Hi Guys I am doing some work on iOS and the work requires use of OpenGL es. So now I have a bunch of squares, cubes and triangles on the screen. Some of these geometries might overlap. Any ideas/ approaches for touch detection?
Regards
To follow up on the answer already given, squares, cubes and triangles are convex shapes so you can perform ray-object intersection quite easily, even directly from the geometry rather than from the mathematical description of the perfect object.
You're going to need to be able to calculate the distance of a point from the plane and the intersection of a ray with the plane. As a simple test you can implement yourself very quickly, for each polygon on the convex shape work out the intersection between the ray and the plane. Then check whether that point is behind all the planes defined by polygons that share an edge with the one you just tested. If so then the hit is on the surface of the object — though you should be careful about coplanar adjoining polygons and rounding errors.
Once you've found a collision you can easily get the length of the ray to the point of collision. The object with the shortest distance is the one that's in front.
If that's fast enough then great, otherwise you'll probably want to look into partitioning the world or breaking objects down to their silhouettes. Convex objects are really simple — consider all the edges that run between one polygon and the next. If only exactly one of those polygons is front facing then the edge is part of the silhouette. All the silhouettes edges together can be projected to a convex 2d shape on the view plane. You can then test touches by performing a 2d point-in-polygon from that.
A further common alternative that eliminates most of the maths is picking. You'd render the scene to an invisible buffer with each object appearing as a solid blob in a suitably unique colour. To test for touch, you'd just do a glReadPixels and inspect the colour.
For the purposes of glu on the iPhone, you can grab SGI's implementation (as used by MESA). I've used its tessellator in a shipping, production project before.
I had that problem in the past. What I have used is an implementation of glu unproject that you can find on google (it uses the inverse of the model view projection matrix and the viewport size). This allows you to map the 2D screen coordinates to a 3D vector into the world. Then, you can use this vector to intersect with your objects and see which one intersects (or comes really close to doing so).
I do hope there are better ways of doing this, so I look forward to other answers as well!
Once you get the inverse-modelview and cast your ray (vector), you still need to know if the ray intersects your geometry. One approach would be to grab the depth (z in view coordinate system) of the object's center and extend (stretch) your vector just that far. Then see if the vector's "head" ends within the volume of your object or not (you need the objects center and e.g. Its radius, if it's a sphere)
Related
I am beating my head a little bit here for a while but I still could bot find a way to set up a matrix that projects my Unity game in a Tibianeske like manner:
Reading on tutorials on internet I could figure out how a normal orthographic perspective works, but tibia's one is kind of odd.
Digging over webs I found in here a guy (Clint Bellanger) who describes really well how to get the same perspective in blender's render according to him:
Start with a scene in 45 degree isometric. Video game style, where
the camera angle is Blender (60,0,45).
In Blender if you look at Buttons Window -> Scene -> Render Buttons ->
Format, you can set the render aspect ratio. Set AspY to half of
AspX. This is the same as taking regular rendered output and scaling
X by 50%. If you rendered a cube, the top of the cube will be a
perfect square (though at a 45 degree angle).
We can then use Blender nodes to rotate the result 45 degrees. The
output:
Note this started as a cube, so there's a lot of "vertical"
distortion. So you might have to scale meshes to 50% Z before using
this method. Also notice the Edge seems to be applied after the
Aspect, so the edge isn't distorted.
Blend file: http://clintbellanger.net/images/temp/UltimaVII.blend (I'm
a Nodes noob so there might be a smarter setup).
For kicks, here is that tower again. I pulled it into the above
workflow scene and scaled Z by 50%. Click "Re-render this layer" on
the first node to create the composite.
On his method, he used stuff like rescaling the render and changing the scale of models, Im convinced I could get along just with the 4x4matrix in unity(or in any other 3d environment really).
Hope someone more experienced with perks of 3D maths could help me to figure it out. Thank you! =D
What you ask for is a simple parallel projection. The typical orthographic projection is just a special case where the projection rays are perpendicular to the image plane. However, every parallel projection can be represented by an affine shear transformation followed by a standard orthogonal projection.
Im convinced I could get along just with the 4x4matrix in unity(or in any other 3d environment really).
Yes. Using default GL conventions here, all you have to do is to take the standard ortho matrix, post-multiply it by an appropriate shear matrix and use that as the projection matrix.
A recent question here made me think of SceneKit again, and I remembered a problem I never solved.
My app displays antenna designs using SK. Most antennas use metal rods and mesh reflectors so I used SCNCylinder for the rods, SCNPlane for the reflector and SCNFloor for the ground. The whole thing took a couple of hours, and I'm utterly noob at 3D.
