I have a text file looking like this:
(-9.1744438E-02,7.6282293E-02) (-9.1744438E-02,7.6282293E-02) ... and so on.
I would like to modify the file by removing all the parenthesis and a new line for each couple
so that it look like this:
-9.1744438E-02,7.6282293E-02
-9.1744438E-02,7.6282293E-02
...
A simple way to do that?
Any help is appreciated,
Fred
I would use tr for this job:
cat in_file | tr -d '()' > out_file
With the -d switch it just deletes any characters in the given set.
To add new lines you could pipe it through two trs:
cat in_file | tr -d '(' | tr ')' '\n' > out_file
As was said, almost:
sed 's/[()]//g' inputfile > outputfile
or in awk:
awk '{gsub(/[()]/,""); print;}' inputfile > outputfile
This would work -
awk -v FS="[()]" '{for (i=2;i<=NF;i+=2) print $i }' inputfile > outputfile
Test:
[jaypal:~/Temp] cat file
(-9.1744438E-02,7.6282293E-02) (-9.1744438E-02,7.6282293E-02)
[jaypal:~/Temp] awk -v FS="[()]" '{for (i=2;i<=NF;i+=2) print $i }' file
-9.1744438E-02,7.6282293E-02
-9.1744438E-02,7.6282293E-02
This might work for you:
echo "(-9.1744438E-02,7.6282293E-02) (-9.1744438E-02,7.6282293E-02)" |
sed 's/) (/\n/;s/[()]//g'
-9.1744438E-02,7.6282293E-02
-9.1744438E-02,7.6282293E-02
Guess we all know this, but just to emphasize:
Usage of bash commands is better in terms of time taken for execution, than using awk or sed to do the same job. For instance, try not to use sed/awk where grep can suffice.
In this particular case, I created a file 100000 lines long file, each containing characters "(" as well as ")". Then ran
$ /usr/bin/time -f%E -o log cat file | tr -d "()"
and again,
$ /usr/bin/time -f%E -ao log sed 's/[()]//g' file
And the results were:
05.44 sec : Using tr
05.57 sec : Using sed
cat in_file | sed 's/[()]//g' > out_file
Due to formatting issues, it is not entirely clear from your question whether you also need to insert newlines.
Related
I have a simple .csv file with lines that holds 't' values. Here is the example:
2ABC;t;t;t;tortuga;fault;t;t;bored
I want to replace them to '1' using sed.
If I make sed "s/;t;/;1;/g" I get the next result:
2ABC;1;t;1;tortuga;fault;1;t;bored
As you can see, consecutive ';t;' have been replaced through one. Yes, I can replace all ';t;' by sed -e "s/;t;/;1;/g" -e "s/;t;/;1;/g" but this is boring.
How can I make the replacement by one sed command?
If there is something to replace, branch to replace again.
sed ': again; /;t;/{ s//;1;/; b again }'
Overall, parsing cvs with sed is crude. Consider awk.
awk -F';' -v OFS=';' '{ for(i=1;i<=NF;++i) if ($i=="t") $i=1 } 1'
Lookarounds is helpful in such cases:
$ s='t;2ABC;t;t;t;tortuga;fault;t;t;bored;t'
$ echo "$s" | perl -lpe 's/(?<![^;])t(?![^;])/1/g'
1;2ABC;1;1;1;tortuga;fault;1;1;bored;1
echo '2ABC;t;t;t;tortuga;fault;t;t;bored' |
— gawk-specific solution
gawk -be '(ORS = RT)^!(NF = NF)' FS='^t$' OFS=1 RS=';'
— cross-awk-solution
{m,g,n}awk 'gsub(FS, OFS, $!(NF = NF))^_' FS=';t;' OFS=';1;' RS=
2ABC;1;1;1;tortuga;fault;1;1;bored
I have a file as below
NAME(BOLIVIA) TYPE(SA)
APPLIC(Java) IP(192.70.xxx.xx)
NAME(BOLIVIA) TYPE(SA)
APPLIC(Java) IP(192.71.xxx.xx)
I am trying to extract the values NAME and IP using sed:
cat file1 |
sed ':a
N
$!ba
s/\n/ /g' | sed -n 's/.*\(NAME(BOLI...)\).*\(IP(.*)\).*/\1 \2/p'
However, I'm only getting the output:
NAME(BOLIVIA) IP(192.71.xxx.xx)
What I would like is:
NAME(BOLIVIA) IP(192.70.xxx.xx)
NAME(BOLIVIA) IP(192.71.xxx.xx)
Would appreciate it if someone could give me a pointer on what I'm missing.
