Using the form api, I'm to display the result of some processing after a post is sent by a form.
So I implement the module_name_submit(...) method:
function cmis_views_block_view($delta = '') {
$cmisview = cmis_views_load($delta);
$block['content'] = cmis_views_info($cmisview);
return $block;
}
The processing is very simple. The call happens properly and I would like to display the $block on screen.
Returning this doesn't help. Maybe a redirect could help, but I'm looking first for something equivalent to drupal_set_message() but that dispays html in the page.
Any leads welcome :-)
Thanks,
J.
You probably need to use $form_state['redirect']
Put the content in a session variable, redirect to that page and have a custom block output that specific variable in the $content
Related
I can set a GET method in Slim to get data from my database but my problem is the POST method, i don't know how to use it correctly. I do some code like:
$app->post('/login',function() use ($app){
$inputs = json_decode($app->request()->getBody());
$result = json_encode($inputs);
return $result;
});
I wanna make a login function by POST method but this is just an example I want to show the data that have been sent in the body by json. I used Advanced Rest Client to test but the result is always "null".
I'm new to Rest and Slim Framework too. Thanks for any helpful idea !
using return doesn't do anything in terms of viewing the output within that route callback function. use print, print_r, echo, $app->response->setBody('Foo'), or $app->response->write('Foo')
in terms of the post, did you try using $data = $app->request()->post() to get your data?
I am writing a custom sh404 file for a custom component in joomla. I have written some of the redirecting urls by using setRedirect function. But it is not redirecting to SH404 URL.
What I have given is:
$link = JURI::base().'index.php?option=com_camassistant&controller=rfp&task=editrfp&var=copy&rfpid='.$insert_id.'&Itemid='.$_REQUEST['Itemid'] ;
$this->setRedirect( $link,$msg );
Can you please say how can I give $link to change SH404 automatically?
Thanks in advance
Sateesh
I didn't get it properly.
If you do something like:
JError::raiseError(404, 'Not Found');
I want to redirect two pages at once.
if(any statement) {
Header("Location: http://example.com/page.php");
Header("Location: folder/page.php"); }
else { echo " comment "; }
Will this work?
Found a solution see on comments.
No. Why on Earth would you want to? Even if you could, how do you think a browser can display the two pages? New windows/tabs? But what if it's a windowless browser (like lynx)?
If you use the above code, PHP will replace the first location header with the second as no headers are actually sent until you start outputting content, after which you cannot call header().
I am a beginner and I am creating some forms to be posted into MySQL using Zend, and I am in the process of debugging but I don't really know how to debug anything using Zend. I want to submit the form and see if my custom forms are concatenating the data properly before it goes into MySQL, so I want to catch the post data to see a few things. How can I do this?
The Default route for zend framework application looks like the following
http://www.name.tld/$controller/$action/$param1/$value1/.../$paramX/$valueX
So all $_GET-Parameters simply get contenated onto the url in the above manner /param/value
Let's say you are within IndexController and indexAction() in here you call a form. Now there's possible two things happening:
You do not define a Form-Action, then you will send the form back to IndexController:indexAction()
You define a Form action via $form->setAction('/index/process') in that case you would end up at IndexController:processAction()
The way to access the Params is already defined above. Whereas $this->_getParam() equals $this->getRequest()->getParam() and $this->_getAllParams() equals $this->getRequest->getParams()
The right way yo check data of Zend Stuff is using Zend_Debug as #vascowhite has pointed out. If you want to see the final Query-String (in case you're manually building queries), then you can simply put in the insert variable into Zend_Debug::dump()
you can use $this->_getAllParams();.
For example: var_dump($this->_getAllParams()); die; will output all the parameters ZF received and halt the execution of the script. To be used in your receiving Action.
Also, $this->_getParam("param name"); will get a specific parameter from the request.
The easiest way to check variables in Zend Framework is to use Zend_Debug::dump($variable); so you can do this:-
Zend_Debug::dump($_POST);
Zend framework is built on the top of the PHP . so you can use var_dump($_POST) to check the post variables.
ZF has provided its own functions to get all the post variables.. Zend_Debug::dump($this->getRequest()->getPost())
or specifically for one variable.. you can use Zend_Debug::dump($this->getRequest()->getPost($key))
You can check post data by using zend
$request->isPost()
and for retrieving post data
$request->getPost()
For example
if ($request->isPost()) {
$postData = $request->getPost();
Zend_Debug::dump($postData );
}
I am developing a website using zend framework.
i have a search form with get method. when the user clicks submit button the query string appears in the url after ? mark. but i want it to be zend like url.
is it possible?
As well as the JS approach you can do a redirect back to the preferred URL you want. I.e. let the form submit via GET, then redirect to the ZF routing style.
This is, however, overkill unless you have a really good reason to want to create neat URLs for your search queries. Generally speaking a search form should send a GET query that can be bookmarked. And there's nothing wrong with ?param=val style parameters in a URL :-)
ZF URLs are a little odd in that they force URL parameters to be part of the main URL. I.e. domain.com/controller/action/param/val/param2/val rather than domain.com/controller/action?param=val¶m2=val
This isn't always what you want, but seems to be the way frameworks are going with URL parameters
There is no obvious solution. The form generated by zf will be a standard html one. When submitted from the browser using GET it will result in a request like
/action/specified/in/form?var1=val1&var2=var2
Only solution to get a "zendlike url" (one with / instead of ? or &), would be to hack the form submission using javascript. For example you can listen for onSubmit, abort the submission and instead redirect browser to a translated url. I personally don't believe this solution is worth the added complexity, but it should perform what you're looking for.
After raging against this for a day-and-a-half, and doing my best to figure out the right way to do this fairly simple this, I gave up and did the following. I still can't believe there's not a better way.
The use case that necessitates this is a simple record listing, with a form up top for adding some filters (via GET), maybe some column sorting, and Zend_Paginate thrown in for good measure. I ran into issues using the Url view helper in my pagination partial, but I suspect with even just sorting and a filter-form, Zend_View_Helper_Url would still fall down.
But I digress. My solution was to add a method to my base controller class that merges any raw query-string parameters with the existing zend-style slashy-params, and redirects (but only if necessary). The method can be called in any action that doesn't have to handle POSTs.
Hopefully someone will find this useful. Or even better, find a better way:
/**
* Translate standard URL parameters (?foo=bar&baz=bork) to zend-style
* param (foo/bar/baz/bork). Query-string style
* values override existing route-params.
*/
public function mergeQueryString(){
if ($this->getRequest()->isPost()){
throw new Exception("mergeQueryString only works on GET requests.");
}
$q = $this->getRequest()->getQuery();
$p = $this->getRequest()->getParams();
if (empty($q)) {
//there's nothing to do.
return;
}
$action = $p['action'];
$controller = $p['controller'];
$module = $p['module'];
unset($p['action'],$p['controller'],$p['module']);
$params = array_merge($p,$q);
$this->_helper->getHelper('Redirector')
->setCode(301)
->gotoSimple(
$action,
$controller,
$module,
$params);
}