I have the follow code:
NSArray *myArray = [NSArray arrayWithObjects: #"e", #"è", #"é",#"i","ò",nil];
NSString *string = #"simpleè";
NSMutablestring *newString;
for(i=0>;i< [string length]; i++){
if([stringa characterAtIndex:i] is in Array){
[newString appendFormat:#"%c", [string characterAtIndex:i]];
}
}
How make finding if single char of string stay in the array?
Example of result:
newString= #"ieè";
I think you want to apply rangeOfCharacterFromSet:options:range: repeatedly. You'll have to create a NSCharacterSet from the characters in your array somehow.
Added
Though it probably would be just as simple to just loop through the string with characterAtIndex and compare each char (in an inner loop) to the chars in your array (which you could extract into a unichar array or put into a single NSString to make easier to access).
Umm... if you want to check what the values are you can use NSLog
NSLog"%f", myFloat;
So you can use this to check your array... Which is what I think you are asking for, but the grammar in your question isn't very good. Please provide more details and better grammar.
You should check the length of your string and then match your string characters with the array and if found append that character in a new string.
NSString *mstr = #"asdf";
NSString *b = [ mstr characterAtIndex:0];
Hope it helps.......
You'll want to create an NSCharacterSet with the characters in the string and then ask each string in the array for its rangeOfCharacterFromSet:. If you find one where a range was actually found, then a character from the string is in the array. If not, then none of them are.
This might seem a bit roundabout, but Unicode makes looking at strings as just a series of "chars" rather unreliable, and you'll want to let your libraries do as much of the heavy lifting for you as they can.
There are better ways to do this, but this is what I think you're trying to do:
NSMutableString* result= [NSMutableString stringWithString:#""];
for( int i= 0; i < [string length]; ++i ) {
NSString* c= [NSString stringWithFormat:#"%C", [string characterAtIndex:i]];
if( [myArray containsObject:c] )
[result appendString:c];
}
Related
I have the following NSMutableString:
#"1*2*3*4*5"
I want to find the first * and remove everything after it, so my string = #"1"; How do I do this?
NSMutableString *string = [NSMutableString stringWithString:#"1*2*3*4*5"];
NSRange range = [string rangeOfString:#"*"];
if (range.location != NSNotFound)
{
[string deleteCharactersInRange:NSMakeRange(range.location, [string length] - range.location)];
}
You could try to divide this string by a separator and get the first object
NSString *result = [[MyString componentsSeparatedByString:#"*"]objectAtIndex:0];
After calling componentsSeparatedByString:#"*" you'll get the array of strings, separated by *,and the first object is right what you need.
Here's yet another strategy, using the very flexible NSScanner.
NSString* beginning;
NSScanner* scanner = [NSScanner scannerWithString:#"1*2*3*4*5"];
[scanner scanUpToString:#"*" intoString:&beginning];
You could use -rangeOfString: to find the index of the first asterisk and use that with -substringToIndex: to extract a substring from the original input. Something like this perhaps...
NSMutableString *input = #"1*2*3*4*5";
// Finds the range of the first instance. See NSString docs for more options.
NSRange firstAsteriskRange = [input rangeOfString:#"*"];
NSString *trimmedString = [input substringToIndex:firstAsteriskRange.location + 1];
i have a nsmutablearray which have 5 objects.
for example if it contain objects like apple, cat , ball, dog ,ant, i want them to append with comma separated that is like apple, cat , ball, dog ,ant. please help me with this.
edit
publishingpost //nsmutable array contains all these object
-(ibaction)post
{
nsstring *str;
nsstring *str2 =#",";
for(int i = 0; i< [publishingpost count]; i++){
nsstring *str = [publishingpost objectAtIndex:i];
//append both str1, str2 to generate comma separated objects
}
use - (NSString *)componentsJoinedByString:(NSString *)separator instead:
- (IBAction)post {
NSString * str = [publishingpost componentsJoinedByString:#", "];
}
Take a look at stringByAppendingString: or stringByAppendingFormat from here. It should be easy enough to do if you already have the Strings.
Declare an NSString object before the for loop (or use str) and append to that while going through the loop. And you're not supposed to declare str twice in your code. Might want to rename one of them.
I have a paragraph (4 sentences) of text in an .plist array that loads into a UITextView.
By default, it presents the text how it is, as one big lump of text in a paragraph. I want to know if it is possible to split this up?
Such as Line 1: sdfafasfsafsa, then line 2: asfdsafs, line 3: adfsfsdfsdfa, etc.