TIA
Your first sed commands reformats the file into one long line. You could have used tr -d "\n" for this, but that is not the problem.
The problem is in the second part, where the .* greedy eats as much as possible until finding the last match.
Your solution could be "fixed" with the ugly
# Do not use this:
sed -zn 's/[^\n]*\(NAME(BOLI...)\)[^\n]*\n[^\n]*\(IP([^)]*)\)[^\n]*/\1 \2/gp' file1
Possible solutions:
cat file1 | paste -d " " - - | sed -n 's/.*\(NAME(BOLI...)\).*\(IP(.*)\).*/\1 \2/p'
# or
grep -Eo "(NAME\(BOLI...\)|IP\(.*\))" file1 | paste -d " " - -
# or
printf "%s %s\n" $(grep -Eo "(NAME\(BOLI...\)|IP\(.*\))" file1)
In case you are ok with awk could you please try following. Written and tested in link
https://ideone.com/bJDzgf with shown samples only.
awk '
match($0,/^NAME\([^)]*/){
name=substr($0,RSTART+5,RLENGTH-5)
next
}
match($0,/IP\([^)]*/){
print name,substr($0,RSTART+3,RLENGTH-3)
name=""
}
' Input_file
This might work for you (GNU sed):
sed -n '/NAME/{N;/IP/s/\s.*\s/ /p}' file
If a line contains NAME and the following line contains IP remove everything between and print the result.
An alternative shorter awk:
awk '$1 ~ /^NAME/ {nm = $1} $2 ~ /^IP/ {print nm, $2}' file
NAME(BOLIVIA) IP(192.70.xxx.xx)
NAME(BOLIVIA) IP(192.71.xxx.xx)
The issue in your script is the use .* which matches in a greedy way
so that you have only the first NAME(BOLI...) and last IP(.*)
If you can use python :
#!/bin/bash
python -c '
import re, sys
for ar in re.findall(r"(NAME\(BOLI.*?\)).*?(IP\(.*?\))", sys.stdin.read(), re.DOTALL):
print(*ar)
' < input-file
This is mostly by curiosity, I am trying to have the same behavior as:
echo -e "test1:test2:test3"| sed 's/:/\n/g' | grep 1
in a single sed command.
I already tried
echo -e "test1:test2:test3"| sed -e "s/:/\n/g" -n "/1/p"
But I get the following error:
sed: can't read /1/p: No such file or directory
Any idea on how to fix this and combine different types of commands into a single sed call?
Of course this is overly simplified compared to the real usecase, and I know I can get around by using multiple calls, again this is just out of curiosity.
EDIT: I am mostly interested in the sed tool, I already know how to do it using other tools, or even combinations of those.
EDIT2: Here is a more realistic script, closer to what I am trying to achieve:
arch=linux64
base=https://chromedriver.storage.googleapis.com
split="<Contents>"
curl $base \
| sed -e 's/<Contents>/<Contents>\n/g' \
| grep $arch \
| sed -e 's/^<Key>\(.*\)\/chromedriver.*/\1/' \
| sort -V > out
What I would like to simplify is the curl line, turning it into something like:
curl $base \
| sed 's/<Contents>/<Contents>\n/g' -n '/1/p' -e 's/^<Key>\(.*\)\/chromedriver.*/\1/' \
| sort -V > out
Here are some alternatives, awk and sed based:
sed -E "s/(.*:)?([^:]*1[^:]*).*/\2/" <<< "test1:test2:test3"
awk -v RS=":" '/1/' <<< "test1:test2:test3"
# or also
awk 'BEGIN{RS=":"} /1/' <<< "test1:test2:test3"
Or, using your logic, you would need to pipe a second sed command:
sed "s/:/\n/g" <<< "test1:test2:test3" | sed -n "/1/p"
See this online demo. The awk solution looks cleanest.
