I have a text field that has the following expression:
$F{casNo} + " Total " + $P{chosenUom} + ": " + $V{total_COUNT}
casNo is a string, chosenUom is a string. total_COUNT is a sum variable of doubles. The total_COUNT variable displays, but it's got 8 - 10 decimal places (1.34324255234), all I need is something along the lines of 1.34.
Here's what I tried already:
$F{casNo} + " Total " + $P{chosenUom} + ": " + new DecimalFormat("0.00").format($V{total_COUNT}).toString()
Any help would be appreciated
For now I'm just doing basic math, but I'm hoping for a real solution, not a workaround
((int)($V{total_COUNT}*100.0))/100.0
You can format the in lline numbers by using:
new DecimalFormat("###0.00").format(YOUR NUMBER)
You might split the text field into two, one containing everything but the $V{total_COUNT}, and the second containing only $V{total_COUNT}, but with the Pattern property set to something like "#0.00".
You'd have to get a bit creative with layout, though, to prevent unwanted word-wrapping and spacing; for example, first text field could be wide and right-aligned, while text field containing the count could be left-aligned and wide enough to accommodate the formatted number.
Related
I'm interested in a pure-Lua (i.e., no external Unicode library) solution to extracting the units of a string between certain Unicode control characters and spaces. The code points I would like to use as delimiters are:
0000-0020
007f-00a0
00ad
1680
2000-200a
2028-2029
202f
205f
3000
I know how to access the code points in a string, for example:
> for i,c in utf8.codes("Ê$ \tĪđ") do print(c) end
233
36
32
9
960
128515
but I am not sure how to "skip" the spaces and tabs and reconstitute the other codepoints into strings themselves. What I would like to do in the example above, is drop the 32 and 9, then perhaps use utf8.char(233, 36) and utf8.char(960, 128515) to somehow get ["Ê$", "Īđ"].
It seems that putting everything into a table of numbers and painstakingly walking through the table with for-loops and if-statements would work, but is there a better way? I looked into string:gmatch but that seems to require making utf8 sequences out of each of the ranges I want, and it's not clear what that pattern would even look like.
Is there a idiomatic way to extract the strings between the spaces? Or must I manually hack tables of code points? gmatch does not look up to the task. Or is it?
would require painstakingly generating the utf8 encodings for all code points at each end of the range.
Yes. But of course not manually.
local function range(from, to)
assert(utf8.codepoint(from) // 64 == utf8.codepoint(to) // 64)
return from:sub(1,-2).."["..from:sub(-1).."-"..to:sub(-1).."]"
end
local function split_unicode(s)
for w in s
:gsub("[\0-\x1F\x7F]", " ")
:gsub("\u{00a0}", " ")
:gsub("\u{00ad}", " ")
:gsub("\u{1680}", " ")
:gsub(range("\u{2000}", "\u{200a}"), " ")
:gsub(range("\u{2028}", "\u{2029}"), " ")
:gsub("\u{202f}", " ")
:gsub("\u{205f}", " ")
:gsub("\u{3000}", " ")
:gmatch"%S+"
do
print(w)
end
end
Test:
split_unicode("#\0#\t#\x1F#\x7F#\u{00a0}#\u{00ad}#\u{1680}#\u{2000}#\u{2005}#\u{200a}#\u{2028}#\u{2029}#\u{202f}#\u{205f}#\u{3000}#")
I am new to spark. I have a huge file which has data like-
18765967790#18765967790#T#20130629#00#31#2981546 " "18765967790#18765967790#T#20130629#19#18#3240165 " "18765967790#18765967790#T#20130629#18#18#1362836
13478756094#13478756094#T#20130629#31#26#2880701 " "13478756094#13478756094#T#20130629#19#18#1230206 " "13478756094#13478756094#T#20130629#00#00#1631440
40072066693#40072066693#T#20130629#79#18#1270246 " "40072066693#40072066693#T#20130629#79#18#3276502 " "40072066693#40072066693#T#20130629#19#07#3321860
I am trying to replace " " with new line character so that my output looks like this-
18765967790#18765967790#T#20130629#00#31#2981546
18765967790#18765967790#T#20130629#19#18#3240165
18765967790#18765967790#T#20130629#18#18#1362836
13478756094#13478756094#T#20130629#31#26#2880701
13478756094#13478756094#T#20130629#19#18#1230206
13478756094#13478756094#T#20130629#00#00#1631440
40072066693#40072066693#T#20130629#79#18#1270246
40072066693#40072066693#T#20130629#79#18#3276502
40072066693#40072066693#T#20130629#19#07#3321860
I have tried with-
val fact1 = sc.textFile("s3://abc.txt").map(x=>x.replaceAll("\"","\n"))
But this doesn't seem to be working. Can someone tell what I am missing?