But some antennas use wires bent into arcs or helixes, and I punted here and made crappy segmented objects using several cylinders end-to-end. It looks ass-tastic.
Ideally I would like a single object that renders the arc or helix with a cylindrical cross section. Basically SCNTorus, but with a start and end angle. This post talks about using a UIBezierPath in SK, but it uses extrude to produce a ribbon-like shape. Is there a way to do something similar but with a cylinder cross section (like a partial SCNTorus)?
I know I can make a custom shape by creating the vertexes (and normals and such) but I'm hoping I missed a simpler solution.
An arc you can do with SCNShape. Start with the technique from my other answer to get an extruded, ribbon-like arc. You'll want to make sure that the part where your path traces back on itself is offset by a distance the same as your extrusion depth, so you end up with a shape that's square in cross section.
To make it circular in cross section, use the chamferProfile property — give it a path that's a quarter circle, and set the chamfer radius equal to half the extrusion depth, and the four quarter-circle chamfers will meet, forming a circular cross section.
A helix is another story. SCNShape takes a planar path — one that varies in only two dimensions — and extrudes it to make a three-dimensional solid. A helix is a path that varies in three dimensions to start with. SceneKit doesn't have anything that describes a shape in such terms, so there's no super simple answer here.
The shader modifier solution #HalMueller alludes to is interesting, but problematic. It's simple to use a modifier at the geometry entry point to make a simple bend — say, offset every y coordinate by some amount, even by an amount that's a function of why. But that's a one-dimensional transform, so you can't use it to wrap a wire around on itself. (It also changes the cross section.) And on top of that, shader modifiers happen on the GPU at render time, so their effects are an illusion: the "real" geometry in SceneKit's model is still a cylinder, so features like hit testing apply to that and not to the transformed geometry.
The best solution to making something like a helix is probably custom geometry — generating your own vertex data (SCNGeometrySource). The math for finding the set of points on a helix is pretty simple if you follow that shape's definition. To wrap a cross section around it, follow the Frenet formulas to create a local coordinate frame at each point on the helix. Then make an index buffer (SCNGeometryElement) to stitch all those points into a surface with triangles or tristrips. (Okay, that's a lot of hand-waving around a deep topic, but a full tutorial is too big for an SO answer. This should be enough of a breadcrumb to get started, though...)
Here are some starting points that might help.
One approach would be to use more cylinders and make them shorter. That's the same idea behind the various segmentCount properties on the SCNGeometry primitives. Can we see a screenshot of the current linked cylinders version?
If you increase the heightSegmentCount, you could use the approach outlined here: scenekit, how to bend an object.
I just took a look at SCNShape. I was thinking you could use a shader modifier to warp the extruded shape into a circular cross section. But SCNShape doesn't seem to expose a segment count property, which I think you'd need to create enough extrusion segments for a good look. The chamferRadius and chamferProfile properties look interesting. I wonder if you could use those to create an extrusion that looks good.
I'm currently trying to implement a silhouette algorithm in my project (using Open GLES, it's for mobile devices, primarily iPhone at the moment). One of the requirements is that a set of 3D lines be drawn. The issue with the default OpenGL lines is that they don't connect at an angle nicely when they are thick (gaps appear). Other subtle artifacts are also evident, which detract from the visual appeal of the lines.
Now, I have looked into using some sort of quad strip as an alternative to this. However, drawing a quad strip in screen space requires some sort of visibility detection - lines obscured in the actual 3D world should not be visible.
There are numerous approaches to this problem - i.e. quantitative invisibility. But such an approach, particularly on a mobile device with limited processing power, is difficult to implement efficiently, considering raycasting needs to be employed. Looking around some more I found this paper, which describes a couple of methods for using z-buffer sampling to achieve such an effect. However, I'm not an expert in this area, and while I understand the theory behind the techniques to an extent, I'm not sure how to go about the practical implementation. I was wondering if someone could guide me here at a more technical level - on the OpenGLES side of things. I'm also open to any suggestions regarding 3D line visibility in general.
The technique with z-buffer will be too complex for iOS devices - it needs heavy pixel shader and (IMHO) it will bring some visual artifacts.
If your models are not complex you can find geometric silhouette in runtime - for example by comparing normals of polygons with common edge: if z value of direction in view space has different sings (one normal is directed to camera and other is from camera) then this edge should be used for silhouette.
Another approach is more "FPS friendly": keep extruded version of your model. And render firstly extruded model with color of silhouette (without textures and lighting) and normal model over it. You will need more memory for vertices, but no real-time computations.
PS: In all games I have look at silhouettes were geometric.
