I would like to search for an NSString in another NSString, such that the result is found even if the second one does not start with the first one, for example:
eg: I have a search string "st". I look in the following records to see if any of the below contains this search string, all of them should return a good result, because all of them have "st".
Restaurant
stable
Kirsten
At the moment I am doing the following:
NSComparisonResult result = [selectedString compare:searchText options:(NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch) range:NSMakeRange(0, [searchText length])];
This works only for "stable" in the above example, because it starts with "st" and fails for the other 2. How can I modify this search so that it returns ok for all the 3?
Thanks!!!
Why not google first?
String contains string in objective-c
NSString *string = #"hello bla bla";
if ([string rangeOfString:#"bla"].location == NSNotFound) {
NSLog(#"string does not contain bla");
} else {
NSLog(#"string contains bla!");
}
Compare is used for testing less than/equal/greater than. You should instead use -rangeOfString: or one of its sibling methods like -rangeOfString:options:range:locale:.
I know this is an old thread thought it might help someone.
The - rangeOfString:options:range: method will allow for case insensitive searches on a string and replace letters like ‘ö’ to ‘o’ in your search.
NSString *string = #"Hello Bla Bla";
NSString *searchText = #"bla";
NSUInteger searchOptions = NSCaseInsensitiveSearch | NSDiacriticInsensitiveSearch;
NSRange searchRange = NSMakeRange(0, string.length);
NSRange foundRange = [string rangeOfString:searchText options:searchOptions range:searchRange];
if (foundRange.length > 0) {
NSLog(#"Text Found.");
}
For more comparison options NSString Class Reference
Documentation on the method - rangeOfString:options:range: can be found on the NSString Class Reference
Related
I am writing code in objective-c. I would like to extract a url from a string.
Here is my code:
NSMutableString *oneContent = [[latestPosts objectAtIndex:i] objectForKey:#"content"];
NSLog(#"%#", oneContent);//no problem
NSString *string = #"http";
if ([oneContent rangeOfString:string].location == NSNotFound) {
NSLog(#"string does not contain substring");
} else {
NSLog(#"string contains substring!");
}
As you can see, I want to extract a url from the oneContent string, and I have checked that oneContent definitely contains "http", but why does the result show nothing?
Is there some better way to extract the url?
Check oneContent or the actual code you are running.
This works:
NSMutableString *oneContent = [#"asdhttpqwe" mutableCopy];
NSLog(#"%#", oneContent);//no problem
NSString *string = #"http";
if ([oneContent rangeOfString:string].location == NSNotFound) {
NSLog(#"string does not contain substring");
} else {
NSLog(#"string contains substring!");
}
NSLog output:
Untitled[5911:707] asdhttpqwe
Untitled[5911:707] string contains substring!
It is probably best not to use a Mutable string unless there is some substantial reason to do so.
I would suggest using NSScanner.
I have the following NSMutableString:
#"1*2*3*4*5"
I want to find the first * and remove everything after it, so my string = #"1"; How do I do this?
NSMutableString *string = [NSMutableString stringWithString:#"1*2*3*4*5"];
NSRange range = [string rangeOfString:#"*"];
if (range.location != NSNotFound)
{
[string deleteCharactersInRange:NSMakeRange(range.location, [string length] - range.location)];
}
You could try to divide this string by a separator and get the first object
NSString *result = [[MyString componentsSeparatedByString:#"*"]objectAtIndex:0];
After calling componentsSeparatedByString:#"*" you'll get the array of strings, separated by *,and the first object is right what you need.
Here's yet another strategy, using the very flexible NSScanner.
NSString* beginning;
NSScanner* scanner = [NSScanner scannerWithString:#"1*2*3*4*5"];
[scanner scanUpToString:#"*" intoString:&beginning];
You could use -rangeOfString: to find the index of the first asterisk and use that with -substringToIndex: to extract a substring from the original input. Something like this perhaps...
NSMutableString *input = #"1*2*3*4*5";
// Finds the range of the first instance. See NSString docs for more options.
NSRange firstAsteriskRange = [input rangeOfString:#"*"];
NSString *trimmedString = [input substringToIndex:firstAsteriskRange.location + 1];
I have a string that contains words with consonants and vowels. How can I extract only consonants from the string?
NSString *str = #"consonants.";
Result must be:
cnsnnts
You could make a character set with all the vowels (#"aeiouy")
+ (id)characterSetWithCharactersInString:(NSString *)aString
then use the
- (NSString *)stringByTrimmingCharactersInSet:(NSCharacterSet *)set
method.