Edit1- My final output will be a dataframe with schema imposed after splitting with delimeter "#".
I am getting below o/p-
scala> fact1.take(5).foreach(println)
18765967790#18765967790#T#20130629#00#31#2981546
18765967790#18765967790#T#20130629#19#18#3240165
18765967790#18765967790#T#20130629#18#18#1362836
13478756094#13478756094#T#20130629#31#26#2880701
13478756094#13478756094#T#20130629#19#18#1230206
13478756094#13478756094#T#20130629#00#00#1631440
40072066693#40072066693#T#20130629#79#18#1270246
40072066693#40072066693#T#20130629#79#18#3276502
40072066693#40072066693#T#20130629#19#07#3321860
I am getting extra blank lines which is further troubling me to create dataframe. This might seem simple here, but the file is huge, also the rows containing " " are long. In the question I have put only 2 double quotes but they can be more than 40-50 in numbers.
There are more than one quote in between textes, which is creating multiple line breaks. You either need to remove additional quotes before replace or empty lines after replace:
.map(x=>x.replaceAll("\"","\n").replaceAll("(?m)^[ \t]*\r?\n", ""))
Reference: Remove all empty lines
You might be missing implicit Encoders and you try the code as below
spark.read.text("src/main/resources/doubleQuoteFile.txt").map(row => {
row.getString(0).replace("\"","\n") // looking to replace " " with next line
row.getString(0).replace("\" \"","\n") // looking to replace " " with next line
})(org.apache.spark.sql.Encoders.STRING)
I have a super simple formula. The problem is that sometimes the data doesn't have a second value, or sometimes the value is blank.
Split ({PO_RECEIVE.VENDOR_LOT_ID}," ")[2]
ID
111 222
123
123 222
I was thinking if I could come up with some logic to figure out whether the string has multiple value's it would solve my problem, but haven't quiet found what I'm looking for:
If {PO_RECEIVE.VENDOR_LOT_ID} = SingleOrBlankString then
{PO_RECEIVE.VENDOR_LOT_ID} else
Split ({PO_RECEIVE.VENDOR_LOT_ID}," ")[2]
Better Example Data:
3011111*42011111111
2711 00291111111
711111//12111111111
/J1111 69111111111
170111
If the string can contain a maximum of two values, separated by a space, then you can check if the string contains a space using the InStr function:
If InStr({PO_RECEIVE.VENDOR_LOT_ID}, " ") > 0 Then
{PO_RECEIVE.VENDOR_LOT_ID}
Else
Split ({PO_RECEIVE.VENDOR_LOT_ID}," ")[2]
If there can be multiple spaces between the parts you can use following formulas to get the values:
Left part:
This function returns the left part of the string until the first space.
If InStr({PO_RECEIVE.VENDOR_LOT_ID}, " ") > 0 Then
Left({PO_RECEIVE.VENDOR_LOT_ID}, InStr({PO_RECEIVE.VENDOR_LOT_ID}, " "))
Right part:
This function returns the right part of the string after the last space.
The InStrRev-function returns the position of the last space because it searches the string backwards.
The Len-function returns the length of the string.
[length] - [position of last space] = [length of the right part]
If InStr({PO_RECEIVE.VENDOR_LOT_ID}, " ") > 0 Then
Right({PO_RECEIVE.VENDOR_LOT_ID}, Len({PO_RECEIVE.VENDOR_LOT_ID}) - InStrRev(testString, " "))
I have a column of strings that look like this:
Target Host: dcmxxxxxxc032.erc.nam.fm.com Target Name:
dxxxxxxgsc047.erc.nam.fm.com Filesystem /u01 has 4.98% available space
- fallen below warning (20) or critical (5) threshold.
