code...
}
}
I have a string like: "mocktail, wine, beer"
How can I convert this into: "mocktail", "wine", "beer"?
the following gives you the desired result:
NSString *_inputString = #"\"mocktail, wine, beer\"";
NSLog(#"input string : %#", _inputString);
NSLog(#"output string : %#", [_inputString stringByReplacingOccurrencesOfString:#", " withString:#"\", \""]);
the result is:
input string : "mocktail, wine, beer"
output string : "mocktail", "wine", "beer"
You need to use:
NSArray * components = [myString componentsSeparatedByString: #", "];
NSString *string = #"mocktail, wine, beer";
//remove whitespaces
NSString *trimmedString = [string stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
//get array of string
NSArray *array = [trimmedString componentsSeparatedByString:#","];
NSMutableArray *newArray = [[NSMutableArray alloc] init];
for (NSString *trimmedString in array) {
NSString *newString = [NSMutableString stringWithFormat:#"'%#'", trimmedString];
[newArray addObject:newString];
}
//merge new strings
NSString *finalString = [NSString stringWithFormat:#"%#", [newArray objectAtIndex:0]];
for (NSInteger i = 1; i < [newArray count]; i++) {
finalString = [NSString stringWithFormat:#"%#, %#", finalString, [newArray objectAtIndex:i]];
}
Without knowing spesifically about iOS or objective-c, I assume you could use a split function.
In almost any higher level programming language there is such a function.
Try:
Objective-C split
This gets you an array of Strings. You can then practically do with those what you want to do, e.g. surrounding them with single quotes and appending them back together. :D
how can I display 5 raise to 1/3 in iphone i.e I want 1/3 written above 5 can anyone help please
I Found this solution, hope so it would be helpful for you.
x to the power of y in a UILabel could be easy. Just replace your indices with unicode superscript characters... I use the following method to turn an integer into a string with superscript characters.
+(NSString *)convertIntToSuperscript:(int)i
{
NSArray *array = [[NSArray alloc] initWithObjects:#"⁰", #"¹", #"²", #"³", #"⁴", #"⁵", #"⁶", #"⁷", #"⁸", #"⁹", nil];
if (i >= 0 && i <= 9) {
NSString *myString = [NSString stringWithFormat:#"%#", [array objectAtIndex:i]];
[array release];
return myString;
}
else {
NSString *base = [NSString stringWithFormat:#"%i", i];
NSMutableString *newString = [[NSMutableString alloc] init];
for (int b = 0; b<[base length]; b++) {
int temp = [[base substringWithRange:NSMakeRange(b, 1)] intValue];
[newString appendString:[array objectAtIndex:temp]];
}
[array release];
NSString *returnString = [NSString stringWithString:newString];
[newString release];
return returnString;
}
}
Try this NSString *cmsquare=#"cm\u00B2";
It will display cm².
Yes you can do that but you need custom UILabel, either Make it by yourself or Get it Open Source..
I am having an array like fallowing,
NSArray*array = [NSArray arrayWithObjects:#"1.1 something", #"1.2 something else", #"1.3 out of left field", #"1.4 yet another!", nil];
Now,i am having the string like fallowing,
NSString*str = #"1.3";
Now i will send the str .Then it needs to find that str in array and it need to return the index of object where that text found.Means i need index 2 has to come as output.Can anyone share the code please.Thanks in advance.
Here is an example using blocks, notice the method: hasPrefix:
NSArray *array = [NSArray arrayWithObjects:#"1.1 problem1", #"1.2 problem2", #"1.3 problem3", #"1.4 problem4", nil];
NSString *str = #"1.3";
NSUInteger index = [array indexOfObjectPassingTest:
^(id obj, NSUInteger idx, BOOL *stop) {
return [obj hasPrefix:str];
}];
NSLog(#"index: %lu", index);
NSLog output:
index: 2
First a comment,
NSString *str = 1.3;
does not create an NSString object. You should instead have
NSString *str = #"1.3";
To search the NSArray, you will either have to change the string to the exact string in the array or search the NSString as well. For the former, simply do
float num = 1.3;
NSString *str = [NSString stringWithFormat:#"%.1f problem%d",num,(num*10)%10];
[array indexOfObject:str];
You can get fancier using NSPredicates as well.
