This is strictly a learning experience:
I have a .CSV file that I'm using to define my deployment environments. One of the variables has to be in a Hash Table format.
Can anyone come up with a clever way to put it all in one line?
Right now I harvest them as a string from CSV, conver to array, convert array to hash table.
Simplified code:
Foreach($i in $DefaultCSV){...
$App_Fabric_Hosts_a = $i.App_Fabric_Hosts.split(",")}
$App_Fabric_Hosts_h = #{}
foreach($r in $App_Fabric_Hosts_a){$App_Fabric_Hosts_h.add($r,"22233")}
This is the best I came up with:
$d=#{};foreach($r in $DefaultCSV[$arrayposition].app_fabric_hosts.split(",")){$d.add($r,"22233")}
Related
I am not looking for a working solution but rather an idea to push me in the right direction as I was thrown a curveball I am not sure how to tackle.
Recently I wrote a script that used split command to check the first part of the file against the folder name. This was successful so now there is a new ask: check all the files against the naming matrix, problem is there are like 50+ file formats on the list.
So for example format of a document would be ID-someID-otherID-date.xls
So for example 12345678-xxxx-1234abc.xls as a format for the amount of characters to see if files have the correct amount of characters in each section to spot typos etc.
Is there any other reasonable way of tackling that besides Regex? I was thinking of using multiple splits using the hyphens but don't really have anything to reference that against other than the amount of characters required in each part.
As always, any (even vague) pointers are most welcome ;-)
Although I would use a regex (as also commented by zett42), there is indeed an other way which is using the ConvertFrom-String cmdlet with a template:
$template = #'
{[Int]Some*:12345678}-{[String]Other:xxxx}-{[DateTime]Date:2022-11-18}.xls
{[Int]Some*:87654321}-{[String]Other:yyyy}-{[DateTime]Date:18Nov2022}.xls
'#
'23565679-iRon-7Oct1963.xls' | ConvertFrom-String -TemplateContent $template
Some : 23565679
Other : iRon
Date : 10/7/1963 12:00:00 AM
RunspaceId : 3bf191e9-8077-4577-8372-e77da6d5f38d
I am looking to convert a collection of comma delimited strings that I have as a variable into a hash table / array in Powershell.
For example
$test =
Heading1,Heading2,Heading3
Line1,Line1,Line1
Line2,Line2,Line2
Is there a way I can easily convert this to a hash table or array so that I can easily retrieve all data under Heading3?
Variable was already in csv format so just had to use convertto-csv $test to get it into hash table / array format.
Thank you to Olaf in the comments for this answer!
I am new to using powershell and I am in need of some assistance.
I have a csv file that looks like this:
DisplayName,AllJSSUSers,ALLMobileDevices,LimitToUsers,Exclusions,DepartmentEx,IconURL,ID
Aurasma,TRUE,TRUE,"G_Year 4,G_Year 7,G_Year 11,G_Year 6,G_Year 10,G_Year 5,G_Year 9,G_Teaching Staff,G_Year 8,G_Supply Teachers,G_Year 3,G_Year 12",,,,5
What I would like to do is split the column "LimitToUsers" where the commas are into multiple column and then output that to a new csv file.
I have no idea where to start with this. Can anyone help?
Thank you
Gavin
You can read CSV data with Import-Csv.
You can access that column from each data object by accessing the LimitToUsers property.
You can split a string with the -split operator.
You can add new properties to object with Add-Member.
You can write CSV with Export-Csv.
Since you somehow have to split a single column into multiple ones, how you do that is up to you and I can't help you there
I have multiple arrays with string data. All of them should be exported into a .csv file. The file should be saved in a subfolder. The file name is variable.
I used the code as follows:
fpath = ('./Subfolder/');
m_date = inputdlg('Date of measurement [yyyymmdd_exp]');
m_name = inputdlg('Characteristic name of the expteriment');
fformat = ('.csv');
fullstring = strcat(fpath, m_date,'_', m_name, fformat);
dlmwrite(fullstring,measurement);
However, I get an error that FILE must be a filename string or numeric FID
What's the reason?
Best
Andreas
What you are asking to do is fairly straightforward for Matlab or Octave. The first part is creating a file with a filename that changes. the best way to do this is by concatenating the strings to build the one you want.
You can use: fullstring = strcat('string1','string2')
Or specifically: filenameandpath = strcat('./Subfolder/FixedFileName_',fname)
note that because strings are pretty much just character arrays, you can also just use:
fullstring = ['string1','string2']
now, if you want to create CSV data, you'll first have to read in the file, possibly parse the data in some way, then save it. As Andy mentioned above you may just be able to use dlmwrite to create the output file. We'll need to see a sample of the string data to have an idea whether any more work would need to be done before dlmwrite could handle it.
I am still learning perl and have all most got a program written. My question, as simple as it may be, is if I want to hardcode a string to a field would the below do that? Thank you :).
$out[45]="VUS";
In the other lines I use the below to define the values that are passed into the `$[out], but the one in question is hardcoded and the others come from a split.
my #vals = split/\t/; # this splits the line at tabs
my #mutations=split/,/,$vals[9]; # splits on comma to create an array of mutations
my ($gene,$transcript,$exon,$coding,$aa);
for (#mutations)
{
($gene,$transcript,$exon,$coding,$aa) = split/\:/; # this takes col AB and splits it at colons
grep {$transcript eq $_} keys %nms or next;
}
my #out=($.,#colsleft,$_,#colsright);
$out[2]=$gene;
$out[3]=$nms{$transcript};
$out[4]=$transcript;
$out[15]=$coding;
$out[17]=$aa;
Your line of code: $out[45]="VUS"; is correct in that it is defining that 46th element of the array #out to the string, "VUS". I am trying to understand from your code, however why you would want to do that? Usually, it is better practice to not hardcode if at all possible. You want to make it your goal to make your program as dynamic as possible.