The column name is [Description]
The substring I would like returned is (dxxxxxxgsc047.erc.nam.fm.com)
The only consistency in this data is that the desired string occurs between the 5th and 6th occurrences of spaces " " in the string, and after the phrase "Target Name: " The length of the substring varies, but it always ends in another " ", hence my attempt to grab the substring between the 5th and 6th spaces.
I have tried
MID([Description],((FIND([Description],"Target Name: "))+13),FIND([Description]," ",((FIND([Description],"Target Name"))+14)))
But that does not work.
(Edit: We use Tableau 8.2, the Tableau 9 only functions can't be part of the solution, thanks though!)
Thank you in advance for your help.
In Tableau 9 you can use regular expressions in formulas, it makes the task simpler:
REGEXP_EXTRACT([Description], "Target Name: (.*?) ")
Alternatively in Tableau 9 you can use the new FINDNTH function:
MID(
[Description],
FINDNTH([Description]," ", 5) + 1,
FINDNTH([Description]," ", 6) - FINDNTH([Description]," ", 5) - 1
)
Prior to Tableau 9 you'd have to use string manipulation methods similar to what you've tried, just need to be very careful with arithmetic and providing the right arguments (the third argument in MID is length, not index of the end character, so we need to subtract the index of the start character):
MID(
[Description]
, FIND([Description], "Target Name:") + 13
, FIND([Description], " ", FIND([Description], "Target Name:") + 15)
- (FIND([Description], "Target Name:") + 13)
)
Well, you need to find "Target name: " and then the " " after it, not so hard. I'll split in 3 fields just to be more clear (you can mix everything in a single field). BTW, you were in the right direction, but the last field on MID() should be the string length, not the char position
[start]:
FIND([Description],"Target name: ")+13
[end]:
FIND([Description]," ",[start])
And finally what you need:
MID([Description],[start]+1,[end]-[start]-1)
This should do. If you want to pursue the 5th and 6th " " approach, I would recommend you to find each of the " " until the 6th.
[1st]:
FIND([Description], " ")
[2nd]:
FIND([Description], " ",[1st] + 1)
And so on. Then:
MID([Description],[5th]+1,[6th]-[5th]-1)
A simple solution -
SPLIT( [Description], " ", 3 )
This returns a substring from the Description string, using the space delimiter character to divide the string into a sequence of tokens.
The string is interpreted as an alternating sequence of delimiters and
tokens. So for the string abc-defgh-i-jkl, where the delimiter
character is â-â, the tokens are abc, defgh, i and jlk. Think of these
as tokens 1 through 4. SPLIT returns the token corresponding to the
token number. When the token number is positive, tokens are counted
starting from the left end of the string; when the token number is
negative, tokens are counted starting from the right. -
Tableau String Functions
I don't know Tableau, but perhaps something like this?
MID(
MID([Description], FIND([Description],"Target Name: ") + 13, 50),
1,
FIND(MID([Description], FIND([Description],"Target Name: ") + 13, 50), " ")
)
Question:
I used the custom date format(e.g., 4/22 11:00), and display these dates on the horizontal axis, however I want to split the date format( 4/22 11:00) into two lines,for instance,
4/22
11:00
Why do I want this
Date( 4/22 ) and time(11:00) are displayed at the distinct lines, which can easily differentiate date from time.
What did I try
I found an item "Wrap" in "Alignment", but it can't work.
Better late than ever, if you're still interested, there's a way.
You need to create a new calculated field, to generate the labels as you wish. If the field you're working if is called Date (for instance), you should do:
STR(DAY([Date])) + '/' + STR(MONTH([Date])) + '/' + STR(YEAR([Date]))
+
'
'
+
IF LEN(STR(DATEPART('hour',[Date]))) == 1
THEN '0' + STR(DATEPART('hour',[Date]))
ELSE STR(DATEPART('hour',[Date]))
END
+
':'
+
IF LEN(STR(DATEPART('minute',[Date]))) == 1
THEN '0' + STR(DATEPART('minute',[Date]))
ELSE STR(DATEPART('minute',[Date]))
END
First line is just to get the date on a d/m/y format. Then the trick is to add + '' separated by blank space (tried \n, but it prints "\n" instead of breaking the line)
The second part is to generate the hh:mm (you can use the same logic to get a dd/mm/yyyy format for the date). Basically it adds a zero if the hour or minute is a one digit number.