Details
In sed solution, (.*:)?([^:]*1[^:]*).* pattern matches an optional sequence of any 0+ chars and a :, then captures into Group 2 any 0 or more chars other than :, 1, again 0 or more chars other than :, and then just matches the rest of the line. The replacement just keeps Group 2 contents.
In awk solution, the record separator is set to : and then /1/ regex is used to only return the record having 1 in it.
This might work for you (GNU sed):
sed 's/:/\n/;/^[^\n]*1/P;D' file
Replace each : and if the first line in the pattern space contains 1 print it.
Repeat.
An alternative:
sed -Ez 's/:/\n/g;s/^[^1]*$//mg;s/\n+/\n/;s/^\n//' file
This slurps the whole file into memory and replaces all colons by newlines. All lines that do not contain 1 are removed and surplus newlines deleted.
An alternative to the really ugly sed is: grep -o '\w*2\w*'
$ printf "test1:test2:test3\nbob3:bob2:fred2\n" | grep -o '\w*2\w*'
test2
bob2
fred2
grep -o: only matching
Or: grep -o '[^:]*2[^:]*'
echo -e "test1:test2:test3" | sed -En 's/:/\n/g;/^[^\n]*2[^\n]*(\n|$)/P;//!D'
sed -n doesn't print unless told to
sed -E allows using parens to match (\n|$) which is newline or the end of the pattern space
P prints the pattern buffer up to the first newline.
D trims the pattern buffer up to the first newline
[^\n] is a character class that matches anything except a newline
// is sed shorthand for repeating a match
//! is then matching everything that didn't match previously
So, after you split into newlines, you want to make sure the 2 character is between the start of the pattern buffer ^ and the first newline.
And, if there is not the character you are looking for, you want to D delete up to the first newline.
At that point, it works for one line of input, with one string containing the character you're looking for.
To expand to several matches within a line, you have to ta, conditionally branch back to label :a:
$ printf "test1:test2:test3\nbob3:bob2:fred2\n" | \
sed -En ':a s/:/\n/g;/^[^\n]*2[^\n]*(\n|$)/P;D;ta'
test2
bob2
fred2
This is simply NOT a job for sed. With GNU awk for multi-char RS:
$ echo "test1:test2:test3:test4:test5:test6"| awk -v RS='[:\n]' '/1/'
test1
$ echo "test1:test2:test3:test4:test5:test6"| awk -v RS='[:\n]' 'NR%2'
test1
test3
test5
$ echo "test1:test2:test3:test4:test5:test6"| awk -v RS='[:\n]' '!(NR%2)'
test2
test4
test6
$ echo "foo1:bar1:foo2:bar2:foo3:bar3" | awk -v RS='[:\n]' '/foo/ || /2/'
foo1
foo2
bar2
foo3
With any awk you'd just have to strip the \n from the final record before operating on it:
$ echo "test1:test2:test3:test4:test5:test6"| awk -v RS=':' '{sub(/\n$/,"")} /1/'
test1
I have a file with many lines, in each line
there is either substring
whatever_blablablalsfjlsdjf;asdfjlds;f/watch?v=yPrg-JN50sw&,whatever_blabla
or
whatever_blablabla"/watch?v=yPrg-JN50sw&" class=whatever_blablablavwhate
I want to extract a substring, like the "yPrg-JN50s" above
the matching pattern is
the 11 characters after the string "/watch?="
how to extract the substring
I hope it is sed, awk in one line
if not, a pn line perl script is also ok
You can do
grep -oP '(?<=/watch\?v=).{11}'