EDIT: This will only remove vowels at the beginning and end of the string as pointed out in the other post, what you could do instead is use
- (NSArray *)componentsSeparatedByCharactersInSet:(NSCharacterSet *)separator
then stick the components back together. You may also need to include capitalized versions of the vowels in the set, and if you want to also deal with accents (à á è è ê ì etc...) you'll probably have to include that also.
Unfortunately stringByTrimmingCharactersInSet wont work as it only trim leading and ending characters, but you could try using a regular expression and substitution like this:
[[NSRegularExpression
regularExpressionWithPattern:#"[^bcdefghjklmnpqrstvwx]"
options:NSRegularExpressionCaseInsensitive
error:NULL]
stringByReplacingMatchesInString:str
options:0
range:NSMakeRange(0, [str length])
withTemplate:#""]
You probably want to tune the regex and options for your needs.
Possible, for sure not-optimal, solution. I'm printing intermediate results for your learning. Take care of memory allocation (I didn't care). Hopefully someone will send you a better solution, but you can copy and paste this for the moment.
NSString *test = #"Try to get all consonants";
NSMutableString *found = [[NSMutableString alloc] init];
NSInteger loc = 0;
NSCharacterSet *consonants = [NSCharacterSet characterSetWithCharactersInString:#"bcdfghjklmnpqrstvwxyz"];
while(loc!=NSNotFound && loc<[test length]) {
NSRange r = [[test lowercaseString] rangeOfCharacterFromSet:consonants options:0 range:NSMakeRange(loc, [test length]-loc)];
if(r.location!=NSNotFound) {
NSString *temp = [test substringWithRange:r];
NSLog(#"Range: %# Temp: %#",NSStringFromRange(r), temp);
[found appendString:temp];
loc=r.location+r.length;
} else {
loc=NSNotFound;
}
}
NSLog(#"Found: %#",found);
Here is a NSString category that does the job:
- (NSString *)consonants
{
NSString *result = [NSString stringWithString:self];
NSCharacterSet *characterSet = [NSCharacterSet characterSetWithCharactersInString:#"aeiou"];
while(1)
{
NSRange range = [result rangeOfCharacterFromSet:characterSet options:NSCaseInsensitiveSearch];
if(range.location == NSNotFound)
break;
result = [result stringByReplacingCharactersInRange:range withString:#""];
}
return result;
}
I would like to test a string to see if anywhere it contains the text "hello". I would like the test to not take into account capitalization. How can I test this string?
Use the below code as reference to find check for a substring into a string.
NSString* string = #"How to test a string for text" ;
NSString* substring = #"string for" ;
NSRange textRange;
textRange =[string rangeOfString:substring options:NSCaseInsensitiveSearch];
if(textRange.location != NSNotFound)
{
//Does contain the substring
}
-[NSString rangeOfString: options:] will do it.
NSRange range = [string rangeOfString:#"hello" options:NSCaseInsensitiveSearch];
BOOL notFound = range.location==NSNotFound;
I am assuming all words are separated by a space, and that there is no punctuation. If there is punctuation.
NSArray *dataArray = [inputString componentsSeparatedByString:#" "];
for(int i=0; i<[dataArray count]){
if([[dataArray objectAtIndex:i] isEqualToString:#"hello"]){
NSLog(#"hello has been found!!!");
}
}
I haven't tested this but it should work in theory.
Check out the docs for ways to remove punctuation and make the string all lower case. This should be pretty straight-forward.
Other solutions here are good but you should really use a regex,
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"^(hello)*$"
options:NSRegularExpressionCaseInsensitive
error:&error];
Docs are here: http://developer.apple.com/library/ios/#documentation/Foundation/Reference/NSRegularExpression_Class/Reference/Reference.html
I searched a bit, but couldn't find an answer to this (probably very simple) question.
I have an NSString, and I'd like to check if it contains a word. Something like this:
NSString *sentence = #"The quick brown fox";
NSString *word = #"quack";
if ([sentence containsWord:word]) {
NSLog(#"Yes it does contain that word");
}
Thanks.
The following should work:
NSString *sentence = #"The quick brown fox";
NSString *word = #"quack";
if ([sentence rangeOfString:word].location != NSNotFound) {
NSLog(#"Yes it does contain that word");
}
It uses rangeOfString: to return an NSRange structure, indicating the location of the word, if it can't find it NSRange.location will be equal to NSNotFound.