Is there a way I can search for a . and then separate the lines accordingly? I would just edit the plist manually but there are hundreds of entries so it isn't easy to do.
NSString* tidiedString = [sourceString stringByReplacingOccurrencesOfString:#"." withString:#"\n"];
Update: OK, so more detail is coming through. You could use a regular expression - but if you're not familiar, the learning curve is a bit steep. Otherwise, as with other answers, crank through the list. You need to take care of whitespaces, empty lines etc. The following snippet isn't pretty, but will do the job.
NSString* sourceString = #"Hyperlinks can be great. They can also dilute your focus and tempt you into putting off what you most want to do. Here I chose to place links at the foot of the page to help you to make an active choice as to whether to surf or refocus your attention elsewhere.";
NSArray* arrayOfStrings = [sourceString componentsSeparatedByString:#"."];
NSMutableString* superString = [NSMutableString stringWithString:#""];
int lineCount = 1;
for (NSString* string in arrayOfStrings)
{
if ([string length] < 1) continue;
[superString appendFormat:#"Line %d: %#.\n", lineCount++, [string stringByTrimmingCharactersInSet: [NSCharacterSet whitespaceAndNewlineCharacterSet]]];
}
[superString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
[[self userEntry] setText:superString];
NSArray *array = [sourceString componentsSeparatedByString:#"."];
NSMutableString *resultString= [[NSMutableString alloc] init];
int linecount=1;
for(NSString *lines in array)
{
[resultString appendString:[NSString stringWithFormat:#"Line%i:%#\n",linecount++,lines]];
}
NSLog(#"resultString:%#",resultString);
this may help..!!
Try making a loop that runs through the array and that adds every line to the UITextView plus #"\n".
So something like...:
NSString *curText = txtView.text;
NSString *lineBreak = #"\n";
txtView.text=[NSString stringWithFormat:#"%# + %#", curText, lineBreak];
Or just replace the dots by #"\n".
I have an NSString of integer values. I need to add each one of the integers as a separate object in an NSMutableArray.
I tried characterAtIndex: but I keep getting errors…
P.s. I've solved over 30 problems thank's to stackoverflow's search, but didn't find any information on this problem.
NSMutableArray *results = [NSMutableArray array];
for (int i = 0; i < [string length]; i++)
{
NSString *substr = [string substringWithRange:NSMakeRange(i,1)];
[results addObject:[NSNumber numberWithInt:[substr intValue]];
}
NSLog(#" %# separated into: %#", string, results);
Consider looking at componentsSeparatedByString: or componentsSeparatedByCharactersInSet: for your purpose. Both methods are available on NSString.
If your integers are more than one digit or are space-separated, consider alternately using an NSScanner - you can read instances of NSInteger off the string one by one, wrap them in NSNumbers, and stick them in your array.
i have a string and i want to check for the multiple characters in this string the following code i working fine for one character how to check for the multiple characters.
NSString *yourString = #"ABCCDEDRFFED"; // For example
NSScanner *scanner = [NSScanner scannerWithString:yourString];
NSCharacterSet *charactersToCount = #"C" // For example
NSString *charactersFromString;
if (!([scanner scanCharactersFromSet:charactersToCount intoString:&charactersFromString])) {
// No characters found
NSLog(#"No characters found");
}
NSInteger characterCount = [charactersFromString length];
UPDATE: The previous example was broken, as NSScanner should not be used like that. Here's a much more straight-forward example:
NSString* string = #"ABCCDEDRFFED";
NSCharacterSet* characters = [NSCharacterSet characterSetWithCharactersInString:#"ABC"];
NSUInteger characterCount;
NSUInteger i;
for (i = 0; i < [yourString length]; i++) {
unichar character = [yourString characterAtIndex:i];
if ([characters characterIsMember:character]) characterCount++;
}
NSLog(#"Total characters = %d", characterCount);
Have a look at the following method in NSCharacterSet:
+ (id)characterSetWithCharactersInString:(NSString *)aString
You can create a character set with more than one character (hence the name character set), by using that class method to create your set. The parameter is a string, every character in that string will end up in the character set.
Also look up NSCountedSet. It can help you keep count of multiple instances of the same character.
For example, from the docs:
countForObject:
Returns the count associated with a given object in the receiver.
- (NSUInteger)countForObject:(id)anObject
Parameters
anObject
The object for which to return the count.
Return Value
The count associated with anObject in the receiver, which can be thought of as the number of occurrences of anObject present in the receiver.