if your grep knows Perl regex, or
sed 's/.*\/watch?v=\(.\{11\}\).*/\1/g'
$ cat file
/watch?v=yPrg-JN50sw&
"/watch?v=yPrg-JN50sw&" class=
$
$ awk 'match($0,/\/watch\?v=/) { print substr($0,RSTART+RLENGTH,11) }' file
yPrg-JN50sw
yPrg-JN50sw
Just with the shell's parameter expansion, extract the 11 chars after "watch?v=":
while IFS= read -r line; do
tmp=${line##*watch?v=}
echo ${tmp:0:11}
done < filename
You could use sed to remove the extraneous information:
sed 's/[^=]\+=//; s/&.*$//' file
Or with awk and sensible field separators:
awk -F '[=&]' '{print $2}' file
Contents of file:
cat <<EOF > file
/watch?v=yPrg-JN50sw&
"/watch?v=yPrg-JN50sw&" class=
EOF
Output:
yPrg-JN50sw
yPrg-JN50sw
Edit accommodating new requirements mentioned in the comments
cat <<EOF > file
<div id="" yt-grid-box "><div class="yt-lockup-thumbnail"><a href="/watch?v=0_NfNAL3Ffc" class="ux-thumb-wrap yt-uix-sessionlink yt-uix-contextlink contains-addto result-item-thumb" data-sessionlink="ved=CAMQwBs%3D&ei=CPTsy8bhqLMCFRR0fAodowXbww%3D%3D"><span class="video-thumb ux-thumb yt-thumb-default-185 "><span class="yt-thumb-clip"><span class="yt-thumb-clip-inner"><img src="//i1.ytimg.com/vi/0_NfNAL3Ffc/mqdefault.jpg" alt="Miniature" width="185" ><span class="vertical-align"></span></span></span></span><span class="video-time">5:15</span>
EOF
Use awk with sensible record separator:
awk -v RS='[=&"]' '/watch/ { getline; print }' file
Note, you should use a proper XML parser for this sort of task.
grep --perl-regexp --only-matching --regexp="(?<=/watch\\?=)([^&]{0,11})"
Assuming your lines have exactly the format you quoted, this should work.
awk '{print substr($0,10,11)}'
Edit: From the comment in another answer, I guess your lines are much longer and complicated than this, in which case something more comprehensive is needed:
gawk '{if(match($0, "/watch\\?v=(\\w+)",a)) print a[1]}'
I have a line:
<random junk>TYPE=snp;<more random junk>
and I need to return everything between the end of TYPE= and the ; (in this case snp but it could be any of a number of text strings.
I tried various sed / awk solutions but I can't seem to get it working. I have the feeling this is a simple problem so, sorry about that.
This seems to work:
sed 's/.*TYPE=\(.*\);.*/\1/'
EDIT:
Ah, so there can be semicolons in the random junk. Try this:
sed 's/.*TYPE=\([^;]*\);.*/\1/'
requires GNU grep:
grep -Po '(?<=TYPE=)[^;]+'
meaning: preceded by "TYPE=", find some non-semicolon characters
One way using GNU sed:
sed -r 's/.*TYPE=([^;]+).*/\1/' file.txt
Since you also tagged this awk:
$ text='<random junk>TYPE=snp;<more random junk>'
$ echo "$text" | awk -FTYPE= '{sub(/;.*/,"",$2); print $2}'
snp
$ text='foo=bar;baz=fnu;TYPE=snp;XAI=0;XAM=0'
$ echo "$text" | awk -FTYPE= '{sub(/;.*/,"",$2); print $2}'
snp
(Only using the variable to keep the lines from wrapping.)
Or, to parse this as set of variable=value pairs rather than just a string of text:
$ echo "$text" | awk -vRS=";" -F= '$1=="TYPE" {print $2}'
snp
You can also do this in pure bash, if you want:
$ t="red=blue;TYPE=snp;XAI=0.0037843;XAM=0.0170293;XAS=0.013245;XRI=0;XRM=0"
$ t=${t#*TYPE=}
$ t=${t%%;*}
$ echo $t
snp