Column A = qty
Column F = Unit Price
Column G = Total Amount
Cell G7 contains =A7*F7. This formula works fine. However, if you copy the formula down, then you get $0.00 on lines that have no data. I tried putting in IF(A7>0,A7*F7). It returns nothing even if there is information in Cell A7 and Cell F7. Can someone help me with the correct syntax to get the value when needed and have the cell be blank when there is no item?
Related
I am trying to remove the formula from a column in a existing sheet with python.
I tryed to set my formula to None using the column object (column.formula = None)
It does not work and my column object remains unchanged. Anyone have inputs to solve this issue ? Thank you !
This took me a bit to figure out, but seems like I've found a solution. Turns out that this is a 2-step process:
Update the column object to remove the formula (by setting column.formula to an empty string).
For each row in the sheet, update the cell within that column to remove the formula (set cell.value to an empty string and cell.formula to None).
Completing the STEP 1 will remove the formula from the column object -- but that cell in each row will still contain the formula. That's why STEP 2 is needed -- STEP 2 will remove the formula from the individual cell in each row.
Here's some example code in Python that does what I've described. (Be sure to update the id values to correspond to your sheet.)
STEP 1: Remove formula from the Column
column_spec = smartsheet.models.Column({
'formula': ''
})
# Update column
sheetId = 3932034054809476
columnId = 4793116511233924
result = smartsheet_client.Sheets.update_column(sheetId, columnId, column_spec)
STEP 2: Remove the formula from that cell in each row
Note: This sample code updates only one specific row -- in your case, you'll need to update every row in the sheet. Just build a row object for each row in the sheet (like shown below), then call smartsheet_client.Sheets.update_rows once, passing in the array of row objects that you've built corresponding to all rows in the sheet. By doing things this way, you're only calling the API once, which is the most efficient way of doing things.
# Build new cell value
new_cell = smartsheet.models.Cell()
new_cell.column_id = 4793116511233924
new_cell.value = ''
new_cell.formula = None
# Build the row to update
row_to_update = smartsheet.models.Row()
row_to_update.id = 5225480965908356
row_to_update.cells.append(new_cell)
# Update row
sheetId = 3932034054809476
result = smartsheet_client.Sheets.update_rows(sheetId, [row_to_update])
I am still new to VBA. I wanted to clear all the contents of the data (Row 3 to Row 12, Row 15 to Row 24, etc) below the yellow headers, without deleting all of the headers as shown in the photos (Fig 1 becomes Fig. 2). The headers go all the way down to row 109 (increments of 12 from Row 1, so Rows 1,13,25 ...85). I have a code but its too basic and long:
Sub Clear_All()
Set Unitsheet = ThisWorkbook.Worksheets("Sheet"1)
Unitsheet.Range("A3:F12").ClearContents
Unitsheet.Range("A15:F24").ClearContents
.
.
.
.'up to
Unitsheet.Range("A111:F120").ClearContents
End Sub
I need a code that is short, since the rows may reach up to more than 1000.
Any help will be much appreciated.
|
|
V
Sub clear()
Dim i, rows As Long
rows = ActiveSheet.UsedRange.rows.Count
For i = 1 To rows
If Sheet1.Cells(i, 1).Interior.ColorIndex = -4142 Then
Sheet1.Cells(i, 1).EntireRow.ClearContents
End If
Next
End Sub
this function finds all used rows in sheet1
it iterates all rows , if color of cell in A column has no color index (-4142) it clears all contents in entire row
I have a 1x1 structure called imu_data.txyzrxyz1. It has one field called txyzrxyz1 and the value is 4877x7 double. I just want to "copy and paste" row 62 into row 63 (double up that row) so that the structure now becomes a 4878x7 structure. I've tried the following, with other versions without success:
extra_63 = imu_data.txyzrxyz1(63,:);
imu_data2.txyzrxyz1 = [{imu_data.txyzrxyz1(1:62,:) extra_63 imu_data.txyzrxyz1(63:end,:)}]
Thanks
You can index the row to duplicate twice while matrix indexing:
row_to_duplicate = 63;
yourdata = rand(100,10);
yourstruct.data = yourdata;
yourstruct.data = yourstruct.data([1:row_to_duplicate, row_to_duplicate:end],:)
So in case of 63, 1:row_to_duplicate will create a column vector from 1:63, and row_to_duplicate:end will create a column vector from 63:100 in this example. When combining these, 63 will occur twice, hence that row is duplicated.