I have worked out a solution that works nicely on an iPhone 4S (not tested on any other devices). It builds on the idea of rendering world-space quads, and does the silhouette detection all on the GPU. It works along these lines (pun not intended):
We generate edge information. This consists of a list of edges/"lines" in the mesh, and for each we associate two normals which represent the tris on either side of the edge.
This is processed into a set of quads that are uploaded to the GPU - each quad represents an edge. Each vertex of each quad is accompanied by three attributes (vec3s), namely the edge direction vector and the two neighbor tri normals. All quads are passed w/o "thickness" - i.e. the vertices on either end are in the same position. However, the edge direction vector is opposite for each vertex in the same position. This means they will extrude in opposite directions to form a quad when required.
We determine whether a vertex is part of a visible edge in the vertex shader by performing two dot products between each tri norm and the view vector and checking if they have opposite signs. (see standard silhouette algorithms around the net for details)
For vertices that are part of visible edges, we take the cross product of the edge direction vector with the view vector to get a screen-oriented "extrusion" vector. We add this vector to the vertex, but divided by the w value of the projected vertex in order to create a constant thickness quad.
This does not directly resolve the gaps that can appear between neighbor edges but is far more flexible when it comes to combating this. One solution may involve bridging the vertices between large angled lines with another quad, which I am exploring at the moment.
Maybe I'm asking this too soon in my research, but I'd better know if this is possible sooner than later.
Imagine I have the following square printed on a paper on top of a table:
The table is brown, so it does not match with any of the colors in the square. Is there a way for me, from a common iPhone camera (non-stereo view), to figure out the distance and angle from which Im looking at the square in the table?
In the end what I'm looking for is being able to draw a 3D square on top of this one using the camera image, but I'm not sure if I am going to be able to figure out the distance and position of the object in space using only a 2D image. Any hints are well appreciated.
Short answer: http://weblog.bocoup.com/javascript-augmented-reality
Big answer:
First posterize, Then vectorize, With the vectors in your power you may need to do some math tricks to define, based on the vectors position, the perspective and then the camera position.
Maybe this help:
www.pixastic.com/lib/docs/actions/posterize/
github.com/selead/cl-vectorizer
vectormagic.com/home
autotrace.sourceforge.net
www.scipy.org/PyLab
raphaeljs.com/
technabob.com/blog/2007/12/29/video-games-get-vectorized/
superuser.com/questions/88415/is-there-an-open-source-alternative-to-vector-magic
Oughta be possible. Scan the image for the red/blue/yellow pattern, then do edge detection to figure out how warped the squares are (they'll be parallelograms in anything but straight-on view). Distance would depend on the camera's zoom setting and scan resolution. But basically you'd count how many pixels are visible in each of the squares, run that past the camera's specs and you should be able to determine a rough distance.
The Screen-to-world problem on the iPhone
I have a 3D model (CUBE) rendered in an EAGLView and I want to be able to detect when I am touching the center of a given face (From any orientation angle) of the cube. Sounds pretty easy but it is not...
The problem:
How do I accurately relate screen-coordinates (touch point) to world-coordinates (a location in OpenGL 3D space)? Sure, converting a given point into a 'percentage' of the screen/world-axis might seem the logical fix, but problems would arise when I need to zoom or rotate the 3D space. Note: rotating & zooming in and out of the 3D space will change the relationship of the 2D screen coords with the 3D world coords...Also, you'd have to allow for 'distance' in between the viewpoint and objects in 3D space. At first, this might seem like an 'easy task', but that changes when you actually examine the requirements. And I've found no examples of people doing this on the iPhone. How is this normally done?
An 'easy' task?:
Sure, one might undertake the task of writing an API to act as a go-between between screen and world, but the task of creating such a framework would require some serious design and would likely take 'time' to do -- NOT something that can be one-manned in 4 hours...And 4 hours happens to be my deadline.
The question:
What are some of the simplest ways to
know if I touched specific locations
in 3D space in the iPhone OpenGL ES
world?
You can now find gluUnProject in http://code.google.com/p/iphone-glu/. I've no association with the iphone-glu project and haven't tried it yet myself, just wanted to share the link.
How would you use such a function? This PDF mentions that:
The Utility Library routine gluUnProject() performs this reversal of the transformations. Given the three-dimensional window coordinates for a location and all the transformations that affected them, gluUnProject() returns the world coordinates from where it originated.
int gluUnProject(GLdouble winx, GLdouble winy, GLdouble winz,
const GLdouble modelMatrix[16], const GLdouble projMatrix[16],
const GLint viewport[4], GLdouble *objx, GLdouble *objy, GLdouble *objz);
Map the specified window coordinates (winx, winy, winz) into object coordinates, using transformations defined by a modelview matrix (modelMatrix), projection matrix (projMatrix), and viewport (viewport). The resulting object coordinates are returned in objx, objy, and objz. The function returns GL_TRUE, indicating success, or GL_FALSE, indicating failure (such as an noninvertible matrix). This operation does not attempt to clip the coordinates to the viewport or eliminate depth values that fall outside of glDepthRange().