Try
NSString *searchString = [str stringByAppendingFormat: #" problem%#", [str substringFromIndex: 2]];
NSUInteger index = [array indexOfObject: searchString];
Or (because you somehow like oneliners):
[array indexOfObject: [[array filteredArrayUsingPredicate: [NSPredicate predicateWithFormat: #"SELF beginswith %#", str]] objectAtIndex: 0]];
The simplest way is to enumerate through values of array and check substrings:
NSArray *array = [NSArray arrayWithObjects: #"1.1 something", #"1.2 something else", #"1.3 out of left field", #"1.4 yet another!", nil];
NSString *str = #"1.33";
int i = -1;
int index = -1;
for (NSString *arrayString in array) {
i++;
if ([arrayString rangeOfString: str].location != NSNotFound) {
index = i;
break;
}
}
NSLog(#"Index: %d", index);
Not optimal but will work.
I want to split an NSString into an NSArray. For example, given:
NSString *myString=#"ABCDEF";
I want an NSArray like:
NSArray *myArray={A,B,C,D,E,F};
How to do this with Objective-C and Cocoa?
NSMutableArray *letterArray = [NSMutableArray array];
NSString *letters = #"ABCDEF𝍱क्";
[letters enumerateSubstringsInRange:NSMakeRange(0, [letters length])
options:(NSStringEnumerationByComposedCharacterSequences)
usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
[letterArray addObject:substring];
}];
for (NSString *i in letterArray){
NSLog(#"%#",i);
}
results in
A
B
C
D
E
F
𝍱
क्
enumerateSubstringsInRange:options:usingBlock: available for iOS 4+ can enumerate a string with different styles. One is called NSStringEnumerationByComposedCharacterSequences, what will enumerate letter by letter but is sensitive to surrogate pairs, base characters plus combining marks, Hangul jamo, and Indic consonant clusters, all referred as Composed Character
Note, that the accepted answer "swallows" 𝍱and breaks क् into क and ्.
Conversion
NSString * string = #"A B C D E F";
NSArray * array = [string componentsSeparatedByString:#" "];
//Notice that in this case I separated the objects by a space because that's the way they are separated in the string
Logging
NSLog(#"%#", array);
This is what the console returned
NSMutableArray *chars = [[NSMutableArray alloc] initWithCapacity:[theString length]];
for (int i=0; i < [theString length]; i++) {
NSString *ichar = [NSString stringWithFormat:#"%C", [theString characterAtIndex:i]];
[chars addObject:ichar];
}
This link contains examples to split a string into a array based on sub strings and also based on strings in a character set. I hope that post may help you.
here is the code snip
NSMutableArray *characters = [[NSMutableArray alloc] initWithCapacity:[myString length]];
for (int i=0; i < [myString length]; i++) {
NSString *ichar = [NSString stringWithFormat:#"%c", [myString characterAtIndex:i]];
[characters addObject:ichar];
}
Without loop you can use this:
NSString *myString = #"ABCDEF";
NSMutableString *tempStr =[[NSMutableString alloc] initWithString:myString];
if([myString length] != 0)
{
NSError *error = NULL;
// declare regular expression object
NSRegularExpression *regex =[NSRegularExpression regularExpressionWithPattern:#"(.)" options:NSMatchingReportCompletion error:&error];
// replace each match with matches character + <space> e.g. 'A' with 'A '
[regex replaceMatchesInString:tempStr options:NSMatchingReportCompletion range:NSMakeRange(0,[myString length]) withTemplate:#"$0 "];
// trim last <space> character
[tempStr replaceCharactersInRange:NSMakeRange([tempStr length] - 1, 1) withString:#""];
// split into array
NSArray * arr = [tempStr componentsSeparatedByString:#" "];
// print
NSLog(#"%#",arr);
}
This solution append space in front of each character with the help of regular expression and uses componentsSeparatedByString with <space> to return an array
Swift 4.2:
String to Array
let list = "Karin, Carrie, David"
let listItems = list.components(separatedBy: ", ")
Output : ["Karin", "Carrie", "David"]
Array to String
let list = ["Karin", "Carrie", "David"]
let listStr = list.joined(separator: ", ")
Output : "Karin, Carrie, David"
In Swift, this becomes very simple.
Swift 3:
myString.characters.map { String($0) }
Swift 4:
myString.map { String($0) }