You were almost there, you only had to get rid of the {}'s and put the data in the right orientation by using ; instead of a space between matrix entries to vertically concatenate instead of horizontally:
extra_63 = imu_data.txyzrxyz1(63,:);
imu_data2.txyzrxyz1 = [imu_data.txyzrxyz1(1:62,:); extra_63; imu_data.txyzrxyz1(63:end,:)]
I'm trying to sum only the visible rows for a report and I know the format is:
=Sum( iif( <use the condition of the Visibility.Hidden expression>, 0, Fields!A.Value))
In my report, I've set row visbility to:
=IIF(CInt(Fields!EM_ET.Value)=1 Or CInt(Fields!EM_ET.Value)= 2,True,False)
Not exactly sure what I'm missing, but when I use this as an expression:
=Sum(IIF(CInt(Fields!EM_ET.Value)=1 Or CInt(Fields!EM_ET.Value)= 2,True,False),0,Fields!EM_ET.Value)
I get this following error: Value expression for textrun'FTD1.Paragraph[0].TextRuns[0]' has a scope argument that is not valid for aggregate function.
You are giving the True/False as output to the SUM() from your expression.You need to change your expression as,
=Sum(IIF(CInt(Fields!EM_ET.Value) = 1 Or CInt(Fields!EM_ET.Value)= 2,0,Fields!EM_ET.Value))
Thanks coder of code.
I am getting some error message if i am using '0', so i replaced with nothing it's working. I thought it would be helpful.
=SUM(IIF(ISNOTHING(Fields!value1.Value) OR ISNOTHING(Fields!value2.Value),NOTHING,Fields!value1.Value))
I was having similar issues. I know this question has a marked answer, however it isn't entirely correct.
The following contains the code from the "marked correct" answer:
=Sum(IIF(CInt(Fields!EM_ET.Value) = 1 Or CInt(Fields!EM_ET.Value) = 2,0,Fields!EM_ET.Value))
The following snipit of code contains the code from above, with a slight tweak:
=Sum(IIF(CInt(Fields!EM_ET.Value) = 1 Or CInt(Fields!EM_ET.Value) = 2,NOTHING,Fields!EM_ET.Value))
By changing the "0" to "NOTHING" this will resolve any lingering issues with your formula. The formula I was having issues with was returning "#Error" in the cell that was supposed to return the sum of the visible cells in the column within the row group.
My formula originally looked like this:
=IIF(Sum(Fields!VCBitType.Value) <> 0 OR (Parameters!Details.Value = "Detail"), Sum(IIF((Fields!VCBitType.Value = 0) and (Parameters!Details.Value = "Dangerous"),0,Fields!VC.Value)), "")
I altered my formula after seeing Hari's comment above:
=IIF(SUM(Fields!VCBitType.Value) <> 0 OR (Parameters!Details.Value = "Detail"), SUM(IIF((Fields!VCBitType.Value = 0) and (Parameters!Details.Value = "Dangerous"),NOTHING, Fields!VC.Value)), "")
I wanted to set the cells value to "" (empty) rather than hide the cell entirely or set that cell's value to "0" in my report (due to the fact that not displaying the cell entirely made the report look really funky). Because I did this, using a "0" in my formula conflicted with the value of the cell which was "" (empty), causing the formula to break. The only change I made was to alter "0" to "Nothing", this resolved the issue I was having with the cell's formula.
I need to load a data file, test.dat, into Matlab. The contents of data file are like
*a682 1233~0.2
*a2345 233~0.8 345~0.2 4567~0.3
*a3457 345~0.9 34557~1.2 34578~0.2 9809~0.1 2345~2.9 23452~0.9 334557~1.2 234578~0.2 19809~0.1 23452~2.9 3452~0.9 4557~1.2 3578~0.2 92809~0.1 12345~2.9 232452~0.9 33557~1.6 23478~0.6 198099~2.1 234532~2.9 …
How to read this type of file into matlab, and use the terms, such as *2345 to identify a row, which links to corresponding terms, including 233~0.8 345~0.2 4567~0.3
Thanks.
Because each of the rows is a different size, you either have to make a cell array, a structure, or deal with adding NaN or zero to a matrix. I chose to use a cell array, hope it is ok! If someone is better with regexp than me please comment, the output cells are now not perfect (i.e. show 345~ instead of 345~0.9) but I am sure it is a minor fix. Here is the code:
datfile = 'test.dat';
text = fileread(datfile);
row1 = regexp(text,'*[a-z]?\d+','match');
data(:,1) = row1';
row2 = regexp(text,'*[a-z]?\d+','split');
row2 = [row2(:,2:end)'];
for i = 1:size(row2,1)
data{i,2} = regexp(row2{i},'\d+\S\d+\s','split');
end
What this creates is a cell array called data where the first column of every row is your *a682 id and the second column of each row is a cell with your data values. To get them you could use:
data{1}
to show the id
data{1,2}
to show the cell contents
data{1,2}{1}
to show the specific data point
This should work and is relatively simple!