I have column of type date time and values are getting stored in format 10-29-2011 08:25.
I would like to find out the rows only which are less then current date-time. What will be the condition for date comparison for current date and this date-time column field?
Thanks.
you could use the datetime function
SELECT * FROM mytable
WHERE mydate > datetime('now')
you can even make date operations
SELECT * FROM mytable
WHERE mydate > datetime('now','-15 days')
Related
I want to query postgres database table which has the column with timestamp in long milliseconds. But I have the time in date format "yyyy-MM-dd HH:mm:ssZ" like this. How can I convert this date format to long milliseconds to run the query?
You can either convert your long value to a proper timestamp:
select *
from the_table
where to_timestamp(the_millisecond_column / 1000) = timestamp '2020-10-05 07:42'
Or extract the seconds from the timestamp value :
select *
from the_table
where the_millisecond_column = extract(epoch from timestamp '2020-10-05 07:42') * 1000
The better solution is however to convert that column to a proper timestamp column to avoid the constant conversion between (milliseconds) and proper timestamp values
I am looking to get the row which has the date is equal to 2017-01-12. The date has field type timestamp without time zone. I tried
SELECT * FROM tabl WHERE date = 2017-01-12;
What is the correct syntax?
try:
SELECT * FROM tabl WHERE date = '2017-01-12';
If that doesn't work, try an explicit cast:
SELECT *
FROM tabl
WHERE date = DATE '2017-01-12';
I'm trying to convert value for DIM_DT_ID to MMddYY. I'm successful in doinf that. However, query fails because ultimately I'm comparing a character value to date here. Is there a way by which I can get value for DIM_DT_ID in MMddyy format and its data type still remains DATE ?
Here DIM_DT_ID
SELECT DIM_DT_ID
DIM_DT_ID >= FORMATDATE('MMddyy',ADDDAY(TO_date('yyyy-MM-dd','2016-12-21'), -25)); from abc;
Regards,
Ajay
In Denodo, to convert a string to a date field, use "to_date()" (which returns a date).
Then, don't convert back to a string, leave that field as a date (so don't use "Formatdate()", which returns a string).
So:
SELECT *
FROM MyTable
WHERE now() >= to_date('yyyy-MM-dd',myStringFieldThatLooksLikeADate)
In my example, "now()" is a date, and so is the output of the to_date function... so you can do a comparison.
If you try to convert the date back to a string using formatdate, it won't work:
#This doesn't work:
SELECT *
FROM MyTable
WHERE now() >= formatdate('MMddyy',to_date('yyyy-MM-dd',myStringFieldThatLooksLikeADate))
It doesn't work because we are comparing a date ("now()") to a string.
What I am trying to do is get a result from sql where the dates are in a certain range but its not working correctly, here is my query.
DECLARE #CurrDate DATETIME
SET #CurrDate = GETDATE()
SELECT dbo.ProductDetails.PartnerID
,dbo.ProductDetails.ProductID
,dbo.Products.ProductName
,StartDate
,EndDate
FROM dbo.ProductDetails
INNER JOIN dbo.Products
ON dbo.ProductDetails.ProductID = dbo.Products.ProductID
WHERE CONVERT(VARCHAR(10),StartDate,111) <= #CurrDate
AND CONVERT(VARCHAR(10),EndDate, 111) >= #CurrDate
but when the Enddate = #CurrDate the row does not show, but if i make that date just one day higher it gets displayed. Am i doing anything wrong? Any advice will do, thanks.
GetDate() returns date and time, while your conversion to varchar strips away the time part (I'm suspecting that's all it's actually supposed to do). So you would need to do the same conversion for #CurrDate.
If what you want is to simply consider the date only (ignoring the time part), you could use DATEDIFF instead of converting to varchar (see here); example:
DECLARE #CurrDate DATETIME
SET #CurrDate = GETDATE()
SELECT dbo.ProductDetails.PartnerID, dbo.ProductDetails.ProductID,
dbo.Products.ProductName , StartDate, EndDate
FROM dbo.ProductDetails INNER JOIN
dbo.Products ON dbo.ProductDetails.ProductID = dbo.Products.ProductID
-- where StartDate is on the same day or before CurrDate:
WHERE DATEDIFF(day, StartDate, #CurrDate) >= 0 AND
-- and where EndDate is on the same day or after CurrDate:
DATEDIFF(day, EndDate, #CurrDate) <= 0
If you want only DATE comparison, without time use the
cast(CONVERT(varchar, StartDate, 112) as datetime)
I am quite sure that the comparison takes into account the time as well as the date, in which case if the dates are the same but the current time is greater than the time being compared to you won't get that row as a result.
So, what you need to do is just extract the date part and compare those.
GETDATE() gives you date and time
if yours column have only date
then
CONVERT(VARCHAR(10),StartDate,111) <= #CurrDate
can give you unexpected result
remember
19.12.2011 14:41 > 19.12.2011 00:00
If you are using SQL 2008 or later, and wanting to compare only the date, not the time, you can also do:
Cast(StartDate as Date)
(This avoids having to convert to a string.)
When I apply a date range to my query, is there anyway to display the dates used in the date range even if there is no data at those dates?
Suppose I use,
... where date between '1/12/2010' and '31/12/2010' order by date
What I want in my result is to show sum of all amount column until 1/12/2010 on that day even if there is no data for that date and also same for 31/12/2010.
Join with generate_series() to fill in the gaps.
Example:
CREATE TEMP TABLE foo AS SELECT CURRENT_DATE AS today;
SELECT
COUNT(foo.*),
generate_series::date
FROM
foo
RIGHT JOIN generate_series('2010-12-18', '2010-12-25', interval '1 day') ON generate_series = today
GROUP BY
generate_series;
Result:
0,'2010-12-18'
0,'2010-12-19'
1,'2010-12-20'
0,'2010-12-21'
0,'2010-12-22'
0,'2010-12-23'
0,'2010-12-24'
0,'2010-12-25'