There are inherent difficulties in trying to reverse the transformation process. A two-dimensional screen location could have originated from anywhere on an entire line in three-dimensional space. To disambiguate the result, gluUnProject() requires that a window depth coordinate (winz) be provided and that winz be specified in terms of glDepthRange(). For the default values of glDepthRange(), winz at 0.0 will request the world coordinates of the transformed point at the near clipping plane, while winz at 1.0 will request the point at the far clipping plane.
Example 3-8 (again, see the PDF) demonstrates gluUnProject() by reading the mouse position and determining the three-dimensional points at the near and far clipping planes from which it was transformed. The computed world coordinates are printed to standard output, but the rendered window itself is just black.
In terms of performance, I found this quickly via Google as an example of what you might not want to do using gluUnProject, with a link to what might lead to a better alternative. I have absolutely no idea how applicable it is to the iPhone, as I'm still a newb with OpenGL ES. Ask me again in a month. ;-)
You need to have the opengl projection and modelview matrices. Multiply them to gain the modelview projection matrix. Invert this matrix to get a matrix that transforms clip space coordinates into world coordinates. Transform your touch point so it corresponds to clip coordinates: the center of the screen should be zero, while the edges should be +1/-1 for X and Y respectively.
construct two points, one at (0,0,0) and one at (touch_x,touch_y,-1) and transform both by the inverse modelview projection matrix.
Do the inverse of a perspective divide.
You should get two points describing a line from the center of the camera into "the far distance" (the farplane).
Do picking based on simplified bounding boxes of your models. You should be able to find ray/box intersection algorithms aplenty on the web.
Another solution is to paint each of the models in a slightly different color into an offscreen buffer and reading the color at the touch point from there, telling you which brich was touched.
Here's source for a cursor I wrote for a little project using bullet physics:
float x=((float)mpos.x/screensize.x)*2.0f -1.0f;
float y=((float)mpos.y/screensize.y)*-2.0f +1.0f;
p2=renderer->camera.unProject(vec4(x,y,1.0f,1));
p2/=p2.w;
vec4 pos=activecam.GetView().col_t;
p1=pos+(((vec3)p2 - (vec3)pos) / 2048.0f * 0.1f);
p1.w=1.0f;
btCollisionWorld::ClosestRayResultCallback rayCallback(btVector3(p1.x,p1.y,p1.z),btVector3(p2.x,p2.y,p2.z));
game.dynamicsWorld->rayTest(btVector3(p1.x,p1.y,p1.z),btVector3(p2.x,p2.y,p2.z), rayCallback);
if (rayCallback.hasHit())
{
btRigidBody* body = btRigidBody::upcast(rayCallback.m_collisionObject);
if(body==game.worldBody)
{
renderer->setHighlight(0);
}
else if (body)
{
Entity* ent=(Entity*)body->getUserPointer();
if(ent)
{
renderer->setHighlight(dynamic_cast<ModelEntity*>(ent));
//cerr<<"hit ";
//cerr<<ent->getName()<<endl;
}
}
}
Imagine a line that extends from the viewer's eye
through the screen touch point into your 3D model space.
If that line intersects any of the cube's faces, then the user has touched the cube.
Two solutions present themselves. Both of them should achieve the end goal, albeit by a different means: rather than answering "what world coordinate is under the mouse?", they answer the question "what object is rendered under the mouse?".
One is to draw a simplified version of your model to an off-screen buffer, rendering the center of each face using a distinct color (and adjusting the lighting so color is preserved identically). You can then detect those colors in the buffer (e.g. pixmap), and map mouse locations to them.
The other is to use OpenGL picking. There's a decent-looking tutorial here. The basic idea is to put OpenGL in select mode, restrict the viewport to a small (perhaps 3x3 or 5x5) window around the point of interest, and then render the scene (or a simplified version of it) using OpenGL "names" (integer identifiers) to identify the components making up each face. At the end of this process, OpenGL can give you a list of the names that were rendered in the selection viewport. Mapping these identifiers back to original objects will let you determine what object is under the mouse cursor.
Google for opengl screen to world (for example there’s a thread where somebody wants to do exactly what you are looking for on GameDev.net). There is a gluUnProject function that does precisely this, but it’s not available on iPhone, so that you have to port it (see this source from the Mesa project). Or maybe there’s already some publicly available source somewhere?