How to assign the NSArray string object values to other NSString variables - iphone

Question

NSMutableArray *nameArray = [[NSMutableArray alloc] init];
[nameArray addObject:#"abc"];
[nameArray addObject:#"cdf"];
[nameArray addObject:#"jkl"];
//Use a for each loop to iterate through the array
for (NSString *s in nameArray) {
NSLog(#"value is %#", s);
}
The above code shows all the values of nameArray. But I want to assign all those values to these NSString:
NSString *a;
NSString *b;
NSString *cd;
An aray can have 1 or more elements but not more than 5.
Actually,I have 5 buttons, each button on click will add a NSString value(values are: f1,f2,f3,f4 and f5) to NSMutableArray. Now its upto the user if he clicks 2 buttons or 3 or 5 in a day. Now all these values will be saved in NSMutableArray (which can be 1 or 2 but not more than 5). That NSMutableArray will be saved in NSUserDefaults. This NSMutableArray than will be used in another view where I have some UIImageView (1,2,3,4 and 5). Now when I will get the string values from that Array(f1,f2,f3). If it is f1 then an image will be assigned to UIImage 1 if it is f3 then to image 3 and so on.
How to achieve this?

Answer 1

I would do something like that:
NSArray *array = [NSArray arrayWithObjects:#"A", #"B", #"C", #"D", #"E", nil];
NSString *a = nil, *b = nil, *c = nil, *d = nil, *e = nil;
NSUInteger idx = 0;
for ( NSString *string in array )
{
switch ( idx++ ) {
case 0: a = string; break;
case 1: b = string; break;
case 2: c = string; break;
case 3: d = string; break;
case 4: e = string; break;
}
}

Answer 2

As at least one element will be there in your array:
NSString *a = (NSString *)[nameArray objectAtIndex:0];
As maximum will be five elements:
for(int i = 1;i<[array count];i++)
{
if(i == 1)
{
NSString *b = (NSString *)[nameArray objectAtIndex:1];
}
else if(i == 2)
{
NSString *c = (NSString *)[nameArray objectAtIndex:2];
}
else if(i == 3)
{
NSString *d = (NSString *)[nameArray objectAtIndex:3];
}
else if(i == 4)
{
NSString *e = (NSString *)[nameArray objectAtIndex:4];
}
}

Answer 3

a = [nameArray objectAtIndex:0];
b = [nameArray objectAtIndex:1];
cd = [nameArray objectAtIndex:2];
If you want to put your array elements into separate variables with distinct names, there is no automation in objective c (unlike say, in JavaScript) since it is a compiled and not a interpreted language. Something similar you can achieve with NSDictionary, i.e. to "index" objects with strings or whatever type you want.

Answer 4

You could go on with a simple C array of 5 unsigned chars, where the index of the array would point to your data. Something like this:
unsigned char nameArray[5] = {0, 0, 0, 0, 0};
// if you want to set the 3rd variable, use:
nameArray[2] = 1;
// to query:
if (nameArray[2]) { ... }
// When you need to save it to NSUserDefaults, wrap it into an NSData:
NSData* nameData = [NSData dataWithBytes:nameArray length:sizeof(nameArray)];
[[NSUserDefaults standardUserDefaults] setObject:nameData forKey:#"myKey"];
// To query it:
NSData* nameData = [[NSUserDefaults standardUserDefaults] dataForKey:#"myKey"];
const unsigned char* nameArray2 = [nameData bytes];
unsigned char second = nameArray2[2];
EDITED: corrected array access

Answer 5

If there is at most five options the easiest way to do it is with an if-else-if chain.
NSString *label1 = nil, *label2 = nil, *label3 = nil, *label4 = nil, *label5 = nil;
for (NSString *s in nameArray) {
if (label1 == nil)
label1 = s;
else if (label2 == nil)
label2 = s;
else if (label3 == nil)
label3 = s;
else if (label4 == nil)
label4 = s;
else if (label5 == nil)
label5 = s;
}

Answer 6

NSString *str1=nil;
NSString *str2=nil;
NSString *str3=nil;
NSString *str4=nil;
for (LocationObject *objLoc in arrLocListFirstView)
{
if (objLoc.isLocSelected)
{
for (LocationObject *obj in arrLocListFirstView)
{
if (str1 == nil)
str1 = objLoc.strLoc;
else if (str2 == nil)
str2 = obj.strLoc;
else if (str3 == nil)
str3 = obj.strLoc;
else if (str4 == nil)
str4 = obj.strLoc;
}
NSString *combined = [NSString stringWithFormat:#"%#,%#,%#,%#", str1,str2,str3,str4];
lblLocation.text=combined; (displaying text in UILabel)
}
}